Is there a way to cast a date to timestamp. For an example if I had a date like 2012/05/01, how can I convert it to a timestamp like 2012-05-01 00:00:01
You can convert it to a timestamp with this code:
SELECT current_date::timestamp
It will directly assign the time 00:00:00 to current_date.
You can cast the date column to text and then concatenate with the time portion of the timestamp. In the query below I create a timestamp from the current date.
select (cast(current_date as text) || ' 00:00:01'):: timestamp
from yourTable;
Or if we already have a date type, we can simply add on the time component:
select current_date + '00:00:01'::time
Output:
11.07.2017 00:00:01
Demo
Update:
If you just want the difference in months between two dates you can use the following:
DATE_PART('month', AGE(end_date, start_date))
Of course, there is no time component involved here, but assuming you were planning to assign the dummy 00:00:01 to both timestamps, the result would not change.
select cast(current_date as timestamp) + interval '1 second'
Close to Standard SQL, only the interval syntax differs interval '1' second.
You can add time part to date
select current_date + '00:00:01'::time
Related
I have a table with date column in which date is updated in this format - 11/21/2022.
How can I get the results for the last 15 days using this date column in Teradata? Looks like need to change the date format in where clause.
I was using below query which does not work with this format
select *
from table_A
WHERE date BETWEEN (CURRENT_DATE - INTERVAL '30' DAY)
AND CURRENT_DATE
This does not give any results.
Assuming your date column be text, then you must first convert it to a bona fide date using the TO_DATE() function:
SELECT *
FROM table_A
WHERE TO_DATE("date", 'MM/DD/YYYY') BETWEEN (CURRENT_DATE - INTERVAL '30' DAY) AND CURRENT_DATE;
Note that ideally you should be storing your dates in actual date columns, not as text. This would avoid the need to call the clunky TO_DATE() function.
I have these varchar : 20211026231735.
So I would like a query to substract actual sysdate to that date and convert the substraction to DAY HOURS AND SECONDS.
select TO_CHAR(SYSDATE,'YYYYMMDDHH24MISS') - start_time from TABLEA where job_name='jOB_AA_BB';
I get 4220.
Any help please? Thanks
When you do datetime arithmetic with the DATE datatype, you get back a NUMBER of days. To get an INTERVAL you can subtract two TIMESTAMPs. You don't say what the data type is for start_time, but you might get away with this:
select localtimestamp - start_time
from tablea where job_name='jOB_AA_BB';
LOCALTIMESTAMP gives you a TIMESTAMP value in the current session time zone. There's also CURRENT_TIMESTAMP, which give you the same thing in a TIMESTAMP WITH TIME ZONE and SYSTIMESTAMP that gives you the database time in TIMESTAMP WITH TIME ZONE. You may need to convert your start_time to avoid time zone differences, if any.
You can us the function numtodsinterval to convert the results of date arithmetic to an interval. If necessary then use extract to pull out the needed components.
with tablea(job_name, start_time) as
(select 'jOB_AA_BB','20211026231735' from dual)
select numtodsinterval((SYSDATE - to_date( start_time,'yyyymmddhh24miss')),'hour') date_diff
from tablea where job_name='jOB_AA_BB' ;
with tablea(job_name, start_time) as
(select 'jOB_AA_BB','20211026231735' from dual)
select extract (hour from date_diff) || ':' || extract (minute from date_diff)
from (
select numtodsinterval((sysdate - to_date( start_time,'yyyymmddhh24miss')),'day') date_diff
from tablea where job_name='jOB_AA_BB'
);
NOTE: I am not sure how you got any result, other than an error, as your query winds up as a string - a string. You should not convert sysdate to a string but your string to a date (better yet store it as the proper data type - date).
You can convert the value to a date (rather than converting SYSDATE to a string) and then subtract and explicitly return the value as an INTERVAL DAY TO SECOND type:
SELECT (SYSDATE - TO_DATE('20211026231735', 'YYYYMMDDHH24MISS')) DAY TO SECOND
FROM DUAL;
Or, for your table:
SELECT (SYSDATE - TO_DATE(start_time,'YYYYMMDDHH24MISS')) DAY(5) TO SECOND
FROM TABLEA
WHERE job_name='jOB_AA_BB';
db<>fiddle here
One of my column needs to be transformed into a date field. It contains a value that gives the YYMM and it should be translated into the last day of that month:
For example, 1312 should become 12/31/2013.
I have tried various last_day, to_char functions but not able to convert 1312 in a date format. Please help !!
Netezza is based on Postgres, so maybe the Postgres method will work. Here is Postgres code that works (see here):
select to_date('1312'||'01', 'YYMMDD') + interval '1 month' - interval '1 day'
I would first convert the number to a date, then add 1 month and subtract 1 day.
select add_months(to_date(1312, 'yymm'), 1) - 1 as the_date
I have a table with two temporal columns. First (name is DATE) is storing the date (not including the time part) and therefor the datatype is DATE. Second column (name is TIME) is for storing the time in seconds and therefor the datatype is NUMBER.
I need to compare this two dates with a timestamp from another table. How can I calculate the date of the two columns (DATE and TIME) and compare to the timestamp of the other table?
I have tried to calculate the hours out of the time column and add it to the date column, but the output seems not correct:
SELECT to_date(date + (time/3600), 'dd-mm-yy hh24:mi:ss') FROM mytable;
The output is just the date, but not the time component.
You can use the INTERVAL DAY TO SECOND type:
SELECT your_date + NUMTODSINTERVAL(your_time_in_seconds, 'SECOND') FROM dual;
Example:
SELECT TRUNC(SYSDATE) + NUMTODSINTERVAL(39687, 'SECOND') FROM dual;
The calculated date with time is: 10-11-2013 11:01:27
This is a better idea than dividing your value by 3600 in my opinion, as you have an interval in seconds, so it feels natural to use an interval to represent your time, which can then be easily added to a column of DATE datatype.
Oracle Interval in Documentation
NUMTODSINTERVAL Function in documentation
date + (time/3600) is already a DATE, so you don't need to do to_date(). It does have the time part you added though, you just aren't displaying it. If you want to output that as a string in the format you've shown, use to_char() instead:
SELECT to_char(date + (time/3600), 'dd-mm-yy hh24:mi:ss') FROM mytable;
... except that if time is actually in seconds, you need to divide by 86400 (24x60x60), not 3600. At the moment you're relying on your client's default date format, probably NLS_DATE_FORMAT, which doesn't include the time portion from what you've said. That doesn't mean the time isn't there, it just isn't displayed.
But that is just for display. Leave it as a date, by just adding the two values, when comparing against you timestamp, e.g.
WHERE date + (time/86400) < systimestamp
Try like this,
SELECT TO_DATE('11/11/2013','dd/mm/yyyy') + 3600/60/60/24 FROM DUAL;
Your query,
SELECT date + time/60/60/24 FROM mytable;
try using to_timestamp instead of to_date
How do I add days to a timestamp? If my timestamp is 01-JAN-2011 11-09-05 and I add 2 days, I want 03-JAN-2011 11-09-05.
select '01-jan-2011 11-09-05' + interval '2' day
A completely Oracle-centric solution is to simply add 2 to the timestamp value as the default interval is days for Oracle dates/timestamps:
SELECT TO_TIMESTAMP('01-jan-2011 11-09-05','DD-Mon-YYYY HH24-MI-SS') + 2
FROM dual;
In a similar case, I used:
SELECT TO_TIMESTAMP('01-jan-2011 11-09-05','DD-Mon-YYYY HH24-MI-SS') + NUMTODSINTERVAL(2, 'DAY')
Because, othewise, the expression is converted to DATE and precission is lost. See: NUMTODSINTERVAL documentation