I am writing a SQL job and I have to set the schedule running stamp to daily at 12:00:00 AM. The date format should be 2017-05-10 00:00:00.000
I have done something like this. But I don't know how to set the exact date and time(which is crucial). Please help
SET #ScheduledStStamp = GETDATE() + 1
Assuming you need to set the date as Tomorrow's date, use Dateadd(d,1,getdate()).
Then convert that date first to varchar(8) and then back to datetime.This will set your time in '00:00:00.000' format.
select convert(datetime,convert(varchar(8),Dateadd(d,1,getdate()),112))
Assign it your variable as below
Declare #ScheduledStStamp datetime
SET #ScheduledStStamp =convert(datetime,convert(varchar(8),Dateadd(d,1,getdate()),112))
select #ScheduledStStamp
I used the below code to get the desired result
SET #ScheduledStStamp = CONVERT(DATETIME, CONVERT(DATE, GETDATE() + 1))
Today's date:
SELECT DATEADD(d,0,DATEDIFF(d,0,GETDATE()))
Tomorrow:
SELECT DATEADD(d,1,DATEDIFF(d,0,GETDATE()))
Yesterday:
SELECT DATEADD(d,-1,DATEDIFF(d,0,GETDATE()))
Related
I have a table with a SMALLDATETIME column and several records with wrong time. e.g.:
2018-07-17 11:06:00
the correct time is 00:00:00, so, for all those entries, I want to change the time to that value (2018-07-17 00:00:00).
In the table the greatest part of records have the correct time.
What's the correct way to achieve this?
Thanks
If you don't want time you can use cast( as date) to drop time component & set it to 00:00:00
update t
set dt = cast(dt as date);
DECLARE #datetime SMALLDATETIME ='2018-07-17 11:06:00'
SELECT CONVERT(DATETIME, CONVERT(DATE, #datetime))
So something like that :
UPDATE MY_TABLE
SET MY_COLUMN = CONVERT(SMALLDATETIME, CONVERT(DATE, MY_COLUMN))
I am tring to add a year to a date if it is not before today. So in the statement below I would like to display 4/20/2018
declare #StartDate datetime
set #StartDate='4/20/2015'
select case when dateadd(year,1,#StartDate)> GETDATE() then
dateadd(year,1,#StartDate) else dATEADD(year,1,(datepart(year,GETDATE()))) end
I've changed the else clause so it works out the difference between the start date and today's date +1 to alter make '4/20/2015' become '4/20/2018'
declare #StartDate date
set #StartDate='4/20/2015'
select
case
when dateadd(year,1,#StartDate)> GETDATE() then dateadd(year,1,#StartDate)
else DATEADD(year,(datepart(year,GETDATE())+1-datepart(year,#StartDate)),#StartDate)
end
Also if you are not using the time part of a datetime data type it's best practice to use date instead as it only requires 3 bytes of storage rather than 8 for datetime.
More on date here: https://learn.microsoft.com/en-us/sql/t-sql/data-types/date-transact-sql
And a cheatsheet of sql data types here: https://sqlserverrider.files.wordpress.com/2013/04/pic116.png
How would I be able to extract the time part of a DateTime field in SQL? For my project I have to return data that has a timestamp of 5pm of a DateTime field no matter what the date is
This will return the time-Only
For SQL Server:
SELECT convert(varchar(8), getdate(), 108)
Explanation:
getDate() is giving current date and time.
108 is formatting/giving us the required portion i.e time in this case.
varchar(8) gives us the number of characters from that portion.
Like:
If you wrote varchar(7) there, it will give you 00:00:0
If you wrote varchar(6) there, it will give you 00:00:
If you wrote varchar(15) there, it will still give you 00:00:00 because it is giving output of just time portion.
SQLFiddle Demo
For MySQL:
SELECT DATE_FORMAT(NOW(), '%H:%i:%s')
SQLFiddle Demo
In SQL Server if you need only the hh:mi, you can use:
DECLARE #datetime datetime
SELECT #datetime = GETDATE()
SELECT RIGHT('0'+CAST(DATEPART(hour, #datetime) as varchar(2)),2) + ':' +
RIGHT('0'+CAST(DATEPART(minute, #datetime)as varchar(2)),2)
If you want only the hour of your datetime, then you can use DATEPART() - SQL Server:
declare #dt datetime
set #dt = '2012-09-10 08:25:53'
select datepart(hour, #dt) -- returns 8
In SQL Server 2008+ you can CAST() as time:
declare #dt datetime
set #dt = '2012-09-10 08:25:53'
select CAST(#dt as time) -- returns 08:25:53
I know this is an old question, but since the other answers all
return strings (rather than datetimes),
rely on the internal representation of dates (conversion to float, int, and back) or
require SQL Server 2008 or beyond,
I thought I'd add a "pure" option which only requires datetime operations and works with SQL Server 2005+:
SELECT DATEADD(dd, -DATEDIFF(dd, 0, mydatetime), mydatetime)
This calculates the difference (in whole days) between date zero (1900-01-01) and the given date and then subtracts that number of days from the given date, thereby setting its date component to zero.
Try this in SQL Server 2008:
select *
from some_table t
where convert(time,t.some_datetime_column) = '5pm'
If you want take a random datetime value and adjust it so the time component is 5pm, then in SQL Server 2008 there are a number of ways. First you need start-of-day (e.g., 2011-09-30 00:00:00.000).
One technique that works for all versions of Microsoft SQL Server as well as all versions of Sybase is to use convert/3 to convert the datetime value to a varchar that lacks a time component and then back into a datetime value:
select convert(datetime,convert(varchar,current_timestamp,112),112)
The above gives you start-of-day for the current day.
In SQL Server 2008, though, you can say something like this:
select start_of_day = t.some_datetime_column
- convert(time, t.some_datetime_column ) ,
from some_table t
which is likely faster.
Once you have start-of-day, getting to 5pm is easy. Just add 17 hours to your start-of-day value:
select five_pm = dateadd(hour,17, t.some_datetime_column
- convert(time,t.some_datetime_column)
)
from some_table t
Note that from MS SQL 2012 onwards you can use FORMAT(value,'format')
e.g. WHERE FORMAT(YourDatetime,'HH:mm') = '17:00'
"For my project, I have to return data that has a timestamp of 5pm of a DateTime field, No matter what the date is."
So I think what you meant was that you needed the date, not the time. You can do something like this to get a date with 5:00 as the time:
SELECT CONVERT(VARCHAR(10), GetDate(), 110) + ' 05:00:00'
This should strip away the date part:
select convert(datetime,convert(float, getdate()) - convert(int,getdate())), getdate()
and return a datetime with a default date of 1900-01-01.
you can use CONVERT(TIME,GETDATE()) in this case:
INSERT INTO infoTbl
(itDate, itTime)
VALUES (GETDATE(),CONVERT(TIME,GETDATE()))
or if you want print it or return that time use like this:
DECLARE #dt TIME
SET #dt = CONVERT(TIME,GETDATE())
PRINT #dt
select cast(getdate() as time(0))
returns for example :- 15:19:43
replace getdate() with the date time you want to extract just time from!
SELECT DISTINCT
CONVERT(VARCHAR(17), A.SOURCE_DEPARTURE_TIME, 108)
FROM
CONSOLIDATED_LIST AS A
WHERE
CONVERT(VARCHAR(17), A.SOURCE_DEPARTURE_TIME, 108) BETWEEN '15:00:00' AND '15:45:00'
declare #datetime as datetime
set #datetime = getdate()
select cast(cast(#datetime as time) as varchar(8))
For year:
SELECT DATEPART(YEAR, '2021-03-21' );
For hour:
SELECT DATEPART(HOUR, '2021-03-21 08:50:30' );
I'm creating a function were I provide 3 inputs #FiscalYEar, #StartDate, #EndDate, I also declare a DATE parameter that the year will be -1 of #FiscalYear
SET #fyLowerBound = OCT 1 OF (#FiscalYear - 1)
how do I properly write the SET statement to make it work?
This should work:
DECLARE #FiscalYear INT = 2014,
#fyLowerBound DATE;
SET #fyLowerBound = CAST(CAST((#FiscalYear - 1) AS CHAR(4)) + '1001' AS DATE)
SELECT #fyLowerBound;
This gives 1st October 2013.
The premise being creating a string date in the format yyyyMMdd, in SQL Server this is the only culture insensitive date for DATETIME (yyyy-MM-dd will work for DATE), you then cast that string to a date (or datetime whatever your preference).
So the first step is to turn your integer date into a CHAR(4), you can then create october 1st of this year by concatenating '1001'. You now have a string that will be cast to a date.
SET #fyLowerBound = DATEADD(yy, -1, #FiscalYear)
This will give you a date that's a year less than #FiscalYear. Although I'm not entirely sure this is what you need, given that 'OCT' in your original statement.
How would I be able to extract the time part of a DateTime field in SQL? For my project I have to return data that has a timestamp of 5pm of a DateTime field no matter what the date is
This will return the time-Only
For SQL Server:
SELECT convert(varchar(8), getdate(), 108)
Explanation:
getDate() is giving current date and time.
108 is formatting/giving us the required portion i.e time in this case.
varchar(8) gives us the number of characters from that portion.
Like:
If you wrote varchar(7) there, it will give you 00:00:0
If you wrote varchar(6) there, it will give you 00:00:
If you wrote varchar(15) there, it will still give you 00:00:00 because it is giving output of just time portion.
SQLFiddle Demo
For MySQL:
SELECT DATE_FORMAT(NOW(), '%H:%i:%s')
SQLFiddle Demo
In SQL Server if you need only the hh:mi, you can use:
DECLARE #datetime datetime
SELECT #datetime = GETDATE()
SELECT RIGHT('0'+CAST(DATEPART(hour, #datetime) as varchar(2)),2) + ':' +
RIGHT('0'+CAST(DATEPART(minute, #datetime)as varchar(2)),2)
If you want only the hour of your datetime, then you can use DATEPART() - SQL Server:
declare #dt datetime
set #dt = '2012-09-10 08:25:53'
select datepart(hour, #dt) -- returns 8
In SQL Server 2008+ you can CAST() as time:
declare #dt datetime
set #dt = '2012-09-10 08:25:53'
select CAST(#dt as time) -- returns 08:25:53
I know this is an old question, but since the other answers all
return strings (rather than datetimes),
rely on the internal representation of dates (conversion to float, int, and back) or
require SQL Server 2008 or beyond,
I thought I'd add a "pure" option which only requires datetime operations and works with SQL Server 2005+:
SELECT DATEADD(dd, -DATEDIFF(dd, 0, mydatetime), mydatetime)
This calculates the difference (in whole days) between date zero (1900-01-01) and the given date and then subtracts that number of days from the given date, thereby setting its date component to zero.
Try this in SQL Server 2008:
select *
from some_table t
where convert(time,t.some_datetime_column) = '5pm'
If you want take a random datetime value and adjust it so the time component is 5pm, then in SQL Server 2008 there are a number of ways. First you need start-of-day (e.g., 2011-09-30 00:00:00.000).
One technique that works for all versions of Microsoft SQL Server as well as all versions of Sybase is to use convert/3 to convert the datetime value to a varchar that lacks a time component and then back into a datetime value:
select convert(datetime,convert(varchar,current_timestamp,112),112)
The above gives you start-of-day for the current day.
In SQL Server 2008, though, you can say something like this:
select start_of_day = t.some_datetime_column
- convert(time, t.some_datetime_column ) ,
from some_table t
which is likely faster.
Once you have start-of-day, getting to 5pm is easy. Just add 17 hours to your start-of-day value:
select five_pm = dateadd(hour,17, t.some_datetime_column
- convert(time,t.some_datetime_column)
)
from some_table t
Note that from MS SQL 2012 onwards you can use FORMAT(value,'format')
e.g. WHERE FORMAT(YourDatetime,'HH:mm') = '17:00'
"For my project, I have to return data that has a timestamp of 5pm of a DateTime field, No matter what the date is."
So I think what you meant was that you needed the date, not the time. You can do something like this to get a date with 5:00 as the time:
SELECT CONVERT(VARCHAR(10), GetDate(), 110) + ' 05:00:00'
This should strip away the date part:
select convert(datetime,convert(float, getdate()) - convert(int,getdate())), getdate()
and return a datetime with a default date of 1900-01-01.
you can use CONVERT(TIME,GETDATE()) in this case:
INSERT INTO infoTbl
(itDate, itTime)
VALUES (GETDATE(),CONVERT(TIME,GETDATE()))
or if you want print it or return that time use like this:
DECLARE #dt TIME
SET #dt = CONVERT(TIME,GETDATE())
PRINT #dt
select cast(getdate() as time(0))
returns for example :- 15:19:43
replace getdate() with the date time you want to extract just time from!
SELECT DISTINCT
CONVERT(VARCHAR(17), A.SOURCE_DEPARTURE_TIME, 108)
FROM
CONSOLIDATED_LIST AS A
WHERE
CONVERT(VARCHAR(17), A.SOURCE_DEPARTURE_TIME, 108) BETWEEN '15:00:00' AND '15:45:00'
declare #datetime as datetime
set #datetime = getdate()
select cast(cast(#datetime as time) as varchar(8))
For year:
SELECT DATEPART(YEAR, '2021-03-21' );
For hour:
SELECT DATEPART(HOUR, '2021-03-21 08:50:30' );