Select rows with same ID/email but different value in other table - sql

Question

Select rows with same ID/email but different value in other table
I have two tables: person and email, now there are mail addresses that have the same value, and persons/ID with different values.
Can anyone tell how to write an SQL query for this? I have tried but I can't figure it out. I have found some answers but then it is always finding the match in the same table
Like this
Table_person. ​​Table_email
1​​​ email#persoon1
2​​​ email#persoon2
3​​​ email#persoon3
4​​​ email#persoon1
5​​​ email#persoon5
6​​​ email#persoon2
The output should be
Table_person​​ Table_email
1​​​ email#persoon1
4​​​ email#persoon1
2​​​ email#persoon2
6​​​ email#persoon2

Answer 1

Using a common table expression with row_number()
;with cte as (
select *
, rn = row_number() over (partition by email order by person_id)
from email e
)
select *
from cte
where exists (
select 1
from cte i
where i.email = cte.email
and rn > 1
)
or using exists()
select *
from email e
where exists (
select 1
from email i
where i.email = e.email
and i.person_id <> e.person_id
)
rextester demo: http://rextester.com/JHFEF82373

Answer 2

Hope it will helps you
;with cte(Table_person,​​Table_email)
AS
(
SELECT 1​​​,'email#persoon1' UNION ALL
SELECT 2​​​,'email#persoon2' UNION ALL
SELECT 3​​​,'email#persoon3' UNION ALL
SELECT 4​​​,'email#persoon1' UNION ALL
SELECT 5​​​,'email#persoon5' UNION ALL
SELECT 6​​​,'email#persoon2'
)
,Cte2
AS
(
SELECT Table_person,​​Table_email From
(
Select Table_person,​​Table_email,ROW_NUMBER()OVER(Partition by Table_email Order By Table_person )Seq
from cte
)dt WHERE dt.Seq>1
)
,Final
AS
(
SELECT Table_person,​​Table_email From
(
Select Table_person,​​Table_email,ROW_NUMBER()OVER(Partition by Table_email Order By Table_email )Seq2
from cte
)dt
where dt.Seq2>1
Union ALL
SELECT Table_person,​​Table_email From cte2
)
SELECt Table_person,​​Table_email from Final