I need a request that displays the name and surname of the clients with the smallest credit limit - among married women who do not live in Japan, Brazil or Italy.
Diagram:
This will Give all the people not in 'Japan', 'Brazil' or 'Italy') ,
Select C.Cust_first_name,C.Cust_Last_name from Customers C
Inner Join Countries C1
on C.Country_Id=C1.Country_Id
Where C1.Country_Name Not in('Japan', 'Brazil' or 'Italy')
and
C.Cust_Credit_Limit=(Select Min(Cust_Credit_Limit) From from Customers C)
If we Convert The Question to Code that will be the above code,
The Script would return the name and last name of person not in ('Japan', 'Brazil' or 'Italy') And has the lowest salary In the entire customer Base.
select top 1 * from Customers C
Inner Join
(
select MIn(cust_credit_limit) from Customers C1
Inner Join Countries CT on C1.Country_id = C1.Country_id
where CT.Country_Name Not in ('Japan', 'Brazil','Italy')
)
C2 on C2.cust_credit_limit = C.cust_credit_limit
Related
For questions below, use the following schema definition.
restaurant(rid, name, phone, street, city, state, zip)
customer(cid, fname, lname, phone, street, city, state, zip)
carrier(crid, fname, lname, lp)
delivery(did, rid, cid, tim, size, weight)
pickup(did, tim, crid)
dropoff(did, tim, crid)
It's a schema for a food delivery business that employs food carriers (carrier table).
Customers (customer table) order food from restaurants (restaurant table).
The restaurants order a delivery (delivery table); to deliver food from restaurant to customer.
The pickup table records when carrier picks up food at restaurant.
The dropoff table records when carrier drops off food at customer.
1.Find customers who have less than 5 deliveries.
a. select cid,count()
from delivery
group by cid
having count() < 5;
b. select a.cid,count()
from customer a
inner join delivery b
using(cid)
group by a.cid
having count() < 5;
c. select a.cid,count()
from customer a
left outer join delivery b
on a.cid=b.cid
group by a.cid
having count() < 5;
d. select cid,sum(case when b.cid is not null then 1 else 0 end)
from customer a
left outer join delivery b
using (cid)
group by cid
having sum(case when b.cid is not null then 1 else 0 end) < 5;
e. (write your own answer)
No, they are not correct. They miss customers who have had no deliveries.
The last is the best of a bunch of not so good queries. A better version would be:
select c.cid, count(d.cid)
from customer c left outer join
delivery d
on c.cid = d.cid
group by c.cid
having count(d.cid) < 5;
The sum(case) is over kill. And Postgres even offers a better solution than that!
count(*) filter (where d.cid is not null)
But count(d.cid) is still more concise.
Also note the use of meaningful table aliases. Don't get into the habit of using arbitrary letters for tables. That just makes queries hard to understand.
query to extract the data from the customer table if and only if one or more of the customers in the customer table are located in London
and my query is
select * from Customer
where 'London' = ANY (select city from Customer)
I know it's not the correct way but I wanted to know if this also works or not.
TIA
Your query works, so that is one way to express it (and rather clever). Here is an example.
More commonly, I think of this as anexists query:
select c.*
from Customer c
where exists (select 1 from Customer c2 where c2.city = 'London');
This will return all customers from any city, even those not in London.
It is quite possible that you just want to return customers in London, in which case a simple where city = 'London' suffices.
select * from Customer where city ='London' and 1 > (select count(*) from Customer where city='London');
Short context:
I would like to show a list of all companies except if they are in the sector 'defense' or 'government' and their individual total spent on training classes. Only the companies that have this total amount above 1000 must be shown.
So I wrote the following query:
SELECT NAME, ADDRESS, ZIP_CODE, CITY, SUM(FEE-PROMOTION) AS "Total spent on training at REX"
FROM COMPANY INNER JOIN PERSON ON (COMPANY_NUMBER = EMPLOYER) INNER JOIN ENROLLMENT ON (PERSON_ID = STUDENT)
WHERE SECTOR_CODE NOT IN (SELECT CODE
FROM SECTOR
WHERE DESCRIPTION = 'Government' OR DESCRIPTION = 'Defense')
GROUP BY NAME, ADDRESS, ZIP_CODE, CITY
HAVING SUM(FEE-PROMOTION) > 1000
ORDER BY SUM(FEE-PROMOTION) DESC
Now what I actually need is, instead of defining every single column in the COMPANY table, I would like to show ALL columns of the COMPANY table using *.
SELECT * (all tables from COMPANY here), SUM(FEE-PROMOTION) AS "Total spent on training at REX"
FROM COMPANY INNER JOIN PERSON ON (COMPANY_NUMBER = EMPLOYER) INNER JOIN ENROLLMENT ON (PERSON_ID = STUDENT)
WHERE SECTOR_CODE NOT IN (SELECT CODE
FROM SECTOR
WHERE DESCRIPTION = 'Government' OR DESCRIPTION = 'Defense')
GROUP BY * (How to fix it here?)
HAVING SUM(FEE-PROMOTION) > 1000
ORDER BY SUM(FEE-PROMOTION) DESC
I could define every single column from COMPANY in the SELECT and that solution will do the job (as in the first example), but how can I make the query shorter using "SELECT * from the table COMPANY"?
The key idea is to summarize in the subquery to get the total spend for the company. This allows you to remove the aggregation from the outer query:
select c.*, pe.total_spend
from company c join
sector s
on c.sector_code = s.code left join
(select p.employer, sum(e.fee - e.promotion) as training_spend
from person p join
enrollment e
on p.person_id = e.student
group by p.employer
) pe
on pe.employer = c.company_number
where s.sector not in ('Government', 'Defense') and
pe.total_spend > 1000
I have 4 different tables:
Address: address_id, postcode.
Patient: address_id, name.
FocusArea: geom.
Postcode: geom, postcode.
I need to find the name of the patients that live within the focus area.
I have managed to get the postcodes where the patients live, and the postcodes within the focus area, but I don't know how to join both queries:
SELECT
air.address.postcode, air.patient.name
FROM
air.address
INNER JOIN
air.patient ON patient.address_id = address.address_id;
SELECT
postcode as postcode
FROM
air.postcode, air.focusarea
WHERE
air.focusarea.objectid = 1
AND ST_Intersects(air.postcode.geom, air.focusarea.geom);
air.focusarea.objectid = 1 as there are different boundaries of the focus area.
Any ideas?
Thank you
Tania
select
a.postcode, p.name
from air.address as a
inner join air.patient as p on
p.address_id = a.address_id
inner join air.postcode as pc on
pc.postcode = a.postcode
inner join air.focusarea as fa on
fa.objectid = 1 and
ST_Intersects(pc.geom, fa.geom);
I'm trying to identify a student's home district by joining a student's zip code to a district zip code. A given district may overlap several zip codes, so several possible home districts may appear for the student. For example, Zip code 99999 may include the Houston and Sugarland school districts. I can narrow down the home district to a single record when the student's city has the same name as the district name as for example if the student's city is Houston and the district name is Houston. In that case, I only want to retrieve the Houston district, not both Houston and Sugarland. However, if the student happened to live in Bayou with the zip code of 99999, then I'd want to retrieve both Houston and Sugarland districts since I don't have a fix on the district. I've tried several approaches but cannot come up with a solution. Here's
a primitive attempt:
Select S.Name, S.City, S.Zip, D.DistrictName
From tblStudent S
Left Join tblDistrict D on D.zip=S.zip
Where
(Case
When D.DistrictName=S.City then D.DistrictName
Else D.DistrictName
End)=D.DistrictName
Any suggestions are greatly appreciated!
You can try selecting each case separately and then making a union of the two queries.
Case 1: District Name equals City Name
Case 2: There is no District Name that is equal to the City Name
Something like this:
Select S.Name, S.City, S.Zip, D.DistrictName
From tblStudent S
Inner Join tblDistrict D on D.zip=S.zip and D.DistrictName = S.City
Union
Select S.Name, S.City, S.Zip, D.DistrictName
From tblStudent S
Inner Join tblDistrict D on D.zip=S.zip
Where not exists (
Select D2.* from tblDistrict D2
Where D2.DistrictName = S.City
And D2.zip = S.zip
)
SQL Fiddle: http://sqlfiddle.com/#!9/06d6d7/2/0