I have the following table named 'MoviesInStock'
I would like to select to latest movies from the last month.
In this case, the result should be only the movie 'The Mummy' since he is latest one.
I was trying the next query:
SELECT MovieName
FROM MovieInStock
WHERE Month = (SELECT MAX(Month) FROM MovieInStock) AND
(SELECT MovieName FROM MovieInStock WHERE Year = (SELECT MAX(Year) FROM MovieInStock))
But choosing the AND operator was not that smart. I was also trying to create a temporary table using SELECT INTO # for selecting the Max Year and then on the temp table to select the Max Month, but then it become complicated to me.
You are overcomplicating the problem. You can use TOP with ORDER BY.
Because you say "movies":
select top (1) with ties mis.*
from movieinstock mis
order by year desc, month desc
other solution, but better is Gordon Solution
with maxdt as (
select MAX(Month) MaxMonth, MAX(Year) MaxYear FROM MovieInStock
)
SELECT top 1 MovieName
FROM MovieInStock f1
inner join maxdt f2 on f1.Month=f2.MaxMonth and f1.Year=MaxYear
Related
As for Table structure, the table has weekly product prices for per country.
My goal here is to select the lowest price of each product for the most recent week/year per country per product.
The query below fulfills this goal, but is pretty slow performance wise. I was wondering if there is a more efficient way of doing the same task.
In the first part Im selecting the latest Year and week of prices per country. I included the CASE When to account for new year.
Im saving this in a #temptable.
Then I am selecting the min price based on the previous selected Year, Week and Country combo.
DECLARE #date DATE SET #date=getdate()
SELECT YearNb, Max(WeekNb) AS WeekNb, ISOCountryCode INTO #TempTable FROM PriceBenchWeekly
WHERE PriceBenchWeekly.YearNb = CASE WHEN DATEPART(ww,#date) = 1 THEN
Year(#date)-1
ELSE
Year(#date)
END
GROUP BY YearNb, ISOCountryCode
SELECT ProdNb,Min(WeeklyPrice) AS MinPrice, MarketPlayerCode, 'MKT' AS PriceOriginTypeCode, NatCoCode
FROM CE.PriceBenchWeekly INNER JOIN #TempTable ON PriceBenchWeekly.YearNb = #TempTable.YearNb AND
PriceBenchWeekly.WeekNb = #TempTable.WeekNb AND PriceBenchWeekly.ISOCountryCode = #TempTable.ISOCountryCode
GROUP BY PriceBenchweekly.YearNb, PriceBenchWeekly.ISOCountryCode, BNCode, MarketPlayerCode
the table has weekly product prices for per country. My goal here is to select the lowest price of each product for the most recent week/year per country per product.
Use window functions. Without sample data and desired results, it is a little hard to figure out what you really want. But the following gets the minimum price for each product from the most recent week in the data:
select pbw.*
from (select pbw.*,
min(weeklyprice) over (partition by prodnb) as min_weeklyprice
from (select pbw.*,
dense_rank() over (order by year desc, weeknb desc) as seqnum
from CE.PriceBenchWeekly pbw
) pbw
where seqnum = 1
) pbw
where weeklyprice = min_weeklyprice;
If you want to go with temp tables, do not create it using select into, use CREATE TABLE #TempTable instead, then you can create a non clustered index for Year, Week and Country code...
Anyway, I would prefer outer apply
SELECT DISTINCT A.ProductCode, A.CountryCode, B.YearNo, B.WeekNo, B.MinPrice
FROM YourTable A
OUTER APPLY (
SELECT TOP 1 YearNo, WeekNo, Min(Price) AS MinPrice
FROM YourTable
WHERE ProductCode = A.ProductCode AND CountryCode = B.CountryCode
GROUP BY YearNo, WeekNo
ORDER BY YearNo DESC, WeekNo DESC
) B
This is my query:
WITH last_transaction AS (
SELECT
month
FROM db.transactions
ORDER BY date DESC
LIMIT 1
)
SELECT
*
FROM db.transactions
-- WHERE month = last_transaction.month
WHERE month = 11
GROUP BY
id
Commented out line doesn't work, but intention is clear, i assume: i need to select transactions for the latest month. Business logic might not make sense, because i've extracted it from a bigger query. The main question is: how do i use a single value, derived with another query.
You have only one row, so you can use a scalar subquery:
SELECT t.*
FROM db.transactions t
WHERE month = (SELECT last_transaction.month FROM last_transaction);
I removed the GROUP BY id because it would be a syntax error in BigQuery and it logically does not make sense. Why would a column called id be duplicated in the table?
However, this query would often be written as:
SELECT t.*
FROM (SELECT t.*, MAX(month) OVER () as max_month
FROM db.transactions t
WHERE month = max_month;
Try to JOIN the last_transaction.
A bit like this;
SELECT *
FROM db.transactions
JOIN last_transaction
ON db.transactions.id = last_transaction.id
WHERE month = last_transaction.month
GROUP BY id
In the database we have the table batter, which contains a record for each batter each year they played as well as their game stats for that year. How would I write a query to select each player that has the max number of homeruns out of all players?
I've been trying with
SELECT *
FROM master
WHERE batting.HR = (
SELECT MAX(batting.HR)
FROM batting
)
But have had no luck. How could I do this?
SELECT b.*
FROM batter b
INNER JOIN (
select year, Max(hr) as MaxHR
from batter
group by year
) y on b.year = y.year and b.HR = y.MaxHR
Note this is vulnerable to two players tying. It's not clear what you want to see in that case.
Assuming your RDBMS supports SQL2003, you can use a window function:
SELECT *
FROM
(
SELECT
batter,
year,
hr,
MAX(hr) OVER (PARTITION BY year) AS year_best_hr
FROM batting
)
WHERE hr = year_best_hr
I have a select query that gets a CarID, month, mileage and CO2 emission.
Now it gives for each month per car the mileage like this:
month 1: 5000
month 2: 5200
...
What I really need is that it takes the current value minus the previous one. I get data between a certain time frame and I already included a mileage point before that time frame. So it would be possible to get the total miles per month, I just don't know how. What I want is this.
pre timeframe: 5000
month 1: 200
month 2: 150
...
How would I do this?
edit: code, I have not yet tried anything as I have no clue how to start to do this.
resultlist as (
SELECT
CarID
, '01/01/2000' as beginmonth
, MAX(kilometerstand) as Kilometers
, MAX(Co2Emission) as CO2
FROM
totalmileagelist
GROUP BY CarID
UNION
SELECT
CarID
, beginmonth
, MAX(kilometerstand) as Kilometers
, MAX(Co2Emission) as CO2
FROM
resultunionlist
GROUP BY CarID, beginmonth
)
select * from resultlist
order by CarID, beginmonth
Edit2: explanation to the code
In the first part of the result list I grab the latest mileage per car. In the second part, after the union, I grab per month per car the latest mileage.
If you just want to subtract the previous milage, use the lag() function:
select ml.*,
(kilometerstand - lag(kilometerstand) over (partition by carid order by month)
) as diff
from totalmileagelist ml;
lag() is available in SQL Server 2012+. In earlier versions you can use a correlated subquery or outer apply.
(I missed the version because it is in the title and not on a tag.) In SQL Server 2008:
select ml.*,
(ml.mileage - mlprev.mileage) as diff
from totalmileagelist ml outer apply
(select top 1 ml2.*
from totalmileagelist ml2
where ml2.CarId = ml.CarId and
ml2.month < ml.month
order by ml2.month desc
) mlprev;
Try like this:
SELECT id, yourColumnValue,
COALESCE(
(
SELECT TOP 1 yourColumnValue
FROM table_name t
WHERE t.id> tbl.id
ORDER BY
rowInt
), 0) - yourColumnValue AS diff
FROM table_name tbl
ORDER BY
id
or like this using rank()
select rank() OVER (ORDER BY id) as 'RowId', mileage into temptable
from totalmileagelist
select t1.mileage - t2.mileage from temptable t1, temptable t2
where t1.RowId = t2.RowId - 1
drop table temptable
I have a table with a series of IDs. Each ID has dates ranging up to year 2025 from current year. Each year for each ID has a specific price.
http://i.imgur.com/srplSDo.jpg
Once I get to a certain point with each ID, it no longer has a specific price. So what I am wanting to do is take the previous years price and increase it by 2.5 percent. I have figured a way to grab the previous years price with this
SELECT a.*,
(CASE
WHEN a.YEARLY_PRICING is not null
THEN a.YEARLY_PRICING
ELSE (SELECT b.YEARLY_PRICING
FROM #STEP3 b
WHERE (a.id = b.id) AND (b.YEAR = a.YEAR-1))*1.025
END) AS TEST
FROM #STEP3 a
which would provide these results:
http://imgur.com/MJutM99
but the problem I am having is after the first null year, it is still recognizing the previous yearly_pricing as null, which gives me the null results, so obviously this method won't work for me. Any other suggestions for improvement?
Thanks
WITH CTE AS
(
SELECT ID, Year, Price, Price AS Prev
FROM T A
WHERE Year = (SELECT min(year) FROM T WHERE T.ID = A.ID GROUP BY T.ID)
UNION ALL
SELECT T.ID, T.Year, T.Price, ISNULL(T.Price, 1.025*Prev)
FROM T JOIN CTE ON T.ID = CTE.ID
AND T.Year - 1 = CTE.YEAR
)
SELECT * FROM CTE
ORDER BY ID, Year
SQL Fiddle Demo
What you want is a way to find not just the previous year (year - 1), but instead the year that is previous and also has a not-null price. To query for such a year (without solving your problem), you would do something like this:
select a.*
, (select max(year)
from step3 b
where a.id=b.id and a.year>b.year and b.yearly_pricing is not null
) PRIOR_YEAR
from step3 a
Since SQL-Server allows common-table expressions, you can call the above query "TMP", and then approach it this way. The CALC_PRICE in any year will be the price from the "PRIOR_YEAR" found as per the above query, multiplied by factor. That factor will be 1.025 to the POWER of the number of years from "PRIOR_YEAR" to the current year.
You would end up with SQL like this:
with TMP AS (
select a.*
, (select max(year)
from step3 b
where a.id=b.id and a.year>b.year and b.yearly_pricing is not null
) PRIOR_YEAR
from step3 a
)
select t.*,
c.yearly_pricing As prior_price,
c.yearly_pricing * POWER(1.025 , (t.year-t.prior_year)) calc_price
from tmp t
left join step3 c
on t.id=c.id and t.prior_year = c.year
It still has nulls, etc. but those are easily handled with COALESCE() or CASE expressions like you had in your question.
Here's an SQL Fiddle which shows how it works: http://sqlfiddle.com/#!3/296a4/21