This is the result of a query.
It is a calendar in essence.
I want to set the start date and for the date field to be populated with a running list of Dates as in the below example. starting with a date I declare (In the example this is set as 2017-04-29)
Order is the order in which the Item is to be made.
Days is the number of days that item has been worked on (first day returns 1, second day: 2, and so on).
It is currently ordered by 'order' column then 'days' column
Current Output
Date Item Order Days
Null WP-1 1 1
Null SP1 2 1
Null SP1 2 2
Null WP-2 3 1
Desired Output
Date Item Order Days
2017-04-29 WP-1 1 1
2017-04-30 SP1 2 1
2017-05-01 SP1 2 2
2017-05-02 WP-2 3 1
I do have 'numbers' and 'dates' tables if they help
This is for SQL Server 2008
Thanks
Use row_number and add it to the specified start date.
declare #startdate date;
set #startdate = '2017-04-29';
select dateadd(day, row_number() over(order by [order],days)-1, #startdate) as [date],
item,[order],days
from yourtable
Related
I'm trying to get detailed data (snapshot) for each month on Business Day=1 for the last 6 months and need to pass 6 different dates (BD1's only) through two date variables.
Two variables will be BOM which will be BD1 for the last 6 months and EOM which will be BD1+1.
For e.g
First snapshot will be
declare #BOM date ='2022-08-01'
declare #EOM date ='2022-09-01'
Second snapshot will be
declare #BOM date ='2022-09-01'
declare #EOM date ='2022-10-01'
and so on for the last 6 months from the current month
Here is what I'm trying to do:
declare #BOM date
set #BOM=
(
select top 6 cast(date_datetime as date) date_datetime
from date_dim
where
datediff(month, date_datetime, getdate()) <= 6
and bd=1
order by date_datetime asc);
declare #EOM date
set #EOM=
(
select top 6 date_datetime
from date_dim
where
datediff(month, date_datetime, getdate()) <= 5
and bd=1
order by date_datetime asc);
But my query does not process it as I'm passing more than 1 value through my BOM & EOM variables in my main query WHERE clause.
I need some help with defining and using these variables in my query so that they can take different snapshots and store it in a table.
As you discovered, you cannot store multiple values in a scalar variable. What you possibly need is to use a table variable (which behaves similarly to a temp table). The table variable can have multiple rows (one for each selected month) and multiple columns (BOM and EOM).
The following code defines such a table variable and populates it with BOM and EOM of the most recent 6 full months from the date_dim table. I used the LEAD() window function to select the corresponding EOM for each BOM.
Lacking any provided sample data to actually query, I added a simple query at the end to just list the selected date ranges and calculated number of business days in each.
-- Table variable to hold selected month information
DECLARE #selected_months TABLE (BOM DATE, EOM DATE)
-- Select last 6 full months
INSERT #selected_months
SELECT *
FROM (
SELECT
date_datetime AS BOM,
LEAD(date_datetime) OVER(ORDER BY date_datetime) AS EOM
FROM date_dim
) D
WHERE DATEDIFF(month, BOM, GETDATE()) BETWEEN 1 AND 6
ORDER BY BOM
-- Sample usage
SELECT M.*, DATEDIFF(day, M.BOM, M.EOM) business_days
FROM #selected_months M
-- JOIN your_data D
-- ON D.your_data_date >= SM.BOM
-- AND D.your_data_date < SM.EOM
GROUP BY M.BOM, M.EOM
ORDER BY M.BOM
Sample results:
BOM
EOM
business_days
2022-08-01
2022-09-05
35
2022-09-05
2022-10-03
28
2022-10-03
2022-11-07
35
2022-11-07
2022-12-05
28
2022-12-05
2023-01-02
28
2023-01-02
2023-02-06
35
See this db<>fiddle for a working demo.
If you have table like this:
Name
Data type
UserID
INT
StartDate
DATETIME
EndDate
DATETIME
With data like this:
UserID
StartDate
EndDate
21
2021-01-02 00:00:00
2021-01-02 23:59:59
21
2021-01-03 00:00:00
2021-01-04 15:42:00
24
2021-01-02 00:00:00
2021-01-06 23:59:59
And you want to calculate number of users that is represented on each day in a week with a result like this:
Year
Week
NumberOfTimes
2021
1
8
2021
2
10
2021
3
4
Basically I want to to a Select like this:
SELECT YEAR(dateColumn) AS yearname, WEEK(dateColumn)as week name, COUNT(somecolumen)
GROUP BY YEAR(dateColumn) WEEK(dateColumn)
The problem I have is the start and end date if the date goes over several days I want it to counted each day. Preferably I don't want the same user counted twice each day. There are millions of rows that are constantly being deleted and added so speed is key.
The database is MS-SQL 2019
I would suggest a recursive CTE:
with cte as (
select userid, startdate, enddate
from t
union all
select userid, startdate,
enddate
from cte
where startdate < enddate and
week(startdate) <> week(enddate)
)
select year(startdate), week(startdate), count(*)
from cte
group by year(startdate), week(startdate)
option (maxrecursion 0);
The CTE expands the data by adding 7 days to each row. This should be one day per week.
There is a little logic in the second part to handle the situation where the enddate ends in the same week as the last start date. The above solution assumes that the dates are all in the same year -- which seems quite reasonable given the sample data. There are other ways to prevent this problem.
You need to cross-join each row with the relevant dates.
Create a calendar table with columns of years and weeks, include a start and end date of the week. See here for an example of how to create one, and make sure you index those columns.
Then you can cross-join like this
SELECT
YEAR(dateColumn) AS yearname,
WEEK(dateColumn)as weekname,
COUNT(somecolumen)
FROM Table t
JOIN CalendarWeek c ON c.StartDate >= t.StartDate AND c.EndDate <= t.EndDate
GROUP BY YEAR(dateColumn), WEEK(dateColumn)
I'm having list of records with a column EffectiveOn in SQL Server database table. I want to fetch the currently applicable EffectiveOn respective to current date. Consider the following table
Id Data EffectiveOn
_____________________________________
1 abc 2020-04-28
2 xyz 2020-08-05
3 dhd 2020-10-30
4 ert 2020-12-28
5 lkj 2021-03-19
In the above table I have to fetch the record (Id: 3) because the current date (i.e., today) is 2020-11-19
Expected Resultset
Id Data EffectiveOn
_____________________________________
3 dhd 2020-10-30
I tried the following solution but I can't How do I get the current records based on it's Effective Date?
Kindly assist me how to get the expected result-set.
You can do:
select top (1) *
from mytable t
where effectiveon <= convert(date, getdate())
order by effectiveon desc
This selects the greatest date before today (or today, if available).
You can try using Row_number function
select id, data, effectiveon
(
select ROW_NUMBER()over(order by effectiveon desc )sno,* from #table
where effectiveon < cast(getdate() as date)
)a where sno=1
Using SQL I need to return a smooth set of results (i.e. one per day) from a dataset that contains 0-N records per day.
The result per day should be the most recent previous value even if that is not from the same day. For example:
Starting data:
Date: Time: Value
19/3/2014 10:01 5
19/3/2014 11:08 3
19/3/2014 17:19 6
20/3/2014 09:11 4
22/3/2014 14:01 5
Required output:
Date: Value
19/3/2014 6
20/3/2014 4
21/3/2014 4
22/3/2014 5
First you need to complete the date range and fill in the missing dates (21/3/2014 in you example). This can be done by either joining a calendar table if you have one, or by using a recursive common table expression to generate the complete sequence on the fly.
When you have the complete sequence of dates finding the max value for the date, or from the latest previous non-null row becomes easy. In this query I use a correlated subquery to do it.
with cte as (
select min(date) date, max(date) max_date from your_table
union all
select dateadd(day, 1, date) date, max_date
from cte
where date < max_date
)
select
c.date,
(
select top 1 max(value) from your_table
where date <= c.date group by date order by date desc
) value
from cte c
order by c.date;
May be this works but try and let me know
select date, value from test where (time,date) in (select max(time),date from test group by date);
I have a rollup table that sums up raw data for a given hour. It looks something like this:
stats_hours:
- obj_id : integer
- start_at : datetime
- count : integer
The obj_id points to a separate table, the start_at field contains a timestamp for the beginning of the hour of the data, and the count contains the sum of the data for that hour.
I would like to build a query that returns a set of data per day, so something like this:
Date | sum_count
2014-06-01 | 2000
2014-06-02 | 3000
2014-06-03 | 0
2014-06-04 | 5000
The query that I built does a grouping on the date column and sums up the count:
SELECT date(start_at) as date, sum(count) as sum_count
FROM stats_hours GROUP BY date;
This works fine unless I have no data for a given date, in which case it obviously leaves out the row:
Date | sum_count
2014-06-01 | 2000
2014-06-02 | 3000
2014-06-04 | 5000
Does anyone know of a good way in SQL to return a zeroed-out row in the case that there is no data for a given date group? Maybe some kind of case statement?
You need a full list of dates first, then connect that list to your available dates and group by that. Try the following:
--define start and end limits
Declare #todate datetime, #fromdate datetime
Select #fromdate='2009-03-01', #todate='2014-06-04'
;With DateSequence( Date ) as
(
Select #fromdate as Date
union all
Select dateadd(day, 1, Date)
from DateSequence
where Date < #todate
)
--select result
SELECT DateSequence.Date, SUM(Stats_Hours.Count) AS Sum_Count
FROM
DateSequence
LEFT JOIN
Stats_Hours ON DateSequence.Date = Stats_Hours.Start_At
GROUP BY DateSequence.Date
option (MaxRecursion 0)
EDIT: CTE code from this post