Which code do I need to retrieve a single value i from a column from table in SQL?
user_comment_count
This is column name in table
table is :
zmar_hreviews_list_total
This is code I use with error:
<?php
$insert1 ="/// ";
$string = "ars <pre>{$insert1}</pre>";
$query = 'SELECT user_comment_count FROM zmar_hreviews_list_total WHERE contentid = '.$item->getId();
$db->setQuery( $query );
$result = $db->loadResult();
if($result) {
$result = str_replace('*','',$result);
print_r($insert1); print_r($result);
}
?>
try:
select user_comment_count from zmar_hreviews_list_total
Related
I'm trying to select a specific row from the SQL database connected to flutter but I want value of the row ID to be supplied remotely from flutter app
<?php
require_once('database.php');
$query = 'SELECT * FROM books WHERE book_id = (this value will be a variable supplied by what the users selects in the app)';
$stm = $db->prepare($query);
$stm->execute();
$array = array();
while ($resultsFrom = $stm -> fetch()){
array_push(
$array,array(
'book_description' => $resultsFrom['description'],
'price' => $resultsFrom['initial_price'],
)
);
}
echo json_encode($array);
?>
I have two tables: products and current_product_attribute_values
I have tried a join query to filter them as per attribute selected by the user but when I try this with an additional condition it gives me 2 results instead of one it is including the first one which is not matching as per query:
select * from `products` inner join `current_product_attribute_values` on `products`.`id` = `current_product_attribute_values`.`product_id` where `current_product_attribute_values`.`attribute_id` = ? or `current_product_attribute_values`.`attribute_value_id` = ? and `current_product_attribute_values`.`attribute_id` = ? or `current_product_attribute_values`.`attribute_value_id` = ? and `product_name` LIKE ?
here is my laravel Controller code :
$all = Input::all();
$q = Input::get('search_text');
$att_val = Input::get('attribute_value');
$subcat = Input::get('subcat_id');
$subcat_name = DB::table('subcategories')->where('id', $subcat)->value('subcategory_name');
$brandname = DB::table('brands')->where('subcat_id', $subcat)->value('brand_name');
$brand_id = DB::table('brands')->where('subcat_id', $subcat)->value('id');
$product_count = DB::table('products')->where('brand_id', $brand_id)->count();
if ($q != "") {
// getting multiple same name params
$query = DB::table('products');
$query->join('current_product_attribute_values', 'products.id', '=', 'current_product_attribute_values.product_id');
$j = 0;
foreach ($all as $key => $values) {
//echo 'my current get key is : ' . urldecode($key). '<br>';
if ($key == $name[$j]) {
$query->where('current_product_attribute_values.attribute_id', '=', $att_id_value[$j]);
echo'<br>';
print_r($query->toSql());
echo'<br>';
//echo '<br> key matched and have some value : <br>';
//echo count($values);
if (count($values) >= 1) {
//echo '<br> it has array inside <br>';
foreach ($values as $val) {
// or waali query in same attribute
echo'<br>';
$query->orwhere('current_product_attribute_values.attribute_value_id', '=', $val);
print_r($query->toSql());
echo'<br>';
}
}
$j++;
}
}
$records = $query->toSql();
$query->where('product_name', 'LIKE', '%' . $q . '%');
$records = $query->toSql();
print_r($records);
$products = $query->paginate(10)->setPath('');
$pagination = $products->appends(array(
'q' => Input::get('q')
));
if (count($products) > 0) {
$filters = DB::table('product_attributes')->where('subcategory_id', $subcat)->get(['attribute_title']);
} else {
$filters = array();
}
$categories = categories::where('add_to_menu', 1)->with('subcategories')->with('brands')->get();
$categoryhome = categories::where('add_to_menu', 1)->with('subcategories')->get();
return view('searchfilter')
->with('productsdata', $products)
->with('filtersdata', $filters)
->with('categories', $categories)
->with('categorieshome', $categoryhome)
->with('subcat_name', $subcat_name)
->with('subcat_id', $subcat)
->with('brandname', $brandname)
->with('product_count', $product_count)
->with('querytext', $q);
}
return 'No Details found. Try to search again !';
its easier if you use raw sql as calling db select function. ex:
$query=DB::select("select * from `products` inner join `current_product_attribute_values` on `products`.`id` = `current_product_attribute_values`.`product_id` where `current_product_attribute_values`.`attribute_id` = ? or `current_product_attribute_values`.`attribute_value_id` = ? and `current_product_attribute_values`.`attribute_id` = ? or `current_product_attribute_values`.`attribute_value_id` = ? and `product_name` LIKE ?
");
indeed you can concat vars in raw sql if you need to, ex:
$queryBrands = "select id from brands where subcat_id =".$subcat;
//echo $queryBrands
$queryBrands = DB::select($queryBrands);
By looking at your tables, product table with id value 17 has two records in table current_product_attribute_values in column product_id (I assume this column is used as foreign key to product table).
With select *, you select all of the columns from both tables. So it would most likely cause your query to return multiple records.
My suggestions:
Only select the columns you need. Avoid using select * in the long run, i.e. select product.id, product.description, current_product_attribute_values.attribute_values ......
Make use of GROUP BY
Hope these helps.
Below is my code:
<?php
$url = $_GET['url'];
$wordlist = array("Www.", "Http://", "Http://www.");
foreach ($wordlist as &$word) {
$word = '/\b' . preg_quote($word, '/') . '\b/';
}
$url = preg_replace($wordlist, '', $url);
?>
<?php
$oDB = new PDO('mysql:dbname=mcnsaoia_onsafe;host=localhost;charset=utf8', 'mcnsaoia_xx', 'PASSWORD');
$hStmt=$oDB->prepare("SELECT * FROM users WHERE hjemmside = :hjemmside AND godkendt=ja");
$hStmt->execute(array('hjemmside' => $url));
if( $row = $hStmt->fetch() ){
echo "EXIST";
}else{
echo "NOT EXIST";
}
?>
My problem is that it says NOT EXIST, because I know that there is a row which should be found with the following query:
SELECT * FROM users WHERE hjemmside = :hjemmside AND godkendt=ja
So why does it say not exist? I have absolutely no idea :(
Instead of
$hStmt=$oDB->prepare("SELECT * FROM users WHERE hjemmside = :hjemmside
AND godkendt=ja");
try
$hStmt=$oDB->prepare("SELECT * FROM users WHERE hjemmside = :hjemmside
AND godkendt='ja'");
The left is most likely a column and the right side is a string? I don't speak your language, but this is the first thing coming to my mind.
You should surround with quotes your not integer variable in your query
AND godkendt='ja'
Or maybe let pdo deal with it
$hStmt=$oDB->prepare("SELECT * FROM users WHERE hjemmside = :hjemmside AND godkendt = :ja");
$hStmt->execute(array(':hjemmside' => $url, ':ja' => 'ja'));
//^ i added : for placeholder here, you missed it
I would also rather check if rows are returned
if($hStmt->$eowVount() > 0){
$row = $hStmt->fetch()
echo "EXIST";
}else{
echo "NOT EXIST";
}
I have a basic MySQL database table People with 3 columns (ID, Name, Distance)
I am trying to output this with PHP as a JSON so my web app can pick it up. I tried using the solution from another answer:
$sth = mysql_query($con,"SELECT * FROM People");
$rows = array();
while($r = mysql_fetch_assoc($sth)) {
$rows[] = $r;
}
print json_encode($rows);
However I am just returning a blank array of [].
Update: Changed to mysqli and added dumps:
$sth = mysqli_query("SELECT * FROM Events",$con);
$rows = array();
var_dump($sth);
while($r = mysqli_fetch_assoc($sth)) {
var_dump($rows);
$rows[] = $r;
}
print json_encode($rows);
Returns:
NULL []
Swap your query and connection in the mysql_query-statement:
$sth = mysql_query("SELECT * FROM People", $con);
Besides that, the mysql-library is deprecated. If you're writing new code consider using mysqli_ or PDO.
Why no mysql_connect ?
var_dump($sth); // check the return of mysql_query()
var_dump($rows); // check the array of mysql_fetch_assoc result
I would check if your query is returning any rows first.
<?php
$rows = array();
array_push($rows, array("name" => "John"));
array_push($rows, array("name" => "Jack"));
array_push($rows, array("name" => "Peter"));
print json_encode($rows);
?>
Produces this output.
[{"name":"John"},{"name":"Jack"},{"name":"Peter"}]
Solved using a combination of answer to get:
$sth = mysqli_query($con,"SELECT * FROM Events");
$datarray = array();
while($row = mysqli_fetch_assoc($sth)) {
$datarray[] = $row;
}
print_r(json_encode($datarray));
The following function gives all the related data except artist_id, when run I have checked all elements in the database and ok.
If I change the artist_id to an actual 'id' it shows in the result of the function as WHERE artist_id = 4 AND........
Confess I do not understand what is causing this.
Result of the function:
SELECT `image_album_id`, `member_id`, `artist_id`, `albumname`, `ext`, `timestamp`
FROM album_images WHERE artist_id = AND member_id = 1 AND
image_album_id = 160
<?php
function get_data_nxtprv($fields, $where) {
$return = FALSE;
// Template
$template = "SELECT %s "
. "FROM album_images "
. "WHERE artist_id = " . $artist_id. "
AND member_id = ".$_SESSION['member_id']." %s";
// Current record
$sql = sprintf($template, $fields, $where);
$query = mysql_query($sql);
$query_result = mysql_fetch_assoc($query);
//print_r($sql);
// If data has been found
if ($query_result)
{
$return = $query_result;
}
return $return;
?>
I am not entirely sure I understand your question. But I noticed that your function uses three input variables:
$artist_id, $fields, $where
But $artist_id is not getting passed as an argument.
You would need to modify the function call:
function get_data_nxtprv($artist_id, $fields, $where)
There is an error in your SQL
SELECT `image_album_id`, `member_id`, `artist_id`, `albumname`, `ext`, `timestamp`
FROM album_images WHERE artist_id = AND member_id = 1 AND
image_album_id = 160
should it not be
SELECT `image_album_id`, `member_id`, `artist_id`, `albumname`, `ext`, `timestamp`
FROM album_images WHERE member_id = 1 AND
image_album_id = 160
if artist_id is one of the fields you're looking for?