A | B | C | D | E
a y 6 12 21
b n 3 10 5
c n 4 12 12
c n 7 12 2
c y 1 12 22
d n 6 10 32
d n 7 10 32
OUTPUT TABLE:
A | B | C | F
a y 6 21
b n 3 12
c y 1 22
d n 6 10
I have a table that contains certain fields. From that table I want to remove duplicate records in A and produce the output table.
Now, the field F is calculated based on the field C when there are no duplicates for the records in A. So, if there is only one record of a in A then if C>5 then the F Column(Output table) pulls the record in E column. So, if record b has the value <5 in field C, then the F column (output table) will pull the record in D column for b. I have been able to achieve this using a case statement.
However, when there are duplicate records in column A, I want only one of the records based on the column B. Only that record should be pulled that has the value 'y' in column B and where the column F contains the value from column E. If none of the duplicate records in A have a value of 'n' in the B column, then pull any record with column D as column F in the output table. I am not able to figure out this part.
Please let me know if anything is not clear.
Code I am using:
SELECT A,B,C,
CASE
WHEN (SELECT COUNT(*) FROM MyTable t2 WHERE t1.A=t2.A)>1
THEN (SELECT TOP 1 CASE WHEN b='y' THEN E ELSE D END
FROM MyTable t3
WHERE t3.A=t1.A
ORDER BY CASE WHEN b='y' THEN 0 ELSE 1 END)
ELSE {
case when cast(C as float) >= 5.00 then (Case when E = '0.00' then D else E end)
when cast(C as float)< 5.00 then D end )
}
END AS F
FROM MyTable t1
You might want to encapsulate this logic in a Function to make it look cleaner, but the logic would go like this:
IF the record count of rows in the table with the same value for A as the current row is greater than 1, THEN SELECT the TOP 1 record with this value for A ORDER BY CASE WHEN b='y' THEN 0 ELSE 1 END
Use another CASE WHEN b='y' to determine if you will use column E or D for output column F.
And ELSE (the record count is not greater than 1), use your existing CASE expression.
EDIT: Here is a more psuedo-codey explanation:
WITH cte AS (SELECT A,B,C,
ROW_NUMBER() OVER (PARTITION BY A, ORDER BY CASE WHEN b='y' THEN 0 ELSE 1 END) rn
FROM MyTable
)
SELECT A,B,C,
CASE
WHEN (SELECT COUNT(*) FROM MyTable t2 WHERE t1.A=t2.A)>1
THEN CASE WHEN b='y' THEN E ELSE D END
ELSE {use your existing CASE Expression}
END AS F
FROM cte t1
WHERE rn=1
Related
I need help with writing a query to generate a result that will provide me with all record numbers NOT assigned to Group D from a table structured like the below example. From the below table my desired result would be record number "3" .
Record_Number Assigned_To_Group
1 A
1 B
1 C
1 D
2 A
2 E
2 D
3 A
3 B
3 E
One method uses aggregation:
select Record_Number
from t
group by Record_Number
having sum(case when Assigned_To_Group = 'D' then 1 else 0 end) = 0;
I would like to know how can i sort values from a table based on hierarchy values of a field.
EX:
A B
--------
1 A
2 F
3 A
4 P
5 O
6 F
I would like sort the values by the B field and appear first the F Values, then A values, then P values and in the end the O values.
In the end, the result must be like this:
2 F
6 F
1 A
3 A
4 P
5 O
Use a case expression in order by.
select *
from tablename
order by case when B = 'F' then 1
when B = 'A' then 2
when B = 'P' then 3
when B = 'O' then 4
end, A
More compact:
order by translate (B, 'FAPO', '1234')
This will also allow you, if needed (now or in the future) to have PF compared to PA, rather than just single letter values in column B.
I have a table that looks similar to this:
ID OLD NEW TIME
1 a b 5
1 b c 7
1 c d 45
1 d e 4
2 a b 1
2 b d 8
2 d e 45
3 b c 15
3 c d 14
And I would like to build a report that looks like this (basically for each OLD data point grab the TIME value):
ID TimeForA TimeForB TimeForC TimeForD
1 5 7 45 4
2 1 8 NULL 45
3 NULL 15 14 NULL
I have been able to get all the data into the correct columns, but have not been able to combine each row into a single row for each ID. My current query looks like this (no I don't have every column in place yet, still just testing):
WITH CTE (id, ATime, BTime)
AS
(
select T1.oid, T1.loggedFor, null, T1.time as Atime
from Table1 T1
where T1.OLD = 'a'
union
select T1.oid, T1.loggedFor, T1.time as BTime, null
from Table1 T1
where T1.old = 'b'
)
select ID, ATime, BTime
from CTE
order by ID
Any help appreciated!
Try this:
select id,
sum(if(old = 'a',time,null)) as time_for_a,
sum(if(old = 'b',time,null)) as time_for_b,
sum(if(old = 'c',time,null)) as time_for_c,
sum(if(old = 'd',time,null)) as time_for_d
from test_tbl
group by id
order by id;
The SQL Server 2005 table I'm working from is really strange. Here's a simplified example:
TABLE 1:
key | a | b | c | d | e | f
z 0 1 2 3 4 5 6
y 1 8 9 10 11 12 13
x 14 15 16 17 18 19 20
w 21 22 23 24 25 26 27
TABLE 2:
id | Value
1 a
2 b
3 c
4 e
5 f
What I need to accomplish is to, in a single statement, select the column name from a different table, then get the value here. So it would be something like "Select (select colName from table2 where id=VAR1) From table1 where key = VAR2"
So table2 will return either a/b/c/d/e/f, and then the main statement will get the value of the corresponding value based on the key.
Table2 will always return a-f, and I will know the VAR1 and VAR2 ahead of time.
You can use UNPIVOT:
SELECT [key], val, col
FROM
(SELECT [key], a, b, c, d, e, f
FROM table1
WHERE [key] = #var2) AS src
UNPIVOT
(val FOR col IN
(a, b, c, d, e, f)
)AS unpvt
WHERE col = (SELECT value FROM table2 WHERE id = #var1)
UNPIVOT operation transposes table data from columns to rows creating an extra field where column name is placed. This way you can query table data using the name of the column that is obtained from table2.
Demo here
still not found the solution described in update 2
thx for help
ill try to explain my issue with my poor english. hope someone can solve my problem.
i got the following table
A B
1 Y
2 null
3 Y
what result i want?
in dependency of the rank in column A i want to combine column B.
the result in that example is ... no result
the reason is because there is a null in rank 2 and the next and the last rank (=3) has a value (=Y).
next example
A B
1 Y
2 null
3 null
result i want is
A B
1 Y
because the way after is free... means 2 and the last 3 has null
another example
A B
1 null
2 N
3 null
again no result is what i want in this case. because first =1 has null value.
i try now to conclude ... if n(e.g. 2) of column B has value Y or N then the elements bevor (in this 1) must have the value Y or N.
thank you very much. i tried different technics without any success...
UPDATE 1
thank you fast comment
some example dates with expected result
example 1
A B
1 Y
2 N
3 null
4 null
expected result
A B
2 N
example 2
A B
1 N
2 Y
3 N
4 null
expected result
A B
3 N
example 3
A B
1 null
2 Y
3 Y
4 null
expected result
no result
example 4
A B
1 Y
2 Y
3 null
4 Y
expected result
no result
UPDATE 2
forget the basic case
A B
1 Y
2 N
3 Y
expected result
A B
3 N
Establish the highest value of A where B is Y or N, and the lowest value of A where B is null. Provided the first value is lower than the second value you have a valid result set.
select yt.A
, yt.B
from
( select max(case when B is not null then A else null end) as max_b_yn
, min(case when B is null then A else null end) as min_b_null
from your_table ) t1
, your_table yt
where ( t1.min_b_null is null
or t1.max_b_yn < t1.min_b_null )
and yt.A = t1.max_b_yn
/
I think you want the last row before the first NULL. If this is correct, then the following gets what you want:
select t.*
from t join
(select min(A) as NullA from t where B is NULL) t2
on t.A = t2.NullA - 1
Ah, I see. To get the last row with an "N":
select t.*
from t
where t.A in (select max(A) as MaxA
from t join
(select min(A) as NullA from t where B is NULL) t2
on t.A < t2.NullA
where t.B = 'N'
)
OK, I think I have what you need. It grabs the last row that has a value in column B as long as there isn't a row with a NULL that precedes it.
select MAX(A), B
from table_a
where B IS NOT NULL
and table_a.A > (
select MIN(A)
FROM table_a
WHERE B IS NULL
)
Group by B
select top 1 A, B
from #Temp
where B is not null
order by A desc
or
select top 1 A, B
from #Temp
where B = 'N'
order by A desc