I've a column like last_located_time which contain values like
2017-05-13T17:33:36.000+0000.
I have tried to remove only time, but no luck.
SELECT USERNAME, TO_DATE(SUBSTR(LAST_LOCATED_TIME,11,17),'HH:MI:SS') "lAST TIME"
FROM Tb_089
How should I extract only time value from the columns for all users?
Thanks in advance!
If you want the time component in the UTC time zone (so all times are being displayed in a common time zone) then:
(assuming you have a TIMESTAMP WITH TIME ZONE data type)
SELECT TO_CHAR(
last_located_time AT TIME ZONE 'UTC',
'HH24:MI:SS'
)
FROM Tb_089;
If you, instead, the column is an ISO 8601 formatted string:
SELECT TO_CHAR(
TO_TIMESTAMP_TZ(
last_located_time,
'YYYY-MM-DD"T"HH24:MI:SS.FFTZHTZM'
) AT TIME ZONE 'UTC',
'HH24:MI:SS'
)
FROM Tb_089;
If you want the time component as an interval:
SELECT CAST( utc_last_located_time AS TIMESTAMP ) - TRUNC( utc_last_located_time )
AS time_interval
FROM (
SELECT TO_TIMESTAMP_TZ(
last_located_time,
'YYYY-MM-DD"T"HH24:MI:SS.FFTZHTZM'
) AT TIME ZONE 'UTC' AS utc_last_located_time
FROM Tb_089
);
If you want the time component of the string (without adjusting for disparate time zones) then you could just do:
SELECT SUBSTR( last_located_time, 12, 8 )
FROM Tb_089
To_Date is used to convert Char and Varchar2 into Date.
You need to use To_Char which is opposite of To_Date
Select To_Char(LAST_LOCATED_TIME, 'HH24:MI:SS') "Last Time" from Tb_089;
Related
HIRE_DATE is in a 'DATE' column. The timestamp is local (Los Angeles); I would like to convert it to UTC.
I can't for the life of me fathom why the UTC output is mangled (Last 2 digits of YY is the DD; and vice-versa) -- and the time does not convert to UTC.
HIRE_DATE: 30/04/2019 12:00:00 AM
select from_tz(to_timestamp(HIRE_DATE,'DD-MM-YY HH24:MI:SS'), 'America/Los_Angeles') at time zone 'UTC' from TABLE
OUTPUT: 19/04/2030 12:00:00 AM
If HIRE_DATE is a DATE data type then you don't need TO_TIMESTAMP.
TO_TIMESTAMP is used to convert a string (i.e. VARCHAR2) into a TIMESTAMP value but you have a DATE value.
Just do
select from_tz(CAST(HIRE_DATE AS TIMESTAMP), 'America/Los_Angeles') at time zone 'UTC'
from TABLE
Actually I don't understand why FROM_TZ does not accept DATE values whereas almost any other date/timestamp related function accept either DATE or TIMESTAMP value as input.
Note, the default output display format of this query is defined by current user session NLS_TIMESTAMP_TZ_FORMAT setting. If you are not satisfied with the output format, either change NLS_TIMESTAMP_TZ_FORMAT setting by executing ALTER SESSION SET NLS_TIMESTAMP_TZ_FORMAT = '...' or use TO_CHAR function to set output format explicitly.
Instead of
... AT TIME ZONE 'UTC'
you can also use
SYS_EXTRACT_UTC(...)
The upper returns a TIMESTAMP WITH TIME ZONE value, the second one returns a TIMESTAMP value.
Would this do any good?
SQL> select from_tz(cast (sysdate as timestamp), 'UTC') result from dual;
RESULT
---------------------------------------------------------------------------
27.09.20 10:59:28,000000 UTC
Or, in your case
select from_tz(cast (hire_date as timestamp), 'UTC' from dual
No need to apply any format mask to hire_date as it is a DATE datatype (at least, that's what you said).
You use the word "convert" which can mean one of two things:
change the data type, which is what FROM_TZ does
change the value from one time zone to another, which FROM_TZ does not do.
You didn't give your expected output, so we may misunderstand.
To change the data type:
with data(dte) as (
select date '2019-04-30' + interval '12' hour from dual
)
select from_tz(cast(dte as timestamp), 'America/Los_Angeles') from data
FROM_TZ(CAST(DTEASTIMESTAMP),'AMERICA/LOS_ANGELES')
30-APR-19 12.00.00.000000 PM AMERICA/LOS_ANGELES
To get the simultaneous datetime value in UTC:
with data(dte) as (
select date '2019-04-30' + interval '12' hour from dual
)
select cast(sys_extract_utc(from_tz(cast(dte as timestamp), 'America/Los_Angeles')) as date) from data
CAST(SYS_EXTRACT_UTC(FROM_TZ(CAST(DTEASTIMESTAMP),'AMERICA/LOS_ANGELES'))ASDATE)
2019-04-30 19:00:00
I need to convert a date from a TextBox from date to epoch time so that I can insert it into Oracle DB.
I managed to convert from epoch to date as below, but couldn't find a way to convert it the other way.
SelectCommand="SELECT ID,
COMPANY,
FIRST_NAME,
LAST_NAME,
ID_NUMBER,
(SELECT TO_CHAR(TO_DATE('01-JAN-1970','DD/MM/YYYY')
+(TRAINING_DATE/60/60/24), 'MM/DD/YYYY') FROM dual) AS TRAINING_DATE,
(SELECT TO_CHAR(TO_DATE('01-JAN-1970','DD/MM/YYYY')
+(TRAINING_VALABILITY/60/60/24),'MM/DD/YYYY') FROM dual) AS TRAINING_VALABILITY
FROM CONTRACTORS
ORDER BY COMPANY"
Subtracting DATE '1970-01-01' from the value will give the number of days (and fractional hours/minutes/seconds) difference and then you can multiply by 24*60*60:
(date_value - DATE '1970-01-01')*24*60*60
Update:
Typically, epoch time is measured from 1970-01-01T00:00:00 UTC. If your date is not in UTC then you will need to convert time zones.
For example, if your date has the time zone Europe/Berlin:
( CAST(
FROM_TZ(
CAST( date_value AS TIMESTAMP ), -- Cast to timestamp
'Europe/Berlin' -- Convert to expected Time Zone
)
AT TIME ZONE 'UTC' -- Convert Time Zone to UTC
AS DATE -- Cast back to DATE data type
)
- DATE '1970-01-01'
)*24*60*60
db<>fiddle
UpdateCommand="UPDATE CONTRACTORS
SET COMPANY=:COMPANY,
FIRST_NAME=:FIRST_NAME,
LAST_NAME=:LAST_NAME,
ID_NUMBER=:ID_NUMBER,
TRAINING_DATE=(TO_DATE(:TRAINING_DATE, 'MM-DD-YYYY HH24:MI:SS') - TO_DATE('01-JAN-1970','DD/MM/YYYY'))*24*60*60,
TRAINING_VALABILITY=(TO_DATE(:TRAINING_VALABILITY, 'MM-DD-YY`enter code here`YY HH24:MI:SS') - TO_DATE('01-JAN-1970','DD/MM/YYYY'))*24*60*60
WHERE (ID=:ID)"
I use this solution which works correctly whether the input date, in local time, is during Daylight Saving Time (DST) or not.
SELECT Round((Cast(Sys_extract_utc( Cast( your_date_field AS TIMESTAMP )) AS DATE) - To_date('1970-01-01','YYYY-MM-DD HH24MISS')) *24*60*60) AS epoch FROM dual;
-- 'your_date_field'
-- '20210112' -> 1610427600 (no DST)
-- '20210512' -> 1620792000 (DST)
I am trying to pull date from one table which is in ISO format and then store it in US date format?
Trunc(cast(to_timestamp(ATTRIBUTE_39,'yyyy-mm-dd"T"hh24:mi:ss.ff3"Z"')as date))
Actual output:
4/11/2018 12:00:00 AM
expected output:
4/11/2018
I am trying to pull date from one table which is in ISO format and then store it in US date format?
Dates (and timestamps) do not have a format - they are represented in a table by 7 bytes for a date or 20 bytes for a timestamp.
You can get the value as a DATE data type using TO_TIMESTAMP_TZ and either the TZR or TZH:THM format models to match the time zone region/offset (they will both work with the Zulu time zone region)
SELECT CAST(
TO_TIMESTAMP_TZ(
ATTRIBUTE_39,
'yyyy-mm-dd"T"hh24:mi:ss.ff3TZH:TZM'
) AT TIME ZONE 'UTC' -- Convert to a common time zone
AS DATE
)
FROM your_table;
When you select from the table then whatever client program you are using (typically) will implicitly convert the 7-bytes it uses internally to something you, the user, can read - a string. SQL/Plus and SQL Developer use the NLS_DATE_FORMAT session parameter as the format model when they perform this implicit conversion.
So your query is effectively converted to:
SELECT TO_CHAR(
CAST(
TO_TIMESTAMP_TZ(
ATTRIBUTE_39,
'yyyy-mm-dd"T"hh24:mi:ss.ff3TZR'
) AT TIME ZONE 'UTC'
AS DATE
),
(
SELECT VALUE
FROM NLS_SESSION_PARAMETERS
WHERE PARAMETER = 'NLS_DATE_FORMAT'
)
)
FROM your_table;
If you want to format a date or a timestamp then you will have to explicitly convert it to a string using TO_CHAR():
SELECT TO_CHAR(
CAST(
TO_TIMESTAMP_TZ(
ATTRIBUTE_39,
'yyyy-mm-dd"T"hh24:mi:ss.ff3TZR'
) AT TIME ZONE 'UTC'
AS DATE
),
'MM/DD/YYYY'
)
FROM your_table;
Or by altering the NLS_DATE_FORMAT session parameter:
ALTER SESSION SET NLS_DATE_FORMAT = 'YYYY-MM-DD HH24:MI:SS';
(Be aware that this will only change the format in the current session and will not change it for any other sessions/users.)
Try this:
select to_char(Trunc(cast(to_timestamp('2016-06-29T13:13:00.123','yyyy-mm-dd"T"hh24:mi:ss.ff3"Z"')as date)),'MM/DD/YYYY') from dual
the default date/time formatting depends on your NLS_DATE_FORMAT setting.
I need to convert a date from a TextBox from date to epoch time so that I can insert it into Oracle DB.
I managed to convert from epoch to date as below, but couldn't find a way to convert it the other way.
SelectCommand="SELECT ID,
COMPANY,
FIRST_NAME,
LAST_NAME,
ID_NUMBER,
(SELECT TO_CHAR(TO_DATE('01-JAN-1970','DD/MM/YYYY')
+(TRAINING_DATE/60/60/24), 'MM/DD/YYYY') FROM dual) AS TRAINING_DATE,
(SELECT TO_CHAR(TO_DATE('01-JAN-1970','DD/MM/YYYY')
+(TRAINING_VALABILITY/60/60/24),'MM/DD/YYYY') FROM dual) AS TRAINING_VALABILITY
FROM CONTRACTORS
ORDER BY COMPANY"
Subtracting DATE '1970-01-01' from the value will give the number of days (and fractional hours/minutes/seconds) difference and then you can multiply by 24*60*60:
(date_value - DATE '1970-01-01')*24*60*60
Update:
Typically, epoch time is measured from 1970-01-01T00:00:00 UTC. If your date is not in UTC then you will need to convert time zones.
For example, if your date has the time zone Europe/Berlin:
( CAST(
FROM_TZ(
CAST( date_value AS TIMESTAMP ), -- Cast to timestamp
'Europe/Berlin' -- Convert to expected Time Zone
)
AT TIME ZONE 'UTC' -- Convert Time Zone to UTC
AS DATE -- Cast back to DATE data type
)
- DATE '1970-01-01'
)*24*60*60
db<>fiddle
UpdateCommand="UPDATE CONTRACTORS
SET COMPANY=:COMPANY,
FIRST_NAME=:FIRST_NAME,
LAST_NAME=:LAST_NAME,
ID_NUMBER=:ID_NUMBER,
TRAINING_DATE=(TO_DATE(:TRAINING_DATE, 'MM-DD-YYYY HH24:MI:SS') - TO_DATE('01-JAN-1970','DD/MM/YYYY'))*24*60*60,
TRAINING_VALABILITY=(TO_DATE(:TRAINING_VALABILITY, 'MM-DD-YY`enter code here`YY HH24:MI:SS') - TO_DATE('01-JAN-1970','DD/MM/YYYY'))*24*60*60
WHERE (ID=:ID)"
I use this solution which works correctly whether the input date, in local time, is during Daylight Saving Time (DST) or not.
SELECT Round((Cast(Sys_extract_utc( Cast( your_date_field AS TIMESTAMP )) AS DATE) - To_date('1970-01-01','YYYY-MM-DD HH24MISS')) *24*60*60) AS epoch FROM dual;
-- 'your_date_field'
-- '20210112' -> 1610427600 (no DST)
-- '20210512' -> 1620792000 (DST)
I need to add seconds and substract variables with type TIMESTAMP WITH TIMEZONE, however, to my understanding, adding numbers to such data causes the information about the timezone to be lost, perhaps because it's converted to a DATE type
That is:
SELECT FROM_TZ(
TO_TIMESTAMP(
TO_DATE('03/09/2012 2:30:30','DD/MM/YYYY HH:MI:SS')
)
, 'America/Chicago')
FROM DUAL;
Gives:
03/09/2012 00:00:00, -05:00
Then
SELECT FROM_TZ(
TO_TIMESTAMP(
TO_DATE('03/09/2012 2:30:30','DD/MM/YYYY HH:MI:SS')
)
, 'America/Chicago') + 1/24 -- add 1 hour
FROM DUAL;
Gives
03/09/2012 01:00:00
and loses the timezone information.
But
SELECT FROM_TZ(
TO_TIMESTAMP(
TO_DATE('03/09/2012 2:30:30','DD/MM/YYYY HH:MI:SS'))
, 'America/Chicago') + INTERVAL '1' hour
FROM DUAL;
Correctly gives
03/09/2012 01:00:00,000000000 -05:00
However the INTERVAL.. syntax expect a char constant, so I can't use that with variables.
How can I perform that kind of arithmetic with TIMESTAMP WITH TIME ZONE datatype while retaining timezone information?
TIA
You can use the NUMTODSINTERVAL function to convert a number to an interval.
SELECT FROM_TZ( TIMESTAMP '2012-10-08 00:00:00','-5:00')
+ NUMTODSINTERVAL(1,'HOUR')
FROM dual;