I am stuck on transforming this SQL query to an eloquent query in Laravel. The SQL query works (tested in Sequel) but I cannot write it in eloquent ...
SELECT faqs.question FROM faqs
JOIN categories c ON c.id = faqs.category_id
WHERE c.subsite = 'sport'
This is what I have tried so far, but it returns all the questions, (ignoring the subsite filter).
$cat = Faq::with(['category' => function($query) use ($subsite) {
$query->where('subsite', $subsite);
}])->get();
Thanks for the help
Try this
$cat = Faq::query();
if (isset($subsite) && !empty($subsite) {
$query->whereHas('category', function ($query) use ($subsite) {
$query->where('subsite', $subsite);
});
}
$query->with('category')->get();
as per you core sql query, here is your laravel query.
$data = DB::table('faqs')
->join('categories', 'categories.id', '=', 'faqs.category_id')
->select('faqs.question')
->where('categories.subsite', '=', 'sport')
->get();
Hope this will help you!
Related
I'm a beginner regarding Laravel Query Builder, can you guys help me convert this SQL to Query Builder
public function check_available_room(Request $request, $checkin_date)
{
$available_rooms = DB::SELECT("SELECT * FROM rooms WHERE id NOT IN (SELECT room_id FROM bookings WHERE '$checkin_date' BETWEEN checkin_date AND checkout_date)");
}
Book model
function rooms() {
return $this->belongsTo(Room::class, 'room_id');
}
Room model
public function bookings() {
return $this->hasMany(Booking::class);
}
Thank you so much
Here is a solution if you have your models and relations in place
$availableRooms = Room::whereDoesntHave('bookings', function($bookingQuery) use ($checkin_date) {
$bookingQuery->where('checkin_date', '<', $checkin_date)
->where('checkout_date', '>=', $checkin_date);
})->get();
$unavailable_room_ids = Booking::where('checkin_date', '<', $checkin_date)
->where('checkout_date', '>=', $checkin_date)
->pluck('room_id')->get();
$available_rooms = Room::whereNotIn('id', $unavailable_room_ids)->get();
I want to make a count by the first letters... I have this column
I would like to count each OE rows and each GICS rows
I'm working with this query
$data4 = DB::table('incidencias')
->select(DB::raw('grupo_asig as grupo_asig'), DB::raw('count(*) as number'))
->whereNotIn('grupo_asig', [''])
->groupBy('grupo_asig')
->orderBy('number', 'desc')
->get();
Use CASE WHEN and count the field like OE and ASIG
$data4 = DB::table('incidencias')
->select(DB::raw("(CASE WHEN grupo_asig LIKE 'OE%' THEN 'OE'
WHEN grupo_asig LIKE 'GICS%' THEN 'GICS'
END) AS grupo_asig_type"),
DB::raw('COUNT(*) as number'))
->whereNotIn('grupo_asig', [''])
->groupBy('grupo_asig_type')
->orderBy('number', 'desc')
->get();
You should try to use the [LIKE][1] function then and add it to your query:
->where('grupo_asig', 'like', 'OE%')
->where('grupo_asig', 'like', 'GICS%')
Edit:
I tried a lot around and came to this solution and made a SQL fiddle: http://sqlfiddle.com/#!9/06a39b/8
Does it help you?
You could use Collections. No real need to change your query much.
$data4 = DB::table('incidencias')
->select('grupo_asig')
->selectRaw('count(*) as number'))
->whereNotIn('grupo_asig', [''])
->groupBy('grupo_asig')
// ->orderBy('number', 'desc') Unless you use this array somewhere, it's not needed.
->get();
use Illuminate\Support\Str;
...
// php >= 7.4.0
$oe_count = $data4->filter(fn($data) => Str::startsWith($data->grupo, 'OE '))->count();
$gigs_count = $data4->filter(fn($data) => Str::startsWith($data->grupo, 'GIGS '))->count();
// php < 7.4.0
$oe_count = $data4->filter(function ($data) {
return Str::startsWith($data->grupo, 'OE ');
})->count();
$gigs_count = $data4->filter(function ($data) {
return Str::startsWith($data->grupo, 'GIGS ');
})->count();
Starting with Laravel 6, you can also use cursor() instead of get() in your query to return a LazyCollection. It's faster for this scenario.
I would suggest using a query for that:
refer to this answer
SELECT
LEFT(grupo_asig, 1) AS first_letter,
COUNT(*) AS total
FROM incidencias
GROUP BY first_letter
I am trying to convert the following query to Laravel:
select libéllé
from application
where libéllé not in (select application_id from application_user
where user_id = $id)
Laravel whereNotIn supports closures for subqueries, so it will be as simple as this:
Using Eloquent:
// Add this to top of your file.
use App\{ Application, ApplicationUser };
// Get your entries.
$rows = Application::whereNotIn('libéllè', function($query) use ($id) {
$query->select('application_id')->from((new ApplicationUser)->getTable())->where('user_id', $id);
})->get(['libéllè']);
Using Query Builder:
$rows = DB::table('application')->whereNotIn('libéllè', function($query) use ($id) {
$query->select('application_id')->from('application_user')->where('user_id', $id);
})->get(['libéllè']);
Please Try it.
$results = DB::select(
select libéllé
from application
where (libéllé)
not in(
select application_id from application_user
where user_id = $id
)
);
Also see this answer: How to convert mysql to laravel query builder
Also see this documentation: https://laracasts.com/discuss/channels/laravel/laravel5-resolve-username-from-2-tables?page=1
How to write this query in Laravel. I am new in laravel.
Example:
SELECT * FROM ((respassanger join ((`reservation` join flightres
on flightres.res_id = reservation.id)) on respassanger.res_id = reservation.id)
join passanger on respassanger.pas_id = passanger.pas_id)
Have you read the documentation? Checkout Laravel's query builder. Using your table names as mentioned, work from the following example in the docs for your needs:
DB::table('users')
->join('contacts', function($join)
{
$join->on('users.id', '=', 'contacts.user_id')->orOn(...);
})
->get();
So something like:
DB::table('respassanger')
->join('reservation', function($join)
{
$join->on('flightres.res_id', '=', 'reservation.id')
})
->join('passanger', 'respassanger.pas_id', '=', 'passanger.pas_id')
->select( ... )
->get();
Not sure how correct the above is, but tweak it if it doesn't work.
Following query returning six values
SELECT tbl_start FROM timetable inner join route ON tbl_rte_id = id WHERE rte_origin = "UL" and rte_destination = "HW" ORDER BY(tbl_start) DESC;
And my laravel code is returning only one value
$tables = Timetable::join('route', 'tbl_rte_id', '=', 'id')
->where('rte_origin', $origin, 'AND')
->where('rte_destination', $destination)
->orderBy('tbl_start', 'desc')
->get();
foreach ($tables as $table) {
$result[$table->id] = $table->tbl_start;
}
This laravel code is not similar or similar. Can anyone help me.
Change this part:
->where('rte_origin', $origin, 'AND')
// to:
->where('rte_origin', $origin)
It will know by default that it's AND operator
And if you want to provide this operator, then do this:
->where('rte_origin', '=', $origin, 'AND')
You may try something like this:
$tables = Timetable::join('route', 'tbl_rte_id', '=', 'timetable.id')
->where('rte_origin', $origin)
->where('rte_destination', $destination)
->orderBy('tbl_start', 'desc')
->get()->lists('tbl_start', 'id');
The $tables will contain an array of id => tbl_start pairs.
Add a listener in your routes.php
Event::listen('illuminate.query', function($sql){
var_dump($sql);
});
Then execute both queries and check if you have the same result