I understand that in order to find records that contain more than one word, I need to use AND between them, like this:
select *
from table1
where contains(name , '"bob" AND "marly"')
The problem is that my user doesn't type "bob" AND "marly", he types bob marly.
Before I start parsing this string and splitting it, is there a cleaner way to do this?
I'm using SQL Server 2012.
Thanks.
The below query will check if the string contains bob marly.
SELECT * FROM table1 WHERE name LIKE '%'+'bob'+'%'+'marly'+'%'
Related
I was reading the article at mssqltips and wanted to try the caret in regex. I understand regex pretty well and use it often, although not much in SQl Server queries.
For the following list of names, I had thought that 1) select * from people where name like '%[^m]%;' will return those names that do not contain 'm'. But it doesn't work like that. I know I can do 2) select * from people where name not like '%m%'; to get the result I want, but I'm just baffled why 1) doesn't work as expected.
Amy
Jasper
Jim
Kathleen
Marco
Mike
Mitchell
I am using SQL Server 2017, but here is a fiddle:
sql fiddle
'%[^m]%' would be true for any string containing a character that is not m. An expanded version would be '%[Any character not m]%'. Since all of those strings contain a character other than m, they are valid results.
If you had a string like mmm, where name like '%[^m]%' would not return that row.
In Postgresql database I have a column called names where I have some names which need to be parsed using regex to clean up punctuation parts. I am able to get a clean name using regexp_replace as follows:
select regexp_replace(name,'\.COM|''[A-Z]|[^a-zA-Z0-9 -]+|\s(?=&)|(?<!\w\w)(?:\s+|-)(?!\w\w)','','g')
from tableA
However, I would like to compare with some strings that are also cleaned of punctuation. How can I use similar to with the formed regular expression?
select name
from tableA
where (lower(name) ~ '\.COM|''[A-Za-z]|[^a-zA-Z0-9 -]+|\s(?=&)|(?<!\w\w)(?:\s+|-)(?!\w\w)') as nameParsed similar to '(fg )%' and
(lower(name) ~ '\.COM|''[A-Za-z]|[^a-zA-Z0-9 -]+|\s(?=&)|(?<!\w\w)(?:\s+|-)(?!\w\w)') as nameParsed similar to '%( cargo| carrier| cartage )%'
With the previous query I am getting this error:
LINE 3: ...-zA-Z0-9 -]+|\s(?=&)|(?<!\w\w)(?:\s+|-)(?!\w\w)') as namePar...
I have tried in where clause like this and it seems to be working:
select name
from tableA
where (select lower(regexp_replace(name,'\.COM|''[A-Z]|[^a-zA-Z0-9 -]+|\s(?=&)|(?<!\w\w)(?:\s+|-)(?!\w\w)','','g'))) similar to '(fg )%'
Is this the best approach? The execution time went to 46 seconds :(
Thanks in advance
You're trying to get a column name in a WHERE clause (is a comparison, not a column). So, you can use as follows:
SELECT name
FROM "tableA"
WHERE (regexp_replace(name,'\.COM|''[A-Z]|[^a-zA-Z0-9 -]+|\s(?=&)|(?<!\w\w)(?:\s+|-)(?!\w\w)','','g') similar to '(fg )%'
OR regexp_replace(name,'\.COM|''[A-Z]|[^a-zA-Z0-9 -]+|\s(?=&)|(?<!\w\w)(?:\s+|-)(?!\w\w)','','g') similar to '%( cargo| carrier| cartage )%');
Alternatively, you can use ilike instead of similar to if you want to find a specific word.
i've got a problem with transferring "real-World" data into my schema.
It's actually a "project" for my Database course and they gave us ab table with dog race results. This Table has a column which contains the name of the Dog (which itself consists of the actuall name and the name of the breeder) and informations about the Birthcountry, actual living Country and the birth year.
Example filed are "Lillycette [AU 2012]" or "Black Bear Lee [AU/AU 2013]" or "Lemon Ralph [IE/UK 1998]".
I've managed it to get out the first word and save it in the right column with split_part like this:
INSERT INTO tblHund (rufname)
SELECT
split_part(name, ' ', 1) AS rufname,
FROM tblimport;
tblimport is a table where I dumped the data from the csv file.
That works just as it should.
Accessing the second part of the Name with this fails because sometimes there isn't a second part and sometimes times there second part consists of two words.
And this is the where iam stuck right now.
I tried it with substring and regular expressions:
INSERT INTO tblZwinger (Name)
SELECT
substring(vatertier from E'[^ ]*\\ ( +)$')AS Name
FROM tblimport
WHERE substring(vatertier from E'[^ ]*\\ ( +)$') != '';
The above code is executed without errors but actually does nothing because the SELECT statement just give empty strings back.
It took me more then 3h to understand a bit of this regular Expressions but I still feel pretty stupid when I look at them.
Is there any other way of doing this. If so just give me a hint.
If not what is wrong with my expression above?
Thanks for your help.
You need to use atom ., which matches any single character inside capturing group:
E'[^ ]*\\ (.+)$'
SELECT
tblimport.*,
ti.parts[1] as f1,
ti.parts[2] as f2, -- It should be the "middle part"
ti.parts[3] as f3
FROM
tblimport,
regexp_matches(tblimport.vatertier, '([^\s]+)\s*(.*)\s+\[(.*)\]') as ti(parts)
WHERE
nullif(ti.parts[2], '') is not null
Something like above.
I want to write an SQL SERVER statement that searches for the beginning of a word in a string that starts with something.
For example, if I search for 'em' on the Company record, I should get:
Emily, Inc
The Emmmy
NOT
Forget Them
Lemming, LLC
I can do this in PHP by extracting/slicing the string into an array and searching the beginning of each words.
But how I would write this query in SQL server without resorting to Stored procedures/functions?
JW's answer will work for entries where Em is at the very beginning of the field.
If you also need to retrieve values where the word is not the first in the string, try:
SELECT * FROM tableName WHERE CompanyName LIKE 'Em%' or CompanyName LIKE '% Em%'
(This is assuming all word are separated by a space.)
use LIKE
SELECT * FROM tableName WHERE CompanyName LIKE 'Em%'
Another option is CONTAINS, something like:
SELECT ... WHERE CONTAINS(CompanyName, 'Em*');
For MS Access:
SELECT * FROM Table1 WHERE Company_Name LIKE 'Word*'
For more standard DBMSs:
SELECT * FROM Table1 WHERE Company_Name LIKE 'Word%'
If I have a query to return all matching entries in a DB that have "news" in the searchable column (i.e. SELECT * FROM table WHERE column LIKE %news%), and one particular row has an entry starting with "In recent World news, Somalia was invaded by ...", can I return a specific "chunk" of an SQL entry? Kind of like a teaser, if you will.
select substring(column,
CHARINDEX ('news',lower(column))-10,
20)
FROM table
WHERE column LIKE %news%
basically substring the column starting 10 characters before where the word 'news' is and continuing for 20.
Edit: You'll need to make sure that 'news' isn't in the first 10 characters and adjust the start position accordingly.
You can use substring function in a SELECT part. Something like:
SELECT SUBSTRING(column, 1,20) FROM table WHERE column LIKE %news%
This will return the first 20 characters from column column
I had the same problem, I ended up loading the whole field into C#, then re-searched the text for the search string, then selected x characters either side.
This will work fine for LIKE, but not full text queries which use FORMS OF INFLECTION because that may match "women" when you search for "woman".
If you are using MSSQL you can perform all kinds VB-like of substring functions as part of your query.