I need a PostgreSQL subquery that can return more than a row. Here's the piece of the query that I have so far:
select (SELECT ARRAY[url, thumb_1, thumb_200, thumb_500]
FROM "Image"
LEFT JOIN "Product_Image"
ON "Image".id = "Product_Image".image_id
WHERE "Product_Image".product_id = 517
ORDER BY "Product_Image".sort ASC) as images
Put the subquery in the FROM clause?
select vals
from (SELECT ARRAY[url, thumb_1, thumb_200, thumb_500] as vals
FROM "Image" LEFT JOIN
"Product_Image"
ON "Image".id = "Product_Image".image_id
WHERE "Product_Image".product_id = 517
) images
Related
I have Oracle SQL like these :
SELECT
z."date", z.id_outlet as idOutlet, z.name as outletName, z.matClass, z.targetBulanan, z.targetBulanan/totalVisit as targetAwal,
z.actual,rownumber = tartot + rownumber as targetTotal
FROM (SELECT
b.visit_date as "date", a.id_outlet, max(o.name) as name, max(a.target_sales) as targetBulanan, a.id_material_class as matClass,
max(x.totalVisit) as totalVisit, NVL(SUM(d.billing_value),0) as actual
FROM (
select * from target_bulanan
where deleted = 0 and enabled = 1 and id_salesman = :id_salesman AND id_material_class like :id_material_class AND id_outlet like :id_outlet AND month = TO_NUMBER(TO_CHAR(current_date,'mm')) and year = to_number(TO_CHAR(current_date,'YYYY'))
) a
INNER JOIN outlet o ON o.id_outlet = a.id_outlet
LEFT JOIN visit_plan b ON b.deleted = 0 and a.id_salesman = b.id_salesman AND a.month = TO_NUMBER(TO_CHAR(b.visit_date,'mm')) AND a.year = to_number(TO_CHAR(b.visit_date,'yyyy')) AND a.id_outlet = b.id_outlet
LEFT JOIN so_header c ON SUBSTR(c.id_to,'0',1) = 'TO' AND a.id_salesman = c.id_salesman AND a.id_outlet = c.id_outlet
LEFT JOIN assign_billing d ON c.no_so_sap = d.no_so_sap AND d.billing_date = b.visit_date AND a.id_material_class = (SELECT id_material_class FROM material WHERE id = d.id_material)
LEFt JOIN (SELECT id_salesman, to_char(visit_date,'mm') as month, to_char(visit_date,'yyyy') as year, id_outlet, COUNT(*) as totalVisit FROM visit_plan
WHERE deleted = 0
group by id_salesman, id_outlet,to_char(visit_date,'mm'), to_char(visit_date,'yyyy')) x on
x.id_salesman = a.id_salesman AND x.month = a.month AND x.year = a.year AND x.id_outlet = a.id_outlet
GROUP BY b.visit_date, a.id_outlet, a.id_material_class) z
CROSS JOIN (SELECT 0 as rownumber FROM DUAL ) r
CROSS JOIN (SELECT 0 as tartot FROM DUAL ) t
CROSS JOIN (SELECT '' as mat FROM DUAL ) m
CROSS JOIN (SELECT '' as outlet FROM DUAL ) o
ORDER by outletName, z.matClass, z."date"
I want value of rownumber is formula in my select query but the result is error with this message
ORA-00923: FROM keyword not found where expected
00923. 00000 - "FROM keyword not found where expected"
Anyone can help me ? thanks
Just for enumeration -
replace the line
rownumber = rownumber + 1 AS row_number
with this
rownum AS row_number
rownum is an Oracle inbuilt function that enumerates each record of the result set and with auto increments
As mentioned by Gordon Linoff in his answer, there are further problems in your query.
At the first look (without executing it), I could list the problematic lines -
AND month = TO_NUMBER(TO_CHAR(current_date,'mm'))
AND year = to_number(TO_CHAR(current_date,'YYYY'))
Instead of current_date use sysdate
LEFT JOIN so_header c ON SUBSTR(c.id_to,'0',1) = 'TO'
I guess, you meant to do this -
LEFT JOIN so_header c ON SUBSTR(c.id_to,0,2) = 'TO'
i.e. substring from index 0 upto 2 characters
Plus, no need of those cross joins
THIS ADDRESSES THE ORIGINAL QUESTION.
You may have multiple problems in your query. After all, the best way to debug and to write queries is to start simple and gradually add complexity.
But, you do have an obvious error. In your outermost select:
SELECT z."date", z.id_outlet as idOutlet, z.name as outletName,
z.matClass, z.targetBulanan, z.targetBulanan/totalVisit as targetAwal,
z.actual,
rownumber = rownumber + 1 as row_number
The = is not Oracle syntax -- it looks like a SQL Server extension for naming a column or a MySQL use of variables.
I suspect that you want to enumerate the rows. If so, one syntax is row_number():
SELECT z."date", z.id_outlet as idOutlet, z.name as outletName,
z.matClass, z.targetBulanan, z.targetBulanan/totalVisit as targetAwal,
z.actual,
row_number() over (order by outletName, z.matClass, z."date") as row_number
In Oracle, you could also do:
rownum as row_number
select *
from EFLOVRelationship R
where R.parentEFLOVValueId = '5320'
and R.childEFLOVId in (select Eflovid
from EFFieldLOVStaticValue
where efLovId = 49)
In the above query I want to fetch 2 columns from EFFieldLOVStaticValue table and display.
Thanks in advance
Use Inner Join
SELECT R.*,
V.field1,
V.field2
FROM eflovrelationship R
INNER JOIN effieldlovstaticvalue V
ON R.childeflovid = V.eflovid
WHERE R.parenteflovvalueid = '5320'
AND V.eflovid = 49
If your table has 1:N relationship then use Distinct to avoid duplicates in result
If you want just one record from effieldlovstaticvalue table for each R.childeflovid column then use Cross Apply but you need to use required column to order the result and choose the top 1 record
SELECT R.*,
CS.field1,
CS.field2
FROM eflovrelationship R
CROSS apply (SELECT TOP 1 field1,
field2
FROM effieldlovstaticvalue V
WHERE R.childeflovid = V.eflovid
AND eflovid = 49
ORDER BY someordercolumn) CS
WHERE R.parenteflovvalueid = '5320'
Use join:
select R.*, sv.?, sv.?
from EFLOVRelationship R join
EFFieldLOVStaticValue sv
ON sv.Eflovid = R.childEFLOVId and sv.efLovId = 49
where R.parentEFLOVValueId = '5320'
I am facing problem in join. I am getting duplicate records.Please help me to resolve that..
This is my query:
select requestinstanceid from
requestidt [RIM]
inner join requestcdt [RCDT] on [RIM].requestinstanceid = [RCDT].requestinstanceid
left join requestcmt [RCMT] on [RCDT].requestcommentid = [RCMT].requestcommentid
inner join requestddt [RDDT] on [RDDT].requestinstanceid = [RIM].requestinstanceid
left join requestdmt [RDMT] on [RDMT].requestdocumentid = [RDDT].requestdocumentid
I am getting result like this:
requestinstanceid
184
184
386
389
389
397
I should get not get duplicate record and I want to get the latest date from each record.
This code joins to the 'top 1' of a derived table. You should be able to work out how it could be applied to join to the Top 1 of sub-query sorted by date DESC.
SELECT T2.TempEmailID, T1.EmailID
FROM tbl1 T1
LEFT JOIN (SELECT *, RANK() Over (Partition By EmailID Order By TempEmailID DESC) as TopOne FROM tbl2) T2 ON T1.EmailID = T2.EmailID AND TopOne = 1
I have the following query:
SELECT sum((select count(*) as itemCount) * "SalesOrderItems"."price") as amount, 'rma' as
"creditType", "Clients"."company" as "client", "Clients".id as "ClientId", "Rmas".*
FROM "Rmas" JOIN "EsnsRmas" on("EsnsRmas"."RmaId" = "Rmas"."id")
JOIN "Esns" on ("Esns".id = "EsnsRmas"."EsnId")
JOIN "EsnsSalesOrderItems" on("EsnsSalesOrderItems"."EsnId" = "Esns"."id" )
JOIN "SalesOrderItems" on("SalesOrderItems"."id" = "EsnsSalesOrderItems"."SalesOrderItemId")
JOIN "Clients" on("Clients"."id" = "Rmas"."ClientId" )
WHERE "Rmas"."credited"=false AND "Rmas"."verifyStatus" IS NOT null
GROUP BY "Clients".id, "Rmas".id;
The problem is that the table "EsnsSalesOrderItems" can have the same EsnId in different entries. I want to restrict the query to only pull the last entry in "EsnsSalesOrderItems" that has the same "EsnId".
By "last" entry I mean the following:
The one that appears last in the table "EsnsSalesOrderItems". So for example if "EsnsSalesOrderItems" has two entries with "EsnId" = 6 and "createdAt" = '2012-06-19' and '2012-07-19' respectively it should only give me the entry from '2012-07-19'.
SELECT (count(*) * sum(s."price")) AS amount
, 'rma' AS "creditType"
, c."company" AS "client"
, c.id AS "ClientId"
, r.*
FROM "Rmas" r
JOIN "EsnsRmas" er ON er."RmaId" = r."id"
JOIN "Esns" e ON e.id = er."EsnId"
JOIN (
SELECT DISTINCT ON ("EsnId") *
FROM "EsnsSalesOrderItems"
ORDER BY "EsnId", "createdAt" DESC
) es ON es."EsnId" = e."id"
JOIN "SalesOrderItems" s ON s."id" = es."SalesOrderItemId"
JOIN "Clients" c ON c."id" = r."ClientId"
WHERE r."credited" = FALSE
AND r."verifyStatus" IS NOT NULL
GROUP BY c.id, r.id;
Your query in the question has an illegal aggregate over another aggregate:
sum((select count(*) as itemCount) * "SalesOrderItems"."price") as amount
Simplified and converted to legal syntax:
(count(*) * sum(s."price")) AS amount
But do you really want to multiply with the count per group?
I retrieve the the single row per group in "EsnsSalesOrderItems" with DISTINCT ON. Detailed explanation:
Select first row in each GROUP BY group?
I also added table aliases and formatting to make the query easier to parse for human eyes. If you could avoid camel case you could get rid of all the double quotes clouding the view.
Something like:
join (
select "EsnId",
row_number() over (partition by "EsnId" order by "createdAt" desc) as rn
from "EsnsSalesOrderItems"
) t ON t."EsnId" = "Esns"."id" and rn = 1
this will select the latest "EsnId" from "EsnsSalesOrderItems" based on the column creation_date. As you didn't post the structure of your tables, I had to "invent" a column name. You can use any column that allows you to define an order on the rows that suits you.
But remember the concept of the "last row" is only valid if you specifiy an order or the rows. A table as such is not ordered, nor is the result of a query unless you specify an order by
Necromancing because the answers are outdated.
Take advantage of the LATERAL keyword introduced in PG 9.3
left | right | inner JOIN LATERAL
I'll explain with an example:
Assuming you have a table "Contacts".
Now contacts have organisational units.
They can have one OU at a point in time, but N OUs at N points in time.
Now, if you have to query contacts and OU in a time period (not a reporting date, but a date range), you could N-fold increase the record count if you just did a left join.
So, to display the OU, you need to just join the first OU for each contact (where what shall be first is an arbitrary criterion - when taking the last value, for example, that is just another way of saying the first value when sorted by descending date order).
In SQL-server, you would use cross-apply (or rather OUTER APPLY since we need a left join), which will invoke a table-valued function on each row it has to join.
SELECT * FROM T_Contacts
--LEFT JOIN T_MAP_Contacts_Ref_OrganisationalUnit ON MAP_CTCOU_CT_UID = T_Contacts.CT_UID AND MAP_CTCOU_SoftDeleteStatus = 1
--WHERE T_MAP_Contacts_Ref_OrganisationalUnit.MAP_CTCOU_UID IS NULL -- 989
-- CROSS APPLY -- = INNER JOIN
OUTER APPLY -- = LEFT JOIN
(
SELECT TOP 1
--MAP_CTCOU_UID
MAP_CTCOU_CT_UID
,MAP_CTCOU_COU_UID
,MAP_CTCOU_DateFrom
,MAP_CTCOU_DateTo
FROM T_MAP_Contacts_Ref_OrganisationalUnit
WHERE MAP_CTCOU_SoftDeleteStatus = 1
AND MAP_CTCOU_CT_UID = T_Contacts.CT_UID
/*
AND
(
(#in_DateFrom <= T_MAP_Contacts_Ref_OrganisationalUnit.MAP_KTKOE_DateTo)
AND
(#in_DateTo >= T_MAP_Contacts_Ref_OrganisationalUnit.MAP_KTKOE_DateFrom)
)
*/
ORDER BY MAP_CTCOU_DateFrom
) AS FirstOE
In PostgreSQL, starting from version 9.3, you can do that, too - just use the LATERAL keyword to achieve the same:
SELECT * FROM T_Contacts
--LEFT JOIN T_MAP_Contacts_Ref_OrganisationalUnit ON MAP_CTCOU_CT_UID = T_Contacts.CT_UID AND MAP_CTCOU_SoftDeleteStatus = 1
--WHERE T_MAP_Contacts_Ref_OrganisationalUnit.MAP_CTCOU_UID IS NULL -- 989
LEFT JOIN LATERAL
(
SELECT
--MAP_CTCOU_UID
MAP_CTCOU_CT_UID
,MAP_CTCOU_COU_UID
,MAP_CTCOU_DateFrom
,MAP_CTCOU_DateTo
FROM T_MAP_Contacts_Ref_OrganisationalUnit
WHERE MAP_CTCOU_SoftDeleteStatus = 1
AND MAP_CTCOU_CT_UID = T_Contacts.CT_UID
/*
AND
(
(__in_DateFrom <= T_MAP_Contacts_Ref_OrganisationalUnit.MAP_KTKOE_DateTo)
AND
(__in_DateTo >= T_MAP_Contacts_Ref_OrganisationalUnit.MAP_KTKOE_DateFrom)
)
*/
ORDER BY MAP_CTCOU_DateFrom
LIMIT 1
) AS FirstOE
Try using a subquery in your ON clause. An abstract example:
SELECT
*
FROM table1
JOIN table2 ON table2.id = (
SELECT id FROM table2 WHERE table2.table1_id = table1.id LIMIT 1
)
WHERE
...
Basically I am trying to do a query to a page that holds just an image. I need to provide the tripID number and then the ROWID (as there could be multiple images) to receive a single image. I will be looping until each image is in its corresponding image box in html.
This code doesn't seem to work(I get Invalid column name 'ROWID'), but if I remove the AND ROWID='1' it returns all the images and its row id like this:
ROWID PHOTO
1 32jjr3h2jh23hj4h32jh42ll23j42
2 HU8308DJAOID9ASIDJI32C89EE29
-
Select ROW_NUMBER() OVER (ORDER BY Photo ASC) AS ROWID, TBL_Photo.Photo
From TBL_Photo
left join TBL_TripDetails
ON TBL_Photo.TripID=TBL_TripDetails.pkiTripID
Where pkiTripID = '121' AND ROWID = '1'
You can't reference a column alias in the WHERE clause -- you need to use a subquery or a CTE:
Subquery Example:
SELECT x.rowid,
x.photo
FROM (SELECT ROW_NUMBER() OVER (ORDER BY p.photo) AS ROWID,
p.photo
FROM TBL_PHOTO p
LEFT JOIN TBL_TRIPDETAILS td ON td.pkitripid = p.tripid
WHERE td.pkiTripID = '121') x
WHERE x.rowid = 1
CTE example:
WITH example AS (
SELECT ROW_NUMBER() OVER (ORDER BY p.photo) AS ROWID,
p.photo
FROM TBL_PHOTO p
LEFT JOIN TBL_TRIPDETAILS td ON td.pkitripid = p.tripid
WHERE td.pkiTripID = '121')
SELECT x.rowid,
x.photo
FROM example x
WHERE x.rowid = 1
Performance
There's no performance difference between the two options, but the WITH syntax isn't supported on all databases.