I have a SQL code that looks like this:
select cast(avg(age) as decimal(16,2)) as 'avg' From
(select distinct acct.Account, cast(Avg(year(getdate())- year(client_birth_date)) as decimal(16,2)) as 'Age'
from WF_PM_ACCT_DB DET
inner join WF_PM_ACCT_DET_DB ACCT
ON det.Account = acct.Account
where (acct_closing_date is null or acct_closing_date > '2017-01-01')
and Acct_Open_Date < '2017-01-01'
group by acct.Account
) x
Then basically what this give me is a simple one cell answer of the average age of accounts in the year Acct_Open_Date < '2017-01-01' . I am an ameture so i change the date everytime and run the query again and again to get the remaining year. Is there an easy way to say lets have all the years as column headings and just one row with the average account age in that year.
Please note that the account closing date being null means accounts never got close and i have to change it to less than the analysis year in order to get a true picture of the average account age that existed at that time
Any help is appreciated. Thanks.
You can run this for multiple dates by including them in a single derived table:
with dates as (
select cast('2017-01-01' as date) as yyyy union all
select cast('2016-01-01' as date)
)
select yyyy, cast(avg(age) as decimal(16,2)) as avg_age
From (select dates.yyyy, acct.Account,
cast(Avg(year(getdate())- year(client_birth_date)) as decimal(16,2)) as Age
from dates cross join
WF_PM_ACCT_DB DET inner join WF_PM_ACCT_DET_DB
ACCT
on det.Account = acct.Account
where (acct_closing_date is null or acct_closing_date > dates.yyyy) and
Acct_Open_Date < dates.yyyy
group by acct.Account, dates.yyyy
) x
group by yyyy
order by yyyy;
Related
This is what my table looks like:
NOTE: Don't worry about the BMI field being empty in some rows. We assume that each row is a reading. I have omitted some columns for privacy reasons.
I want to get a count of the number of active customers per month. A customer is active if they have at least 18 readings in total (1 reading per day for 18 days in a given month). How do I write this SQL query? Assume the table name is 'cust'. I'm using SQL Server. Any help is appreciated.
Presumably a patient is a customer in your world. If so, you can use two levels of aggregation:
select yyyy, mm, count(*)
from (select year(createdat) as yyyy, month(createdat) as mm,
patient_id,
count(distinct convert(date, createdat)) as num_days
from t
group by year(createdat), month(createdat), patient_id
) ymp
where num_days >= 18
group by yyyy, mm;
You need to group by patient and the month, then group again by just the month
SELECT
mth,
COUNT(*) NumPatients
FROM (
SELECT
EOMONTH(c.createdat) mth
FROM cust c
GROUP BY EOMONTH(c.createdat), c.patient_id
HAVING COUNT(*) >= 18
-- for distinct days you could change it to:
-- HAVING COUNT(DISTINCT CAST(c.createdat AS date)) >= 18
) c
GROUP BY mth;
so the question is "Produce a list of those employees who have made bookings at the Sports Club more than 5 times in the last calendar year (this should be calculated and not hard coded). Order these by the number of bookings made."
what i am struggling with is being able to get todays year and then subtract 1 year aswell as showing ONLY one name of people appearing 5 times.
this is what i have so far, but it doesnt work.
SELECT DISTINCT
FIRSTNAME,SURNAME,DATEBOOKED,MEMBERSHIPTYPEID,BOOKINGID,MEMBER.MEMBERID
FROM MEMBERSHIP,MEMBER,BOOKING
WHERE MEMBER.MEMBERID = BOOKING.MEMBERID
AND MEMBERSHIP.MEMBERSHIPTYPEID = 3 AND BOOKING.DATEBOOKED = (SYSDATE,
'DD/MON/YY -1') AND FIRSTNAME IN (
SELECT FIRSTNAME
FROM MEMBER
GROUP BY FIRSTNAME,SURNAME
HAVING COUNT(FIRSTNAME) >= 5
)
ORDER BY MEMBER.MEMBERID;
EDR
tabele structures
What you need is this day last year. There are various different ways of calculating that. For instance,
add_months(sysdate, -12)
or
sysdate - interval '1' year
The subquery looks a bit whacky too. What you're after is the number of BOOKING records in the last year. So the subquery should drive off the BOOKING table, and the date filter should be there.
Finally, there is a missing join condition between MEMBER and MEMBERSHIP. That's probably why you think you need that distinct; fix the join and you'll get the result set you want and not a product. One advantage of the ANSI 92 explicit join syntax is that it stops us from missing joins.
Your query needs to be sorted by the number of bookings, so you need to count those and sort by the total. This means you don't actually need a subquery at all.
So your query should look something like:
SELECT MEMBER.MEMBERID
, MEMBER.FIRSTNAME
, MEMBER.SURNAME
, count(BOOKING.BOOKID) as no_of_bookings
FROM MEMBER
inner join MEMBERSHIP
on MEMBER.MEMBERID = MEMBERSHIP.MEMBERID
inner join BOOKING
on MEMBER.MEMBERID = BOOKING.MEMBERID
WHERE MEMBERSHIP.MEMBERSHIPTYPEID = 3
and BOOKING.DATEBOOKED >= add_months(trunc(sysdate), -12)
GROUP BY MEMBER.MEMBERID
, MEMBER.FIRSTNAME
, MEMBER.SURNAME
HAVING COUNT(*) >= 5
ORDER BY no_of_bookings desc;
Here is a SQL Fiddle demo for my query.
SELECT
FIRSTNAME,SURNAME,DATEBOOKED,MEMBERSHIPTYPEID,BOOKINGID,MEMBER.MEMBERID
FROM MEMBERSHIP,MEMBER,BOOKING
WHERE MEMBER.MEMBERID = BOOKING.MEMBERID
AND MEMBERSHIP.MEMBERSHIPTYPEID = 3 AND BOOKING.DATEBOOKED between (SYSDATE) and
(sysdate - interval '1' year)
AND FIRSTNAME IN (
SELECT distinct FIRSTNAME
FROM MEMBER
GROUP BY FIRSTNAME,SURNAME
HAVING COUNT(FIRSTNAME) >= 5
)
ORDER BY MEMBER.MEMBERID;
I think this answers the question:
SELECT m.FIRSTNAME, m.SURNAME, m.MEMBERID
FROM MEMBER m JOIN
BOOKING b
ON m.MEMBERID = b.MEMBERID JOIN
MEMBERSHIP ms
ON ms.MEMBERID = m.MEMBERID
WHERE ms.MEMBERSHIPTYPEID = 3 AND
B.DATEBOOKED >= SYSDATE - INTERVAL '1 YEAR'
GROUP BY m.FIRSTNAME, m.SURNAME, m.MEMBERID
HAVING COUNT(*) >= 5
ORDER BY COUNT(* DESC;
Table aliases make the query much easier to write and to read.
I need help in business days calculation.
I've two tables
1) One table ACTUAL_TABLE containing order date and contact date with timestamp datatypes.
2) The second table BUSINESS_DATES has each of the calendar dates listed and has a flag to indicate weekend days.
using these two tables, I need to ensure business days and not calendar days (which is the current logic) is calculated between these two fields.
My thought process was to first get a range of dates by comparing ORDER_DATE with TABLE_DATE field and then do a similar comparison of CONTACT_DATE to TABLE_DATE field. This would get me a range from the BUSINESS_DATES table which I can then use to calculate count of days, sum(Holiday_WKND_Flag) fields making the result look like:
Order# | Count(*) As DAYS | SUM(WEEKEND DATES)
100 | 25 | 8
However this only works when I use a specific order number and cant' bring all order numbers in a sub query.
My Query:
SELECT SUM(Holiday_WKND_Flag), COUNT(*) FROM
(
SELECT
* FROM
BUSINESS_DATES
WHERE BUSINESS.Business BETWEEN (SELECT ORDER_DATE FROM ACTUAL_TABLE
WHERE ORDER# = '100'
)
AND
(SELECT CONTACT_DATE FROM ACTUAL_TABLE
WHERE ORDER# = '100'
)
TEMP
Uploading the table structure for your reference.
SELECT ORDER#, SUM(Holiday_WKND_Flag), COUNT(*)
FROM business_dates bd
INNER JOIN actual_table at ON bd.table_date BETWEEN at.order_date AND at.contact_date
GROUP BY ORDER#
Instead of joining on a BETWEEN (which always results in a bad Product Join) followed by a COUNT you better assign a bussines day number to each date (in best case this is calculated only once and added as a column to your calendar table). Then it's two Equi-Joins and no aggregation needed:
WITH cte AS
(
SELECT
Cast(table_date AS DATE) AS table_date,
-- assign a consecutive number to each busines day, i.e. not increased during weekends, etc.
Sum(CASE WHEN Holiday_WKND_Flag = 1 THEN 0 ELSE 1 end)
Over (ORDER BY table_date
ROWS Unbounded Preceding) AS business_day_nbr
FROM business_dates
)
SELECT ORDER#,
Cast(t.contact_date AS DATE) - Cast(t.order_date AS DATE) AS #_of_days
b2.business_day_nbr - b1.business_day_nbr AS #_of_business_days
FROM actual_table AS t
JOIN cte AS b1
ON Cast(t.order_date AS DATE) = b1.table_date
JOIN cte AS b2
ON Cast(t.contact_date AS DATE) = b2.table_date
Btw, why are table_date and order_date timestamp instead of a date?
Porting from Oracle?
You can use this query. Hope it helps
select order#,
order_date,
contact_date,
(select count(1)
from business_dates_table
where table_date between a.order_date and a.contact_date
and holiday_wknd_flag = 0
) business_days
from actual_table a
I'm trying to refine this question a little since I didn't really ask correctly last time. I am essentially doing this query:
Select count(orders)
From Orders_Table
Where Order_Open_Date<=To_Date('##/##/####','MM/DD/YYYY')
and Order_Close_Date>=To_Date('##/##/####','MM/DD/YYYY')
Where ##/##/#### is the same day. In essence this query is designed to find the number of 'open' orders on any given day. The only problem is I'm wanting to do this for each day of a year or more. I think if I knew how to define the ##/##/#### as a variable and then grouped the count by that variable then I could get this to work but I'm not sure how to do that-or there may be another way as well. I am currently using Oracle SQL on SQL developer. Thanks for any input.
You could use a "row generator" technique like this (edited for Hogan's comments):
Select RG.Day,
count(orders)
From Orders_Table,
(SELECT trunc(SYSDATE) - ROWNUM as Day
FROM (SELECT 1 dummy FROM dual)
CONNECT BY LEVEL <= 365
) RG
Where RG.Day <=To_Date('##/##/####','MM/DD/YYYY')
and RG.Day >=To_Date('##/##/####','MM/DD/YYYY')
and Order_Open_Date(+) <= RG.Day
and Order_Close_Date(+) >= RG.Day - 1
Group by RG.Day
Order by RG.Day
This should list each day of the previous year with the corresponding number of orders
Lets say you had a table datelist with a column adate
aDate
1/1/2012
1/2/2012
1/3/2012
Now you join that to your table
Select *
From Orders_Table
join datelist on Order_Open_Date<=adate and Order_Close_Date>=adate
This gives you a list of all the orders you care about, now you group by and count
Select aDate, count(*)
From Orders_Table
join datelist on Order_Open_Date<=adate and Order_Close_Date>=adate
group by adate
If you want to pass in a parameters then just generate the dates with a recursive cte
with datelist as
(
select #startdate as adate
UNION ALL
select adate + 1
from datelist
where (adate + 1) <= #lastdate
)
Select aDate, count(*)
From Orders_Table
join datelist on Order_Open_Date<=adate and Order_Close_Date>=adate
group by adate
NOTE: I don't have an Oracle DB to test on so I might have some syntax wrong for this platform, but you get the idea.
NOTE2: If you want all dates listed with 0 for those that have nothing use this as your select statement:
Select aDate, count(Order_Open_Date)
From Orders_Table
left join datelist on Order_Open_Date<=adate and Order_Close_Date>=adate
group by adate
If you want only one day you can query using TRUNC like this
select count(orders)
From orders_table
where trunc(order_open_date) = to_date('14/05/2012','dd/mm/yyyy')
I have a table containing date, employeeID(int) , and ShiftWorked (can be night/day/weekend or evening) . There is a row for each employee and date combination
I would like to construct a query that gives me a count of how many people have worked a night shift in the week before and after each date in the roster period.
--------------------------------------------------------------------------
Date (yyyy-MM-dd) | CountOfNightshifts(for 1 week either side of date)
--------------------------------------------------------------------------
2012-1-1 | 8
2012-1-2 | 12
2012-1-3 | 11
2012-1-4 | 6
etc | etc
I hope this is clear. I have spent days trying to get this to work but I am not getting anywhere.
For example:
SELECT COUNT(id), [date]
FROM ROSTER
WHERE Shift = night AND [date] BETWEEN DATEADD(D,-7,[date]) AND DATEADD(d,7,[date])
GROUP by [date]
group by [date]
This will give me a list of dates and a count of nights on that particular day - not all night shifts in the 7 days before and after the date.
The following query will return two columns: the reference (roster) date and the number of (distinct) people that have worked on the night sift seven days before to seven days after the reference date.
SELECT tmain.date,
(
SELECT COUNT(DISTINCT taux.employeeId)
FROM roster taux
WHERE taux.shiftWorked = 'night'
AND taux.date >= DATEADD(DAY, -7, tmain.date)
AND taux.date <= DATEADD(DAY, 7, tmain.date)
) AS [number_of_distinct_people_with_night_shift]
FROM roster tmain
ORDER BY tmain.date;
Note 1: Usually I prefer joins over sub-queries, but I guess this solution is easier to read.
Note 2: I am assuming the time component of date values are irrelevant and all dates have the same time (i.e. '00:00:00.00'); if it is not the case, there are more adjustments to be done on the date comparison.
how about this?
SELECT
[date]
,count(*)
FROM
Shifts as s
WHERE
s.Date > DATEADD(day,-7,GETDATE())
AND ShiftWorked = 'Night'
GROUP BY
date
http://sqlfiddle.com/#!3/e88cc/1
a bit more data:
http://sqlfiddle.com/#!3/b7793/2
If you are only interested in a specific date then you could use:
DECLARE #target datetime
SET #target = GETDATE()
SELECT
count(*) as NightShifts
FROM
Shifts as s
WHERE
ShiftWorked = 'Night'
AND s.Date > DATEADD(day,-7,#target)
AND s.Date < DATEADD(day,7,#target)
http://sqlfiddle.com/#!3/b7793/20
but if you have another table that actually has the periods in it (e.g. billing or payroll dates):
DECLARE #target datetime
SET #target = GETDATE()
SELECT
p.periodDate
,count(*)
FROM
Shifts as s
INNER JOIN periods as p
ON s.date > dateadd(day,-7,p.periodDate)
AND s.date < dateadd(day,7,p.periodDate)
WHERE
ShiftWorked = 'Night'
GROUP BY p.periodDate
http://sqlfiddle.com/#!3/fc54d/2
OR to get ) when no night shift was worked:
SELECT
p.periodDate
,ISNULL(t.num,0) as nightShifts
FROM
periods as p
LEFT OUTER JOIN (
SELECT
p.periodDate
,count(*) as num
FROM
Shifts as s
INNER JOIN periods as P
ON s.date > dateadd(day,-7,p.periodDate)
AND s.date < dateadd(day,7,p.periodDate)
WHERE
ShiftWorked = 'Night'
GROUP BY p.periodDate
) as t
ON p.periodDate = t.periodDate
http://sqlfiddle.com/#!3/fc54d/11
You can pull it off by joining the ROSTER table to itself, thereby creating several result rows per employee and day. Otherwise your GROUP BY clause will group the resulting rows from the period you are after into the dates of the original table.
SELECT
r.[date],
COUNT(period.id)
FROM ROSTER r
JOIN ROSTER period
ON period.employeeID=r.employeeID
AND period.shift = night
AND r.[date] BETWEEN DATEADD(d,-7,period.[date]) and DATEADD(d,7,period.[date])
WHERE
r.shift = night
GROUP BY r.[date]