I'm scraping http://www.germandeli.com/Meats/Sausages
I would like to extract the link for every product(or item) from the page. I use scrapy shell to test but it keeps return the empty value [ ].
Here is the code I use:
response.xpath('*//h2[#class="item-cell-name"]/a/#href')
Any helps would be greatly appreciated.
Well unfortunately the item content is rendered through JS. But luckily the URL sends a AJAX request to fetch a JSON of the items. This makes it much easier for us to parse it. You can check the XHR tab in the google chrome console to imitate the request with the required headers.
This URL returns the list of products. The limit and the offset parameters in the URL can be played around with to fetch the next set of data. Also to parse the JSON content you can use json.loads from the standard library.
Related
I am testing a login functionality on a 3rd party website. I have this url example.com/login . When I copy and paste this into the browser (chrome), page sometimes load, but sometime does not (empty blank white page).
The problem is that I have to run a script on this page to click one of the elements (all the elements are embedded inside #shadow-root). If the page loads, no problem, script is evaluated successfully. But page sometimes does not load and it returns a 404 in response to an XHR request, and as a result, my * eval(scrip("script") step returns "js eval failed...".
So I found the solution to refresh the page, and to do that, I am considering to capture the xhr request response. If the status code is 404, then refresh the page. If not, continue with the following steps.
Now, I think this may work, but I do not know how to implement karate's Intercepting HTTP Requests. And firstly, is that something doable?
I have looked into documentation here, but could not understand the examples.
https://github.com/karatelabs/karate/tree/master/karate-netty
Meanwhile, if there is another way of refreshing the page conditionally, I will be more than happy to hear about it. Thanks anyone in advance.
First, using JavaScript you should be able to handle shadow roots: https://stackoverflow.com/a/60618233/143475
And the above answer links to advanced examples of executing JS in the context of the current page. I suggest you do some research into that, try to take the help of someone who knows JS, the DOM and HTML well - and you should be find a way to know if the XHR has been made successfully or not - for e.g. based on whether some element on the page has changed etc.
Finally here is how you can do interception: https://stackoverflow.com/a/61372471/143475
So, I'm trying to scrape a website with infinite scrolling.
I'm following this tutorial on scraping infinite scrolling web pages: https://blog.scrapinghub.com/2016/06/22/scrapy-tips-from-the-pros-june-2016
But the example given looks pretty easy, it's an orderly JSON object with the data you want.
I want to scrape this https://www.bahiablancapropiedades.com/buscar#/terrenos/venta/bahia-blanca/todos-los-barrios/rango-min=50.000,rango-max=350.000
The XHR response for each page is weird, looks like corrupted html code
This is how the Network tab looks
I'm not sure how to navigate the items inside "view". I want the spider to enter each item and crawl some information for every one.
In the past I've succesfully done this with normal pagination and rules guided by xpaths.
https://www.bahiablancapropiedades.com/buscar/resultados/0
This is XHR url.
While scrolling the page it will appear the 8 records per request.
So do one thing get all records XPath. these records divide by 8. it will appear the count of XHR requests.
do below process. your issue will solve. I get the same issue as me. I applied below logic. it will resolve.
pagination_count = xpath of presented number
value = int(pagination_count) / 8
for pagination_value in value:
url = https://www.bahiablancapropiedades.com/buscar/resultados/+[pagination_value]
pass this url to your scrapy funciton.
It is not corrupted HTML, it is escaped to prevent it from breaking the JSON. Some websites will return simple JSON data and others, like this one, will return the actual HTML to be added.
To get the elements you need to get the HTML out of the JSON response and create your own parsel Selector (this is the same as when you use response.css(...)).
You can try the following in scrapy shell to get all the links in one of the "next" pages:
scrapy shell https://www.bahiablancapropiedades.com/buscar/resultados/3
import json
import parsel
json_data = json.loads(response.text)
sel = parsel.Selector(json_data['view']) # view contains the HTML
sel.css('a::attr(href)').getall()
I am trying to scrape flyers from flipp.com/weekly_ads using Scrapy. Before I can scrape the flyers, I need to input my area code, and search for local flyers (on the site, this is done by clicking a button).
I am trying to input a value, and simualate "clicking a button" using Scrapy.
Initially, I thought that I would be able to use a FormRequest.from_response to search for the form, and input my area code as a value. However, the button is written in javascript, meaning that the form cannot be found.
So, I tried to find the HTTP call via Inspect Element > Developer Tools > Network > XHR to see if any of the calls would load the equivalent flipp page with the new, inputted area code (my area code).
Now, I am very new to Scrapy, and HTTP requests/responses, so I am unsure if the link I found is the correct one (as in, the response with the new area code), or not.
This is the request I found:
https://gateflipp.flippback.com/bf/flipp/data?locale=en-us&postal_code=90210&sid=10775773055673477
I used an arbitrary postal code for the request (90210).
I suspect this is the incorrect request, but in the case that I am wrong, and this is correct:
How do I navigate to - flipp.com/weekly_ads/groceries from this request, while maintaining the new area code?
If this is incorrect:
How do I input a value for a javascript button, and get the result using Scrapy?
import scrapy
import requests
import json
class flippSpider(scrapy.Spider):
name = "flippSpider"
postal_code = "M1T2R8"
start_urls = ["https://flipp.com/weekly_ads"]
def parse(self, response): #Input value and simulate button click
return Request() #Find http call to simulate button click with correct field/value parameters
def parse_formrequest(self, response):
yield scrapy.Request("https://flipp.com/weekly_ads/groceries", callback= self.parse_groceries)
def parse_groceries(self, response):
flyers = []
flyer_names = response.css("class.flyer-name").extract()
for flyer_name in flyer_names:
flyer = FlippspiderItem()
flyer["name"] = flyer_name
flyers.append(flyer)
self.log(flyer["name"])
print(flyer_name)
return flyers
I expected to find the actual javascript button request within the XHR links but the one I found seems to be incorrect.
Edit: I do not want to use Selenium, it's slow, and I do not want a browser to pop up during execution of the spider.
I suspect this is the incorrect request, but in the case that I am wrong, and this is correct:
That is the correct URL to get the data powering that website; the things you see on screen when you go to flipp.com/weekly_ads/groceries is just packaging that data in HTML
How do I navigate to - flipp.com/weekly_ads/groceries from this request, while maintaining the new area code?
I am pretty sure you are asking the wrong question. You don't need to -- and in fact navigating to flipp.com/weekly_ads/groceries will 100% not do what you want anyway. You can observe that when you click on "Groceries", the content changes but the browser does not navigate to any new page, nor does it make a new XHR request. Thus, everything that you need is in that JSON. What is happening is they are using the flyers.*.categories that contains "Groceries" to narrow down the 129 flyers that are returned to just those related to Groceries.
As for "maintaining the new area code," it's a similar "wrong question" because every piece of data that is returned by that XHR is scoped to the postal code in question. Thus, you don't need to re-submit anything, and nor would I expect any data that comes back from your postal_code=90210 request to contain 30309 (or whatever) data.
Believe it or not, you're actually in a great place: you don't need to deal with complicated CSS or XPath queries to liberate the data from its HTML prison: they are kind enough to provide you with an API to their data. You just need to deal with unpacking the content from their structure into your own.
I have been following the scrapy tutorial trying to create a very simple web scraper for warframe.market. I have about a year of coding experience from school, but no python experience. I simply want to get the price of an item from the website. I used the following to scrape the page:
scrapy shell "https://warframe.market/items/hydroid_prime_set"
then I inspected the web page to find the individual elements that I am trying to scrape. I used this command to try to view the results I wanted:
response.css("div.order-row.d-flex.col-12").extract()
This did not work, so I used view(response) to see what I had scraped, and my cmd just waits endlessly at this point.
Is HTTPS stopping me from scraping? Am I selecting the wrong css in my response? Is the webpage too big? Could someone please show me where I went wrong?
Thanks
The response isn't empty, but it's rendered using javascript (you can validate it inspecting the response.body), for example try this in the shell:
import json
data = json.loads(response.css('#application-state::text').extract_first())
for order in data.get('payload',{}).get('orders', []):
print '"{}" price: {}'.format(order.get('platinum'),
order.get('user',{}).get('ingame_name'))
I am using scrapy tool to scrape content from website, i need help from you guys how to scrape the reponse which is dynamically loaded from ajax.
when content loading from ajax at that mean time url not changing it keep remains same but content would be changed so on that event i need to crawl.
thank you,
G.kavirajan
yield FormRequest('http://addons.prestashop.com/en/modules/featureproduct/ajax-homefeatured.php',
formdata={'type':'new','ajax':'1'},
callback=self.your_callback_method)
bellow are the urls that you can easily catch using fiddler or firebug
this is for featured tab http://addons.prestashop.com/en/modules/featureproduct/ajax-homefeatured.php?ajax=1&type=random
this is for new tab http://addons.prestashop.com/en/modules/featureproduct/ajax-homefeatured.php?ajax=1&type=new
you can request on these url directly to get results you required, although website is using POST request to get data for these url, but i tried with parameter GET request is also working properly