I have a bit of problem regarding sql select statement.
I have a column value that look like this
2>4>5 or
28>30>52 or
300>410>500 or
2>4>5>8
My question is, how can i get the value from RIGHT after the >
character, so the select statement from the value above will return
4
30
410
5
Thanks in advance
If you need second value from right, then try:
SELECT SUBSTRING_INDEX( SUBSTRING_INDEX(your_column, '>', -2), '>', 1);
EDIT
One solution for sql server:
DECLARE #str varchar(max);
set #str = '2>4>5>8';
SELECT reverse( substring(
substring( reverse(#str), charindex( '>', reverse(#str) )+1, len(#str) ), 0,
charindex( '>', substring( reverse(#str), charindex( '>', reverse(#str) )+1, len(#str) ) )
) );
This is similar to extracting the n-th element from a delimited string. The only difference is that in this case we want the n-th-to-last element. The change can be achieved with a double use of reverse. Assuming the table is MyTable and the field is MyColumn, here's one way:
SELECT
Reverse(
CAST('<x>' + REPLACE(Reverse(MyColumn),'>','</x><x>') + '</x>' AS XML).value('/x[2]', --x[2] because it's the second element in the reversed string
'varchar(5)' --Use something long enough to catch any number which might occur here
))
FROM
MyTable
With credit to #Shnugo for his efforts here: Using T-SQL, return nth delimited element from a string
You can't cast as an int where I've put varchar(5)since at that stage the strings are still reversed. If you need to convert to an integer, do that by wrapping a convert/cast on the outside.
;WITH cte1(Value)
AS
(
SELECT '2>4>5' Union all
SELECT '28>30>52' Union all
SELECT '300>410>500' Union all
SELECT '2>4>5>8'
)
SELECT
SUBSTRING(
(
REVERSE(SUBSTRING(((REVERSE((SUBSTRING(Value, RIGHT(CHARINDEX('>', Value), Len(Value)) + 1, Len(Value)))))),
CHARINDEX('>',((REVERSE((SUBSTRING(Value, RIGHT(CHARINDEX('>', Value), Len(Value)) + 1, Len(Value)))))))+1,LEN(Value)))
),CHARINDEX('>',(
REVERSE(SUBSTRING(((REVERSE((SUBSTRING(Value, RIGHT(CHARINDEX('>', Value), Len(Value)) + 1, Len(Value)))))),
CHARINDEX('>',((REVERSE((SUBSTRING(Value, RIGHT(CHARINDEX('>', Value), Len(Value)) + 1, Len(Value)))))))+1,LEN(Value)))
))+1,LEN(Value))
AS ExpectedValue
FROM cte1
Related
I have this data point:
455-U-202007302233,455-L-202007302233,422-U-202008011052,422-L-202008011052,857-U-202008041142,857-L-202008061215
Column: ,[t810str]
How would I be able to modify column [t810str] in order to pull out the last comma set before 857?
Desired Result = 422-L-202008011052
First you need to implement some kind of splitter that respects ordinal position (STRING_SPLIT does not). I'm therefore going to make use of DelimitedSplit8k_LEAD. Then you can split the value, and use LAG to get the prior value. Finally you can filter on where the item has a value LIKE '857%' but the previous does not:
WITH CTE AS(
SELECT DS.Item,
LAG(DS.Item) OVER (PARTITION BY YourColumn ORDER BY DS.itemNumber) AS PrevItem
FROM (VALUES('455-U-202007302233,455-L-202007302233,422-U-202008011052,422-L-202008011052,857-U-202008041142,857-L-202008061215'))V(YourColumn)
CROSS APPLY dbo.DelimitedSplit8K_LEAD(V.YourColumn,',') DS)
SELECT C.PrevItem
FROM CTE C
WHERE C.Item LIKE '857%'
AND C.PrevItem NOT LIKE '857%';
Based on your data and the assumption that items are 18 characters (your data do not indicate otherwise):
DECLARE #t AS NVARCHAR(255) = '455-U-202007302233,455-L-202007302233,422-U-202008011052,422-L-202008011052,857-U-202008041142,857-L-202008061215';
SELECT RIGHT(LEFT(#t,CHARINDEX(',857',#t)-1),18)
Using cross apply (which you can also rewrite using a CTE or a subquery for readability). This removes everything after first occurrence of 857 and then grabs the last set that's left. So even if you have multiple 857 and varying length of delimited strings, this should work
select *, right(remind , charindex (',' ,reverse(remind))-1)
from t t1
cross apply (select stuff(col, charindex(',857',col), len(col),'') as remind) t2
DEMO
Another solution use a recursive CTE
DECLARE #Var VARCHAR(200) = '455-U-202007302233,455-L-202007302233,422-U-202008011052,422-L-202008011052,857-U-202008041142,857-L-202008061215';
WITH CTE AS
(
SELECT 0 N, LEFT(#Var, CHARINDEX(',', #Var)-1) Part,
RIGHT(#Var, LEN(#Var) - CHARINDEX(',', #Var)) Remind
UNION ALL
SELECT N + 1,
LEFT(Remind, CHARINDEX(',', Remind) - 1),
RIGHT(Remind, LEN(Remind) - CHARINDEX(',', Remind))
FROM CTE
WHERE CHARINDEX(',', Remind) <> 0
)
SELECT TOP 1 Part
FROM CTE
WHERE LEFT(Remind, 3) = '857'
ORDER BY N;
Demo
Implemented with string functions (and assuming your data items can have variable length :-) it might look a bit confusing (therefore I'd prefer #Larnu's answer):
DECLARE #string VARCHAR(2000) = '455-U-202007302233,455-L-202007302233,422-U-202008011052,422-L-202008011052,857-U-202008041142,857-L-202008061215'
SELECT SUBSTRING(#string, CHARINDEX(',857',#string) - CHARINDEX(',', REVERSE( LEFT(#string, PATINDEX('%,857%',#string) - 1)) ) + 1, CHARINDEX(',', REVERSE( LEFT(#string, PATINDEX('%,857%',#string) - 1)))-1 )
Parts of the latter separated:
DECLARE #string VARCHAR(2000) = '455-U-202007302233,455-L-202007302233,422-U-202008011052,422-L-202008011052,857-U-202008041142,857-L-202008061215'SELECT CHARINDEX(',857',#string)
SELECT LEFT(#string, PATINDEX('%,857%',#string) - 1)
SELECT REVERSE( LEFT(#string, PATINDEX('%,857%',#string) - 1) )
SELECT CHARINDEX(',', REVERSE( LEFT(#string, PATINDEX('%,857%',#string) - 1)) )
I need to perform a substring operation in SQL Server and get a string from start of hyphen character (-).
My input string is :
'44345434595-E535-12349-5273-202003-16785'
and I want to extract the string from 4th instance of hyphen to 5th instance of hyphen and my desired result is : 202003
You can use string_split function in sqlserver
declare #str varchar(max)= '44345434595-E535-12349-5273-202003-16785'
select * from (select value, row_number() over (order by charindex('-' + value + '-', '-' + #str + '-')) rn
from string_split(#str, '-')) t1
where t1.rn in (5)
Since there's no guarantee of ordering using string_split function, we need to sort by position based on your -
row_number() over (order by charindex('-' + value + '-', '-' + #str + '-'))
If your input string has fixed format you can set position and lenght directly
SELECT SUBSTRING(yourColumn, 29, 5) FROM YourTable
If the Format is Fixed You can use Substring for that:
DECLARE #STR VARCHAR(100)
SELECT #STR='44345434595-E535-12349-5273-202003-16785'
SELECT SUBSTRING(#STR, 29, 6)
Output: 202003
Below is the code that might suit your requirement and will work if the input has exactly 5 hypen.
DECLARE #data varchar(50)= '44345434595-E535-12349-5273-202003-16785'
select
reverse(
SUBSTRING
(
SUBSTRING
(
reverse(#data),
charindex('-',reverse(#data),1)+1,
len(#data)
),
1,
charindex('-',SUBSTRING(reverse(#data),
charindex('-',reverse(#data),1)+1,
len(#data)))-1)
);
Basically what I am trying to do is that I want to get the middle word, using the second occurrence of the same character (on this case, dash "-").
This is the sample input:
declare #word nvarchar(max)
set #word = 'Technical Materials - Conversion - Team Dashboard'
There are three parts on this sentence, and they are divided by '-' dash line.
The first part is 'Technical Materials' which I am able to get using:
SELECT LTRIM(RTRIM(SUBSTRING(#word, 0, CHARINDEX('-', #word, 0))))
The last set was 'Team Dashboard' which I am able to get using:
SELECT CASE WHEN LEN(#word) - LEN(REPLACE(#word, '-', '')) = 1
THEN NULL
ELSE
RIGHT(#word,CHARINDEX('-', REVERSE(#word))-1)
END
The problem was, I am having a hard time getting the middle words which is 'Conversion' in this example.
If the format is fixed, you can use PARSENAME to achieve your expectation:
DECLARE #Word AS NVARCHAR(MAX) = 'Technical Materials - Conversion - Team Dashboard'
SELECT PARSENAME(REPLACE(#Word, '-', '.'), 2)
if you want to trim the extra spaces, then:
SELECT LTRIM(RTRIM(PARSENAME(REPLACE(#Word, '-', '.'), 2)))
Try this query:
SELECT
SUBSTRING(#word,
CHARINDEX('-', #word) + 2,
CHARINDEX('-', #word, CHARINDEX('-', #word) + 1) -
CHARINDEX('-', #word) - 3)
FROM yourTable
The general strategy here is to use SUBSTRING(), which requires the starting and ending positions of the middle string in question. We can use CHARINDEX to find both the first and second dash in the string. From this, we can compute the positions of the middle substring we want.
Demo here:
Rextester
This will find the text between the first 2 occurrences of '-'
DECLARE #word nvarchar(max)
SET #word = 'Technical Materials - Conversion - Team Dashboard'
SELECT SUBSTRING(x, 0, charindex('-', x))
FROM (values(stuff(#word, 1, charindex('-', #word), ''))) x(x)
This will find the middle element. In case of an even number of elements it will pick the first of the 2 middle elements
DECLARE #word nvarchar(max)
SET #word = 'Technical Materials - Conversion - Team Dashboard'
;WITH CTE(txt, rn, cnt) as
(
SELECT
t.c.value('.', 'VARCHAR(2000)'),
row_number() over (order by (select 1)), count(*) over()
FROM (
SELECT x = CAST('<t>' +
REPLACE(#word, ' - ', '</t><t>') + '</t>' AS XML)
) a
CROSS APPLY x.nodes('/t') t(c)
)
SELECT txt
FROM CTE
WHERE (cnt+1) / 2 = rn
This is my String
Declare #qstr as varchar(max)='hireteammember.aspx?empemail=kuldeep#asselsolutions.com&empid=376&empname=kuldeep&adminname=TMA1&term=5&teamid=161&contactid=614¥1&WP=100¥5¥Months&Amt=500&DueDay=5&StrDt=12/31/2013&MemCatg=Employees&StrTm=21:05&PlnHrs=5&WrkDays=true¥true¥true¥true¥true¥false¥false'
I want to extract the values of empid,empname,adminname,term,teamid,contactid,WP,Months,Dueday,StrDt,MemCatgmStrTm,PlnHrs,WrkDays and assign them to new variables
I have used
select ( SUBSTRING(#qstr,CHARINDEX('=',#qstr)+1,CHARINDEX('&',#qstr)-CHARINDEX('=',#qstr)-1)))
but only getting the 'empemail' , for the next occurance of special char '&' , not able to get the values of further terms , if i am using '&' in spite of '=' .
Help me to split the whole string
How about using XML to split the values into rows, and then splitting them into columns.
Something like
Declare #qstr as varchar(max)='hireteammember.aspx?empemail=kuldeep#asselsolutions.com&empid=376&empname=kuldeep&adminname=TMA1&term=5&teamid=161&contactid=614¥1&WP=100¥5¥Months&Amt=500&DueDay=5&StrDt=12/31/2013&MemCatg=Employees&StrTm=21:05&PlnHrs=5&WrkDays=true¥true¥true¥true¥true¥false¥false'
DECLARe #str VARCHAR(MAX) = SUBSTRING(#qstr,CHARINDEX('?',#qstr,0) + 1, LEN(#qstr)-CHARINDEX('?',#qstr,0))
DECLARE #xml XML
SELECT #xml = CAST('<d>' + REPLACE(#str, '&', '</d><d>') + '</d>' AS XML)
;WITH Vals AS (
SELECT T.split.value('.', 'nvarchar(max)') AS data
FROM #xml.nodes('/d') T(split)
)
SELECT LEFT(data,CHARINDEX('=',data,0) - 1),
RIGHT(data,LEN(data) - CHARINDEX('=',data,0))
FROM Vals
SQL Fiddle DEMO
CREATE FUNCTION dbo.SplitQueryString (#s varchar(8000))
RETURNS table
AS
RETURN (
WITH splitter_cte AS (
SELECT CHARINDEX('&', #s) as pos, 0 as lastPos
UNION ALL
SELECT CHARINDEX('&', #s, pos + 1), pos
FROM splitter_cte
WHERE pos > 0
),
pair_cte AS (
SELECT chunk,
CHARINDEX('=', chunk) as pos
FROM (
SELECT SUBSTRING(#s, lastPos + 1,
case when pos = 0 then 80000
else pos - lastPos -1 end) as chunk
FROM splitter_cte) as t1
)
SELECT substring(chunk, 0, pos) as keyName,
substring(chunk, pos+1, 8000) as keyValue
FROM pair_cte
)
GO
declare #queryString varchar(2048)
set #queryString = 'foo=bar&temp=baz&key=value';
SELECT *
FROM dbo.SplitQueryString(#queryString)
OPTION(MAXRECURSION 0);
when run produces the following output.
keyName keyValue
------- --------
foo bar
temp baz
key value
(3 row(s) affected)
I believe that this will do exactly what you are asking.
SQL FIDDLE DEMO
If the order of the values in the html string remains same i would suggest using the whole string name like
select ( SUBSTRING(#qstr,CHARINDEX('empemail=',#qstr)+1,CHARINDEX('&empid=',#qstr)-CHARINDEX('empemail=',#qstr)-1)))
If you are still looking for nth occurance then refer to this link
Declare #qstr as varchar(max)='hireteammember.aspx?empemail=kuldeep#asselsolutions.com&empid=376&empname=kuldeep&adminname=TMA1&term=5&teamid=161&contactid=614¥1&WP=100¥5¥Months&Amt=500&DueDay=5&StrDt=12/31/2013&MemCatg=Employees&StrTm=21:05&PlnHrs=5&WrkDays=true¥true¥true¥true¥true¥false¥false'
(select ( SUBSTRING(#qstr,CHARINDEX('&empname=',#qstr)+1,CHARINDEX('&adminname=',#qstr)-CHARINDEX('&empname=',#qstr)-1)))
(select ( SUBSTRING(#qstr,CHARINDEX('?empemail=',#qstr)+1,CHARINDEX('&empid=',#qstr)-CHARINDEX('?empemail=',#qstr)-1)))
like this i have splitted and updated The whole string. Thank you All for your answers, Your answers Helped me to solve this
I have a SQL statement,
select ColumnName from Table
And I get this result,
Error 192.168.1.67 UserName 0bce6c62-1efb-416d-bce5-71c3c8247b75 An existing ....
So anyway the field has a lot of stuff in it, I just want to get out the 'UserName'.
Can I use a regex for that?
I mean it would be kind of like this,
select SUBSTRING(ColumnName, 0, 5) from Table
Except the SUBSTRING would be replaced with a regex of some kind. I am comfortable with regex, but I am not sure how to apply it in this case, or even if you can.
If I could get this working it would be great because I plan to pull the data into a temporary table, and do some quite complicated things matching it with other tables etc. If I can get this all working it would save me writing a C# app to do it with.
Thanks.
No, out of the box, SQL Server doesn't support regexs.
You could retrofit those by means of a SQL-CLR assembly that you deploy into SQL Server.
I think going you should use SUBSTRING anyway. Using regular expression is more flexible but also lead to a large processing overhead. This becomes even worse if your have to process a large recordsets.
You have to justify if there's the need for flexibility in first place.
If so you should read about it here:
http://msdn.microsoft.com/en-us/magazine/cc163473.aspx
Using T-SQL only can look like that:
SELECT 'Error 192.168.1.67 XUserNameX 0bce6c62-1efb-416d-bce5-71c3c8247b75 An existing' expr
INTO log_table
GO
WITH
split1 (expr, cstart, cend)
AS (
SELECT
expr, 1, 0
FROM
log_table a
), split2 (expr, cstart, cend, div)
AS (
SELECT
a.expr, a.cend + 1, CHARINDEX(' ', a.expr, a.cend + 1), 1
FROM
split1 a
UNION ALL
SELECT
a.expr, a.cend + 1, CHARINDEX(' ', a.expr, a.cend + 1), div+1
FROM
split2 a
WHERE
a.cend > 1
), substrings(expr, div)
AS (
SELECT
SUBSTRING(expr, cstart, cend - cstart), div
FROM
split2
)
SELECT expr from
substrings a
where
a.div = 3
UPDATE
we cannot tell where the start of the
username is. Unless we can say 'find
me the start character after the
second space'
That is fairly straightforward:
Filter out strings that have fewer than
two spaces (alternatively, have three
or more words);
Find the position after the first
space (alternatively, the beginning
of the second word);
Find the position after the the first
space after the first space
(alternatively, the beginning of the
third word);
Determine the length of the third
word using the position of the next
space (or the end of the string is
there are only three words);
Use the above values with the
SUBSTRING() function to return the
third word.
Example:
WITH MyTable (ColumnName)
AS
(
SELECT NULL
UNION ALL
SELECT ''
UNION ALL
SELECT 'One.'
UNION ALL
SELECT 'Two words.'
UNION ALL
SELECT 'Three word sentence.'
UNION ALL
SELECT 'Sentence containing four words.'
UNION ALL
SELECT 'Five words in this sentence.'
UNION ALL
SELECT 'Sentence containing more than five words.'
),
AtLeastThreeWords (ColumnName, pos_word_2_start)
AS
(
SELECT M1.ColumnName, CHARINDEX(' ', M1.ColumnName) + LEN(' ') + 1
FROM MyTable AS M1
WHERE LEN(M1.ColumnName) - LEN(REPLACE(M1.ColumnName, ' ', '')) >= 2
),
MyTable2 (ColumnName, pos_word_3_start)
AS
(
SELECT M1.ColumnName,
CHARINDEX(' ', M1.ColumnName, pos_word_2_start) + LEN(' ') + 1
FROM AtLeastThreeWords AS M1
),
MyTable3 (ColumnName, pos_word_3_start, pos_word_3_end)
AS
(
SELECT M1.ColumnName, M1.pos_word_3_start,
CHARINDEX(' ', M1.ColumnName, pos_word_3_start) + LEN(' ')
FROM MyTable2 AS M1
),
MyTable4 (ColumnName, pos_word_3_start, word_3_length)
AS
(
SELECT M1.ColumnName, M1.pos_word_3_start,
CASE
WHEN pos_word_3_start < pos_word_3_end
THEN pos_word_3_end - pos_word_3_start
ELSE LEN(M1.ColumnName) - pos_word_3_start + 1
END
FROM MyTable3 AS M1
)
SELECT M1.ColumnName,
SUBSTRING(M1.ColumnName, pos_word_3_start, word_3_length)
AS word_3
FROM MyTable4 AS M1;
ORIGINAL ANSWER:
Is the problem that the position and/or length of the username value may not be constant in the data but always follows the string 'username '? If so, you can use CHARINDEX with SUBSTRING e.g.
WITH MyTable (ColumnName)
AS
(
SELECT 'Error 192.168.1.67 UserName 0bce6c62-1efb-416d-bce5-71c3c8247b75 An existing ....'
UNION ALL
SELECT 'Username onedaywhen is invalid'
),
MyTable1 (ColumnName, pos1)
AS
(
SELECT M1.ColumnName, CHARINDEX('UserName ', M1.ColumnName) + LEN('UserName ') + 1
FROM MyTable AS M1
),
MyTable2 (ColumnName, pos1, pos2)
AS
(
SELECT M1.ColumnName, M1.pos1,
CHARINDEX(' ', M1.ColumnName, pos1) - M1.pos1
FROM MyTable1 AS M1
)
SELECT SUBSTRING(M1.ColumnName, M1.pos1, M1.pos2)
FROM MyTable2 AS M1;
...though you'd need to make it more robust e.g. when there is no trailing space after the username value etc.