SQL Substring Functions - sql

Question

I have a column named full name. I want to split them into two columns, first name and last name.
I am having a trouble with a persons with two first names. If the first name encounters a space it was considered last name.
I want this:
Full name : John Michael Smith
Firstname: John Michael
Lastname: Smith
However, I am getting:
Firstname: John
Lastname: Michael Smith

Answer 1

Try:
declare #n varchar(max) = 'John Michael Smith'
select REVERSE(SUBSTRING(REVERSE(#n), CHARINDEX(' ', REVERSE(#n)), 100)) FirstName

Answer 2

Check the below link:
SQL SERVER – Reverse String Word By Word – Part 2

Answer 3

You can split the string by checking for the index of last space and using it with LEFT and RIGHT function.
DECLARE #name varchar(100)= 'John Michael Smith'
SELECT LEFT(#name,LEN(#name)-CHARINDEX(' ',REVERSE(#name))) AS [Firstname],RIGHT(#name,CHARINDEX(' ',REVERSE(#name))) AS [LastName]

Answer 4

--Create table from below script
create table users(id int IDENTITY(1,1) PRIMARY KEY, name varchar(50));
--Insert Record for query for testing
insert into users(name)
values('John Abraham'),
('John Mark Abraham'),
('John Vens Abraham'),
('John Abraham');
--Run below query for getting all inserted records.
select * from users;
--Run below query for getting first and last name from name
select id , name, SUBSTRING(name,0, CHARINDEX(last_name,name)) as first_name, last_name from
(
select id, name, REVERSE(SUBSTRING(REVERSE(name),0,CHARINDEX(' ',REVERSE(name)))) as last_name from users
) as A

Answer 5

You can hi-jack 'parsename'. This only works up to 4 intervals but a nice option;
declare #name varchar(100)
set #name='John Michael Smith'
select PARSENAME(REPLACE(#name,' ','.'),1) -- returns Smith
select PARSENAME(REPLACE(#name,' ','.'),2) -- returns Micheal
select PARSENAME(REPLACE(#name,' ','.'),3) -- Returns John
select PARSENAME(REPLACE(#name,' ','.'),4) -- returns NULL