I'm adding dates to my database but the issue is that they're a day behind. The data isn't too sensitive so simply adding a day will work. I'm not super familiar with SQL Server and have already searched trying to find how to add a day to a UNIX timestamp.
I simply wanna add a day to my timestamp. For example: 1492560000 is for yesterday and needs to be for today.
Any help would be great, thanks!
As stated in the comments, you can add 60*60*24 for adding a a day. If you want to be able to add additional date parts without mathing it, you can convert the unix timestamp to a SQL one, use dateadd, and then convert it back.
declare #date datetime = getutcdate()
declare #unixstartdate datetime = '1970-01-01'
declare #unixdate int = datediff(second, #unixstartdate, #date)
--Add datepart to unix
select
datediff(second, #unixstartdate, dateadd(/*date part you are adding*/day, /*number of dateparts to add*/1, dateadd(second, #unixdate, #unixstartdate)))
--Here's how we got there
select
#unixdate AS [current_unix_date]
,dateadd(second, #unixdate, #unixstartdate) AS [sql_datetime] --Convert the unix timestamp to a sql datetime.
,dateadd(day, 1, dateadd(second, #unixdate, #unixstartdate)) AS [updated_sql_datetime] --Add your dayparts. Here we add 1 day.
,datediff(second, #unixstartdate, dateadd(day, 1, dateadd(second, #unixdate, #unixstartdate))) --Convert the updated sql datetime back to unix.
Related
How would I be able to extract the time part of a DateTime field in SQL? For my project I have to return data that has a timestamp of 5pm of a DateTime field no matter what the date is
This will return the time-Only
For SQL Server:
SELECT convert(varchar(8), getdate(), 108)
Explanation:
getDate() is giving current date and time.
108 is formatting/giving us the required portion i.e time in this case.
varchar(8) gives us the number of characters from that portion.
Like:
If you wrote varchar(7) there, it will give you 00:00:0
If you wrote varchar(6) there, it will give you 00:00:
If you wrote varchar(15) there, it will still give you 00:00:00 because it is giving output of just time portion.
SQLFiddle Demo
For MySQL:
SELECT DATE_FORMAT(NOW(), '%H:%i:%s')
SQLFiddle Demo
In SQL Server if you need only the hh:mi, you can use:
DECLARE #datetime datetime
SELECT #datetime = GETDATE()
SELECT RIGHT('0'+CAST(DATEPART(hour, #datetime) as varchar(2)),2) + ':' +
RIGHT('0'+CAST(DATEPART(minute, #datetime)as varchar(2)),2)
If you want only the hour of your datetime, then you can use DATEPART() - SQL Server:
declare #dt datetime
set #dt = '2012-09-10 08:25:53'
select datepart(hour, #dt) -- returns 8
In SQL Server 2008+ you can CAST() as time:
declare #dt datetime
set #dt = '2012-09-10 08:25:53'
select CAST(#dt as time) -- returns 08:25:53
I know this is an old question, but since the other answers all
return strings (rather than datetimes),
rely on the internal representation of dates (conversion to float, int, and back) or
require SQL Server 2008 or beyond,
I thought I'd add a "pure" option which only requires datetime operations and works with SQL Server 2005+:
SELECT DATEADD(dd, -DATEDIFF(dd, 0, mydatetime), mydatetime)
This calculates the difference (in whole days) between date zero (1900-01-01) and the given date and then subtracts that number of days from the given date, thereby setting its date component to zero.
Try this in SQL Server 2008:
select *
from some_table t
where convert(time,t.some_datetime_column) = '5pm'
If you want take a random datetime value and adjust it so the time component is 5pm, then in SQL Server 2008 there are a number of ways. First you need start-of-day (e.g., 2011-09-30 00:00:00.000).
One technique that works for all versions of Microsoft SQL Server as well as all versions of Sybase is to use convert/3 to convert the datetime value to a varchar that lacks a time component and then back into a datetime value:
select convert(datetime,convert(varchar,current_timestamp,112),112)
The above gives you start-of-day for the current day.
In SQL Server 2008, though, you can say something like this:
select start_of_day = t.some_datetime_column
- convert(time, t.some_datetime_column ) ,
from some_table t
which is likely faster.
Once you have start-of-day, getting to 5pm is easy. Just add 17 hours to your start-of-day value:
select five_pm = dateadd(hour,17, t.some_datetime_column
- convert(time,t.some_datetime_column)
)
from some_table t
Note that from MS SQL 2012 onwards you can use FORMAT(value,'format')
e.g. WHERE FORMAT(YourDatetime,'HH:mm') = '17:00'
"For my project, I have to return data that has a timestamp of 5pm of a DateTime field, No matter what the date is."
So I think what you meant was that you needed the date, not the time. You can do something like this to get a date with 5:00 as the time:
SELECT CONVERT(VARCHAR(10), GetDate(), 110) + ' 05:00:00'
This should strip away the date part:
select convert(datetime,convert(float, getdate()) - convert(int,getdate())), getdate()
and return a datetime with a default date of 1900-01-01.
you can use CONVERT(TIME,GETDATE()) in this case:
INSERT INTO infoTbl
(itDate, itTime)
VALUES (GETDATE(),CONVERT(TIME,GETDATE()))
or if you want print it or return that time use like this:
DECLARE #dt TIME
SET #dt = CONVERT(TIME,GETDATE())
PRINT #dt
select cast(getdate() as time(0))
returns for example :- 15:19:43
replace getdate() with the date time you want to extract just time from!
SELECT DISTINCT
CONVERT(VARCHAR(17), A.SOURCE_DEPARTURE_TIME, 108)
FROM
CONSOLIDATED_LIST AS A
WHERE
CONVERT(VARCHAR(17), A.SOURCE_DEPARTURE_TIME, 108) BETWEEN '15:00:00' AND '15:45:00'
declare #datetime as datetime
set #datetime = getdate()
select cast(cast(#datetime as time) as varchar(8))
For year:
SELECT DATEPART(YEAR, '2021-03-21' );
For hour:
SELECT DATEPART(HOUR, '2021-03-21 08:50:30' );
I'm having a bit of trouble with truncating data. I'm using SQL's GETDATE() function to get the current date and time and enter them into a database. However, I only want to save the date and time up until the minute. In other words, I want dd/mm/yyyy hh:mm:00.000 or dd/mm/yyyy hh:mm to be saved when I input new data. How can I go about doing this?
I should note I'm using MS-SQL.
There are a number of ways to go about doing this.
For example, you could convert the generated datetime from GetDate() to a smalldatetime first, à la:
CAST(GetDate() AS smalldatetime)
To be clear, this will round the generated seconds up (or down) to the nearest minute depending up the value of the current second.
EDIT:
Alternatively, you can have SQL Server truncate a datetime for you for a "cleaner" (READ: no rounding, since the value is pre-truncated) conversion to smalldatetime:
CAST(DateAdd(minute, DateDiff(minute, 0, GetDate()), 0) AS smalldatetime)
For truncation:
SELECT SMALLDATETIMEFROMPARTS(
datepart(year ,dt)
,datepart(month ,dt)
,datepart(day ,dt)
,datepart(hour ,dt)
,datepart(minute,dt)
)
FROM (SELECT GETDATE()) t(dt)
One way is to convert it to smalldatetime for the assignment (and back as needed).
smalldatetime always has seconds and beyond set to 00.
SELECT CONVERT(smalldatetime, GETDATE())
As this may round up or down, another way to safely truncate the seconds would be this:
SELECT CONVERT(datetime, CONVERT(nchar(16), GETDATE(), 120), 120)
The conversion code 120 returns the format yyyy-mm-dd hh:mi:ss.
Combine DATEADD and SMALLDATETIME to truncate
CAST(DATEADD(S, -30, dt) AS SMALLDATETIME)
The other option is not sure why you cannot consider the front-end instead of the back-end so don't change the SQL and thus format in the front-end as dd/MM/yyyy HH:mm or whatever format you need if that is doable or appropriate in the context of what you are trying to achieve. For example in an SSRS report you could format the field in question in the report designer or use the Format function. If it is a webpage or Excel I am sure you could also do something similar.
Ii have values stored in the SQL Server in the following manner : 02-Jul-12 12:00:00 AM here the time and minutes, seconds can be anything like 02-Jul-12 12:15:52 PM ,02-Jul-12 6:02:12 AM so on.
I want to have a where condition which will omit the time and take the data based on the date like the following where some_Date='02-Jul-12'
How would I do this?
SELECT * FROM whatever WHERE some_Date LIKE '02-Jul-12%';
If you are on SQL2008 or later, you can cast your DATETIME to DATE.
See this post: http://blog.sqlauthority.com/2012/09/12/sql-server-get-date-and-time-from-current-datetime-sql-in-sixty-seconds-025-video/
But in a WHERE-clause it is better to search between dates, like this:
DECLARE #startDate DATETIME = '02-Jul-2012'
DECLARE #endDate DATETIME = DATEADD(DAY, 1, #startDate)
SELECT * FROM [table] WHERE [some_Date] BETWEEN #startDate AND #endDate
SELECT * FROM dbo.tbl_MyTable
WHERE
REPLACE(CONVERT(VARCHAR(9), DateTimeValueColumn, 6), ' ', '-')='02-Jul-12'
or
On chage in code is instead of using getdate function voncert you datestring in datetime format and do compare this follow query will work for you
SELECT * FROM dbo.tbl_MyTable
WHERE
CAST(CONVERT(CHAR(10), DateTimeValueColumn, 102) AS DATE) =
CAST(CONVERT(CHAR(10),GETDATE(),102) AS DATE)
If you are storing dates as characters -- which is not recommended -- you should at least use ISO format: YYYY-MM-DD hh:mm:ss. This makes the date useful for sorting and comparisons ("<" works, ">" works, "between" works as well as equals).
To extract the date, you can then use left(datestr, 10). In your format, you would use:
where left(datestr, 9) = '01-Jan-13'
If you are storing the fields as a datetime or smalldatetime, you may think they are stored as a string. They are not. They are stored as some number of days since some particular date, with day parts stored as fractional days. If you are using SQL Server 2005 or greater, then the best way is:
where cast(datetime as date) = '2013-01-01' -- I recommend ISO formats, even for constants. '20130101' is even better
To select rows with today's date (not time)
select * from myTable where datediff(dd, dateColumn, getdate()) = 0
How would I be able to extract the time part of a DateTime field in SQL? For my project I have to return data that has a timestamp of 5pm of a DateTime field no matter what the date is
This will return the time-Only
For SQL Server:
SELECT convert(varchar(8), getdate(), 108)
Explanation:
getDate() is giving current date and time.
108 is formatting/giving us the required portion i.e time in this case.
varchar(8) gives us the number of characters from that portion.
Like:
If you wrote varchar(7) there, it will give you 00:00:0
If you wrote varchar(6) there, it will give you 00:00:
If you wrote varchar(15) there, it will still give you 00:00:00 because it is giving output of just time portion.
SQLFiddle Demo
For MySQL:
SELECT DATE_FORMAT(NOW(), '%H:%i:%s')
SQLFiddle Demo
In SQL Server if you need only the hh:mi, you can use:
DECLARE #datetime datetime
SELECT #datetime = GETDATE()
SELECT RIGHT('0'+CAST(DATEPART(hour, #datetime) as varchar(2)),2) + ':' +
RIGHT('0'+CAST(DATEPART(minute, #datetime)as varchar(2)),2)
If you want only the hour of your datetime, then you can use DATEPART() - SQL Server:
declare #dt datetime
set #dt = '2012-09-10 08:25:53'
select datepart(hour, #dt) -- returns 8
In SQL Server 2008+ you can CAST() as time:
declare #dt datetime
set #dt = '2012-09-10 08:25:53'
select CAST(#dt as time) -- returns 08:25:53
I know this is an old question, but since the other answers all
return strings (rather than datetimes),
rely on the internal representation of dates (conversion to float, int, and back) or
require SQL Server 2008 or beyond,
I thought I'd add a "pure" option which only requires datetime operations and works with SQL Server 2005+:
SELECT DATEADD(dd, -DATEDIFF(dd, 0, mydatetime), mydatetime)
This calculates the difference (in whole days) between date zero (1900-01-01) and the given date and then subtracts that number of days from the given date, thereby setting its date component to zero.
Try this in SQL Server 2008:
select *
from some_table t
where convert(time,t.some_datetime_column) = '5pm'
If you want take a random datetime value and adjust it so the time component is 5pm, then in SQL Server 2008 there are a number of ways. First you need start-of-day (e.g., 2011-09-30 00:00:00.000).
One technique that works for all versions of Microsoft SQL Server as well as all versions of Sybase is to use convert/3 to convert the datetime value to a varchar that lacks a time component and then back into a datetime value:
select convert(datetime,convert(varchar,current_timestamp,112),112)
The above gives you start-of-day for the current day.
In SQL Server 2008, though, you can say something like this:
select start_of_day = t.some_datetime_column
- convert(time, t.some_datetime_column ) ,
from some_table t
which is likely faster.
Once you have start-of-day, getting to 5pm is easy. Just add 17 hours to your start-of-day value:
select five_pm = dateadd(hour,17, t.some_datetime_column
- convert(time,t.some_datetime_column)
)
from some_table t
Note that from MS SQL 2012 onwards you can use FORMAT(value,'format')
e.g. WHERE FORMAT(YourDatetime,'HH:mm') = '17:00'
"For my project, I have to return data that has a timestamp of 5pm of a DateTime field, No matter what the date is."
So I think what you meant was that you needed the date, not the time. You can do something like this to get a date with 5:00 as the time:
SELECT CONVERT(VARCHAR(10), GetDate(), 110) + ' 05:00:00'
This should strip away the date part:
select convert(datetime,convert(float, getdate()) - convert(int,getdate())), getdate()
and return a datetime with a default date of 1900-01-01.
you can use CONVERT(TIME,GETDATE()) in this case:
INSERT INTO infoTbl
(itDate, itTime)
VALUES (GETDATE(),CONVERT(TIME,GETDATE()))
or if you want print it or return that time use like this:
DECLARE #dt TIME
SET #dt = CONVERT(TIME,GETDATE())
PRINT #dt
select cast(getdate() as time(0))
returns for example :- 15:19:43
replace getdate() with the date time you want to extract just time from!
SELECT DISTINCT
CONVERT(VARCHAR(17), A.SOURCE_DEPARTURE_TIME, 108)
FROM
CONSOLIDATED_LIST AS A
WHERE
CONVERT(VARCHAR(17), A.SOURCE_DEPARTURE_TIME, 108) BETWEEN '15:00:00' AND '15:45:00'
declare #datetime as datetime
set #datetime = getdate()
select cast(cast(#datetime as time) as varchar(8))
For year:
SELECT DATEPART(YEAR, '2021-03-21' );
For hour:
SELECT DATEPART(HOUR, '2021-03-21 08:50:30' );
I am running a select against a datetime column in SQL Server 2005. I can select only the date from this datetime column?
Best way is:
SELECT DATEADD(day, DATEDIFF(Day, 0, #ADate), 0)
This is because internally, SQL Server stores all dates as two integers, of which the first one is the ****number of days*** since 1 Jan 1900. (the second one is the time portion, stored as the number of seconds since Midnight. (seconds for SmallDateTimes, or milleseconds for DateTimes)
Using the above expression is better because it avoids all conversions, directly reading and accessing that first integer in a dates internal representation without having to perform any processing... the two zeroes in the above expression (which represent 1 Jan 1900), are also directly utilized w/o processing or conversion, because they match the SQL server internal representation of the date 1 jan 1900 exactly as presented (as an integer)..
*NOTE. Actually, the number of date boundaries (midnights) you have to cross to get from the one date to the other.
Yes, by using the convert function. For example:
select getdate(), convert(varchar(10),getdate(),120)
RESULTS:
----------------------- ----------
2010-05-21 13:43:23.117 2010-05-21
You can use the functions:
day(date)
month(date)
year(date)
Also the Datepart() function might be of some use:
http://msdn.microsoft.com/en-us/library/ms174420(SQL.90).aspx
DECLARE #dToday DATETIME
SET #dToday = CONVERT(nvarchar(20), GETDATE(), 101)
SELECT #dToday AS Today
This returns today's date at 12:00am : '2010-05-21 00:00:00.000'
Then you can use the #dToday variable in a query as needed
CONVERT (date, GETUTCDATE())
CONVERT (date, GETDATE())
CONVERT (date, '2022-18-01')
I don't know why the others recommend it with varchar(x) tbh.
https://learn.microsoft.com/de-de/sql/t-sql/functions/getdate-transact-sql