I would have a problem with a query
I should make a query that takes the last state ( so check the date), Grouped for a called column mat_calc.
mat_calc | STATE | DATE
1 | NEW | 25/03/2016
1 | DONE |25/01/2016
2 |PROC |25/04/2016
2 |PROC |25/07/2016
2 |DONE |25/09/2016
3 |NEW |25/01/2016
3 |PROC |25/06/2016
3 |DONE |25/02/2016
3 |OK |25/12/2016
4 |OK |25/03/2016
So I should give it back :
the mat_cal With its status
1 | NEW
2 | DONE
3 | OK
4 | OK
My query is
select mat_cal AS mat_cal , STATO AS STATO, MAX(DATA) AS DATA
from CALC
group by mat_cal ;
It gives me trouble on the group id because it looks like I DO NOT use it.
How can i do it? Thanks
Sorry,i can't do a tables with stack overflow
Use row_number():
select c.*
from (select c.*,
row_number() over (partition by mat_cal order by data desc) as seqnum
from calc c
) c
where seqnum = 1;
you can try the following:
--creating the data you publishied
with calc (mat_cal,STATO,date)
as
(
select '1' as mat_cal,'NEW' as STATO,'25/03/2016' as date
union
select '1','DONE','25/01/2016'
union
select '2','PROC','25/04/2016'
union
select '2','PROC','25/07/2016'
union
select '2','DONE','25/09/2016'
union
select '3','NEW','25/01/2016'
union
select '3','PROC','25/06/2016'
union
select '3','DONE','25/02/2016'
union
select '3','OK','25/12/2016'
union
select '4','OK','25/03/2016')
--the query to solve the problem
select mat_cal , STATO ,date
from CALC as c
where c.date = (select max(date) from calc as c2 where c.mat_cal = c2.mat_cal group by c2.mat_cal)
When you use the Group By clause you need to do it with all the columns selected. If you don't do that you'll get the ORA-00979 exception.
Try adding the STATO column to the Group By.
select mat_cal AS mat_cal , STATO AS STATO, MAX(DATA) AS DATA
from CALC
group by mat_cal, STATO ;
Related
I have following dataset
and want to get this
How can I do it?
Using SQL Server, you can use a PIVOT, such as :
SELECT Time, [a],[b],[c]
FROM
(
SELECT time, [group],value
FROM dataset) d
PIVOT
(
SUM(value)
FOR [group] IN ([a],[b],[c])
) AS pvt
You can try it on the following fiddle.
Changed the column names to not conflict with reserved words. You would have to put them into single quotes otherwise.
WITH
-- the input
indata(grp,tm,val) AS (
SELECT 'a',1,44
UNION ALL SELECT 'a',2,22
UNION ALL SELECT 'a',3, 1
UNION ALL SELECT 'b',1, 1
UNION ALL SELECT 'b',2, 5
UNION ALL SELECT 'b',3, 6
UNION ALL SELECT 'c',1, 7
UNION ALL SELECT 'c',2, 8
UNION ALL SELECT 'c',3, 9
)
SELECT tm
, SUM(CASE grp WHEN 'a' THEN val END) AS a
, SUM(CASE grp WHEN 'b' THEN val END) AS b
, SUM(CASE grp WHEN 'c' THEN val END) AS c
FROM indata
GROUP BY tm
;
tm | a | b | c
----+----+---+---
1 | 44 | 1 | 7
2 | 22 | 5 | 8
3 | 1 | 6 | 9
select * from
(
select
time,[group],value
from yourTable
group by time,[group],value
)
as table
pivot
(
sum([value])
for [group] in ([a],[b],[c])
) as p
order by time
This is the result
for Vertica,
SELECT time
, SUM(value) FILTER (WHERE group = a) a
, SUM(value) FILTER (WHERE group = b) b
, SUM(value) FILTER (WHERE group = c) c
FROM yourTable
GROUP BY time
I am newbie to Oracle. I have a requirement in which I need to fetch all the error codes from the comment field and then check it in another table to see the type of code. Depending on the type of code I have to give preference to particular type and then display that error code and type into a csv along with other columns. Below how the data is present in a column
TABLE 1 : COMMENTS_TABLE
id | comments
1 | Manually added (BPM001). Currency code does not exists(TECH23).
2 | Invalid counterparty (EXC001). Manually added (BPM002)
TABLE 2 : ERROR_CODES
id | error_code | error_type
1 | BPM001 | MAN
2 | EXC001 | EXC
3 | EXC002 | EXC
4 | BPM002 | MAN
I am able to get all error codes using REGEX_SUBSTR but not sure how to check it with other table and depending on type display only one. For eg. if the type is MAN only that error code should be returned in select clause.
I propose you to define a hierarchy of error_codes
within the FIRST function to search for the best fit.
SQL Fiddle
Query 1:
SELECT c.id,
MAX (
ERROR_CODE)
KEEP (DENSE_RANK FIRST
ORDER BY CASE ERROR_TYPE WHEN 'MAN' THEN 1 WHEN 'EXC' THEN 2 END)
AS ERROR_CODE,
MAX (
ERROR_TYPE)
KEEP (DENSE_RANK FIRST
ORDER BY CASE ERROR_TYPE WHEN 'MAN' THEN 1 WHEN 'EXC' THEN 2 END)
AS ERROR_TYPE
FROM ERROR_CODES e
JOIN COMMENTS_TABLE c ON c.COMMENTS LIKE '%' || e.ERROR_CODE || '%'
GROUP BY c.id
Results:
| ID | ERROR_CODE | ERROR_TYPE |
|----|------------|------------|
| 1 | BPM001 | MAN |
| 2 | BPM002 | MAN |
EDIT : You said in your comments
This is helpul, but I have multiple fields in select clause and adding
that in group by could be a problem
One option could be to use a WITH clause to define this result set and then join with other columns.
with res as
(
select ...
--query1
)
select t.other_columns, r.id, r.error_code ...
from other_table join res on ...
You may also use row_number() alternatively ( Which was actually my original answer. But I changed it to KEEP .. DENSE_RANK as it is efficient.
SELECT * FROM
( SELECT c.id
,ERROR_CODE
,ERROR_TYPE
--Other columns,
,row_number() OVER (
PARTITION BY c.id ORDER BY CASE error_type
WHEN 'MAN'
THEN 1
WHEN 'EXC'
THEN 2
ELSE 3
END
) AS rn
FROM ERROR_CODES e
INNER JOIN COMMENTS_TABLE c
ON c.COMMENTS LIKE '%' || e.ERROR_CODE || '%'
) WHERE rn = 1;
Fiddle
You can sort, prioritize and filter records with analytic functions.
with comments as(
select 1 as id
,'Manually added (BPM001). Currency code does not exists(TECH23).' as comments
from dual union all
select 2 as id
,'Invalid counterparty (EXC001). Manually added (BPM002)' as comments
from dual
)
,error_codes as(
select 1 as id, 'BPM001' as error_code, 'MAN' as error_type from dual union all
select 2 as id, 'EXC001' as error_code, 'EXC' as error_type from dual union all
select 3 as id, 'EXC002' as error_code, 'EXC' as error_type from dual union all
select 4 as id, 'BPM002' as error_code, 'MAN' as error_type from dual
)
-- Everything above this line is not part of the query. Just for generating test data
select *
from (select c.id as comment_id
,c.comments
,e.error_code
,row_number() over(
partition by c.id -- For each comment
order by case error_type when 'MAN' then 1 -- First prio
when 'EXC' then 2 -- Second prio
else 3 -- Everything else
end) as rn
from comments c
join error_codes e on(
e.error_code = regexp_substr(c.comments, e.error_code)
)
)
where rn = 1 -- Pick the highest priority code
/
If you could add a priority column to your error code (or even error_type) you could skip the case/when logic in the order by and simply replacing it with the priority column.
I have the following table:
ClientId | CalculationDate | TransactedAmount |
1 13/02/2015 3
1 14/02/2015 3
2 14/02/2015 5
3 15/03/2015 6
2 15/03/2015 5
As a result I want table which contains ClientId and minimal Months passed since
maximum amount were transacted for each clientId.
How can i do that?
SELECT DISTINCT ClientId , MaxAmount.TransactedAmount , DATEDIFF(MONTH,MaxAmount.CalculationDate ,getdate())
FROM TABLENAME T1
CROSS APPLY(SELECT TOP 1 TransactedAmount ,CalculationDate
FROM TABLENAME T2
WHERE T1.ClientId = T2.ClientId
ORDER BY TransactedAmount DESC) MaxAmount
Using Window Function like Row_Nummber() we can achieve the same
;With cte(ClientId , CalculationDate , TransactedAmount )
AS
(
SELECT 1,'13/02/2015',3 UNION ALL
SELECT 1,'14/02/2015',3 UNION ALL
SELECT 2,'14/02/2015',5 UNION ALL
SELECT 3,'15/03/2015',6 UNION ALL
SELECT 2,'15/03/2015',5
)
SELECT ClientId , CalculationDate,TransactedAmount From
(
SELECT ClientId , CalculationDate ,MAX(TransactedAmount)OVER(Partition by ClientId Order by CalculationDate) As TransactedAmount ,
ROW_NUMBER()OVER(Partition by ClientId Order by CalculationDate) AS RNo From cte
)Dt
WHERE Dt.RNo=1
I need a bit of help with a SQL query.
Imagine I've got the following table
id | date | price
1 | 1999-01-01 | 10
2 | 1999-01-01 | 10
3 | 2000-02-02 | 15
4 | 2011-03-03 | 15
5 | 2011-04-04 | 16
6 | 2011-04-04 | 20
7 | 2017-08-15 | 20
What I need is all dates where only one price is present.
In this example I need to get rid of row 5 and 6 (because there is two difference prices for the same date) and either 1 or 2(because they're duplicate).
How do I do that?
select date,
count(distinct price) as prices -- included to test
from MyTable
group by date
having count(distinct price) = 1 -- distinct for the duplicate pricing
The following should work with any DBMS
SELECT id, date, price
FROM TheTable o
WHERE NOT EXISTS (
SELECT *
FROM TheTable i
WHERE i.date = o.date
AND (
i.price <> o.price
OR (i.price = o.price AND i.id < o.id)
)
)
;
JohnHC answer is more readable and delivers the information the OP asked for ("[...] I need all the dates [...]").
My answer, though less readable at first, is more general (allows for more complexes tie-breaking criteria) and also is capable of returning the full row (with id and price, not just date).
;WITH CTE_1(ID ,DATE,PRICE)
AS
(
SELECT 1 , '1999-01-01',10 UNION ALL
SELECT 2 , '1999-01-01',10 UNION ALL
SELECT 3 , '2000-02-02',15 UNION ALL
SELECT 4 , '2011-03-03',15 UNION ALL
SELECT 5 , '2011-04-04',16 UNION ALL
SELECT 6 , '2011-04-04',20 UNION ALL
SELECT 7 , '2017-08-15',20
)
,CTE2
AS
(
SELECT A.*
FROM CTE_1 A
INNER JOIN
CTE_1 B
ON A.DATE=B.DATE AND A.PRICE!=B.PRICE
)
SELECT * FROM CTE_1 WHERE ID NOT IN (SELECT ID FROM CTE2)
I have a scenario to get the respective field value of "Max" and "Min" records
Please find the sample data below
-----------------------------------------------------------------------
ID Label ProcessedDate
-----------------------------------------------------------------------
1 Label1 11/01/2016
2 Label2 11/02/2016
3 Label3 11/03/2016
4 Label4 11/04/2016
5 Label5 11/05/2016
I have the "ID" field populated in another table as a foreign key. While querying those records in that table based on the "ID" field I need to get the "Label" field of "Max" Processed date and "Min" processed date.
-----------------------------------------------------------------------
ID LabelID GroupingField
-----------------------------------------------------------------------
1 1 101
2 2 101
3 3 101
4 4 101
5 5 101
6 1 102
7 2 102
8 3 102
9 4 102
And the final result set I expect it to look something like this.
-----------------------------------------------------------------------
GroupingField FirstProcessed LastProcessed
-----------------------------------------------------------------------
101 Label1 Label5
102 Label1 Label4
I have 'almost' managed to get this above result using rank function but still not satisfied with it. So I am looking if someone can provide me with a better option.
Thanks,
Prakazz
CREATE TABLE #Details (ID INT,LabelID INT,GroupingField INT)
CREATE TABLE #Details1 (ID INT,Label VARCHAR(100),ProcessedDate VARCHAR(100))
INSERT INTO #Details1 (ID ,Label ,ProcessedDate )
SELECT 1,'Label1','11/01/2016' UNION ALL
SELECT 2,'Label2','11/02/2016' UNION ALL
SELECT 3,'Label3','11/03/2016' UNION ALL
SELECT 4,'Label4','11/04/2016' UNION ALL
SELECT 5,'Label5','11/05/2016'
INSERT INTO #Details (ID ,LabelID ,GroupingField )
SELECT 1,1,101 UNION ALL
SELECT 2,2,101 UNION ALL
SELECT 3,3,101 UNION ALL
SELECT 4,4,101 UNION ALL
SELECT 5,5,101 UNION ALL
SELECT 6,1,102 UNION ALL
SELECT 7,2,102 UNION ALL
SELECT 8,3,102 UNION ALL
SELECT 9,4,102
;WITH CTE (GroupingField , MAXId ,MinId) AS
(
SELECT GroupingField,MAX(LabelID) MAXId,MIN(LabelID) MinId
FROM #Details
GROUP BY GroupingField
)
SELECT GroupingField ,B.Label FirstProcessed, A.Label LastProcessed
FROM CTE
JOIN #Details1 A ON MAXId = A.ID
JOIN #Details1 B ON MinId = B.ID
You can use SQL Row_Number() function using Partition By as follows with a combination of Group By
;with cte as (
select
t.Label, t.ProcessedDate,
g.GroupingField,
ROW_NUMBER() over (partition by GroupingField Order By ProcessedDate ASC) minD,
ROW_NUMBER() over (partition by GroupingField Order By ProcessedDate DESC) maxD
from tbl t
inner join GroupingFieldTbl g
on t.ID = g.LabelID
)
select GroupingField, max(FirstProcessed) FirstProcessed, max(LastProcessed) LastProcessed
from (
select
GroupingField,
FirstProcessed = CASE when minD = 1 then Label else null end,
LastProcessed = CASE when maxD = 1 then Label else null end
from cte
where
minD = 1 or maxD = 1
) t
group by GroupingField
order by GroupingField
I also used CTE expression to make coding easier and understandable
Output is as