SQL - SHOW ALL DATES between two dates - sql

Question

I have following data saved as dates in my [OccuredAtUtc] that look like this:
-- Spoiler ALERT: "2017-04-26" and "2017-04-29" are missing.
Original dates in [OccuredAtUtc]:
2017-04-24 12:16:58.5080000
2017-04-24 18:11:53.3090000
2017-04-25 18:34:18.3090000
2017-04-27 20:42:28.8570000
2017-04-28 21:10:36.7070000
2016-04-28 10:37:57.5970000
2016-04-30 10:38:55.7010000
2016-04-30 10:48:19.0390000
2016-04-31 10:48:19.2990000
.
.
.
And I have this code that returns correctly data from two intervals (previous week).
SELECT
[MessageType].[Name] AS [Channel],
CONVERT(VARCHAR(11), [OccuredAtUtc], 106) AS [Time],
COUNT(*) AS [Count]
FROM #table1
INNER JOIN #table2 ON ... = ...
WHERE ( [OccuredAtUtc] > '2017-04-24'
AND [OccuredAtUtc] < '2017-04-30' )
GROUP BY (CONVERT(VARCHAR(11), [OccuredAtUtc], 106)),
[MessageType].[Name]
ORDER BY [Time] ASC
But the output won't show a row of the "26 Apr 2017" and "29 Apr 2017" because there are not records on these days in my DB.
OLD OUTPUT : with missing 26th & 29th Apr.
[Channel] [Time] [Count]
------------------------------------
FTP 24 Apr 2017 7
HTTP 24 Apr 2017 9
FTP 25 Apr 2017 6
HTTP 25 Apr 2017 2
------MISSING 26 Apr--------
FTP 27 Apr 2017 56
HTTP 27 Apr 2017 12
FTP 28 Apr 2017 5
------MISSING 29 Apr--------
HTTP 28 Apr 2017 17
FTP 30 Apr 2017 156
HTTP 30 Apr 2017 19
I would like to show rows WITH THE MISSING DATE even if there was not an incident saved on this day...
So the new OUTPUT should look like this.
WANTED OUTPUT :
[Channel] [Time] [Count]
------------------------------------
FTP 24 Apr 2017 7
HTTP 24 Apr 2017 9
FTP 25 Apr 2017 6
HTTP 25 Apr 2017 2
0 26 Apr 2017 0 -- here we go
FTP 27 Apr 2017 56
HTTP 27 Apr 2017 12
FTP 28 Apr 2017 5
HTTP 28 Apr 2017 17
0 29 Apr 2017 0 -- here we go
FTP 30 Apr 2017 156
HTTP 30 Apr 2017 19
I know there are answered question like mine and I was trying to remake my code but I failed.
( SHOW ALL Dates data between two dates; if no row exists for particular date then show zero in all columns )
( How to generate all dates between two dates )

Answer 1

Similar to #DhruvJoshi's answer but using a recursive CTE to generate the dates instead:
DECLARE #MinDate DATE = '20170424',
#MaxDate DATE = '20170430';
WITH allDates AS
(
SELECT #MinDate AS dates
UNION ALL
SELECT DATEADD(DAY, 1, ad.[dates] )
FROM allDates AS ad
WHERE ad.[dates] < #MaxDate
)
SELECT
ISNULL([MessageType].[Name],0) AS [Channel],
dates AS [Time],
COUNT([MessageType].[Name]) AS [Count]
FROM
(
SELECT dates
FROM allDates
) AS T
LEFT JOIN
#table1 ON T.dates=CONVERT(VARCHAR(11), #table1.[OccuredAtUtc], 106)
LEFT JOIN #table2 ON ... = ...
GROUP BY dates,
[MessageType].[Name]
ORDER BY [Time] ASC

Answer 2

You can use something like a Tally table to generate all dates between certain time interval.
SELECT
ISNULL([MessageType].[Name],0) AS [Channel],
dates AS [Time],
COUNT([MessageType].[Name]) AS [Count]
FROM
(
SELECT
TOP (DATEDIFF(d,'2017-04-24','2017-04-30')+1)
DATEADD(d,ROW_NUMBER() OVER( ORDER BY (SELECT 1))-1,'2017-04-24') dates
FROM sys.objects a CROSS JOIN sys.objects b
)T
LEFT JOIN
#table1 ON T.dates=CONVERT(VARCHAR(11), #table1.[OccuredAtUtc], 106)
LEFT JOIN #table2 ON ... = ...
AND ( [OccuredAtUtc] > '2017-04-24'
AND [OccuredAtUtc] < '2017-04-30' )
GROUP BY dates,
[MessageType].[Name]
ORDER BY [Time] ASC
For more explanation on Tally tables please read this article

Answer 3

declare #t table ( i int identity , b bit, d as dateadd (dd, i - 1, 0 ))
insert into #t (b)
VALUES (0),(0),(0),(0),(0),(0),(0),(0),(0)
insert into #t (b)
select 0
from #t t1
cross apply ( select b from #t) as t2
cross apply ( select b from #t) as t3
cross apply ( select b from #t) as t4
cross apply ( select b from #t) as t5
select t.d, isnull(y.channel,0), count(y.[date])
from #t t
left join yourtable y on y.[date] = t.d
where d between getdate() - 30 and getdate()
group by t.d, isnull(y.channel,0)