finding consecutive numbers - sql

Question

ok - so i searched the internet for this, and none of the examples i found are exactly like mine.
i have a table with 5 columns and thousands of rows.
i need to find consecutive numbers within each row. i need to end up with 3 queries for the situations shown below
n1 n2 n3 n4 n5
=======================
1 3 4 6 9 = should result in 1 (when checking for pairs)
1 3 4 5 9 = should result in 1 (when checking for triplets)
1 2 5 8 9 = should result in 1 (when checking for double pairs)
This is what i have to move the columns into rows, but i am not sure how to check this now.
select n1 from (
select n1 from myTable where Id = 1
union all select n2 from myTable where Id = 1
union all select n3 from myTable where Id = 1
union all select n4 from myTable where Id = 1
union all select n5 from myTable where Id = 1
) t
order by n1
Thank you for all your help!
#TimBiegeleise, update :
so i found this on google for Gaps & Islands:
SELECT ID, StartSeqNo=MIN(SeqNo), EndSeqNo=MAX(SeqNo)
FROM (
SELECT ID, SeqNo
,rn=SeqNo-ROW_NUMBER() OVER (PARTITION BY ID ORDER BY SeqNo)
FROM dbo.GapsIslands) a
GROUP BY ID, rn;
this is my updated query converting the columns to rows (but it requires 2 statements, i much rather have 1) and implementing the island part - but i don't understand how that give me the result what i need (see above). below i show the original row data and the result.
select n1, IDENTITY (INT, 1, 1) AS ID
into #test
from (
select n1 from myTable where Id = 8
union all select n2 from myTable where Id = 8
union all select n3 from myTable where Id = 8
union all select n4 from myTable where Id = 8
union all select n5 from myTable where Id = 8
) as t
order by n1
SELECT ID, StartSeqNo=MIN(n1), EndSeqNo=MAX(n1)
FROM (
SELECT ID, n1
,rn=n1-ROW_NUMBER() OVER (PARTITION BY ID ORDER BY n1)
FROM #test) a
GROUP BY ID, rn
drop table #test
original row - should return 1 (when checking for "pair"/consecutive numbers
n1 n2 n3 n4 n5
=======================
31 27 28 36 12
the result i get with the above query:
StartSeqNo EndSeqNo
1 12 12
2 27 27
3 28 28
4 31 31
5 36 36
help :-) !

Answer 1

ok, i got it. this query returns a value of 1 for the above stated row
select COUNT(*) as pairs
from (
SELECT StartSeqNo=MIN(n1), EndSeqNo=MAX(n1)
FROM (
SELECT n1, rn=n1-ROW_NUMBER() OVER (ORDER BY n1)
from (
select n1 from myTable where Id = 8
union all select n2 from myTable where Id = 8
union all select n3 from myTable where Id = 8
union all select n4 from myTable where Id = 8
union all select n5 from myTable where Id = 8
) t
) x
GROUP BY rn
) z
where StartSeqNo+1 = EndSeqNo