I want to get the below result:
source table :
Cnt A B
4 ABC YU/FGH
5 ABC YU/DFE
5 ABC KL
2 LKP BN/ER
4 JK RE
Result:
Cnt A B
9 ABC YU
5 ABC KL
2 LKP BN
4 JK RE
Here I want the count by grouping 'B' and want to display the 'B' record only till the special character (/)
Basically, you will have to filter out the all the characters after the "/" symbol and then apply a SUM and a GROUP BY. You can see this below. The inner query filters out the unwanted string and the outer query does the SUM and the GROUP BY :
SELECT SUM(t.Cnt), t.A, t.B
FROM (
SELECT Cnt,
A,
CASE
WHEN CHARINDEX('/', B) > 0 THEN SUBSTRING(B, 0, CHARINDEX('/', B))
ELSE B
END AS B
FROM #Tab
) t
GROUP BY t.A, t.B
ORDER BY t.A
You can see this working here -> http://rextester.com/IQJ79191
Hope this helps!!!
You can get your string till '/' by using SUBSTRING.
select
count(SUBSTRING(reverse(B),0,charindex('/',reverse(B)))),
A,
SUBSTRING(reverse(B),0,charindex('/',reverse(B)))
from source_table group by B;
Solution for Oracle - substr(B,0,instr(B,'/',1)-1) B
Put this both in select and groupby
I can suggest you to use a query like this:
select
sum(Cnt) Cnt,
A,
left(B, charindex('/',B+'/',0)-1) B -- Using `+'\'` will do the trick
from
t
group by
A,
left(B, charindex('/',B+'/',0)-1);
By using String and CharIndex Functions.
;WITH SourceTable(Cnt,A,B) AS
(
SELECT 4,'ABC','YU/FGH'UNION ALL
SELECT 5,'ABC','YU/DFE'UNION ALL
SELECT 5,'ABC','KL' UNION ALL
SELECT 2,'LKP','BN/ER' UNION ALL
SELECT 4,'JK','RE'
)
SELECT SUM(Cnt) AS Cnt,A,CASE WHEN CHARINDEX('/',B) = 0 THEN B
ELSE SUBSTRING(B,0,CHARINDEX('/',B)) END AS [B] FROM SourceTable
GROUP BY A,CASE WHEN CHARINDEX('/',B) = 0 THEN B
ELSE SUBSTRING(B,0,CHARINDEX('/',B)) END
ORDER BY Cnt DESC
Try this query --
SELECT SUM(Cnt) AS [COUNT]
,A
,CASE
WHEN CHARINDEX('/', B) > 0
THEN SUBSTRING(B, 1, (CHARINDEX('/', B) - 1))
ELSE B
END
FROM tblSample
GROUP BY A, B
ORDER BY A, B
Related
MS SQL Server
I have two tables with different accounts from the same customer:
Table1:
ID
ACCOUNT
FROM
TO
1
A
01.10.2019
01.12.2019
1
A
01.02.2020
09.09.9999
and table2:
ID
ACCOUNT
FROM
TO
1
B
01.12.2019
01.01.2020
As result I want a table that summarize the story of this costumer and shows when he had an active account and when he doesn't.
Result:
ID
FROM
TO
ACTIV Y/N
1
01.10.2019
01.01.2020
Y
1
02.01.2020
31.01.2020
N
1
01.02.2020
09.09.9999
Y
Can someone help me with some ideas how to proceed?
This is the typical gaps and island problem, and it's not usually easy to solve.
You can achieve your goal using this query, I will explain it a little bit.
You can test on this db<>fiddle.
First of all... I have unified your two tables into one to simplify the query.
-- ##table1
select 1 as ID, 'A' as ACCOUNT, convert(date,'2019-10-01') as F, convert(date,'2019-12-01') as T into ##table1
union all
select 1 as ID, 'A' as ACCOUNT, convert(date,'2020-02-01') as F, convert(date,'9999-09-09') as T
-- ##table2
select 1 as ID, 'B' as ACCOUNT, convert(date,'2019-12-01') as F, convert(date,'2020-01-01') as T into ##table2
-- ##table3
select * into ##table3 from ##table1 union all select * from ##table2
You can then get your gaps and island using, for example, a query like this.
It combines recursive cte to generate a calendar (cte_cal) and lag and lead operations to get the previous/next record information to build the gaps.
with
cte_cal as (
select min(F) as D from ##table3
union all
select dateadd(day,1,D) from cte_cal where d < = '2021-01-01'
),
table4 as (
select t1.ID, t1.ACCOUNT, t1.F, isnull(t2.T, t1.T) as T, lag(t2.F, 1,null) over (order by t1.F) as SUP
from ##table3 t1
left join ##table3 t2
on t1.T=t2.F
)
select
ID,
case when T = D then F else D end as "FROM",
isnull(dateadd(day,-1,lead(D,1,null) over (order by D)),'9999-09-09') as "TO",
case when case when T = D then F else D end = F then 'Y' else 'N' end as "ACTIV Y/N"
from (
select *
from cte_cal c
cross apply (
select t.*
from table4 t
where t.SUP is null
and (
c.D = t or
c.D = dateadd(day,1,t.T)
)
) t
union all
select F, * from table4 where T = '9999-09-09'
) p
order by 1
option (maxrecursion 0)
Dates like '9999-09-09' must be treated like exceptions, otherwise I would have to create a calendar until that date, so the query would take long time to resolve.
Say I have a BQ table containing the following information
id
test.name
test.score
1
a
5
b
7
2
a
8
c
3
Where test is nested. How would I pivot test into the following table?
id
a
b
c
1
5
7
2
8
3
I cannot pivot test directly, as I get the following error message at pivot(test): Table-valued function not found. Previous questions (1, 2) don't deal with nested columns or are outdated.
The following query looks like a useful first step:
select a.id, t
from `table` as a,
unnest(test) as t
However, this just provides me with:
id
test.name
test.score
1
a
5
1
b
7
2
a
8
2
c
3
Conditional aggregation is a good approach. If your tables are large, you might find that this has the best performance:
select t.id,
(select max(tt.score) from unnest(t.score) tt where tt.name = 'a') as a,
(select max(tt.score) from unnest(t.score) tt where tt.name = 'b') as b,
(select max(tt.score) from unnest(t.score) tt where tt.name = 'c') as c
from `table` t;
The reason I recommend this is because it avoids the outer aggregation. The unnest() happens without shuffling the data around -- and I have found that this is a big win in terms of performance.
One option could be using conditional aggregation
select id,
max(case when test.name='a' then test.score end) as a,
max(case when test.name='b' then test.score end) as b,
max(case when test.name='c' then test.score end) as c
from
(
select a.id, t
from `table` as a,
unnest(test) as t
)A group by id
Below is generic/dynamic way to handle your case
EXECUTE IMMEDIATE (
SELECT """
SELECT id, """ ||
STRING_AGG("""MAX(IF(name = '""" || name || """', score, NULL)) AS """ || name, ', ')
|| """
FROM `project.dataset.table` t, t.test
GROUP BY id
"""
FROM (
SELECT DISTINCT name
FROM `project.dataset.table` t, t.test
ORDER BY name
)
);
If to apply to sample data from your question - output is
Row id a b c
1 1 5 7 null
2 2 8 null 3
I try to understand how PIVOT table works
These 2 requests with pivot table seem equivalent:
I only write
tablename.column1, ...........column2 instead of tablename.*
You can find the requests here:
https://dbfiddle.uk/?rdbms=oracle_11.2&fiddle=a5c3aacdaebe599bb050295caf3512b6
with
a as
(
select
a1.column_value a, a2.column_value b , cos(a1.r) c
from
(select column_value, rownum r from table(sys.odcinumberlist(1,2,3,4,5))) a1 ,
(select column_value, rownum r from table(sys.odcivarchar2list('a','b','a','b','a'))) a2
where
a1.r = a2.r)
select a.a,a.b,a.c from a --a.a,a.b
PIVOT
(
count(a.a)--,sum(a.c)
FOR b IN ('a', 'b')
)
ORA-00904: "A"."C": invalid identifier
with
a as
(
select
a1.column_value a, a2.column_value b , cos(a1.r) c
from
(select column_value, rownum r from table(sys.odcinumberlist(1,2,3,4,5))) a1 ,
(select column_value, rownum r from table(sys.odcivarchar2list('a','b','a','b','a'))) a2
where
a1.r = a2.r)
select * from a
PIVOT
(
COUNT(a.a)--,sum(a.c)
FOR b IN ('a', 'b')
)
intended result
When you do a PIVOT, Oracle will name the resulting columns just like their original values.
You can see this behavior when you do your select * that is working :
with
a as
(
select
a1.column_value a, a2.column_value b , cos(a1.r) c
from
(select column_value, rownum r from table(sys.odcinumberlist(1,2,3,4,5))) a1 ,
(select column_value, rownum r from table(sys.odcivarchar2list('a','b','a','b','a'))) a2
where
a1.r = a2.r)
select * from a
PIVOT
(
COUNT(a.a)--,sum(a.c)
FOR b IN ('a', 'b')
)
result is
C 'a' 'b'
-.65364362086361191463916818309775038145 0 1
.5403023058681397174009366074429766037354 1 0
-.98999249660044545727157279473126130238 1 0
.2836621854632262644666391715135573083265 1 0
-.41614683654714238699756822950076218977 0 1
Your columns headings have been turned by Oracle into the exact values you've got in the IN clause, including the surrounding quotes.
So to refer them in your SELECT clause, you should use double quotes like this:
select "'a'","'b'", c from a
PIVOT
(
count(a.a)--,sum(a.c)
FOR b IN ('a', 'b')
)
An alternative is to alias your values directly in the IN clause
select val_a, val_b, c from a --a.a,a.b
PIVOT
(
count(a.a)--,sum(a.c)
FOR b IN ('a' val_a, 'b' val_b )
)
VAL_A VAL_B C
0 1 -.65364362086361191463916818309775038145
1 0 .5403023058681397174009366074429766037354
1 0 -.98999249660044545727157279473126130238
1 0 .2836621854632262644666391715135573083265
0 1 -.41614683654714238699756822950076218977
And finally, you had another mistake in your initial approach:
select a.a,a.b,a.c from a --a.a,a.b
PIVOT
(
count(a.a)--,sum(a.c)
FOR b IN ('a', 'b')
)
in this query a refers to your initial a CTE. When you do a.a,a.b,a.c, Oracle doesn't know what you are referencing because of the PIVOT that comes afterwards.
You should properly alias the PIVOT results if you want to refer to it in the SELECT clause :
select pa."'a'",pa."'b'", pa.c from a
PIVOT
(
count(a.a)--,sum(a.c)
FOR b IN ('a', 'b')
) pa
I have a table that contains comma-separated values in a column In Postgres.
ID PRODS
--------------------------------------
1 ,142,10,75,
2 ,142,87,63,
3 ,75,73,2,58,
4 ,142,2,
Now I want a query where I can give a comma-separated string and it will tell me the number of matches between the input string and the string present in the row.
For instance, for input value ',142,87,', I want the output like
ID PRODS No. of Match
------------------------------------------------------------------------
1 ,142,10,75, 1
2 ,142,87,63, 2
3 ,75,73,2,58, 0
4 ,142,2, 1
Try this:
SELECT
*,
ARRAY(
SELECT
*
FROM
unnest(string_to_array(trim(both ',' from prods), ','))
WHERE
unnest = ANY(string_to_array(',142,87,', ','))
)
FROM
prods_table;
Output is:
1 ,142,10,75, {142}
2 ,142,87,63, {142,87}
3 ,75,73,2,58, {}
4 ,142,2, {142}
Add the cardinality(anyarray) function to the last column to get just a number of matches.
And consider changing your database design.
Check This.
select T.*,
COALESCE(No_of_Match,'0')
from TT T Left join
(
select ID,count(ID) No_of_Match
from (
select ID,unnest(string_to_array(trim(t.prods, ','), ',')) A
from TT t)a
Where A in ('142','87')
group by ID
)B
On T.Id=b.id
Demo Here
OutPut
If you install the intarray extension, this gets quite easy:
select id, prods, cardinality(string_to_array(trim(prods, ','), ',')::int[] & array[142,87])
from bad_design;
Otherwise it's a bit more complicated:
select bd.id, bd.prods, m.matches
from bad_design bd
join lateral (
select bd.id, count(v.p) as matches
from unnest(string_to_array(trim(bd.prods, ','), ',')) as l(p)
left join (
values ('142'),('87') --<< these are your input values
) v(p) on l.p = v.p
group by bd.id
) m on m.id = bd.id
order by bd.id;
Online example: http://rextester.com/ZIYS97736
But you should really fix your data model.
with data as
(
select *,
unnest(string_to_array(trim(both ',' from prods), ',') ) as v
from myTable
),
counts as
(
select id, count(t) as c from data
left join
( select unnest(string_to_array(',142,87,', ',') ) as t) tmp on tmp.t = data.v
group by id
order by id
)
select t1.id, t1.prods, t2.c as "No. of Match"
from myTable t1
inner join counts t2 on t1.id = t2.id;
This question already has answers here:
Pivoting in DB2
(3 answers)
Closed 5 years ago.
I have table A, below, where for each unique id, there are three codes with some value.
ID Code Value
---------------------
11 1 x
11 2 y
11 3 z
12 1 p
12 2 q
12 3 r
13 1 l
13 2 m
13 3 n
I have a second table B with format as below:
Id Code1_Val Code2_Val Code3_Val
Here there is just one row for each unique id. I want to populate this second table B from first table A for each id from the first table.
For the first table A above, the second table B should come out as:
Id Code1_Val Code2_Val Code3_Val
---------------------------------------------
11 x y z
12 p q r
13 l m n
How can I achieve this in a single SQL query?
select Id,
max(case when Code = '1' then Value end) as Code1_Val,
max(case when Code = '2' then Value end) as Code2_Val,
max(case when Code = '3' then Value end) as Code3_Val
from TABLEA
group by Id
SELECT Id,
max(DECODE(Code, 1, Value)) AS Code1_Val,
max(DECODE(Code, 2, Value)) AS Code2_Val,
max(DECODE(Code, 3, Value)) AS Code3_Val
FROM A
group by Id
If your version doesn't have DECODE(), you can also use this:
INSERT INTO B (id, code1_val, code2_val, code3_val)
WITH Ids (id) as (SELECT DISTINCT id
FROM A) -- Only to construct list of ids
SELECT Ids.id, a1.value, a2.value, a3.value
FROM Ids -- or substitute the actual id table
JOIN A a1
ON a1.id = ids.id
AND a1.code = 1
JOIN A a2
ON a2.id = ids.id
AND a2.code = 2
JOIN A a3
ON a3.id = ids.id
AND a3.code = 3
(Works on my V6R1 DB2 instance, and have an SQL Fiddle Example).
Here is a SQLFiddle example
insert into B (ID,Code1_Val,Code2_Val,Code3_Val)
select Id, max(V1),max(V2),max(V3) from
(
select ID,Value V1,'' V2,'' V3 from A where Code=1
union all
select ID,'' V1, Value V2,'' V3 from A where Code=2
union all
select ID,'' V1, '' V2,Value V3 from A where Code=3
) AG
group by ID
Here is the SQL Query:
insert into pivot_insert_table(id,code1_val,code2_val, code3_val)
select * from (select id,code,value from pivot_table)
pivot(max(value) for code in (1,2,3)) order by id ;
WITH Ids (id) as
(
SELECT DISTINCT id FROM A
)
SELECT Ids.id,
(select sub.value from A sub where Ids.id=sub.id and sub.code=1 fetch first rows only) Code1_Val,
(select sub.value from A sub where Ids.id=sub.id and sub.code=2 fetch first rows only) Code2_Val,
(select sub.value from A sub where Ids.id=sub.id and sub.code=3 fetch first rows only) Code3_Val
FROM Ids
You want to pivot your data. Since DB2 has no pivot function, yo can use Decode (basically a case statement.)
The syntax should be:
SELECT Id,
DECODE(Code, 1, Value) AS Code1_Val,
DECODE(Code, 2, Value) AS Code2_Val,
DECODE(Code, 3, Value) AS Code3_Val
FROM A