I need to calculate YTD and last year YTD on a table [SQL Server 2012]. Below is the query I tried. Its getting doubled and tripled for some cases.
SELECT SUM(A.RevisionNumber)YTD,SUM(P.RevisionNumber)LY_YTD,B.OrderDateM,B.OrderDateY
FROM
(select MONTH(OrderDate)OrderDateM,YEAR(OrderDate)OrderDateY from sales.SalesOrderHeader B
group by MONTH(OrderDate),YEAR(OrderDate))B
LEFT JOIN
(select SUM(RevisionNumber)RevisionNumber,MONTH(OrderDate)OrderDateM,YEAR(OrderDate)OrderDateY
from sales.SalesOrderHeader
group by MONTH(OrderDate),YEAR(OrderDate))A
ON A.OrderDateM<=B.OrderDateM AND A.OrderDateY=B.OrderDateY
LEFT JOIN
(select SUM(RevisionNumber)RevisionNumber,MONTH(OrderDate)OrderDateM,YEAR(OrderDate)OrderDateY
from sales.SalesOrderHeader
group by MONTH(OrderDate),YEAR(OrderDate))P
ON P.OrderDateM<=B.OrderDateM AND P.OrderDateY=B.OrderDateY-1
GROUP BY B.OrderDateM,B.OrderDateY
ORDER BY B.OrderDateY,B.OrderDateM
You can use windowing function as below:
;With cte as (
Select Sum(RevisionNumber) As SM_RevisionNumber, Month(OrderDate) as OrderM,
Year(OrderDate) as OrderY
From Sales.SalesOrderHeader
Group by Month(OrderDate), Year(OrderDate)
), cte2 as (
Select YTD = Sum(SM_RevisionNumber) over (partition by OrderY order by OrderM),
OrderM, OrderY, RowN = Row_Number() over(order by OrderY, OrderM)
from cte
)
Select YTD, LY_YTD = lag(YTD, 12, null) over(Order by RowN), OrderM, ORderY
from cte2
But this solution assumes we have atleast one entry for each month and year.
Related
I am working on a restaurant management system. There I have two tables
order_details(orderId,dishId,createdAt)
dishes(id,name,imageUrl)
My customer wants to see a report top 3 selling items / least selling 3 items by the month
For the moment I did something like this
SELECT
*
FROM
(SELECT
SUM(qty) AS qty,
order_details.dishId,
MONTHNAME(order_details.createdAt) AS mon,
dishes.name,
dishes.imageUrl
FROM
rms.order_details
INNER JOIN dishes ON order_details.dishId = dishes.id
GROUP BY order_details.dishId , MONTHNAME(order_details.createdAt)) t
ORDER BY t.qty
This gives me all the dishes sold count order by qty.
I have to manually filter max 3 records and reject the rest. There should be a SQL way of doing this. How do I do this in SQL?
You would use row_number() for this purpose. You don't specify the database you are using, so I am guessing at the appropriate date functions. I also assume that you mean a month within a year, so you need to take the year into account as well:
SELECT ym.*
FROM (SELECT YEAR(od.CreatedAt) as yyyy,
MONTH(od.createdAt) as mm,
SUM(qty) AS qty,
od.dishId, d.name, d.imageUrl,
ROW_NUMBER() OVER (PARTITION BY YEAR(od.CreatedAt), MONTH(od.createdAt) ORDER BY SUM(qty) DESC) as seqnum_desc,
ROW_NUMBER() OVER (PARTITION BY YEAR(od.CreatedAt), MONTH(od.createdAt) ORDER BY SUM(qty) DESC) as seqnum_asc
FROM rms.order_details od INNER JOIN
dishes d
ON od.dishId = d.id
GROUP BY YEAR(od.CreatedAt), MONTH(od.CreatedAt), od.dishId
) ym
WHERE seqnum_asc <= 3 OR
seqnum_desc <= 3;
Using the above info i used i combination of group by, order by and limit
as shown below. I hope this is what you are looking for
SELECT
t.qty,
t.dishId,
t.month,
d.name,
d.mageUrl
from
(
SELECT
od.dishId,
count(od.dishId) AS 'qty',
date_format(od.createdAt,'%Y-%m') as 'month'
FROM
rms.order_details od
group by date_format(od.createdAt,'%Y-%m'),od.dishId
order by qty desc
limit 3) t
join rms.dishes d on (t.dishId = d.id)
I have the following problem.
Part of a task is to determine the visitor(s) with the most money spent between 2000 and 2020.
It just looks like this.
SELECT UserEMail FROM Visitor
JOIN Ticket ON Visitor.UserEMail = Ticket.VisitorUserEMail
where Ticket.Date> date('2000-01-01') AND Ticket.Date < date ('2020-12-31')
Group by Ticket.VisitorUserEMail
order by SUM(Price) DESC;
Is it possible to output more than one person if both have spent the same amount?
Use rank():
SELECT VisitorUserEMail
FROM (SELECT VisitorUserEMail, SUM(PRICE) as sum_price,
RANK() OVER (ORDER BY SUM(Price) DESC) as seqnum
FROM Ticket t
WHERE t.Date >= date('2000-01-01') AND Ticket.Date <= date('2021-01-01')
GROUP BY t.VisitorUserEMail
) t
WHERE seqnum = 1;
Note: You don't need the JOIN, assuming that ticket buyers are actually visitors. If that assumption is not true, then use the JOIN.
Use a CTE that returns all the total prices for each email and with NOT EXISTS select the rows with the top total price:
WITH cte AS (
SELECT VisitorUserEMail, SUM(Price) SumPrice
FROM Ticket
WHERE Date >= '2000-01-01' AND Date <= '2020-12-31'
GROUP BY VisitorUserEMail
)
SELECT c.VisitorUserEMail
FROM cte c
WHERE NOT EXISTS (
SELECT 1 FROM cte
WHERE SumPrice > c.SumPrice
)
or:
WITH cte AS (
SELECT VisitorUserEMail, SUM(Price) SumPrice
FROM Ticket
WHERE Date >= '2000-01-01' AND Date <= '2020-12-31'
GROUP BY VisitorUserEMail
)
SELECT VisitorUserEMail
FROM cte
WHERE SumPrice = (SELECT MAX(SumPrice) FROM cte)
Note that you don't need the function date() because the result of date('2000-01-01') is '2000-01-01'.
Also I think that the conditions in the WHERE clause should include the =, right?
I need to create a Sales Report that shows all years sales per month, and cumulative sales.
The database table is simple:
Transactions
(
ID INT,
TransactionDate DATETIME,
SalesAmount MONEY
)
I want the results to look similar to ExcelSheet below (I am showing only 2017/2018 amounts, but actual query needs to return results for all available years according to TransactionDate)
This is aggregation and a cumulative sum:
select year(TransactionDate), month(TransactionDate),
sum(SalesAmount),
sum(sum(SalesAmount)) over (partition by year(TransactionDate) order by min(TransactionDate))
from Transactions
group by year(TransactionDate), month(TransactionDate)
order by year(TransactionDate), month(TransactionDate);
Try it:
With Q
as
(
Select DatePart(yyyy,TransactionDate) 'Year',DatePart(m,TransactionDate) 'Month', sum(SalesAmount) 'Sales'
From Transactions
Group by DatePart(yyyy,TransactionDate),DatePart(m,TransactionDate)
)
Select q.Year,q.Month,q.sales,( Select sum(q1.Sales)
From Q q1
Where q1.Year=q.Year
And q1.Month <= q.Month
) 'Cumulative Sale'
From Q q
Order by q.Year,q.Month
Try this:
with cte as
(
select year(TransactionDate) as Year, month(TransactionDate) as Month, SalesAmount
)
select a.Year, a.Month, a.SalesAmount, sum(b.SalesAmount) as cumulativeSalesAmount
from Transactions a inner join Transactions b on a.STORE_ID = b.STORE_ID and a.Year = b.Year and a.Month >= b.Month
group by a.Year, a.Month
order by 1, 2
I have a date column Order_date and I am looking for ways to calculate the date difference between customer last order date and his recent previous ( previous form last) order_date ....
Example
Customer : 1, 2 , 1 , 1
Order_date: 01/02/2007, 02/01/2015, 06/02/2014, 04/02/2015
As you can see customer # 1 has three orders.
I want to know the date difference between his recent order date (04/02/2015) and his recent previous (06/02/2014).
For SQL Server 2012 & 2014 you could use LAG with a DATEDIFF to see the number of days between them.
For older versions, a CTE would probably be your best bet:
;WITH CTE AS
(
SELECT CustomerID,
Order_Date,
rn = ROW_NUMBER() OVER (PARTITION BY CustomerID ORDER BY Order_Date DESC)
)
SELECT c1.CustomerID,
DATEDIFF(d, c1.Order_Date, c2.Order_Date)
FROM CTE c1
INNER JOIN CTE c2 ON c2.rn = c1.rn + 1
In SQL Server 2012+, you can use lag() to get the difference between any two dates:
select t.*,
datediff(day, lag(order_date) over (partition by customer order by order_date),
order_date) as days_dff
from table t;
If you have an older version, you can do something similar with correlated subqueries or outer apply.
EDIT:
If you just want the difference between the two most recent dates, use conditional aggregation instead:
select customer,
datediff(day, max(case when seqnum = 2 then order_date end),
max(case when seqnum = 1 then order_date end)
) as MostRecentDiff
from (select t.*,
row_number() over (partition by customer order by order_date desc) as seqnum
from table t
) t
group by customer;
If you're using SQL Server 2008 or later, you can try CROSS APPLY.
SELECT [customers].[customer_id], DATEDIFF(DAY, MIN([recent_orders].[order_date]), MAX([recent_orders].[order_date])) AS [elapsed]
FROM [customers]
CROSS APPLY (
SELECT TOP 2 [order_date]
FROM [orders]
WHERE ([orders].[customer_id] = [customers].[customer_id])
) [recent_orders]
GROUP BY [customers].[customer_id]
SELECT DATEDIFF(DAY, Y.PrevLastOrderDate, Y.LastOrderDate) AS PreviousDays
FROM
(
SELECT X.LastOrderDate
, (SELECT MAX(OrderDate) FROM dbo.Orders SO WHERE SO.CustomerID=1 AND SO.OrderDate < X.LastOrderDate) AS PrevLastOrderDate
FROM
(
select MAX(OrderDate) AS LastOrderDate
FROM dbo.Orders O
WHERE O.CustomerID=1
)X
)Y
drop table #Invoices
create table #Invoices ( OrderId int , OrderDate datetime )
insert into #Invoices (OrderId , OrderDate )
select 101, '01/01/2001' UNION ALL Select 202, '02/02/2002' UNION ALL Select 303, '03/03/2003'
UNION ALL Select 808, '08/08/2008' UNION ALL Select 909, '09/09/2009'
;
WITH
MyCTE /* http://technet.microsoft.com/en-us/library/ms175972.aspx */
( OrderId,OrderDate,ROWID) AS
(
SELECT
OrderId,OrderDate
, ROW_NUMBER() OVER ( ORDER BY OrderDate ) as ROWID
FROM
#Invoices inv
)
SELECT
OrderId,OrderDate
,(Select Max(OrderDate) from MyCTE innerAlias where innerAlias.ROWID = (outerAlias.ROWID-1) ) as PreviousOrderDate
,
[MyDiff] =
CASE
WHEN (Select Max(OrderDate) from MyCTE innerAlias where innerAlias.ROWID = (outerAlias.ROWID-1) ) iS NULL then 0
ELSE DATEDIFF (mm, OrderDate , (Select Max(OrderDate) from MyCTE innerAlias where innerAlias.ROWID = (outerAlias.ROWID-1) ) )
END
, ROWIDMINUSONE = (ROWID-1)
, ROWID as ROWID_SHOWN_FOR_KICKS , OrderDate as OrderDateASecondTimeForConvenience
FROM
MyCTE outerAlias
ORDER BY outerAlias.OrderDate Desc , OrderId
I am trying to return the most ordered product per month, of the year 2007. I would like to see the name of the product, how many of them where ordered that month, and the month. I am using the AdventureWorks2012 database. I have tried a few different ways but each time multiple product orders are returned for the same month, instead of the one product that had the most order quantity that month. Sorry if this is not clear. I am trying to test myself so I make up my own questions and try to answer them. If anyone knows a site that have questions and answers like this so I can verify that would be super helpful! Thanks for any help. Here is the farthest I have been able to get with the query.
WITH Ord2007Sum
AS (SELECT sum(od.orderqty) AS sorder,
od.productid,
oh.orderdate,
od.SalesOrderID
FROM Sales.SalesOrderDetail AS od
INNER JOIN
sales.SalesOrderHeader AS oh
ON od.SalesOrderID = oh.SalesOrderID
WHERE year(oh.OrderDate) = 2007
GROUP BY ProductID, oh.OrderDate, od.SalesOrderID)
SELECT max(sorder),
s.productid,
month(h.orderdate) AS morder --, s.salesorderid
FROM Ord2007Sum AS s
INNER JOIN
sales.SalesOrderheader AS h
ON s.OrderDate = h.OrderDate
GROUP BY s.ProductID, month(h.orderdate)
ORDER BY morder;
Make a CTE that groups our products by month and creates a sum
;WITH OrderRows AS
(
SELECT
od.ProductId,
MONTH(oh.OrderDate) SalesMonth,
SUM(od.orderqty) OVER (PARTITION BY od.ProductId, MONTH(oh.OrderDate) ORDER BY oh.OrderDate) ProdMonthSum
FROM SalesOrderDetail AS od
INNER JOIN SalesOrderHeader AS oh
ON od.SalesOrderID = oh.SalesOrderID
WHERE year(oh.OrderDate) = 2007
),
Make a simple numbers table to break out each month of the year
Months AS
(
SELECT 1 AS MonthNum UNION SELECT 2 UNION SELECT 3 UNION SELECT 4
UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8
UNION SELECT 9 UNION SELECT 10 UNION SELECT 11 UNION SELECT 12
)
We query our months table against the data and select the top product for each month based on the sum
SELECT
m.MonthNum,
d.ProductID,
d.ProdMonthSum
FROM Months m
OUTER APPLY
(
SELECT TOP 1 r.ProductID, r.ProdMonthSum
FROM OrderRows r
WHERE r.SalesMonth = m.MonthNum
ORDER BY ProdMonthSum DESC
) d
Your group by statement should not include oh.OrderDate, od.SalesOrderID because this will aggregate your data to the incorrect level. You want the ProductID that was most commonly sold per month so the group by conditions become ProductID, datepart(mm,oh.OrderDate). As Andrew suggested the Row_Number function is useful in this case as it lets you create a key that is ordered by month and sorder and which resets each month. Finally in the outer query limits the results to the first instance (which is the highest quantity)for each month.
WITH Ord2007Sum
AS(
SELECT sum(od.orderqty) AS sorder,
od.productid,
datepart(mm,oh.OrderDate) AS 'Month'
row_number() over (partition by datepart(mm,oh.OrderDate)
Order by datepart(mm,oh.OrderDate)desc, sorder desc) row
FROM Sales.SalesOrderDetail AS od
INNER JOIN
sales.SalesOrderHeader AS oh
ON od.SalesOrderID = oh.SalesOrderID
WHERE datepart(yyyy,oh.OrderDate) = 2007
GROUP BY ProductID, datepart(mm,oh.OrderDate)
)
SELECT productid,
sorder,
[month]
FROM Ord2007Sum
WHERE row =1