Hi please let me know how to extract the last day of Financial year in sql server.my financial year start from 2016-04-01 to 2017-03-31
Closest you can use is End Of Month for that you need to provide one date to that month as below:
select eomonth('2017-03-01')
To get the last day of the financial year for any date, you need to find the last of march if before march, or the last of march next year if after march:
declare #yourdate datetime = getdate();
select case when month(#yourdate) < 4 then CONVERT(datetime,cast(YEAR(#yourdate) as char(4)) + '-03-31' ,120)
else CONVERT(datetime,cast(YEAR(#yourdate) + 1 as char(4)) + '-03-31' ,120)
end as financial_year_end
Edit:
If you want last date derived based on from_date, then use something like this
Rextester Demo
select
case when datepart(mm,from_date) <=3 then
cast(concat(year(from_date),'-03-31') as datetime)
else
dateadd(year,1,cast(concat(year(from_date),'-03-31') as datetime))
end as last_date_fin
from
(select '2017-04-30' as from_date union all
select '2017-01-13') t;
This way from_date between Jan - Mar will give same year's 31st march. Else it will give next year's 31st March.
Previous answer:
http://rextester.com/AXVM26769
If you want to get last day of march for same year as passed, then use
select cast(concat(given_year,'-03-31') as datetime)
from
(select '2017' as given_year) t
If you want to pass 2016 and then get 2017-03-31 then use. You can change the year in derived table and change the output based on that.
select dateadd(year,1,cast(concat(given_year,'-03-31') as datetime))
from
(select '2016' as given_year) t;
This Code will work to find the last date of Financial Year.
For Previous Year case matches and 'THEN' part will Execute and for current year 'ELSE'
part will execute.
select CASE WHEN (MONTH(GETDATE())) <= 3
THEN convert(varchar(4), YEAR(GETDATE())-1) + '-' + '03-31'
ELSE convert(varchar(4),YEAR(GETDATE()))+ '-' + '03-31'
end
> LastDayOfYearFY] =
> eomonth( dateadd(month, 5,
> dateadd(year, datepart(year, (dateadd(month, 6, [date])) ) -1900, 0)))
Idea extension taken from return-first-day-of-financial-year
You can select all the dates order them descendant and take the first one.
SELECT date
FROM table
ORDER BY date desc
LIMIT 1;
Related
I'm using SSMS/SSRS2012 working on report to capture all hours worked in the current fiscal year, which for this purpose is Oct 1-Sep 30.
I'm looking for a case statement that says the following:
if the current month < 10 (october) then #FYStart = last year
if the current month >= 10 then #FYStart = current year
When I query SELECT GETDATE() here is the format: 2020-06-16 15:24:57.637
I have tried the following, but it only half works.
SELECT CASE WHEN DATEPART(MONTH,(CAST(getdate() AS INT)))>09
THEN YEAR(CAST(getdate() AS INT))
ELSE DATEADD(YEAR,-1,(CAST(getdate() AS INT)))
END
The result from this gives me 2019-06-17 00:00:00.000 which is a step in the right direction, but if I change the month to a month that has already passed,
SELECT CASE WHEN DATEPART(MONTH,(CAST(getdate() AS INT)))>03
THEN YEAR(CAST(getdate() AS INT))
ELSE DATEADD(YEAR,-1,(CAST(getdate() AS INT)))
END
I get this result: 1905-07-14 00:00:00.000
Something is obviously going wrong here but I'm not sure what exactly. I'm thinking it's something with the data types but I'm not sure what to check/where to start.
So from what I gather, you are trying to isolate the year (as an integer) from today's date and store it in #FYStart. If today's date is before October, you want to assign it to last year, and if it's October or later, assign it to this year, correct?
If so, try this:
DECLARE #FYStart int
SET #FYStart = (
SELECT CASE WHEN DATEPART(MONTH, GETDATE()) < 10
THEN DATEPART(YEAR, DATEADD(YEAR, -1, GETDATE())) -- last year
ELSE DATEPART(YEAR, GETDATE()) -- this year
END
)
Unless I'm overlooking something, is it not just something as simple as...
SELECT CASE WHEN MONTH(getdate()) <10
THEN YEAR(getdate()) -1
ELSE YEAR(getdate())
END
I have two date columns, which takes into account only working days. A_date and E_date.
E_date is calculated adding +2 days to A_date, because that's the request
The problem is that if the day of A_date is 30th or 31st of the month, then E_date date needs to be the last day of the current month, and not the first or second working day of the next month.
i have tried eomonth function but that does not work because it would need a explicit date.
Do you have any idea how to solve it?
You can use EOMONTH() in SQLServer to get the last day of the month.
Example:
EOMONTH(A_date)
SELECT CASE WHEN dateadd(month,1+datediff(month,0,A_date),-1)< DATEADD(day, 2, A_date) THEN dateadd(month,1+datediff(month,0,A_date),-1) ELSE DATEADD(day, 2, A_date) END E_date
FOR input of 2019/09/30 output is 2019-09-30 00:00:00.000
I'm not sure what your question is. What I've understood so far is that you want the last date of the month in case when adding two days to A_Date jumps to the next month.
Why don't you use CASE WHEN and compare out the months, this way :
DECLARE #A_Date date = '2019/09/30';
DECLARE #A_Date_Month int = 0;
DECLARE #E_Date_Month int = 0;
SELECT #A_Date_Month = Month(Cast(#A_Date AS datetime));
SELECT #E_Date_Month = Month(DATEADD(day, 2, #A_Date));
SELECT CASE
WHEN #A_Date_Month = #E_Date_Month
THEN DATEADD(day, 2, #A_Date)
ELSE EOMONTH(#A_Date) END AS OUTPUTValue
Try out the above set and do let me know if it resolves your issue!
How to get from a date column the last date of the previous month?
It depends on your RDBMS, so let's take the opportunity to make a generic answer:
In Oracle:
LAST_DAY(ADD_MONTHS(mydate ,-1))
In MySQL:
LAST_DAY(mydate - INTERVAL 1 MONTH)
In SQL Server:
DATEADD(MONTH, DATEDIFF(MONTH, -1, mydate )-1, -1)
-- or simply:
EOMONTH(DATEADD(Month, -1, mydate ))
In Postgres:
date_trunc('month', now())::mydate - 1
have two date columns, which takes into account only working days. A_date and E_date. E_date is calculated adding +2 days to A_date, because that's the request
I would simply do:
(case when dateadd(day, 2, a_date) < eomonth(a_date)
then dateadd(day, 2, a_date)
else eomonth(a_date)
end) as e_date
If you truly want this only on the 30th or 31st of any given month and not the last 2 days of any month (since obviously not every month has 31 days) --
select A_date
,case when day(A_date) >= 30
then eomonth(A_date)
else dateadd("dd",2,A_date)
end as E_date
Other answers work for "last 2 days of any month".
How to get the current month end date through db2 query.
I should not need to modify the query for every month
Every month the sql is executing so it need to automatically take care
In Db2 11.1 this could be a solution:
select next_month(current date) - 1 day from sysibm.sysdummy1
Next_Month will return the first day of the next month from the data provided.
SELECT LAST_DAY(CURRENT_DATE) AS LASTDAY
FROM SYSIBM.SYSDUMMY1;
The query is working
LASTDAY
2019-04-30
The old way would be
CURRENT DATE - (DAY(CURRENT DATE)) DAYS + 1 MONTH
To get the last day of the current month, use this:
SELECT DATEADD (dd, -1, DATEADD(mm, DATEDIFF(mm, 0, GETDATE()) + 1, 0))
This will format the date for you
SELECT CONVERT(VARCHAR(10), DATE, 12)
See this for more information regarding the '12'. 12 is the right code
Another solution is to use TIMESTAMP_FORMAT as such:
TIMESTAMP_FORMAT('190404', 'YYMMDD')
Can someone suggest me how do we consider week to start on Sunday and end on Saturday, while numbering them backwards in a 52 week rolling report like week1, week2.. week52
I want to count my current week as Week1 starting on Sunday, so even if its partial week its still week1 and last week Sunday-Saturday is week2 and so on until 52nd week last year (that would roughly be in September counting backwards). I need this as I am working on a daily report that will look for sales for current week and past 51 (full) weeks. My report should also return any week without sales '0' without skipping it.
Here is a way. Note I created the recursive CTE to populate some dates. You won't have to do this step, and real only need the YourWeekOrder = ... part.
declare #startDate date = dateadd(year,-1,getdate())
declare #endDate date = getdate()
;with cte as(
select #startDate as TheDate
union all
select dateadd(day,1,TheDate)
from cte
where TheDate < #endDate)
select
TheDate
,TheWeekOfYear = datepart(week,TheDate)
,YourWeekOrder = dense_rank() over (order by cast(datepart(year,TheDate) as char(4)) + case when len(datepart(week,TheDate)) = 1 then '0' + cast(datepart(week,TheDate) as char(2)) else cast(datepart(week,TheDate) as char(2)) end desc)
from cte
order by
TheDate
option(maxrecursion 0)
SEE IT IN ACTION HERE
I have a resources table, one of the fields is a date field with the Data Type of date. I want to have to following output:
Current month records (say May - year is not important)
Then the following (again, assuming May is the current month)
June Records
July Records
August Records
September Records
October Records
November Records
December Records
January Records
February Records
March Records
April Records
Come June, June is the current month and then the order would be:
July Records
August Records
...
Here is my SQL...I don't know how to ORDER the output to achieve the desired order (5,6,7,8,9,10,11,12,1,2,3,4):
SELECT
resource_id,
resource_title,
resource_summary,
resource_category,
resource_status,
resource_date,
DATEPART(month, resource_date) AS resource_month,
DATEPART(day, resource_date) AS resource_day
FROM dbo.resources
WHERE (resource_category = N'Quotes')
AND (resource_status <> N'Draft')
I found this possible solution for MySQL:
I need unusual ordering mysql results
but I'm missing something on my end.
ORDER BY
(MONTH(resource_date) - MONTH(GETDATE()) + 12) % 12,
DATEADD(year, YEAR(GETDATE()) - YEAR(resource_date), resource_date),
YEAR(resource_date)
The first term sets the primary order by the month of resource_date (the current month will be first, the previous one, last). The second term orders the timestamps within a month regardless of the year of the date. If your dates do not contain time parts or if the time parts are absolutely irrelevant, you could replace it with DAY(resource_date). Finally, the last term takes the year into account for otherwise identical dates (could also be simply resource_date).
Will it work for you?
ORDER BY
CASE DATEPART(month, resource_date)
WHEN 5 THEN 0
WHEN 6 THEN 1
... etc
END
I think something like this might be what you're looking for:
SELECT
resource_id,
resource_title,
resource_summary,
resource_category,
resource_status,
resource_date
FROM
dbo.resources
WHERE
resource_date >= DATE_FORMAT(NOW() ,'%Y-%m-01') AND
resource_date < DATE_FORMAT(DATE_ADD(NOW(), INTERVAL 1 YEAR) ,'%Y-%m-01')
ORDER BY
resource_date;
How 'bout ORDER BY (DATEPART(month,resource_date) - (DATEPART(month,getdate() -1)) % 12)
So in May (month 5), you order by the month in the row -6 (mod 12). So, June (month 6) would be 0, July (7) would be 1.
In June, July would be 0, etc.
You should be able to adapt the MySQL solution by using DATEPART in place of DATE_FORMAT:
SELECT resource_id, resource_title, resource_summary, resource_category, resource_status, resource_date, DATEPART(month, resource_date) AS resource_month, DATEPART(day, resource_date) AS resource_day
FROM dbo.resources
WHERE (resource_category = N'Quotes') AND (resource_status <> N'Draft')
ORDER BY DATEPART(month, resource_date) < DATEPART(month, GETDATE()),
DATEPART(month, resource_date)
I don't have SQL Server handy so I'm not sure if it will be happy with a boolean in the ORDER BY clause though. If it doesn't like the boolean ORDER BY, then a CASE should do the trick:
ORDER BY
CASE WHEN DATEPART(month, resource_date) < DATEPART(month, GETDATE())
THEN 0
ELSE 1
END,
DATEPART(month, resource_date)
I assume that there is a year within "resource_date" - isn't it?
In this case you can simply filter and order by
WHERE resource_date >= getdate()
AND resource_date < DATEADD(year,1,getdate())
ORDER BY resource_date;
If there is no year (or more exactly: different unknown years) you can do this:
ORDER BY
CASE
WHEN DATEADD(year,-year(resource_date),resource_date) <
DATEADD(year,-year(getdate()),getdate())
THEN 1
ELSE 0
END ASC,
DATEADD(year,-year(resource_date),resource_date);
Hope it helped ...