Splitting single row into more columns based on column value - sql

Question

I've a requirement to get 3 similar set of row data replacing the column value if any certain value exists in the given column('[#]' in this case). For example
---------------------
Type Value
---------------------
1 Apple[#]
2 Orange
3 Peach[#]
I need to modify the query to get value as below
----------------------
Type Value
--------------------
1 Apple1
1 Apple2
1 Apple3
2 Orange
3 Peach1
3 Peach2
3 Peach3
I could not come up with logic how to get this

Answer 1

You can also get the same result without recursivity :
select Type, Value from MyTable where Right(Value, 3) <> '[#]'
union
select Type, Replace(Value, '[#]', '1') from MyTable where Right(Value, 3) = '[#]'
union
select Type, Replace(Value, '[#]', '2') from MyTable where Right(Value, 3) = '[#]'
union
select Type, Replace(Value, '[#]', '3') from MyTable where Right(Value, 3) = '[#]'
order by 1, 2

Answer 2

Assuming there is only one digit (as in your example), then I would go for:
with cte as (
select (case when value like '%\[%%' then left(right(value, 2), 1) + 0
else 1
end) as cnt, 1 as n,
left(value, charindex('[', value + '[')) as base, type
from t
union all
select cnt, n + 1, base, type
from cte
where n + 1 <= cnt
)
select type,
(case when cnt = 1 then base else concat(base, n) end) as value
from cte;
Of course, the CTE can be easily extended to any number of digits:
(case when value like '%\[%%'
then stuff(left(value, charindex(']')), 1, charindex(value, '['), '') + 0
else 1
end)
And once you have the number, you can use another source of numbers. But the recursive CTE seems like the simplest solution for the particular problem in the question.

Answer 3

Try this query
DECLARE #SampleData AS TABLE
(
Type int,
Value varchar(100)
)
INSERT INTO #SampleData
VALUES (1, 'Apple[#]'), (2, 'Orange'), (3, 'Peach[#]')
SELECT sd.Type, cr.Value
FROM #SampleData sd
CROSS APPLY
(
SELECT TOP (IIF(Charindex('[#]', sd.Value) > 0, 3, 1))
x.[Value] + Cast(v.t as nvarchar(5)) as Value
FROM
(SELECT Replace(sd.Value, '[#]', '') AS Value) x
Cross JOIN (VALUES (1),(2),(3)) v(t)
Order by v.t asc
) cr
Demo link: Rextester

Answer 4

Using a recursive CTE
CREATE TABLE #test
(
Type int,
Value varchar(50)
)
INSERT INTO #test VALUES
(1, 'Apple[#]'),
(2, 'Orange'),
(3, 'Peach[#]');
WITH CTE AS (
SELECT
Type,
IIF(RIGHT(Value, 3) = '[#]', LEFT(Value, LEN(Value) - 3), Value) AS 'Value',
IIF(RIGHT(Value, 3) = '[#]', 1, NULL) AS 'Counter'
FROM
#test
UNION ALL
SELECT
B.Type,
LEFT(B.Value, LEN(B.Value) - 3) AS 'Value',
Counter + 1
FROM
#test AS B
JOIN CTE
ON B.Type = CTE.Type
WHERE
RIGHT(B.Value, 3) = '[#]'
AND Counter < 3
)
SELECT
Type,
CONCAT(Value, Counter) AS 'Value'
FROM
CTE
ORDER BY
Type,
Value
DROP TABLE #test