Displaying multiple select in a single cell - sql

Question

Please help me to solve the following issue .
consider i have two tables in a Database
1.employee 2.Details
In employee table data will be
eid ename level
1 x 9th
2 y 10th
In Address Table data will be
AId eid location Adreess_type
1 1 india permananet
2 1 US Temporary
3 2 Japan permananet
4 2 China Temporary
I need output in the below format
eid ename fulllocation
1 X INDIA -US
2 y Japan-CHINA

Answer 1

Try this:
SELECT
e.eid,
e.name,
GROUP_CONCAT(a.location SEPARATOR '-') AS fulllocation
FROM
employee as e
INNER JOIN address as a
ON e.eid = a.eid
GROUP BY
e.eid

Answer 2

select employee.eid, employee.ename, t.fulllocation
from employee
inner join (select eid, group_concat(location SEPARATOR '-') as fulllocation from Address group by eid) t
on employee.eid = t.eid
Consider that GROUP_CONCAT have some limitations, what is this and how can change (if needed) it? please check documentation for this.

Answer 3

DECLARE #t1 TABLE
(
eid int NOT NULL,
ename varchar(50),
level varchar(50)
)
DECLARE #t2 TABLE
(
aid int NOT NULL,
eid int,
location varchar(50),
address_type varchar(50)
)
INSERT INTO #t1 SELECT 1, 'x', '9th'
INSERT INTO #t1 SELECT 2, 'y', '10th'
INSERT INTO #t2 SELECT 1, 1, 'india', 'permanent'
INSERT INTO #t2 SELECT 2, 1, 'US', 'temporary'
INSERT INTO #t2 SELECT 3, 2, 'Japan', 'permanent'
INSERT INTO #t2 SELECT 4, 2, 'China', 'temporary'
SELECT * FROM #t1
SELECT * FROM #t2
SELECT t1.eid, t1.ename, t2.fullLocation
FROM #t1 AS t1
INNER JOIN (
SELECT eid, COUNT(*) AS noofrecs
, fullLocation = LTRIM(RTRIM(ISNULL(STUFF(
(
SELECT DISTINCT '-' + CAST(t2.location as nvarchar(max))
FROM #t2 t2
WHERE t1.eid = t2.eid
FOR XML PATH (''), TYPE).value('.', 'nvarchar(max)'
), 1, 1, ''), '')))
FROM #t2 as t1
GROUP BY eid
) AS t2
ON t1.eid = t2.eid

Answer 4

DECLARE #t1 TABLE
(
eid int NOT NULL,
ename varchar(50),
level varchar(50)
)
DECLARE #t2 TABLE
(
aid int NOT NULL,
eid int,
location varchar(50),
address_type varchar(50)
)
INSERT INTO #t1 SELECT 1, 'x', '9th'
INSERT INTO #t1 SELECT 2, 'y', '10th'
INSERT INTO #t2 SELECT 1, 1, 'india', 'permanent'
INSERT INTO #t2 SELECT 2, 1, 'US', 'temporary'
INSERT INTO #t2 SELECT 3, 2, 'Japan', 'permanent'
INSERT INTO #t2 SELECT 4, 2, 'China', 'temporary'
SELECT * FROM #t1
SELECT * FROM #t2
SELECT b.eid,b.ename
, STUFF((SELECT '_ ' + a.location FROM #t2 A
Where A.eid=B.eid FOR XML PATH('')),1,1,'') As fulllocation
From #t1 B
Group By b.eid,b.ename

Answer 5

In order to preserve the order of the locations, you could work along
SELECT
e.eid
, e.ename
, CONCAT_WS('-', p.location, t.location) AS fulllocation
FROM Employee e
JOIN Address p
ON e.eid = p.eid
AND p.address_type = 'permananet'
JOIN Address t
ON e.eid = t.eid
AND t.address_type = 'Temporary'
;
See it in action: SQL Fiddle.
Please comment if and as this requrires adjustment / further detail.