I have one case-sensitive column.
How can I replace (Shpersonel,shPersonel, sHperSonel) to ShPersonel in all records?
my column Data is:
1- SHpersonel = 12 And Password= Ayuy122
2- ShpeRsonel = 10 And Password= jkjIUD122
3- ShPersonel = 08 And Password= Kjjam
...
You could use LOWER (or UPPER), which lots of DBMSes support, to look for a value case insensitively and update:
update your_table
set col = 'ShPersonel'
where lower(col) = 'shpersonel';
EDIT:
Further clarification explained that above data is stored in a single column - Which is not how it should be stored.
You should store the data in separate columns and then look for further normalization to remove unwanted dependencies.
UPDATE your_table
SET your_column = 'ShPersonel'
WHERE upper(your_column) = 'SHPERSONEL';
You didn't say what DBMS you're using. If it's SQL-Server, the following should work for you:
update MyTable
set TheData =
concat(
left(TheData,charindex('shpersonel',lower(t.TheData))-1),
'ShPersonel',
right(t.TheData,len(t.TheData) - charindex('shpersonel',lower(t.TheData)) - len('ShPersonel'))
)
from MyTable t
where
charindex('shpersonel',lower(t.TheData))>0
For other DBMS's you need to replace charindex with whatever that DBMS's equivalent may be. For example, Oracle and MySQL use InStr (which needs its arguments in the reverse order).
Related
I want to change the string of AttachmentCopyLoc columns from D:\IT\Public\FTX_RobotAlerts\336 to V:\IT\Public\FTX_RobotAlerts\336 only change here is D to V, the remaining string is the same (I don't event want to change that).
How can I do that?
Thanks in advance for your help.
The exact syntax depends on the platform, but it would be something akin to
UPDATE {table}
SET AttachmentCopyLoc = REPLACE ( AttachmentCopyLoc , 'D:' , 'V:' )
WHERE AttachmentCopyLoc LIKE 'D:%'
In SQL Server, I would recommend using stuff():
update t
set AttachmentCopyLoc = stuff(AttachmentCopyLoc, 1, 1, 'V')
where AttachmentCopyLoc like 'D:%';
This version has two advantages:
The use of STUFF() ensures that only the first occurrence of 'D:' is replaced. Admittedly, it is unlikely that this substring occurs more than once in the column, but why take the chance?
The use of LIKE allows an index on AttachmentCopyLoc to be used, if one is available and use of hte index is appropriate.
Another way would be basic string manipulation
UPDATE {table}
SET AttachmentCopyLoc ='V' + substring(AttachmentCopyLoc,2,len(AttachmentCopyLoc ))
where AttachmentCopyLoc like 'D%'
This will only alter the first letter of the string:
update <tablename>
set AttachmentCopyLoc = 'V'+substring(AttachmentCopyLoc,2,len(AttachmentCopyLoc)-1)
In a column in a SQL Server database table, the value has a format of X=****;Y=****;Z=5****, where the asterisks represent strings of any lengths and of any values. What I need to do is to change that 5 to a 4 and keep the rest of the string unchanged.
Is there a way to use something like regular expressions to achieve what I want to do? If not using regular expressions, can it be done at all?
MS SQL sadly doesn't have any built in regex support (although it can be added via CLR) but if the format is fixed so that the part you want to change isZ=5toZ=4then usingREPLACEshould work:
REPLACE(your_string,'Z=5','Z=4')
For example:
declare #t table (str varchar(max))
insert #t values
('X=****;Y=****;Z=5****'),
('X=****;Y=**df**;Z=3**sdf**'),
('X=11**;Y=**sdfdf**;Z=5**')
update #t
set str = replace(str,'Z=5','Z=4')
-- or a slightly more ANSI compliant and portable way
update #t
set str = SUBSTRING(str,0, CHARINDEX('Z=5', str)) + 'Z=4' + SUBSTRING(str, CHARINDEX('Z=5', str)+3,LEN(str))
select * from #t
str:
X=****;Y=****;Z=4****
X=****;Y=**df**;Z=3**sdf**
X=11**;Y=**sdfdf**;Z=4**
We need more information. Under what circumstances should 5 be replaced by 4? If it's just where it occurs as the first character after the Z=, then you could simply do...
set Col = Replace(Col,'Z=5','Z=4')
Or, do you just want to replace 5 with 4 anywhere in the column value. In which case you'd obviously just do...
set Col = Replace(Col,'5','4')
Or possibly you mean that 5's should be replaced by 4's anywhere within the value after Z= which would be a lot harder.
update Table set Field = replace(Field, ';Z=5', ';Z=4')
And let's hope that your asterisked data doesn't contain semicolons and equality signs...
How to take a string from a row in a column named 'link', and modify it by adding three letters to a specific index position in the string.
Specific example:
I want to select the value 'http://www.hello.no' and UPDATE it with 'http://www-x1.hello.no' using SQL statement(s).
Lets say the index position where '-x1' starts at will always be 10.
This needs to be accomplished using PostgreSQL. But if you can capture the logic with a generic SQL statement then great. :)
Postgresql has a function for doing replacements with patterns called regexp_replace. You can use that function like this:
UPDATE my_table
SET link = regexp_replace(link, 'www', 'www-x1')
WHERE <...>
Of course you could do it with the straight string manipulation, too:
UPDATE my_table
SET link = left(link, 10) || '-x1' || substring(link from 10)
WHERE <...>
This does what you ask for:
update the_table
set the_column = left(the_column, 10) || '-x1' || substring(the_column, 10);
however I'm not sure that this is what you want. It seems you want to insert the '-x1' in front of the first . which would be something different.
I have stored values in my database that look like 5XXXXXX, where X can be any digit. In other words, I need to match incoming SQL query strings like 5349878.
Does anyone have an idea how to do it?
I have different cases like XXXX7XX for example, so it has to be generic. I don't care about representing the pattern in a different way inside the SQL Server.
I'm working with c# in .NET.
You can write queries like this in SQL Server:
--each [0-9] matches a single digit, this would match 5xx
SELECT * FROM YourTable WHERE SomeField LIKE '5[0-9][0-9]'
stored value in DB is: 5XXXXXX [where x can be any digit]
You don't mention data types - if numeric, you'll likely have to use CAST/CONVERT to change the data type to [n]varchar.
Use:
WHERE CHARINDEX(column, '5') = 1
AND CHARINDEX(column, '.') = 0 --to stop decimals if needed
AND ISNUMERIC(column) = 1
References:
CHARINDEX
ISNUMERIC
i have also different cases like XXXX7XX for example, so it has to be generic.
Use:
WHERE PATINDEX('%7%', column) = 5
AND CHARINDEX(column, '.') = 0 --to stop decimals if needed
AND ISNUMERIC(column) = 1
References:
PATINDEX
Regex Support
SQL Server 2000+ supports regex, but the catch is you have to create the UDF function in CLR before you have the ability. There are numerous articles providing example code if you google them. Once you have that in place, you can use:
5\d{6} for your first example
\d{4}7\d{2} for your second example
For more info on regular expressions, I highly recommend this website.
Try this
select * from mytable
where p1 not like '%[^0-9]%' and substring(p1,1,1)='5'
Of course, you'll need to adjust the substring value, but the rest should work...
In order to match a digit, you can use [0-9].
So you could use 5[0-9][0-9][0-9][0-9][0-9][0-9] and [0-9][0-9][0-9][0-9]7[0-9][0-9][0-9]. I do this a lot for zip codes.
SQL Wildcards are enough for this purpose. Follow this link: http://www.w3schools.com/SQL/sql_wildcards.asp
you need to use a query like this:
select * from mytable where msisdn like '%7%'
or
select * from mytable where msisdn like '56655%'
How do I write a query in Oracle ignoring the case of the strings being compared? For example "angel", "Angel", "ANGEL", "angel", "AngEl" would all be equal when compared.
If you are matching the full value of the field use
WHERE UPPER(fieldName) = 'ANGEL'
EDIT: From your comment you want to use:
SELECT
RPAD(a.name, 10,'=') "Nombre del Cliente"
, RPAD(b.name, 12,'*') "Nombre del Consumidor"
FROM
s_customer a,
s_region b
WHERE
a.region_id = b.id
AND UPPER(a.name) LIKE '%SPORT%'
You could use the UPPER keyword:
SELECT *
FROM Customers
WHERE UPPER(LastName) = UPPER('AnGel')
You can use:
select * from your_table where upper(your_column) like '%ANGEL%'
Otherwise, you can use:
select * from your_table where upper(your_column) = 'ANGEL'
Which will be more efficient if you are looking for a match with no additional characters before or after your_column field as Gary Ray suggested in his comments.
before comparing the two or more strings first execute the following commands
alter session set NLS_COMP=LINGUISTIC;
alter session set NLS_SORT=BINARY_CI;
after those two statements executed then you may compare the strings and there will be case insensitive.for example you had two strings s1='Apple' and s2='apple', if yow want to compare the two strings before executing the above statements then those two strings will be treated as two different strings but when you compare the strings after the execution of the two alter statements then those two strings s1 and s2 will be treated as the same string
reasons for using those two statements
We need to set NLS_COMP=LINGUISTIC and NLS_SORT=BINARY_CI in order to use 10gR2 case insensitivity. Since these are session modifiable, it is not as simple as setting them in the initialization parameters. We can set them in the initialization parameters but they then only affect the server and not the client side.
More detail on Mr Dredel's answer and tuinstoel's comment.
The data in the column will be stored in its specific case, but you can change your session's case-sensitivity for matching.
You can change either the session or the database to use linguistic or case insensitive searching. You can also set up indexes to use particular sort orders.
eg
ALTER SESSION SET NLS_SORT=BINARY_CI;
Once you start getting into non-english languages, with accents and so on, there's additional support for accent-insensitive.
Some of the capabilities vary by version, so check out the Globablization document for your particular version of Oracle. The latest (11g) is here
SELECT STRCMP("string1", "string2");
this returns 0 if the strings are equal.
If string1 = string2, this function returns 0 (ignoring the case)
If string1 < string2, this function returns -1
If string1 > string2, this function returns 1
https://www.w3schools.com/sql/func_mysql_strcmp.asp
To avoid string conversions comparisons, use COLLATE SQL_Latin1_General_CP1_CI_AS.
EXAMPLE:
SELECT UserName FROM Users
WHERE UserName COLLATE SQL_Latin1_General_CP1_CI_AS = 'Angel'
That will return any usernames, whether ANGEL, angel, or Angel, etc.
I don't recall the exact syntax, but you may set the table column to be case insensitive. But be careful because then you won't be able to match based on case anymore and if you WANT 'cool' to not match 'CoOl' it will no longer be possible.