How to embed a 'lastrow' in a VBA code [duplicate] - vba

Question

How can I find the last row that contains data in a specific column and on a specific sheet?

Answer 1

How about:
Function GetLastRow(strSheet, strColumn) As Long
Dim MyRange As Range
Set MyRange = Worksheets(strSheet).Range(strColumn & "1")
GetLastRow = Cells(Rows.Count, MyRange.Column).End(xlUp).Row
End Function
Regarding a comment, this will return the row number of the last cell even when only a single cell in the last row has data:
Cells.Find("*", SearchOrder:=xlByRows, SearchDirection:=xlPrevious).Row

Answer 2

You should use the .End(xlup) but instead of using 65536 you might want to use:
sheetvar.Rows.Count
That way it works for Excel 2007 which I believe has more than 65536 rows

Answer 3

Simple and quick:
Dim lastRow as long
Range("A1").select
lastRow = Cells.Find("*",SearchOrder:=xlByRows,SearchDirection:=xlPrevious).Row
Example use:
cells(lastRow,1)="Ultima Linha, Last Row. Youpi!!!!"
'or
Range("A" & lastRow).Value = "FIM, THE END"

Answer 4

function LastRowIndex(byval w as worksheet, byval col as variant) as long
dim r as range
set r = application.intersect(w.usedrange, w.columns(col))
if not r is nothing then
set r = r.cells(r.cells.count)
if isempty(r.value) then
LastRowIndex = r.end(xlup).row
else
LastRowIndex = r.row
end if
end if
end function
Usage:
? LastRowIndex(ActiveSheet, 5)
? LastRowIndex(ActiveSheet, "AI")

Answer 5

Public Function LastData(rCol As Range) As Range
Set LastData = rCol.Find("*", rCol.Cells(1), , , , xlPrevious)
End Function
Usage: ?lastdata(activecell.EntireColumn).Address

Answer 6

All the solutions relying on built-in behaviors (like .Find and .End) have limitations that are not well-documented (see my other answer for details).
I needed something that:
Finds the last non-empty cell (i.e. that has any formula or value, even if it's an empty string) in a specific column
Relies on primitives with well-defined behavior
Works reliably with autofilters and user modifications
Runs as fast as possible on 10,000 rows (to be run in a Worksheet_Change handler without feeling sluggish)
...with performance not falling off a cliff with accidental data or formatting put at the very end of the sheet (at ~1M rows)
The solution below:
Uses UsedRange to find the upper bound for the row number (to make the search for the true "last row" fast in the common case where it's close to the end of the used range);
Goes backwards to find the row with data in the given column;
...using VBA arrays to avoid accessing each row individually (in case there are many rows in the UsedRange we need to skip)
(No tests, sorry)
' Returns the 1-based row number of the last row having a non-empty value in the given column (0 if the whole column is empty)
Private Function getLastNonblankRowInColumn(ws As Worksheet, colNo As Integer) As Long
' Force Excel to recalculate the "last cell" (the one you land on after CTRL+END) / "used range"
' and get the index of the row containing the "last cell". This is reasonably fast (~1 ms/10000 rows of a used range)
Dim lastRow As Long: lastRow = ws.UsedRange.Rows(ws.UsedRange.Rows.Count).Row - 1 ' 0-based
' Since the "last cell" is not necessarily the one we're looking for (it may be in a different column, have some
' formatting applied but no value, etc), we loop backward from the last row towards the top of the sheet).
Dim wholeRng As Range: Set wholeRng = ws.Columns(colNo)
' Since accessing cells one by one is slower than reading a block of cells into a VBA array and looping through the array,
' we process in chunks of increasing size, starting with 1 cell and doubling the size on each iteration, until MAX_CHUNK_SIZE is reached.
' In pathological cases where Excel thinks all the ~1M rows are in the used range, this will take around 100ms.
' Yet in a normal case where one of the few last rows contains the cell we're looking for, we don't read too many cells.
Const MAX_CHUNK_SIZE = 2 ^ 10 ' (using large chunks gives no performance advantage, but uses more memory)
Dim chunkSize As Long: chunkSize = 1
Dim startOffset As Long: startOffset = lastRow + 1 ' 0-based
Do ' Loop invariant: startOffset>=0 and all rows after startOffset are blank (i.e. wholeRng.Rows(i+1) for i>=startOffset)
startOffset = IIf(startOffset - chunkSize >= 0, startOffset - chunkSize, 0)
' Fill `vals(1 To chunkSize, 1 To 1)` with column's rows indexed `[startOffset+1 .. startOffset+chunkSize]` (1-based, inclusive)
Dim chunkRng As Range: Set chunkRng = wholeRng.Resize(chunkSize).Offset(startOffset)
Dim vals() As Variant
If chunkSize > 1 Then
vals = chunkRng.Value2
Else ' reading a 1-cell range requires special handling <http://www.cpearson.com/excel/ArraysAndRanges.aspx>
ReDim vals(1 To 1, 1 To 1)
vals(1, 1) = chunkRng.Value2
End If
Dim i As Long
For i = UBound(vals, 1) To LBound(vals, 1) Step -1
If Not IsEmpty(vals(i, 1)) Then
getLastNonblankRowInColumn = startOffset + i
Exit Function
End If
Next i
If chunkSize < MAX_CHUNK_SIZE Then chunkSize = chunkSize * 2
Loop While startOffset > 0
getLastNonblankRowInColumn = 0
End Function

Answer 7

Here's a solution for finding the last row, last column, or last cell. It addresses the A1 R1C1 Reference Style dilemma for the column it finds. Wish I could give credit, but can't find/remember where I got it from, so "Thanks!" to whoever it was that posted the original code somewhere out there.
Sub Macro1
Sheets("Sheet1").Select
MsgBox "The last row found is: " & Last(1, ActiveSheet.Cells)
MsgBox "The last column (R1C1) found is: " & Last(2, ActiveSheet.Cells)
MsgBox "The last cell found is: " & Last(3, ActiveSheet.Cells)
MsgBox "The last column (A1) found is: " & Last(4, ActiveSheet.Cells)
End Sub
Function Last(choice As Integer, rng As Range)
' 1 = last row
' 2 = last column (R1C1)
' 3 = last cell
' 4 = last column (A1)
Dim lrw As Long
Dim lcol As Integer
Select Case choice
Case 1:
On Error Resume Next
Last = rng.Find(What:="*", _
After:=rng.Cells(1), _
LookAt:=xlPart, _
LookIn:=xlFormulas, _
SearchOrder:=xlByRows, _
SearchDirection:=xlPrevious, _
MatchCase:=False).Row
On Error GoTo 0
Case 2:
On Error Resume Next
Last = rng.Find(What:="*", _
After:=rng.Cells(1), _
LookAt:=xlPart, _
LookIn:=xlFormulas, _
SearchOrder:=xlByColumns, _
SearchDirection:=xlPrevious, _
MatchCase:=False).Column
On Error GoTo 0
Case 3:
On Error Resume Next
lrw = rng.Find(What:="*", _
After:=rng.Cells(1), _
LookAt:=xlPart, _
LookIn:=xlFormulas, _
SearchOrder:=xlByRows, _
SearchDirection:=xlPrevious, _
MatchCase:=False).Row
lcol = rng.Find(What:="*", _
After:=rng.Cells(1), _
LookAt:=xlPart, _
LookIn:=xlFormulas, _
SearchOrder:=xlByColumns, _
SearchDirection:=xlPrevious, _
MatchCase:=False).Column
Last = Cells(lrw, lcol).Address(False, False)
If Err.Number > 0 Then
Last = rng.Cells(1).Address(False, False)
Err.Clear
End If
On Error GoTo 0
Case 4:
On Error Resume Next
Last = rng.Find(What:="*", _
After:=rng.Cells(1), _
LookAt:=xlPart, _
LookIn:=xlFormulas, _
SearchOrder:=xlByColumns, _
SearchDirection:=xlPrevious, _
MatchCase:=False).Column
On Error GoTo 0
Last = R1C1converter("R1C" & Last, 1)
For i = 1 To Len(Last)
s = Mid(Last, i, 1)
If Not s Like "#" Then s1 = s1 & s
Next i
Last = s1
End Select
End Function
Function R1C1converter(Address As String, Optional R1C1_output As Integer, Optional RefCell As Range) As String
'Converts input address to either A1 or R1C1 style reference relative to RefCell
'If R1C1_output is xlR1C1, then result is R1C1 style reference.
'If R1C1_output is xlA1 (or missing), then return A1 style reference.
'If RefCell is missing, then the address is relative to the active cell
'If there is an error in conversion, the function returns the input Address string
Dim x As Variant
If RefCell Is Nothing Then Set RefCell = ActiveCell
If R1C1_output = xlR1C1 Then
x = Application.ConvertFormula(Address, xlA1, xlR1C1, , RefCell) 'Convert A1 to R1C1
Else
x = Application.ConvertFormula(Address, xlR1C1, xlA1, , RefCell) 'Convert R1C1 to A1
End If
If IsError(x) Then
R1C1converter = Address
Else
'If input address is A1 reference and A1 is requested output, then Application.ConvertFormula
'surrounds the address in single quotes.
If Right(x, 1) = "'" Then
R1C1converter = Mid(x, 2, Len(x) - 2)
Else
x = Application.Substitute(x, "$", "")
R1C1converter = x
End If
End If
End Function

Answer 8

I would like to add one more reliable way using UsedRange to find the last used row:
lastRow = Sheet1.UsedRange.Row + Sheet1.UsedRange.Rows.Count - 1
Similarly to find the last used column you can see this
Result in Immediate Window:
?Sheet1.UsedRange.Row+Sheet1.UsedRange.Rows.Count-1
21

Answer 9

Public Function GetLastRow(ByVal SheetName As String) As Integer
Dim sht As Worksheet
Dim FirstUsedRow As Integer 'the first row of UsedRange
Dim UsedRows As Integer ' number of rows used
Set sht = Sheets(SheetName)
''UsedRange.Rows.Count for the empty sheet is 1
UsedRows = sht.UsedRange.Rows.Count
FirstUsedRow = sht.UsedRange.Row
GetLastRow = FirstUsedRow + UsedRows - 1
Set sht = Nothing
End Function
sheet.UsedRange.Rows.Count: retrurn number of rows used, not include empty row above the first row used
if row 1 is empty, and the last used row is 10, UsedRange.Rows.Count will return 9, not 10.
This function calculate the first row number of UsedRange plus number of UsedRange rows.

Answer 10

Last_Row = Range("A1").End(xlDown).Row
Just to verify, let's say you want to print the row number of the last row with the data in cell C1.
Range("C1").Select
Last_Row = Range("A1").End(xlDown).Row
ActiveCell.FormulaR1C1 = Last_Row

Answer 11

get last non-empty row using binary search
returns correct value event though there are hidden values
may returns incorrect value if there are empty cells before last non-empty cells (e.g. row 5 is empty, but row 10 is last non-empty row)
Function getLastRow(col As String, ws As Worksheet) As Long
Dim lastNonEmptyRow As Long
lastNonEmptyRow = 1
Dim lastEmptyRow As Long
lastEmptyRow = ws.Rows.Count + 1
Dim nextTestedRow As Long
Do While (lastEmptyRow - lastNonEmptyRow > 1)
nextTestedRow = Application.WorksheetFunction.Ceiling _
(lastNonEmptyRow + (lastEmptyRow - lastNonEmptyRow) / 2, 1)
If (IsEmpty(ws.Range(col & nextTestedRow))) Then
lastEmptyRow = nextTestedRow
Else
lastNonEmptyRow = nextTestedRow
End If
Loop
getLastRow = lastNonEmptyRow
End Function

Answer 12

Function LastRow(rng As Range) As Long
Dim iRowN As Long
Dim iRowI As Long
Dim iColN As Integer
Dim iColI As Integer
iRowN = 0
iColN = rng.Columns.count
For iColI = 1 To iColN
iRowI = rng.Columns(iColI).Offset(65536 - rng.Row, 0).End(xlUp).Row
If iRowI > iRowN Then iRowN = iRowI
Next
LastRow = iRowN
End Function

Answer 13

Sub test()
MsgBox Worksheets("sheet_name").Range("A65536").End(xlUp).Row
End Sub
This is looking for a value in column A because of "A65536".

Answer 14

The first line moves the cursor to the last non-empty row in the column. The second line prints that columns row.
Selection.End(xlDown).Select
MsgBox(ActiveCell.Row)