I am currently running a query that runs a sum function and also divides this number. Currently I get values like 0.0904246741698848, and 1.6419814808335567. I want these decimals to be trimmed to 2 spaces past the decimal point. Their schema is a float. Here is my code. Thanks for the help.
#standardSQL
SELECT
Serial,
MAX(createdAt) AS Latest_Use,
SUM(ConnectionTime/3600) as Total_Hours,
COUNT(DISTINCT DeviceID) AS Devices_Connected
FROM `dataworks-356fa.FirebaseArchive.Firebase_ConnectionInfo`
WHERE PeripheralType = 1 or PeripheralType = 2 or PeripheralType = 12
GROUP BY Serial
ORDER BY Latest_Use DESC
#standardSQL
WITH `data` AS (
SELECT 0.0904246741698848 AS val UNION ALL
SELECT 1.6419814808335567
)
SELECT val, ROUND(val, 2) AS rounded_val
FROM `data`
for example, assuming your want apply this to your Total_Hours column :
#standardSQL
SELECT
Serial,
MAX(createdAt) AS Latest_Use,
ROUND(SUM(ConnectionTime/3600),2) AS Total_Hours,
COUNT(DISTINCT DeviceID) AS Devices_Connected
FROM `dataworks-356fa.FirebaseArchive.Firebase_ConnectionInfo`
WHERE PeripheralType = 1 OR PeripheralType = 2 OR PeripheralType = 12
GROUP BY Serial
ORDER BY Latest_Use DESC
I found that rounding was problematic if my data had a whole number such as 2.00 and I needed all of my data to reflect 2 decimal places as these were for prices that end up getting displayed. Big Query was returning 2.0 no matter what I specified to round to using ROUND.
Assuming you're working with data that never surpasses 2 decimal places, and it is stored as a STRING, this code will work (if it's more decimal places, add another 0 to the addition for each space).
FORMAT("%.*f",2,CAST(GROSS_SALES_AMT AS FLOAT64) + .0001)
This will take a float in BigQuery and format it with two decimal points.
CAST(SUM(ConnectionTime/3600) AS STRING FORMAT '999,999.99')
Note: Add a a currency symbol (e.g., $) for currency ($999,999.99).
Example:
You can always use the round() function.
If you are looking for precision after decimal (as using round will round-off the values) you can use substr(str(value),precision) which will give exact output after decimal.
Related
I have a table in PostgreSQL, that have a Float column. In my select I use AVG() on that column, so often it gives a number with many decimals. Is there any way to retrict the number of decimals to a maximum of 3, meaning there can be less but not more than 3.
This is the Query:
SELECT team, AVG(score) FROM team_score_table GROUP BY team
You can use round():
select round(val::numeric, 3)
You can also convert to a numeric, but you need a precision appropriate for your values:
select val::numeric(20, 3)
I actually prefer the explicit cast() because it sets the data type of the column to a numeric with an explicit scale -- so downstream apps are aware of the number of decimal places intended in the result.
round() returns a numeric value but it is a "generic" numeric, with no specified scale and precision.
You can see the difference in this example.
You can use a several functions to do that:
SELECT round(42.43666, 2) -- 42.44
SELECT trunc(42.43666, 2) -- 42.43
or cast:
SELECT cast(42.43666 as numeric(20, 2)) -- 42.44
according to your example should be:
SELECT team, round(AVG(score)::numeric, 2) FROM team_score_table GROUP BY team
SELECT team, trunc(AVG(score)::numeric, 2) FROM team_score_table GROUP BY team
SELECT team, cast(AVG(score) as numeric(20,2)) FROM team_score_table GROUP BY team
I am trying to calculate the average ice creams a kid will have during summer.
I want the result to have 2 decimals.
Query:
Select day, (sum(ice_cream_cones) *1.0)/(select count(kids))
From t1 Group by 1
The result I get is something like 1.0003. I only want 2 decimal points.
Any suggestions?
You can do this with round
Select day, round((sum(ice_cream_cones) *1.0)/(select count(kids) ), 2)
From t1
Assuming your source data are integers...
SUM(ice_cream_cones) * 100 / COUNT(kids) / 100.0
Or, cast your existing calculation to a decimal?
CAST(<calc> AS DECIMAL(8,2))
I have two columns called quantity and price. Quantity is divided by price. If the result contains decimal, I want the number before the decimal. Or else, the number as it is.
I think you are looking for:
select floor(quantity / price) as output
Casting issues?
select cast(quantity / price as bigint)
By the way, I think you may want this:
Hive Data Types Manual
Also DIV operator can be used (for integer arguments):
with your_data as (
select stack(3, 13,2,8,2,233,2) as(quantity,price)
)
select quantity div price
from your_data d
;
Result:
6
4
116
I am working on SQL Server. I have a table that has an int column HalfTimeAwayGoals and I am trying to get the AVG with this code:
select
CAST(AVG(HalfTimeAwayGoals) as decimal(4,2))
from
testtable
where
AwayTeam = 'TeamA'
I get as a result 0.00. But the correct result should be 0.55.
Do you have any idea what is going wrong ?
select
AVG(CAST(HalfTimeAwayGoals as decimal(4,2)))
from
testtable
where
AwayTeam = 'TeamA'
If the field HalfTimeAwayGoals is an integer, then the avg function does an integer average. That is, the result is 0 or 1, but cannot be in between.
The solution is to convert the value to a number. I often do this just by multiplying by 1.0:
select CAST(AVG(HalfTimeAwayGoals * 1.0) as decimal(4, 2))
from testtable
where AwayTeam = 'TeamA';
Note that if you do the conversion to a decimal before the average, the result will not necessary have a scale of 4 and a precision of 2.
Can you try dividing by 1.00 to convert the integer into decimal?
select
AVG(HalfTimeAwayGoals/1.00) as average
from
testtable
where
AwayTeam = 'TeamA'
I used the /1.00 OR /1.0000 trick on various databases to do the job. Unfortunately, I don't have access MS-SQL to try it. The division of integer by 1.00 will change the integer to decimal.
SELECT AVG(integerfield/1.00) FROM table
In MySQL
SELECT AVG(integerfield) FROM table
gives me 4 decimal points.
If I do
SELECT AVG(integerfield/1.00) FROM table
I get 8 decimal points.
I'm loading big data into database,
i want to know how this process going.
i use
select count(*) from table
to check how many rows loaded.
and now i want to get a Percentage of the process.
i tried:
select ( count(*)/20000 ) from table
and
select cast( ( count(*)/20000 ) as DECIMAL(6,4) ) from table
but they all return 0 ,
so how can i do this?
And better if it can show the percentage .
thanks
Integer division returns an integer, the decimal part is truncated. You could divide by 20000.0:
select ( count(*)/20000.0 ) from table
Demo
MSDN / (Divide)
If an integer dividend is divided by an integer divisor, the result is
an integer that has any fractional part of the result truncated.
Select CONVERT(DECIMAL(6,4),COUNT(*)) / CONVERT(DECIMAL(6,4),20000) FROM TABLE
-
Its important that you match the type explicitly because not all numbers are integers and not all decimals are the same. DECIMAL(6,4) is effectively its own data type which is not the same as DECIMAL(6,3).