I have a data set in google sheets, for each week of data I have 3 rows. I wish to query the data in every second row to calculate the max value and the last value.
For instance:
ROW
DATA
1
800
2
Text
3
500
4
More text
5
600
6
Blah
7
700
8
Blah
For Max value I have the following which will return 800
MAX(FILTER(QUERY(A1:A,"Select * skipping 2"), QUERY(A1:A,"Select * skipping 2") <> 0))
How do I change it up to return the last value? Which should return 700
try:
=LOOKUP(2^99,FILTER(A:A,A:A<>0))
#rockinfreakshow answer will successfully find the last number.
To filter a range by n amount of rows, you can use:
=FILTER(A:A,MOD(ROW(A:A),n)=1)
Change n with your desired value, and 1 with the number of row you want to get. 1 for the first, 2 for the second, but 0 if you want the nth one. To find MAX, just wrap it in MAX()
To find the last one, even if it's a text or number, you can use SORTN and SEQUENCE:
=SORTN(FILTER(A:A,MOD(ROW(A:A),n)=1,A:A<>""),1,1, SEQUENCE(COUNTA(FILTER(A:A,MOD(ROW(A:A),n)=1,A:A<>""))),0)
It orders the elements in reverse order and only chooses the first one
Remember to change n with the number of rows and =1 with the number of row you want to choose
I have a table that looks like:
col1
------
2
2
3
4
5
6
7
with values sorted in ascending order.
I want to assign each row to groups with labels 0,1,...,n so that each group has a total of no more than 10. So in the above example it would look like this:
col1 |label
------------
2 0
2 0
3 0
4 1
5 1
6 2
7 3
I tried using this:
floor(sum(col1) OVER (partition by ORDER BY col1 ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) /10))
But this doesn't work correctly because it is performing the operations
as:
floor(2/10) = 0
floor([2+2]/10) = 0
floor([2+2+3]/10) = 0
floor([2+2+3+4]/10) = 1
floor([2+2+3+4+5]/10 = 1
floor([2+2+3+4+5+6]/10 = 2
floor([2+2+3+4+5+6+7]/10) = 2
It's all coincidentally correct until the last calculation, because even though
[2+2+3+4+5+6+7] / 10 = 2.9
and
floor(2.9) = 2
what it should do is realise 6+7 is > 10 so the 5th row with value 7 needs be in its own group so iterate the group number + 1 and allocate this row into a new group.
What I really want it to do is when it encounters a sum > 10 then set group number = group number + 1, allocate the CURRENT ROW into this new group, and then finally set the new start row to be the CURRENT ROW.
This is too long for a comment.
Solving this problem requires scanning the table, row-by-row. In SQL, this would be through a recursive CTE (or hierarchical query). Hive supports neither of these.
The issue is that each time a group is defined, the difference between 10 and the sum is "forgotten". That is, when you are further down in the list, what happens earlier on is not a simple accumulation of the available data. You need to know how it was split into groups.
A related problem is solvable. The related problem would assign all rows to groups of size 10, splitting rows between two groups. Then you would know what group a later row is in based only on the cumulative sum of the previous rows.
I have the following Expression in a field in SSRS:
=iif(Fields!Score.Value > Previous(Fields!Score.Value),"Greater","Less Than")
I have the following Scores in my scenario across 4 rows:
3
3
4
5
It results in:
3 - Greater
3 - Less Than
4 - Greater
5 - Greater
The issue is with the first row always being Greater. It should be blank because there isn't a previous row to compare against. I would expect the results to be as follows:
3 -
3 - Same
4 - Greater
5 - Greater
How could I change the above formula to produce the above result?
The above is an example of only one row group. There are then further row groups with different Scores, so the different results of Same/Greater/Less Than need to work across the different row groups.
Try following:
=IIF(RowNumber(NOTHING)=1,"",IIF(Fields!Score.Value = Previous(Fields!Score.Value),"Same",IIF(Fields!Score.Value > Previous(Fields!Score.Value),"Greater","Less Than")))
modified. try now.
So I have a column with this data
1
1
1
2
3
4
5
5
5
how can I do a count if where the value at any given location in the above table is equal to a cell i select? i.e. doing Count([NUMBER]) Where([NUMBER] = Coordinates(0,0)) would return 3, because there are 3 rows where the value is one in the 0 position.
it's basically like in excel where you can do COUNTIF(A:A, 1) and it would give you the total number of rows where the value in A:A is 1. is this possible to do in business objects web intelligence?
Functions in WebI operate on rows, so you have to think about it a little differently.
If your intent is to create a cell outside of the report block and display the count of specific values, you can use Count() with Where():
=Count([NUMBER];All) Where ([NUMBER] = "1")
In a freestanding cell, the above will produce a value of "3" for your sample data.
If you want to put the result in the same block and have it count up the occurrences of values on that row, for example:
NUMBER NUMBER Total
1 3
1 3
1 3
2 1
3 1
4 1
5 3
5 3
5 3
it gets a little more complicated. You have to have at least one other dimension in the query to reference. It can be anything, but you have to be counting something in conjunction with the NUMBER dimension. So, the following would work, assuming there's another dimension in the query named [Duh]:
=Count([NUMBER];All) ForAll([Duh])
Let's say I have two columns.
3.5463 11
4.5592 12
1.6993 111
0.92521 112
1.7331 121
2.1407 122
1.4082 1111
2.0698 1112
2.3973 1121
2.4518 1122
1.1719 1211
1.153 1212
0.67139 1221
0.64744 1222
1.3705 11111
0.9557 11112
0.64868 11121
0.7325 11211
0.58874 11212
0.86673 11221
0.17075 11222
0.64026 12111
0.80229 12112
0.43422 12122
1.0405 12211
0.63376 12212
0.56491 12221
0.34626 12222
0.81631 111111
0.91837 111112
0.70013 111121
0.87384 111122
1.1474 111211
0.47411 111221
0.12249 111222
0.56728 112111
0.88169 112112
0.14509 112121
0.68655 112211
0.36274 112212
1.1652 121111
0.99314 121112
0.42024 121121
0.23937 121122
1.0346 122111
0.64642 122112
0.15632 122121
0.41725 122122
0.40793 122211
In the first column, there is a number. With every one of those numbers, in the second column, is an associated ID. Now, there are some blank rows that do not contain any numbers in them.
Define one of these numbers to be a "daughter" of another number if the ID of the first number is the same as the ID of the second, with an extra digit on the end. For example, both IDs 11211 and 11212 are daughters of 1121, because the ID of 1121 has an extra digit, either a 1 or a 2, added onto the end to form the ID of its daughters. Thus, 1121 is the parent of both 11211 and 11212.
Here is what I want the macro to do. It must output a third column which contains, for every row, a cumulative sum of the number of the first column in that row, plus the parent number of that number, and the parent number of the parent number, etc. all the way up until it reachers either 11 or 12. It will begin by simply outputting the numbers in column 1 for 11 and 12 in the third column. Then, in a loop beginning with 111, it will add up the cumulative sum of every row (the number in that row plus the third column output of the parent), only if that row has a number and an id, and only if the parent exists and has an output in column 3. So for example, the number in the 3rd column of the row with ID 11222 should be the number in column 1 of that row, plus that of 1122, plus that of 112, plus that of 11. So, 0.17075+2.4518+0.92521+3.5463, or 7.09406. However, if you try to do this for ID 111221, you will notice that the row where the parent 11122 should be is empty. Thus, the parent does not exist, and no value will be outputted in column 3 for 111221.
I would greatly appreciate it if someone has some time on their hands to code up this VBA macro for me in exchange for an accepted solution.
Thanks
I don't think a macro is needed, just some formulas. First, I put a header on my columns of data, such as "value," and "id." If you then highlight the column labels (i.e., A and B) and sort by B ("id") then A ("value"), you'll group your blank rows. You can then delete those rows. Now you have the data almost ready. When I did this, I converted the id column to text, as opposed to a number value, so if I sort the table by id, the pattern will be, "11, 111, 1111," and so on, instead of, "11, 12, 111, 112, 121." Then, I added columns to separate the separate characters or levels of the ids. This is to help with parents and children. You can use text-to-columns, or a MID formula, but what I did was have 6 more columns to the right. For each id row, each column would either have a "1," a "2," or a blank (null) value. Then I added another column, calling it "level." I used a formula like COUNTA across all my id splitting columns. So, for 11, my level value was 2. 111 would be 3, 11221 would be 5, and so on. This gives me the id level (parent, child, grandchild, etc). Then I added my final column to the right to compute my cumulative sum of the values. In concept I have one big nested IF statement, but in practice, I needed two. My formula says, if the row above me has a lower level number (i.e., it is some kind of parent), add the value of the current row to the value of the above row. Otherwise, keep going up a row till I do get a parent, and add the current row value to that number.
My final formula for all but the first 5 rows of data was (in the 6th row of data):
=if(K6
rest of answer is below
=if(K6<K7,L6+C7,if(K5<K7,L5+C7,if(K4<K7,L4+C7,if(K3<K7,L3+C7,if(K2<K7,L2+C7,C7)))))
The values were column C, the original id in column D, the id split columns were E through J, the level column was K, and my formula was in L. This formula can be copied down the table. For the first 4 rows, you just need 1 less IF statement each row you go up. The fifth row of data might take the above formula; it depends how it will deal with the column headers in row one. The formula on the 4 row of data might be:
=if(K4<K5,L4+C5,if(K3<K5,L3+C5,if(K2<K5,L2+C5,if(K1<K5,L1+C5,C5))))
I'm still learning how to format these comments, so I'll try to provide a sample of the layout I have...
C D E F G H I J K L
1 value id 1 2 3 4 5 6 lvl cumul_sum
2 3.546300 11 1 1 2 3.546300
3 1.699300 111 1 1 1 3 5.245600
4 1.408200 1111 1 1 1 1 4 6.653800
5 1.370500 11111 1 1 1 1 1 5 8.024300
6 0.816310 111111 1 1 1 1 1 1 6 8.840610
7 0.918370 111112 1 1 1 1 1 2 6 8.942670
8 0.955700 11112 1 1 1 1 2 5 7.609500
So for example, the number in the 3rd column of the row with ID 11222 should be the number in column 1 of that row, plus that of 1122, plus that of 112, plus that of 11. So, 0.17075+2.4518+0.92521+3.5463, or 7.09406.However, if you try to do this for ID 111221, you will notice that the row where the parent 11122 should be is empty. Thus, the parent does not exist, and no value will be outputted in column 3 for 111221.
As a native worksheet array formula¹ in D1,
=IF(LEN(B1), SUM(SUMIFS(A$1:INDEX(A:A, MATCH(1E+99, A:A)),
B$1:INDEX(B:B, MATCH(1E+99, A:A)), LEFT(B1, ROW(INDIRECT("2:"&LEN(B1)))))), TEXT(,))
The above does not compensate for missing parents (null string). It totals everything it can find and uses zero for missing parents.
As a VBA UDF² in E1,
Function conditionalCumulativeSum(nums As Range, _
ids As Range, sib As Range, _
Optional nullOnBlank As Boolean = True)
Dim i As Integer
'truncate any full column reference to the UsedRange
Set nums = Intersect(nums, nums.Parent.UsedRange)
'match the nums and ids ranges
Set ids = ids.Resize(nums.Rows.Count, nums.Columns.Count)
For i = Len(sib.Value2) To 2 Step -1
If nullOnBlank And IsError(Application.Match(--Left(sib, i), ids, 0)) Then
conditionalCumulativeSum = vbNullString
Exit For
End If
conditionalCumulativeSum = conditionalCumulativeSum + _
Application.SumIfs(nums, ids, Left(sib, i))
Next i
If i = 0 Then conditionalCumulativeSum = vbNullString
End Function
The above defaults to return a null string when it encounters any missing parent through the hereditary chain. This can be turned off by adding FALSE as the optional fourth parameter and then the UDF will behave identically to the native formula.
Results from sample data
¹ Array formulas need to be finalized with Ctrl+Shift+Enter↵. If entered correctly, Excel with wrap the formula in braces (e.g. { and }). You do not type the braces in yourself. Once entered into the first cell correctly, they can be filled or copied down or right just like any other formula. Try and reduce your full-column references to ranges more closely representing the extents of your actual data. Array formulas chew up calculation cycles logarithmically so it is good practise to narrow the referenced ranges to a minimum. See Guidelines and examples of array formulas for more information.
² A User Defined Function (aka UDF) is placed into a standard module code sheet. Tap Alt+F11 and when the VBE opens, immediately use the pull-down menus to Insert ► Module (Alt+I,M). Paste the function code into the new module code sheet titled something like Book1 - Module1 (Code). Tap Alt+Q to return to your worksheet(s).