How to avoid showing duplicate values in an inner join - sql

Question

I am trying not to show duplicate values in the ORDER column from the results list; however, I am showing duplicate "ORDER" values. How can I fix this?
select i.contractnumber as "CONTRACT NUMBER", t.ordernumber as
"ORDER", t.title as "ORDER TITLE", c.companyname as "COMPANY",
LEFT(cs.firstname, 1) +'. '+ cs.lastname as "TECHINICAN",
REPLACE(cs.CONTACT,'703-735-', 'x') as "CONTACT (703) 735....)"
from Company c inner join CONTRACTS i
on i.Company_ID = c.Company_ID
inner join Orders t
on t.ordernumberid = i.ordernumberid
inner join hub rut
on rut.titleOrder_ID = t.titleOrder_ID
inner join hub2 r
on r.Role_ID = rut.Role_ID
inner join Customer u
on u.Customer_ID = rut.Customer_ID
inner join CORD cs
on cs.CORD_ID = u.CORD_ID
inner join Method cv
on cv.Method_ID = i.Method_ID
where cs.Contact LIKE '%703-735-%'
and cv.Method_ID = 1;

Answer 1

The simple way to fix this is with a group by -- eg GROUP BY Order however if you have more than one value for the other columns you will have an issue -- you can pick a value -- for example max. That would like like this:
select
max(i.contractnumber) as "CONTRACT NUMBER",
t.ordernumber as "ORDER",
max(mat.title) as "ORDER TITLE",
max(c.companyname) as "COMPANY",
max(LEFT(cs.firstname, 1) +'. '+ cs.lastname) as "TECHINICAN",
max(REPLACE(cs.CONTACT,'703-735-', 'x')) as "CONTACT (703) 735....)"
-- etc as you have
-- ...
-- end with
GROUP BY t.ordernumber