AWK: add a sequential number out of 4 digits - awk

How do I achieve from following string.ext
>Lipoprotein releasing system transmembrane protein LolC
MKWLWFAYQNVIRNRRRSLMTILIIAVGTAAILLSNGFALYTYDNLREGSALASGHVIIAHVDHFDKEEEIPMEYGLSDYEDIERHIAADDRVRMAIPRLQFSGLISNGDKSVIFMGTGVDPEGEFDIGGVLTNVLTGNTLSTHSAPDAVPEVMLAKDLAKQLHADIGGLLTLLATTADGALNALDVQVRGIFSTGVPEMDKRMLAVALPTAQELIMTDKVGTLSVYLHEIEQTDAMWAVLAEWYPNFATQPWWEQASFYFKVRALYDIIFGVMGVIILLIVFFTITNTLSMTIVERTRETGTLLALGTLPRQIMRNFALEALLIGLAGALLGMLIAGFTSITLFIAEIQMPPPPGSTEGYPLYIYFSPWLYGITSLLVVTLSIAAAFLTSRKAARKPIVEALAHV
>Phosphoserine phosphatase (EC 3.1.3.3)
MFQEHALTLAIFDLDNTLLAGDSDFLWGVFLVERGIVDGDEFERENERFYRAYQEGDLDIFEFLRFAFRPLRDNRLEDLKRWRQDFLREKIEPAILPMACELVEHHRAAGDTLLIITSTNEFVTAPIAEQLGIPNLIATVPEQLHGCYTGEAAGTPAFQAGKVKRLLDWLEETSTELAGSTFYSDSHNDIPLLEWVDHPVATDPDDRLRGYARDRGWPIISLREEIAP
to change the sequential number after string to a 4 digit number (starting with 0001) and separate that number with | from string, so that output is returned like:
>string|0001|Lipoprotein_releasing_system_transmembrane_protein_LolC
MKWLWFAYQNVIRNRRRSLMTILIIAVGTAAILLSNGFALYTYDNLREGSALASGHVIIAHVDHFDKEEEIPMEYGLSDYEDIERHIAADDRVRMAIPRLQFSGLISNGDKSVIFMGTGVDPEGEFDIGGVLTNVLTGNTLSTHSAPDAVPEVMLAKDLAKQLHADIGGLLTLLATTADGALNALDVQVRGIFSTGVPEMDKRMLAVALPTAQELIMTDKVGTLSVYLHEIEQTDAMWAVLAEWYPNFATQPWWEQASFYFKVRALYDIIFGVMGVIILLIVFFTITNTLSMTIVERTRETGTLLALGTLPRQIMRNFALEALLIGLAGALLGMLIAGFTSITLFIAEIQMPPPPGSTEGYPLYIYFSPWLYGITSLLVVTLSIAAAFLTSRKAARKPIVEALAHV
>string|0002|Phosphoserine_phosphatase_(EC_3_1_3_3)
MFQEHALTLAIFDLDNTLLAGDSDFLWGVFLVERGIVDGDEFERENERFYRAYQEGDLDIFEFLRFAFRPLRDNRLEDLKRWRQDFLREKIEPAILPMACELVEHHRAAGDTLLIITSTNEFVTAPIAEQLGIPNLIATVPEQLHGCYTGEAAGTPAFQAGKVKRLLDWLEETSTELAGSTFYSDSHNDIPLLEWVDHPVATDPDDRLRGYARDRGWPIISLREEIAP
the commands I came up until here are ($faa is referring to the filename string.ext)
faa=$1
var=$(basename "$faa" .ext)
awk '!/^>/ { printf "%s", $0; n = "\n" } /^>/ { print n $0; n = "" } END { printf "%s", n }' $faa >$faa.tmp
sed 's/ /_/g' $faa.tmp >$faa.tmp2
awk -v var="$var" '/>/{sub(">","&"var"|");sub(/\.ext/,x)}1' $faa.tmp2 >$faa.tmp3
awk '/>/{sub(/\|/,++i"|")}1' $faa.tmp3 >$faa.tmp4
tr '\.' '_' <$faa.tmp4 | tr '\:' '_' | sed 's/__/_/g' >$faa.tmp5
Edit: I also want to change following characters to 1 underscore: / . :

I'd use perl here:
perl -pe '
next unless /^>/; # only transform the "header" lines
s/[\h.]/_/g; # change dots and horizontal whitespace
substr($_,1,0) = sprintf("string|%04d|", ++$n) # insert the counter
' file

$ awk '
FNR==1 {base=FILENAME; sub(/\.[^.]+$/,"",base) }
sub(/^>/,"") { gsub(/[\/ .:]+/,"_"); $0=sprintf(">%s|%04d|%s",base,++c,$0) }
1' string.ext
>string|0001|Lipoprotein_releasing_system_transmembrane_protein_LolC
MKWLWFAYQNVIRNRRRSLMTILIIAVGTAAILLSNGFALYTYDNLREGSALASGHVIIAHVDHFDKEEEIPMEYGLSDYEDIERHIAADDRVRMAIPRLQFSGLISNGDKSVIFMGTGVDPEGEFDIGGVLTNVLTGNTLSTHSAPDAVPEVMLAKDLAKQLHADIGGLLTLLATTADGALNALDVQVRGIFSTGVPEMDKRMLAVALPTAQELIMTDKVGTLSVYLHEIEQTDAMWAVLAEWYPNFATQPWWEQASFYFKVRALYDIIFGVMGVIILLIVFFTITNTLSMTIVERTRETGTLLALGTLPRQIMRNFALEALLIGLAGALLGMLIAGFTSITLFIAEIQMPPPPGSTEGYPLYIYFSPWLYGITSLLVVTLSIAAAFLTSRKAARKPIVEALAHV
>string|0002|Phosphoserine_phosphatase_(EC_3_1_3_3)
MFQEHALTLAIFDLDNTLLAGDSDFLWGVFLVERGIVDGDEFERENERFYRAYQEGDLDIFEFLRFAFRPLRDNRLEDLKRWRQDFLREKIEPAILPMACELVEHHRAAGDTLLIITSTNEFVTAPIAEQLGIPNLIATVPEQLHGCYTGEAAGTPAFQAGKVKRLLDWLEETSTELAGSTFYSDSHNDIPLLEWVDHPVATDPDDRLRGYARDRGWPIISLREEIAP
I'm assuming from your posted sample and code that you actually want every contiguous sequence of any combination of spaces, periods, forward slashes and/or colons converted to a single underscore.

In awk.
$ awk '/^>/{n=sprintf("%04d",++i);sub(/^>/,">string|" n "|")}1' file
>string|0001|Lipoprotein releasing system transmembrane protein LolC
MKWLWFAYQNVIRNRRRSLMTILIIAVGTAAILLSNGFALYTYDNLREGSALASGHVIIAHVDHFDKEEEIPMEYGLSDYEDIERHIAADDRVRMAIPRLQFSGLISNGDKSVIFMGTGVDPEGEFDIGGVLTNVLTGNTLSTHSAPDAVPEVMLAKDLAKQLHADIGGLLTLLATTADGALNALDVQVRGIFSTGVPEMDKRMLAVALPTAQELIMTDKVGTLSVYLHEIEQTDAMWAVLAEWYPNFATQPWWEQASFYFKVRALYDIIFGVMGVIILLIVFFTITNTLSMTIVERTRETGTLLALGTLPRQIMRNFALEALLIGLAGALLGMLIAGFTSITLFIAEIQMPPPPGSTEGYPLYIYFSPWLYGITSLLVVTLSIAAAFLTSRKAARKPIVEALAHV
>string|0002|Phosphoserine phosphatase (EC 3.1.3.3)
MFQEHALTLAIFDLDNTLLAGDSDFLWGVFLVERGIVDGDEFERENERFYRAYQEGDLDIFEFLRFAFRPLRDNRLEDLKRWRQDFLREKIEPAILPMACELVEHHRAAGDTLLIITSTNEFVTAPIAEQLGIPNLIATVPEQLHGCYTGEAAGTPAFQAGKVKRLLDWLEETSTELAGSTFYSDSHNDIPLLEWVDHPVATDPDDRLRGYARDRGWPIISLREEIAP
Explained:
$ awk '
/^>/ { # if string starts with >
n=sprintf("%04d",++i) # iterate i from 1 and zeropad
sub(/^>/,">string|" n "|") # replace the > with stuff
}1' file # implicit output
Don't include & in string (see comments).

awk -F'[ \.]' 'BEGIN{a=1;OFS="_"}/^>/{$1=sprintf(">String|%04d",a);++a;print $0; next;}{print $0}' filename

Related

How to replace all escape sequences with non-escaped equivalent with unix utilities (sed/tr/awk)

I'm processing a Wireshark config file (dfilter_buttons) for display filters and would like to print out the filter of a given name. The content of file is like:
Sample input
"TRUE","test","sip contains \x22Hello, world\x5cx22\x22",""
And the resulting output should have the escape sequences replaced, so I can use them later in my script:
Desired output
sip contains "Hello, world\x22"
My first pass is like this:
Current parser
filter_name=test
awk -v filter_name="$filter_name" 'BEGIN {FS="\",\""} ($2 == filter_name) {print $3}' "$config_file"
And my output is this:
Current output
sip contains \x22Hello, world\x5cx22\x22
I know I can handle these exact two escape sequences by piping to sed and matching those exact two sequences, but is there a generic way to substitutes all escape sequences? Future filters I build may utilize more escape sequences than just " and , and I would like to handle future scenarios.
Using gnu-awk you can do this using split, gensub and strtonum functions:
awk -F '","' -v filt='test' '$2 == filt {n = split($3, subj, /\\x[0-9a-fA-F]{2}/, seps); for (i=1; i<n; ++i) printf "%s%c", subj[i], strtonum("0" substr(seps[i], 2)); print subj[i]}' file
sip contains "Hello, world\x22"
A more readable form:
awk -F '","' -v filt='test' '
$2 == filt {
n = split($3, subj, /\\x[0-9a-fA-F]{2}/, seps)
for (i=1; i<n; ++i)
printf "%s%c", subj[i], strtonum("0" substr(seps[i], 2))
print subj[i]
}' file
Explanation:
Using -F '","' we split input using delimiter ","
$2 == filt we filter input for $2 == "test" condition
Using /\\x[0-9a-fA-F]{2}/ as regex (that matches 2 digit hex strings) we split $3 and save split tokens into array subj and matched separators into array seps
Using substr we remove first char i.e \\ and prepend 0
Using strtonum we convert hex string to equivalent ascii number
Using %c in printf we print corresponding ascii character
Last for loop joins $3 back using subj and seps array elements
Using GNU awk for FPAT, gensub(), strtonum(), and the 3rd arg to match():
$ cat tst.awk
BEGIN { FPAT="([^,]*)|(\"[^\"]*\")"; OFS="," }
$2 == ("\"" filter_name "\"") {
gsub(/^"|"$/,"",$3)
while ( match($3,/(\\x[0-9a-fA-F]{2})(.*)/,a) ) {
printf "%s%c", substr($3,1,RSTART-1), strtonum(gensub(/./,0,1,a[1]))
$3 = a[2]
}
print $3
}
$ awk -v filter_name='test' -f tst.awk file
sip contains "Hello, world\x22"
The above assumes your escape sequences are always \x followed by exactly 2 hex digits. It isolates every \xHH string in the input, replaces \ with 0 in that string so that strtonum() can then convert the string to a number, then uses %c in the printf formatting string to convert that number to a character.
Note that GNU awk has a debugger (see https://www.gnu.org/software/gawk/manual/gawk.html#Debugger) so if you're ever not sure what any part of a program does you can just run it in the debugger (-D) and trace it, e.g. in the following I plant a breakpoint to tell awk to stop at line 1 of the script (b 1), then start running (r) and the step (s) through the script printing the value of $3 (p $3) at each line so I can see how it changes after the gsub():
$ awk -D -v filter_name='test' -f tst.awk file
gawk> b 1
Breakpoint 1 set at file `tst.awk', line 1
gawk> r
Starting program:
Stopping in BEGIN ...
Breakpoint 1, main() at `tst.awk':1
1 BEGIN { FPAT="([^,]*)|(\"[^\"]*\")"; OFS="," }
gawk> p $3
$3 = uninitialized field
gawk> s
Stopping in Rule ...
2 $2 == "\"" filter_name "\"" {
gawk> p $3
$3 = "\"sip contains \\x22Hello, world\\x5cx22\\x22\""
gawk> s
3 gsub(/^"|"$/,"",$3)
gawk> p $3
$3 = "\"sip contains \\x22Hello, world\\x5cx22\\x22\""
gawk> s
4 while ( match($3,/(\\x[0-9a-fA-F]{2})(.*)/,a) ) {
gawk> p $3
$3 = "sip contains \\x22Hello, world\\x5cx22\\x22"

Awk column with pattern array

Is it possible to do this but use an actual array of strings where it says "array"
array=(cat
dog
mouse
fish
...)
awk -F "," '{ if ( $5!="array" ) { print $0; } }' file
I would like to use spaces in some of the strings in my array.
I would also like to be able to match partial matches, so "snow" in my array would match "snowman"
It should be case sensitive.
Example csv
s,dog,34
3,cat,4
1,african elephant,gd
A,African Elephant,33
H,snowman,8
8,indian elephant,3k
7,Fish,94
...
Example array
snow
dog
african elephant
Expected output
s,dog,34
H,snowman,8
1,african elephant,gd
Cyrus posted this which works well, but it doesn't allow spaces in the array strings and wont match partial matches.
echo "${array[#]}" | awk 'FNR==NR{len=split($0,a," "); next} {for(i=1;i<=len;i++) {if(a[i]==$2){next}} print}' FS=',' - file
The brief approach using a single regexp for all array contents:
$ array=('snow' 'dog' 'african elephant')
$ printf '%s\n' "${array[#]}" | awk -F, 'NR==FNR{r=r s $0; s="|"; next} $2~r' - example.csv
s,dog,34
1,african elephant,gd
H,snowman,8
Or if you prefer string comparisons:
$ cat tst.sh
#!/bin/env bash
array=('snow' 'dog' 'african elephant')
printf '%s\n' "${array[#]}" |
awk -F',' '
NR==FNR {
array[$0]
next
}
{
for (val in array) {
if ( index($2,val) ) { # or $2 ~ val for a regexp match
print
next
}
}
}
' - example.csv
$ ./tst.sh
s,dog,34
1,african elephant,gd
H,snowman,8
This prints no line from csv file which contains an element from array in column 5:
echo "${array[#]}" | awk 'FNR==NR{len=split($0,a," "); next} {for(i=1;i<=len;i++) {if(a[i]==$5){next}} print}' FS=',' - file

How to extend a string in awk

I need to add dashes (-) to the end of a string in awk. The number of dashes is dynamic (it can be anything from 0 to like 1024), so it cannot be hard-coded. How to achieve it in awk?
In can be implemented like this:
function gen_chars(N) { s=""; for (i=1;i<=N; i++) {s = s "-"}; return s; }
but it looks ugly
create a long pad with the desired char and cut the required length, for example
awk -v size=5 'BEGIN {s="-"; for(i=1;i<=10;i++) s=s s;
print "string" substr(s,1,size)}'
This is an alternative with gnu awk:
$ cat file5
home
help
$ awk -vnd="15" '{$(NF+1)=sprintf("%*s",nd,"-");gsub(/[ ]/,"-",$NF)}1' file5 #nd=number of dashes
home ---------------
help ---------------
Another alternative would be to have a text/var with the maximum dashes (i.e 1024) and using printf to limit the max width:
$ md=$(printf '%.s-' {1..1024}) #md=max dashes = 1024
$ awk -vmd=$md -vnd="15" '{printf "%s%.*s\n",$0,nd,md}' file5 #nd=size of dashes
home---------------
help---------------
With GNU awk for gensub():
awk '
function gen_chars(n) { return gensub(/ /,"-","g",sprintf("%*s",n,"")) }
BEGIN { print gen_chars(3) }
'
---
with other awks:
function gen_chars(n, s) { s=sprintf("%*s",n,""); gsub(/ /,"-",s); return s }

How to print specific duplicate line based on fields number

I need to print out only one of various consecutive lines with same first field, and the one must be the one with "more fields in its last field". That means that last field is a set of words, and I need to print the line with more elements in its last field. In case of same number of max elements in last field, any of the max is ok.
Example input:
("aborrecimento",[Noun],[Masc],[Reg:Sing],[Bulk])
("aborrecimento",[Noun],[Masc],[Reg:Sing],[Device,Concrete,Count])
("aborrecimento",[Noun],[Masc],[Reg:Sing],[])
("adiamento",[Noun],[Masc],[Reg:Sing],[])
("adiamento",[Noun],[Masc],[Reg:Sing],[Count])
("adiamento",[Noun],[Masc],[Reg:Sing],[VerbNom])
Example output:
("aborrecimento",[Noun],[Masc],[Reg:Sing],[Device,Concrete,Count])
("adiamento",[Noun],[Masc],[Reg:Sing],[VerbNom])
solution with awk would be nice, but no need of one liner.
generate index file
$ cat input.txt |
sed 's/,\[/|[/g' |
awk -F'|' '
{if(!gensub(/[[\])]/, "", "g", $NF))n=0;else n=split($NF, a, /,/); print NR,$1,n}
' |
sort -k2,2 -k3,3nr |
awk '$2!=x{x=$2;print $1}' >idx.txt
content of index file
$ cat idx.txt
2
5
select lines
$ awk 'NR==FNR{idx[$0]; next}; (FNR in idx)' idx.txt input.txt
("aborrecimento",[Noun],[Masc],[Reg:Sing],[Device,Concrete,Count])
("adiamento",[Noun],[Masc],[Reg:Sing],[Count])
Note: no space in input.txt
Use [ as the field delimiter, then split the last field on ,:
awk -F '[[]' '
{split($NF, f, /,/)}
length(f) > max[$1] {line[$1] = $0; max[$1] = length(f)}
END {for (l in line) print line[l]}
' filename
Since order is important, an update:
awk -F '[[]' '
{split($NF, f, /,/)}
length(f) > max[$1] {line[$1] = $0; max[$1] = length(f); nr[$1] = NR}
END {for (l in line) printf("%d\t%s\n", nr[$1], line[l])}
' filename |
sort -n |
cut -f 2-
Something like this might work:
awk 'BEGIN {FS="["}
Ff != gensub("^([^,]+).*","\\1","g",$0) { Ff = gensub("^([^,]+).*","\\1","g",$0) ; Lf = $NF ; if (length(Ml) > 0) { print Ml } }
Ff == gensub("^([^,]+).*","\\1","g",$0) { if (length($NF) > length(Lf)) { Lf=$NF ; Ml=$0 } }
END {if (length(Ml) > 0) { print Ml } }' INPUTFILE
See here in action. BUT it's not the solution you want to use, as this is rather a hack. And it fails you if you meant that your last field is longer if it contains more , separated elements than the length of your last element. (E.g. the above script happily reports [KABLAMMMMMMMMMMM!] as longer than [A,B,C].)
This might work for you:
sort -r file | sort -t, -k1,1 -u

Use Awk to Print every character as its own column?

I am in need of reorganizing a large CSV file. The first column, which is currently a 6 digit number needs to be split up, using commas as the field separator.
For example, I need this:
022250,10:50 AM,274,22,50
022255,11:55 AM,275,22,55
turned into this:
0,2,2,2,5,0,10:50 AM,274,22,50
0,2,2,2,5,5,11:55 AM,275,22,55
Let me know what you think!
Thanks!
It's a lot shorter in perl:
perl -F, -ane '$,=","; print split("",$F[0]), #F[1..$#F]' <file>
Since you don't know perl, a quick explanation. -F, indicates the input field separator is the comma (like awk). -a activates auto-split (into the array #F), -n implicitly wraps the code in a while (<>) { ... } loop, which reads input line-by-line. -e indicates the next argument is the script to run. $, is the output field separator (it gets set iteration of the loop this way, but oh well). split has obvious purpose, and you can see how the array is indexed/sliced. print, when lists as arguments like this, uses the output field separator and prints all their fields.
In awk:
awk -F, '{n=split($1,a,""); for (i=1;i<=n;i++) {printf("%s,",a[i])}; for (i=2;i<NF;i++) {printf("%s,",$i)}; print $NF}' <file>
I think this might work. The split function (at least in the version I am running) splits the value into individual characters if the third parameter is an empty string.
BEGIN{ FS="," }
{
n = split( $1, a, "" );
for ( i = 1; i <= n; i++ )
printf("%s,", a[i] );
sep = "";
for ( i = 2; i <= NF; i++ )
{
printf( "%s%s", sep, $i );
sep = ",";
}
printf("\n");
}
here's another way in awk
$ awk -F"," '{gsub(".",",&",$1);sub("^,","",$1)}1' OFS="," file
0,2,2,2,5,0,10:50 AM,274,22,50
0,2,2,2,5,5,11:55 AM,275,22,55
Here's a variation on a theme. One thing to note is it prints the remaining fields without using a loop. Another is that since you're looping over the characters in the first field anyway, why not just do it without using the null-delimiter feature of split() (which may not be present in some versions of AWK):
awk -F, 'BEGIN{OFS=","} {len=length($1); for (i=1;i<len; i++) {printf "%s,", substr($1,i,1)}; printf "%s", substr($1,len,1);$1=""; print $0}' filename
As a script:
BEGIN {FS = OFS = ","}
{
len = length($1);
for (i=1; i<len; i++)
{printf "%s,", substr($1, i, 1)};
printf "%s", substr($1, len, 1)
$1 = "";
print $0
}