Related
DECLARE #c varchar(100)
SET #c = 'This is and example #COIN-XXXX data only'
So basically, I want everything after #COIN- to the space i.e.(XXXX only).
How can I solve it?
another method is:
DECLARE #word varchar(max) = '#COIN-XXXX This is and example data only'
DECLARE #c varchar(100) = '#COIN1-'
DECLARE #CharIndex int = (select CHARINDEX(#c, #word))
if #CharIndex = 0
select 'No matching word'
DECLARE #firstSpaceAfter_index int = (select CHARINDEX(' ', #word, #CharIndex))
if #firstSpaceAfter_index = 0
set #firstSpaceAfter_index = len(#word) + 1
SELECT REPLACE(SUBSTRING(#WORD, #CharIndex, #firstSpaceAfter_index - #CharIndex),#c, '')
One method is:
select left(v.str, charindex(' ', v.str) - 1)
from (select #c as str) x cross apply
(values (stuff(x.str, 1, charindex('#COIN', x.str) + 5, ''))) v(str);
Here is a db<>fiddle.
What’s the best way to capitalize the first letter of each word in a string in SQL Server.
From http://www.sql-server-helper.com/functions/initcap.aspx
CREATE FUNCTION [dbo].[InitCap] ( #InputString varchar(4000) )
RETURNS VARCHAR(4000)
AS
BEGIN
DECLARE #Index INT
DECLARE #Char CHAR(1)
DECLARE #PrevChar CHAR(1)
DECLARE #OutputString VARCHAR(255)
SET #OutputString = LOWER(#InputString)
SET #Index = 1
WHILE #Index <= LEN(#InputString)
BEGIN
SET #Char = SUBSTRING(#InputString, #Index, 1)
SET #PrevChar = CASE WHEN #Index = 1 THEN ' '
ELSE SUBSTRING(#InputString, #Index - 1, 1)
END
IF #PrevChar IN (' ', ';', ':', '!', '?', ',', '.', '_', '-', '/', '&', '''', '(')
BEGIN
IF #PrevChar != '''' OR UPPER(#Char) != 'S'
SET #OutputString = STUFF(#OutputString, #Index, 1, UPPER(#Char))
END
SET #Index = #Index + 1
END
RETURN #OutputString
END
GO
There is a simpler/smaller one here (but doesn't work if any row doesn't have spaces, "Invalid length parameter passed to the RIGHT function."):
http://www.devx.com/tips/Tip/17608
As a table-valued function:
CREATE FUNCTION dbo.InitCap(#v AS VARCHAR(MAX))
RETURNS TABLE
AS
RETURN
WITH a AS (
SELECT (
SELECT UPPER(LEFT(value, 1)) + LOWER(SUBSTRING(value, 2, LEN(value))) AS 'data()'
FROM string_split(#v, ' ')
ORDER BY CHARINDEX(value,#v)
FOR XML PATH (''), TYPE) ret)
SELECT CAST(a.ret AS varchar(MAX)) ret from a
GO
Note that string_split requires COMPATIBILITY_LEVEL 130.
A variation of the one I've been using for quite some time is:
CREATE FUNCTION [widget].[properCase](#string varchar(8000)) RETURNS varchar(8000) AS
BEGIN
SET #string = LOWER(#string)
DECLARE #i INT
SET #i = ASCII('a')
WHILE #i <= ASCII('z')
BEGIN
SET #string = REPLACE( #string, ' ' + CHAR(#i), ' ' + CHAR(#i-32))
SET #i = #i + 1
END
SET #string = CHAR(ASCII(LEFT(#string, 1))-32) + RIGHT(#string, LEN(#string)-1)
RETURN #string
END
You can easily modify to handle characters after items other than spaces if you wanted to.
Another solution without using the loop - pure set-based approach with recursive CTE
create function [dbo].InitCap (#value varchar(max))
returns varchar(max) as
begin
declare
#separator char(1) = ' ',
#result varchar(max) = '';
with r as (
select value, cast(null as varchar(max)) [x], cast('' as varchar(max)) [char], 0 [no] from (select rtrim(cast(#value as varchar(max))) [value]) as j
union all
select right(value, len(value)-case charindex(#separator, value) when 0 then len(value) else charindex(#separator, value) end) [value]
, left(r.[value], case charindex(#separator, r.value) when 0 then len(r.value) else abs(charindex(#separator, r.[value])-1) end ) [x]
, left(r.[value], 1)
, [no] + 1 [no]
from r where value > '')
select #result = #result +
case
when ascii([char]) between 97 and 122
then stuff(x, 1, 1, char(ascii([char])-32))
else x
end + #separator
from r where x is not null;
set #result = rtrim(#result);
return #result;
end
If you are looking for the answer to the same question in Oracle/PLSQL then you may use the function INITCAP. Below is an example for the attribute dname from a table department which has the values ('sales', 'management', 'production', 'development').
SQL> select INITCAP(dname) from department;
INITCAP(DNAME)
--------------------------------------------------
Sales
Management
Production
Development
;WITH StudentList(Name) AS (
SELECT CONVERT(varchar(50), 'Carl-VAN')
UNION SELECT 'Dean o''brian'
UNION SELECT 'Andrew-le-Smith'
UNION SELECT 'Eddy thompson'
UNION SELECT 'BOBs-your-Uncle'
), Student AS (
SELECT CONVERT(varchar(50), UPPER(LEFT(Name, 1)) + LOWER(SUBSTRING(Name, 2, LEN(Name)))) Name,
pos = PATINDEX('%[-'' ]%', Name)
FROM StudentList
UNION ALL
SELECT CONVERT(varchar(50), LEFT(Name, pos) + UPPER(SUBSTRING(Name, pos + 1, 1)) + SUBSTRING(Name, pos + 2, LEN(Name))) Name,
pos = CASE WHEN PATINDEX('%[-'' ]%', RIGHT(Name, LEN(Name) - pos)) = 0 THEN 0 ELSE pos + PATINDEX('%[-'' ]%', RIGHT(Name, LEN(Name) - pos)) END
FROM Student
WHERE pos > 0
)
SELECT Name
FROM Student
WHERE pos = 0
ORDER BY Name
This will result in:
Andrew-Le-Smith
Bobs-Your-Uncle
Carl-Van
Dean O'Brian
Eddy Thompson
Using a recursive CTE set based query should out perform a procedural while loop query.
Here I also have made my separate to be 3 different characters [-' ] instead of 1 for a more advanced example. Using PATINDEX as I have done allows me to look for many characters. You could also use CHARINDEX on a single character and this function excepts a third parameter StartFromPosition so I could further simply my 2nd part of the recursion of the pos formula to (assuming a space): pos = CHARINDEX(' ', Name, pos + 1).
The suggested function works fine, however, if you do not want to create any function this is how I do it:
select ID,Name
,string_agg(concat(upper(substring(value,1,1)),lower(substring(value,2,len(value)-1))),' ') as ModifiedName
from Table_Customer
cross apply String_Split(replace(trim(Name),' ',' '),' ')
where Name is not null
group by ID,Name;
The above query split the words by space (' ') and create different rows of each having one substring, then convert the first letter of each substring to upper and keep remaining as lower. The final step is to string aggregate based on the key.
BEGIN
DECLARE #string varchar(100) = 'asdsadsd asdad asd'
DECLARE #ResultString varchar(200) = ''
DECLARE #index int = 1
DECLARE #flag bit = 0
DECLARE #temp varchar(2) = ''
WHILE (#Index <LEN(#string)+1)
BEGIN
SET #temp = SUBSTRING(#string, #Index-1, 1)
--select #temp
IF #temp = ' ' OR #index = 1
BEGIN
SET #ResultString = #ResultString + UPPER(SUBSTRING(#string, #Index, 1))
END
ELSE
BEGIN
SET #ResultString = #ResultString + LOWER(SUBSTRING(#string, #Index, 1))
END
SET #Index = #Index+ 1--increase the index
END
SELECT #ResultString
END
It can be as simple as this:
DECLARE #Name VARCHAR(500) = 'Roger';
SELECT #Name AS Name, UPPER(LEFT(#Name, 1)) + SUBSTRING(#Name, 2, LEN(#Name)) AS CapitalizedName;
fname is column name if fname value is akhil then UPPER(left(fname,1)) provide capital First letter(A) and substring function SUBSTRING(fname,2,LEN(fname)) provide(khil) concate both using + then result is (Akhil)
select UPPER(left(fname,1))+SUBSTRING(fname,2,LEN(fname)) as fname
FROM [dbo].[akhil]
On SQL Server 2016+ using JSON which gives guaranteed order of the words:
CREATE FUNCTION [dbo].[InitCap](#Text NVARCHAR(MAX))
RETURNS NVARCHAR(MAX)
AS
BEGIN
RETURN STUFF((
SELECT ' ' + UPPER(LEFT(s.value,1)) + LOWER(SUBSTRING(s.value,2,LEN(s.value)))
FROM OPENJSON('["' + REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(#Text,'\','\\'),'"','\"'),CHAR(9),'\t'),CHAR(10),'\n'),' ','","') + '"]') s
ORDER BY s.[key]
FOR XML PATH(''),TYPE).value('(./text())[1]','NVARCHAR(MAX)'),1,1,'');
END
GO
CREATE FUNCTION [dbo].[Capitalize](#text NVARCHAR(MAX)) RETURNS NVARCHAR(MAX) AS
BEGIN
DECLARE #result NVARCHAR(MAX) = '';
DECLARE #c NVARCHAR(1);
DECLARE #i INT = 1;
DECLARE #isPrevSpace BIT = 1;
WHILE #i <= LEN(#text)
BEGIN
SET #c = SUBSTRING(#text, #i, 1);
SET #result += IIF(#isPrevSpace = 1, UPPER(#c), LOWER(#c));
SET #isPrevSpace = IIF(#c LIKE '[ -]', 1, 0);
SET #i += 1;
END
RETURN #result;
END
GO
DECLARE #sentence NVARCHAR(100) = N'i-thINK-this soLUTION-works-LiKe-a charm';
PRINT dbo.Capitalize(#sentence);
-- I-Think-This Solution-Works-Like-A Charm
Here is the simplest one-liner to do this:
SELECT LEFT(column, 1)+ lower(RIGHT(column, len(column)-1) ) FROM [tablename]
I was looking for the best way to capitalize and i recreate simple sql script
how to use SELECT dbo.Capitalyze('this is a test with multiple spaces')
result "This Is A Test With Multiple Spaces"
CREATE FUNCTION Capitalyze(#input varchar(100) )
returns varchar(100)
as
begin
declare #index int=0
declare #char as varchar(1)=' '
declare #prevCharIsSpace as bit=1
declare #Result as varchar(100)=''
set #input=UPPER(LEFT(#input,1))+LOWER(SUBSTRING(#input, 2, LEN(#input)))
set #index=PATINDEX('% _%',#input)
if #index=0
set #index=len(#input)
set #Result=substring(#input,0,#index+1)
WHILE (#index < len(#input))
BEGIN
SET #index = #index + 1
SET #char=substring(#input,#index,1)
if (#prevCharIsSpace=1)
begin
set #char=UPPER(#char)
if (#char=' ')
set #char=''
end
if (#char=' ')
set #prevCharIsSpace=1
else
set #prevCharIsSpace=0
set #Result=#Result+#char
--print #Result
END
--print #Result
return #Result
end
IF OBJECT_ID ('dbo.fnCapitalizeFirstLetterAndChangeDelimiter') IS NOT NULL
DROP FUNCTION dbo.fnCapitalizeFirstLetterAndChangeDelimiter
GO
CREATE FUNCTION [dbo].[fnCapitalizeFirstLetterAndChangeDelimiter] (#string NVARCHAR(MAX), #delimiter NCHAR(1), #new_delimeter NCHAR(1))
RETURNS NVARCHAR(MAX)
AS
BEGIN
DECLARE #result NVARCHAR(MAX)
SELECT #result = '';
IF (LEN(#string) > 0)
DECLARE #curr INT
DECLARE #next INT
BEGIN
SELECT #curr = 1
SELECT #next = CHARINDEX(#delimiter, #string)
WHILE (LEN(#string) > 0)
BEGIN
SELECT #result =
#result +
CASE WHEN LEN(#result) > 0 THEN #new_delimeter ELSE '' END +
UPPER(SUBSTRING(#string, #curr, 1)) +
CASE
WHEN #next <> 0
THEN LOWER(SUBSTRING(#string, #curr+1, #next-2))
ELSE LOWER(SUBSTRING(#string, #curr+1, LEN(#string)-#curr))
END
IF (#next > 0)
BEGIN
SELECT #string = SUBSTRING(#string, #next+1, LEN(#string)-#next)
SELECT #next = CHARINDEX(#delimiter, #string)
END
ELSE
SELECT #string = ''
END
END
RETURN #result
END
GO
I'm trying to compare assembly versions using SQL Server, however there can be more than one version returned and I need it be in a six digit format.
For example, the assembly version 2.00.0001 and I need that to be returned as 2.0.1.
There could be versions like 1.01.0031 that I would need to be 1.1.31.
This works but is there a better way of doing it?
select left(left([output],9),1)+'.'+substring(left([output],9),3,1)+'.'+substring(right(left([output],9),1),1,1)
Using ParseName function, you can achieve this. Try this -
DECLARE #val VARCHAR(100) = '01.10.0031'
SELECT CONVERT(VARCHAR, CONVERT(INT, PARSENAME(#val, 3))) + '.' +
CONVERT(VARCHAR, CONVERT(INT, PARSENAME(#val, 2))) + '.' +
CONVERT(VARCHAR, CONVERT(INT, PARSENAME(#val, 1)))
Result
1.10.31
For limited numbers of zeros, you can replace .0 with .:
select replace(replace(replace([output], '.00', '.'), '.0', '.'), '..', '.0.')
This is a bit of a hack, but it is relatively simple.
Because the pattern would always be fixed, you could use substring and cast to do this.
select substring(col,1,1) + '.'
cast(cast(substring(col,3,2) as int) as varchar(2)) + '.'
cast(cast(substring(col,6,4) as int) as varchar(4))
from tablename
Here is a dynamic solution that will work with any format provided there are no alpha and '.' is the seperator.
Create Function [dbo].[SplitString] ( #stringToSplit VARCHAR(MAX) )
RETURNS
varchar(MAX)
AS
BEGIN
DECLARE #name VARCHAR(MAX)
DECLARE #pos INT
Declare #Return Varchar(MAX) = ''
WHILE CHARINDEX('.', #stringToSplit) > 0
BEGIN
SELECT #pos = CHARINDEX('.', #stringToSplit)
SELECT #name = Convert(Varchar(MAX), Convert(Int, SUBSTRING(#stringToSplit, 1, #pos-1)))
Set #Return = #Return + #name + '.'
SELECT #stringToSplit = SUBSTRING(#stringToSplit, #pos+1, LEN(#stringToSplit)-#pos)
END
RETURN #Return + Convert(Varchar(MAX), Convert(Int, #stringToSplit))
END
Declare #ver Varchar(100) = '7.00.0001'
Select dbo.splitstring(#ver)
I believe this should work as long as the pattern contains two decimal points and should handle any number of zeros in each position
DECLARE #version VARCHAR(19)
SET #version = '2.00.0001'
SELECT
CAST(CAST(SUBSTRING(#version,1,CHARINDEX('.',#version,1)-1) AS INT) AS VARCHAR(5)) + '.'+
CAST(CAST(SUBSTRING(#version,CHARINDEX('.',#version,1)+1,CHARINDEX('.',#version,CHARINDEX('.',#version,1) + 1)-CHARINDEX('.',#version,1)-1) AS INT) AS VARCHAR(5)) + '.' +
CAST(CAST(SUBSTRING(#version,CHARINDEX('.',#version,CHARINDEX('.',#version,1) + 1)+1,LEN(#version)) AS INT) AS VARCHAR(5))
how can i get SQL to take a sting and return the first letter of each word passed into it.
I want to use this UDF for generating initials for peoples names I have in the DB.
names can be 2 (fname, lname)or 3(...mname) words
i am using sql2005
This should work for both "Firstname Lastname" and "Firstname Middlename Lastname" combinations.
DECLARE #name AS NVARCHAR(50)
SET #name = 'Firstname Middle Lastname'
SELECT SUBSTRING(#name, 1, 1) + --First initial
SUBSTRING(#name, CHARINDEX(' ', #name) + 1, 1) + --Middle/Last initial
CASE WHEN 0 <> CHARINDEX(' ', #name, CHARINDEX(' ', #name) + 1) -- More than two words
THEN SUBSTRING(#name, CHARINDEX(' ', #name, CHARINDEX(' ', #name) + 1) + 1, 1) --Last initial
ELSE '' --Have to add empty string to avoid NULLing entire result
END
Of course, if users have a space in one of their names for some reason you will have an issue parsing this out, but I suspect that would be the case anyways when not storing your names in separate fields.
For SQL Server 2017 and newer:
CREATE FUNCTION dbo.fnGetFirstChars (#string NVARCHAR(max), #seperator NVARCHAR(MAX))
RETURNS NVARCHAR(max)
AS BEGIN
DECLARE #result NVARCHAR(MAX)
SELECT #result = STRING_AGG(SUBSTRING(value, 1, 1), '')
FROM STRING_SPLIT(#string, #seperator)
RETURN #result
END;
CREATE FUNCTION dbo.GetFirstLetter ( #Array VARCHAR(1000), #separator VARCHAR(10))
RETURNS #resultTable TABLE
(parseValue VARCHAR(100))
AS
BEGIN
DECLARE #separator_position INT
DECLARE #array_value VARCHAR(1000)
SET #array = #array + #separator
WHILE patindex('%' + #separator + '%' , #array) <> 0
BEGIN
SELECT #separator_position = patindex('%' + #separator + '%', #array)
SELECT #array_value = left(#array, #separator_position - 1)
INSERT #resultTable
VALUES (SUBSTRING(Cast(#array_value AS varchar), 1, 1))
SELECT #array = stuff(#array, 1, #separator_position, '')
END
RETURN
END
Here's my solution, and it has these features/peculiarities:
It can process however many names there are in the string. (That is, both less than two and more than three.)
All spaces between the names are preserved.
I know the OP has specified that there can only be 2 or 3 names in his case. I don't mind. I'm just sharing a solution that works, and if it's not best for the particular problem, it's fine.
So, here's the function:
CREATE FUNCTION dbo.fnGetInitials (#name varchar(max))
RETURNS varchar(max)
AS BEGIN
DECLARE #cutpos int, #spacepos int, #result varchar(max);
DECLARE #cutlist TABLE (CutPos int, SpacePos int);
SET #result = LTRIM(RTRIM(#name));
SET #cutpos = 2;
SET #spacepos = CHARINDEX(' ', #result);
WHILE #spacepos > 0 BEGIN
INSERT INTO #cutlist VALUES (#cutpos, #spacepos);
SET #spacepos = #spacepos + 1;
SET #cutpos = #spacepos + 1;
SET #spacepos = CHARINDEX(' ', #result, #spacepos);
END;
DELETE FROM #cutlist WHERE CutPos >= SpacePos;
SELECT #result = STUFF(#result, CutPos, SpacePos - CutPos, '')
FROM #cutlist
ORDER BY CutPos DESC;
RETURN #result;
END;
And here's a test call:
SELECT dbo.fnGetInitials(' John Ronald Reuel Tolkien ');
and the result:
----------------------------------------------------------------------------------------------------
J R R Tolkien
You can achieve it via xquery as well.
Declare #Xml XML
Declare #String Varchar(Max)
Declare #firstletter Varchar(Max)
Declare #delimiter Varchar(5)
SET #delimiter=' '
SET #String= 'THIS IS SQL'
SET #Xml = cast(('<a>'+replace(#String,#delimiter,'</a><a>')+'</a>') AS XML)
;WITH CTE AS
(SELECT A.value('.', 'varchar(max)') as [Column]FROM #Xml.nodes('a') AS FN(a) )
SELECT Stuff((SELECT '' + LEFT([Column],1)from CTE
FOR XML PATH ('') ),1,0,'')
Here is the complete solution.
http://raresql.com/2013/04/12/sql-server-get-the-first-letter-of-each-word-in-a-string-column/
A Picture is 100 times better than description. Here is an example of UDF declaration:
CREATE FUNCTION dbo.GetOnlyFirstLetters(#str NVARCHAR(4000),#sep NVARCHAR(10) )
RETURNS NVARCHAR(100)
AS
BEGIN
DECLARE #textXML XML
SELECT #textXML = CAST('<d>' + replace(#str, #sep, '</d><d>') + '</d>' AS XML)
DECLARE #result VARCHAR(8000)
SET #result = ''
SELECT #result = #result + LEFT(T.split.value ('.', 'nvarchar(max)'), 1)
FROM #textXML.nodes ('/d') T (split)
RETURN #result
END
GO
Here is how to call:
SELECT dbo.GetOnlyFirstLetters('Humayoun Kabir Sohel',' ');
Result will be:
HKS
What’s the best way to capitalize the first letter of each word in a string in SQL Server.
From http://www.sql-server-helper.com/functions/initcap.aspx
CREATE FUNCTION [dbo].[InitCap] ( #InputString varchar(4000) )
RETURNS VARCHAR(4000)
AS
BEGIN
DECLARE #Index INT
DECLARE #Char CHAR(1)
DECLARE #PrevChar CHAR(1)
DECLARE #OutputString VARCHAR(255)
SET #OutputString = LOWER(#InputString)
SET #Index = 1
WHILE #Index <= LEN(#InputString)
BEGIN
SET #Char = SUBSTRING(#InputString, #Index, 1)
SET #PrevChar = CASE WHEN #Index = 1 THEN ' '
ELSE SUBSTRING(#InputString, #Index - 1, 1)
END
IF #PrevChar IN (' ', ';', ':', '!', '?', ',', '.', '_', '-', '/', '&', '''', '(')
BEGIN
IF #PrevChar != '''' OR UPPER(#Char) != 'S'
SET #OutputString = STUFF(#OutputString, #Index, 1, UPPER(#Char))
END
SET #Index = #Index + 1
END
RETURN #OutputString
END
GO
There is a simpler/smaller one here (but doesn't work if any row doesn't have spaces, "Invalid length parameter passed to the RIGHT function."):
http://www.devx.com/tips/Tip/17608
As a table-valued function:
CREATE FUNCTION dbo.InitCap(#v AS VARCHAR(MAX))
RETURNS TABLE
AS
RETURN
WITH a AS (
SELECT (
SELECT UPPER(LEFT(value, 1)) + LOWER(SUBSTRING(value, 2, LEN(value))) AS 'data()'
FROM string_split(#v, ' ')
ORDER BY CHARINDEX(value,#v)
FOR XML PATH (''), TYPE) ret)
SELECT CAST(a.ret AS varchar(MAX)) ret from a
GO
Note that string_split requires COMPATIBILITY_LEVEL 130.
A variation of the one I've been using for quite some time is:
CREATE FUNCTION [widget].[properCase](#string varchar(8000)) RETURNS varchar(8000) AS
BEGIN
SET #string = LOWER(#string)
DECLARE #i INT
SET #i = ASCII('a')
WHILE #i <= ASCII('z')
BEGIN
SET #string = REPLACE( #string, ' ' + CHAR(#i), ' ' + CHAR(#i-32))
SET #i = #i + 1
END
SET #string = CHAR(ASCII(LEFT(#string, 1))-32) + RIGHT(#string, LEN(#string)-1)
RETURN #string
END
You can easily modify to handle characters after items other than spaces if you wanted to.
Another solution without using the loop - pure set-based approach with recursive CTE
create function [dbo].InitCap (#value varchar(max))
returns varchar(max) as
begin
declare
#separator char(1) = ' ',
#result varchar(max) = '';
with r as (
select value, cast(null as varchar(max)) [x], cast('' as varchar(max)) [char], 0 [no] from (select rtrim(cast(#value as varchar(max))) [value]) as j
union all
select right(value, len(value)-case charindex(#separator, value) when 0 then len(value) else charindex(#separator, value) end) [value]
, left(r.[value], case charindex(#separator, r.value) when 0 then len(r.value) else abs(charindex(#separator, r.[value])-1) end ) [x]
, left(r.[value], 1)
, [no] + 1 [no]
from r where value > '')
select #result = #result +
case
when ascii([char]) between 97 and 122
then stuff(x, 1, 1, char(ascii([char])-32))
else x
end + #separator
from r where x is not null;
set #result = rtrim(#result);
return #result;
end
If you are looking for the answer to the same question in Oracle/PLSQL then you may use the function INITCAP. Below is an example for the attribute dname from a table department which has the values ('sales', 'management', 'production', 'development').
SQL> select INITCAP(dname) from department;
INITCAP(DNAME)
--------------------------------------------------
Sales
Management
Production
Development
;WITH StudentList(Name) AS (
SELECT CONVERT(varchar(50), 'Carl-VAN')
UNION SELECT 'Dean o''brian'
UNION SELECT 'Andrew-le-Smith'
UNION SELECT 'Eddy thompson'
UNION SELECT 'BOBs-your-Uncle'
), Student AS (
SELECT CONVERT(varchar(50), UPPER(LEFT(Name, 1)) + LOWER(SUBSTRING(Name, 2, LEN(Name)))) Name,
pos = PATINDEX('%[-'' ]%', Name)
FROM StudentList
UNION ALL
SELECT CONVERT(varchar(50), LEFT(Name, pos) + UPPER(SUBSTRING(Name, pos + 1, 1)) + SUBSTRING(Name, pos + 2, LEN(Name))) Name,
pos = CASE WHEN PATINDEX('%[-'' ]%', RIGHT(Name, LEN(Name) - pos)) = 0 THEN 0 ELSE pos + PATINDEX('%[-'' ]%', RIGHT(Name, LEN(Name) - pos)) END
FROM Student
WHERE pos > 0
)
SELECT Name
FROM Student
WHERE pos = 0
ORDER BY Name
This will result in:
Andrew-Le-Smith
Bobs-Your-Uncle
Carl-Van
Dean O'Brian
Eddy Thompson
Using a recursive CTE set based query should out perform a procedural while loop query.
Here I also have made my separate to be 3 different characters [-' ] instead of 1 for a more advanced example. Using PATINDEX as I have done allows me to look for many characters. You could also use CHARINDEX on a single character and this function excepts a third parameter StartFromPosition so I could further simply my 2nd part of the recursion of the pos formula to (assuming a space): pos = CHARINDEX(' ', Name, pos + 1).
The suggested function works fine, however, if you do not want to create any function this is how I do it:
select ID,Name
,string_agg(concat(upper(substring(value,1,1)),lower(substring(value,2,len(value)-1))),' ') as ModifiedName
from Table_Customer
cross apply String_Split(replace(trim(Name),' ',' '),' ')
where Name is not null
group by ID,Name;
The above query split the words by space (' ') and create different rows of each having one substring, then convert the first letter of each substring to upper and keep remaining as lower. The final step is to string aggregate based on the key.
BEGIN
DECLARE #string varchar(100) = 'asdsadsd asdad asd'
DECLARE #ResultString varchar(200) = ''
DECLARE #index int = 1
DECLARE #flag bit = 0
DECLARE #temp varchar(2) = ''
WHILE (#Index <LEN(#string)+1)
BEGIN
SET #temp = SUBSTRING(#string, #Index-1, 1)
--select #temp
IF #temp = ' ' OR #index = 1
BEGIN
SET #ResultString = #ResultString + UPPER(SUBSTRING(#string, #Index, 1))
END
ELSE
BEGIN
SET #ResultString = #ResultString + LOWER(SUBSTRING(#string, #Index, 1))
END
SET #Index = #Index+ 1--increase the index
END
SELECT #ResultString
END
It can be as simple as this:
DECLARE #Name VARCHAR(500) = 'Roger';
SELECT #Name AS Name, UPPER(LEFT(#Name, 1)) + SUBSTRING(#Name, 2, LEN(#Name)) AS CapitalizedName;
fname is column name if fname value is akhil then UPPER(left(fname,1)) provide capital First letter(A) and substring function SUBSTRING(fname,2,LEN(fname)) provide(khil) concate both using + then result is (Akhil)
select UPPER(left(fname,1))+SUBSTRING(fname,2,LEN(fname)) as fname
FROM [dbo].[akhil]
On SQL Server 2016+ using JSON which gives guaranteed order of the words:
CREATE FUNCTION [dbo].[InitCap](#Text NVARCHAR(MAX))
RETURNS NVARCHAR(MAX)
AS
BEGIN
RETURN STUFF((
SELECT ' ' + UPPER(LEFT(s.value,1)) + LOWER(SUBSTRING(s.value,2,LEN(s.value)))
FROM OPENJSON('["' + REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(#Text,'\','\\'),'"','\"'),CHAR(9),'\t'),CHAR(10),'\n'),' ','","') + '"]') s
ORDER BY s.[key]
FOR XML PATH(''),TYPE).value('(./text())[1]','NVARCHAR(MAX)'),1,1,'');
END
GO
CREATE FUNCTION [dbo].[Capitalize](#text NVARCHAR(MAX)) RETURNS NVARCHAR(MAX) AS
BEGIN
DECLARE #result NVARCHAR(MAX) = '';
DECLARE #c NVARCHAR(1);
DECLARE #i INT = 1;
DECLARE #isPrevSpace BIT = 1;
WHILE #i <= LEN(#text)
BEGIN
SET #c = SUBSTRING(#text, #i, 1);
SET #result += IIF(#isPrevSpace = 1, UPPER(#c), LOWER(#c));
SET #isPrevSpace = IIF(#c LIKE '[ -]', 1, 0);
SET #i += 1;
END
RETURN #result;
END
GO
DECLARE #sentence NVARCHAR(100) = N'i-thINK-this soLUTION-works-LiKe-a charm';
PRINT dbo.Capitalize(#sentence);
-- I-Think-This Solution-Works-Like-A Charm
Here is the simplest one-liner to do this:
SELECT LEFT(column, 1)+ lower(RIGHT(column, len(column)-1) ) FROM [tablename]
I was looking for the best way to capitalize and i recreate simple sql script
how to use SELECT dbo.Capitalyze('this is a test with multiple spaces')
result "This Is A Test With Multiple Spaces"
CREATE FUNCTION Capitalyze(#input varchar(100) )
returns varchar(100)
as
begin
declare #index int=0
declare #char as varchar(1)=' '
declare #prevCharIsSpace as bit=1
declare #Result as varchar(100)=''
set #input=UPPER(LEFT(#input,1))+LOWER(SUBSTRING(#input, 2, LEN(#input)))
set #index=PATINDEX('% _%',#input)
if #index=0
set #index=len(#input)
set #Result=substring(#input,0,#index+1)
WHILE (#index < len(#input))
BEGIN
SET #index = #index + 1
SET #char=substring(#input,#index,1)
if (#prevCharIsSpace=1)
begin
set #char=UPPER(#char)
if (#char=' ')
set #char=''
end
if (#char=' ')
set #prevCharIsSpace=1
else
set #prevCharIsSpace=0
set #Result=#Result+#char
--print #Result
END
--print #Result
return #Result
end
IF OBJECT_ID ('dbo.fnCapitalizeFirstLetterAndChangeDelimiter') IS NOT NULL
DROP FUNCTION dbo.fnCapitalizeFirstLetterAndChangeDelimiter
GO
CREATE FUNCTION [dbo].[fnCapitalizeFirstLetterAndChangeDelimiter] (#string NVARCHAR(MAX), #delimiter NCHAR(1), #new_delimeter NCHAR(1))
RETURNS NVARCHAR(MAX)
AS
BEGIN
DECLARE #result NVARCHAR(MAX)
SELECT #result = '';
IF (LEN(#string) > 0)
DECLARE #curr INT
DECLARE #next INT
BEGIN
SELECT #curr = 1
SELECT #next = CHARINDEX(#delimiter, #string)
WHILE (LEN(#string) > 0)
BEGIN
SELECT #result =
#result +
CASE WHEN LEN(#result) > 0 THEN #new_delimeter ELSE '' END +
UPPER(SUBSTRING(#string, #curr, 1)) +
CASE
WHEN #next <> 0
THEN LOWER(SUBSTRING(#string, #curr+1, #next-2))
ELSE LOWER(SUBSTRING(#string, #curr+1, LEN(#string)-#curr))
END
IF (#next > 0)
BEGIN
SELECT #string = SUBSTRING(#string, #next+1, LEN(#string)-#next)
SELECT #next = CHARINDEX(#delimiter, #string)
END
ELSE
SELECT #string = ''
END
END
RETURN #result
END
GO