I need your help please, i have a simple code in python which lists all the fields in the tables in all the databases that are on databricks, there are a little nearly 90 tables and I would like to save the result in a txt or csv file. here is the code used it works but it takes 8 hours to finish it is too long how can I optimize or have another way for it to be faster?
# table containing all name of database in databricks
#df_tables = spark.sql("SELECT * FROM bd_xyh_name")
#DynoSQL is a string table for result in txt
def discribe():
try:
for i in df_tables.collect():
showTables="""show tables in {};""".format(i.nombd)
df1=spark.sql(showTables)
for j in df1.collect():
describeTable="""describe table {0}.{1};""".format(j.database,j.tableName)
df2=spark.sql(describeTable)
#df3=df2.collect()
df3 = df2.rdd.toLocalIterator()
for k in df3:
#df=df2.select(df2.col_name;k.data_type)
#spark.sql("insert into NewTable VALUES ("+j.database+";"+j.tableName+";"+k.col_name+";"+k.data_type+");")
spark.sql("insert into DynoSQL select \""+j.database+";"+j.tableName+";"+k.col_name+";"+k.data_type+"\"")
# request="insert into NewTable VALUES ({};{};{};{});""".format(j.database,j.tableName,k.col_name,k.data_type)
#spark.sql(request)
except:
raise
You can try with below logic .
Logic :
Get the available databases within workspace and make list
Iterate the databases name and get the available tables within databases and write into temp table. (Temp table you should create as managed one)
Advantage : Based on this logic , at a time only one databases only will be processed and if fails during the process , we can start from failing databases instead of whole workspace level.
Code Snippet :
from pyspark.sql.types import *
import pyspark.sql.functions as f
from pyspark.sql import functions as F
from pyspark.sql.functions import col, concat, lit
df = spark.sql("show databases")
list = [x["databaseName"] for x in df.collect()]
for x in list:
df = spark.sql(f"use {x}")
df1 = spark.sql("show tables")
df_loc.write.insertInto("writeintotable")
display(df1)
Screenshot :
I have a problem that 1) I don't really know how to call a registered UDF. I found some answer saying use callUDF so this is how I call the function in my code. 2) I don't really know how to pass in arrays as parameters.
Here is my code:
val df = Seq(("1","2","3","4","5","6")).toDF("A","B","C","D","E","F")
val newdf = Seq(("1","2","3","4","5","6")).toDF("A","B","C","D","E","F")
val cols = df.columns
val temp = Array(df.select($"A"),df.select($"B"),df.select($"C"),df.select($"D"),df.select($"E"),df.select($"F"))
val temp2 = Array(newdf.select($"A"),newdf.select($"B"),newdf.select($"C"),newdf.select($"D"),newdf.select($"E"),newdf.select($"F"))
sparkSession.udf.register ( "myfunc" , ((A:Array[String],B:Array[String]) => {for(i <- 0 to 5)yield( if (A(i)==B(i)) "U" else "N")} ) )
val a = df.withColumn("A",callUDF("myfunc",(temp,temp2)))
Thanks in advance!
You are trying to use columns from two different dataframes which is illegal in a UDF. Spark's UDF can only work on a per row basis. You can't combine rows from different dataframes. To do so you need to perform a join between the two.
In your case you have just one row but in a realistic case you would have multiple rows, you need to make sure you have some unique key to join by such as a unique id.
If you don't and both dataframes have the same number of rows and the same number of partitions you can easily create an id for both dataframes like this:
df.withColumn("id",monotonicallyIncreasingId)
You should probably also rename the columns to have different names.
Look at the different options for join (see http://spark.apache.org/docs/latest/api/scala/index.html#org.apache.spark.sql.Dataset) to see what best matches your need.
As for registering and calling a udf you can do:
def myFunc(s1: Seq[Int], s2: Seq[Int]) = {
for(i <- 0 to 5) yield {
if (s1(i)==s2(i)) "U" else "N"
}
}
val u = udf(myFunc)
val a = df.withColumn("A", myFunc(temp,temp2))
note that temp and temp2 should each be a column representing an array in the same dataframe, i.e. you should define them after the join on the relevant columns.
How do we concatenate two columns in an Apache Spark DataFrame?
Is there any function in Spark SQL which we can use?
With raw SQL you can use CONCAT:
In Python
df = sqlContext.createDataFrame([("foo", 1), ("bar", 2)], ("k", "v"))
df.registerTempTable("df")
sqlContext.sql("SELECT CONCAT(k, ' ', v) FROM df")
In Scala
import sqlContext.implicits._
val df = sc.parallelize(Seq(("foo", 1), ("bar", 2))).toDF("k", "v")
df.registerTempTable("df")
sqlContext.sql("SELECT CONCAT(k, ' ', v) FROM df")
Since Spark 1.5.0 you can use concat function with DataFrame API:
In Python :
from pyspark.sql.functions import concat, col, lit
df.select(concat(col("k"), lit(" "), col("v")))
In Scala :
import org.apache.spark.sql.functions.{concat, lit}
df.select(concat($"k", lit(" "), $"v"))
There is also concat_ws function which takes a string separator as the first argument.
Here's how you can do custom naming
import pyspark
from pyspark.sql import functions as sf
sc = pyspark.SparkContext()
sqlc = pyspark.SQLContext(sc)
df = sqlc.createDataFrame([('row11','row12'), ('row21','row22')], ['colname1', 'colname2'])
df.show()
gives,
+--------+--------+
|colname1|colname2|
+--------+--------+
| row11| row12|
| row21| row22|
+--------+--------+
create new column by concatenating:
df = df.withColumn('joined_column',
sf.concat(sf.col('colname1'),sf.lit('_'), sf.col('colname2')))
df.show()
+--------+--------+-------------+
|colname1|colname2|joined_column|
+--------+--------+-------------+
| row11| row12| row11_row12|
| row21| row22| row21_row22|
+--------+--------+-------------+
One option to concatenate string columns in Spark Scala is using concat.
It is necessary to check for null values. Because if one of the columns is null, the result will be null even if one of the other columns do have information.
Using concat and withColumn:
val newDf =
df.withColumn(
"NEW_COLUMN",
concat(
when(col("COL1").isNotNull, col("COL1")).otherwise(lit("null")),
when(col("COL2").isNotNull, col("COL2")).otherwise(lit("null"))))
Using concat and select:
val newDf = df.selectExpr("concat(nvl(COL1, ''), nvl(COL2, '')) as NEW_COLUMN")
With both approaches you will have a NEW_COLUMN which value is a concatenation of the columns: COL1 and COL2 from your original df.
concat(*cols)
v1.5 and higher
Concatenates multiple input columns together into a single column. The function works with strings, binary and compatible array columns.
Eg: new_df = df.select(concat(df.a, df.b, df.c))
concat_ws(sep, *cols)
v1.5 and higher
Similar to concat but uses the specified separator.
Eg: new_df = df.select(concat_ws('-', df.col1, df.col2))
map_concat(*cols)
v2.4 and higher
Used to concat maps, returns the union of all the given maps.
Eg: new_df = df.select(map_concat("map1", "map2"))
Using concat operator (||):
v2.3 and higher
Eg: df = spark.sql("select col_a || col_b || col_c as abc from table_x")
Reference: Spark sql doc
If you want to do it using DF, you could use a udf to add a new column based on existing columns.
val sqlContext = new SQLContext(sc)
case class MyDf(col1: String, col2: String)
//here is our dataframe
val df = sqlContext.createDataFrame(sc.parallelize(
Array(MyDf("A", "B"), MyDf("C", "D"), MyDf("E", "F"))
))
//Define a udf to concatenate two passed in string values
val getConcatenated = udf( (first: String, second: String) => { first + " " + second } )
//use withColumn method to add a new column called newColName
df.withColumn("newColName", getConcatenated($"col1", $"col2")).select("newColName", "col1", "col2").show()
From Spark 2.3(SPARK-22771) Spark SQL supports the concatenation operator ||.
For example;
val df = spark.sql("select _c1 || _c2 as concat_column from <table_name>")
Here is another way of doing this for pyspark:
#import concat and lit functions from pyspark.sql.functions
from pyspark.sql.functions import concat, lit
#Create your data frame
countryDF = sqlContext.createDataFrame([('Ethiopia',), ('Kenya',), ('Uganda',), ('Rwanda',)], ['East Africa'])
#Use select, concat, and lit functions to do the concatenation
personDF = countryDF.select(concat(countryDF['East Africa'], lit('n')).alias('East African'))
#Show the new data frame
personDF.show()
----------RESULT-------------------------
84
+------------+
|East African|
+------------+
| Ethiopian|
| Kenyan|
| Ugandan|
| Rwandan|
+------------+
Here is a suggestion for when you don't know the number or name of the columns in the Dataframe.
val dfResults = dfSource.select(concat_ws(",",dfSource.columns.map(c => col(c)): _*))
Do we have java syntax corresponding to below process
val dfResults = dfSource.select(concat_ws(",",dfSource.columns.map(c => col(c)): _*))
In Spark 2.3.0, you may do:
spark.sql( """ select '1' || column_a from table_a """)
In Java you can do this to concatenate multiple columns. The sample code is to provide you a scenario and how to use it for better understanding.
SparkSession spark = JavaSparkSessionSingleton.getInstance(rdd.context().getConf());
Dataset<Row> reducedInventory = spark.sql("select * from table_name")
.withColumn("concatenatedCol",
concat(col("col1"), lit("_"), col("col2"), lit("_"), col("col3")));
class JavaSparkSessionSingleton {
private static transient SparkSession instance = null;
public static SparkSession getInstance(SparkConf sparkConf) {
if (instance == null) {
instance = SparkSession.builder().config(sparkConf)
.getOrCreate();
}
return instance;
}
}
The above code concatenated col1,col2,col3 seperated by "_" to create a column with name "concatenatedCol".
In my case, I wanted a Pipe-'I' delimited row.
from pyspark.sql import functions as F
df.select(F.concat_ws('|','_c1','_c2','_c3','_c4')).show()
This worked well like a hot knife over butter.
use concat method like this:
Dataset<Row> DF2 = DF1
.withColumn("NEW_COLUMN",concat(col("ADDR1"),col("ADDR2"),col("ADDR3"))).as("NEW_COLUMN")
Another way to do it in pySpark using sqlContext...
#Suppose we have a dataframe:
df = sqlContext.createDataFrame([('row1_1','row1_2')], ['colname1', 'colname2'])
# Now we can concatenate columns and assign the new column a name
df = df.select(concat(df.colname1, df.colname2).alias('joined_colname'))
Indeed, there are some beautiful inbuilt abstractions for you to accomplish your concatenation without the need to implement a custom function. Since you mentioned Spark SQL, so I am guessing you are trying to pass it as a declarative command through spark.sql(). If so, you can accomplish in a straight forward manner passing SQL command like:
SELECT CONCAT(col1, '<delimiter>', col2, ...) AS concat_column_name FROM <table_name>;
Also, from Spark 2.3.0, you can use commands in lines with:
SELECT col1 || col2 AS concat_column_name FROM <table_name>;
Wherein, is your preferred delimiter (can be empty space as well) and is the temporary or permanent table you are trying to read from.
We can simple use SelectExpr as well.
df1.selectExpr("*","upper(_2||_3) as new")
We can use concat() in select method of dataframe
val fullName = nameDF.select(concat(col("FirstName"), lit(" "), col("LastName")).as("FullName"))
Using withColumn and concat
val fullName1 = nameDF.withColumn("FullName", concat(col("FirstName"), lit(" "), col("LastName")))
Using spark.sql concat function
val fullNameSql = spark.sql("select Concat(FirstName, LastName) as FullName from names")
Taken from https://www.sparkcodehub.com/spark-dataframe-concat-column
val newDf =
df.withColumn(
"NEW_COLUMN",
concat(
when(col("COL1").isNotNull, col("COL1")).otherwise(lit("null")),
when(col("COL2").isNotNull, col("COL2")).otherwise(lit("null"))))
Note: For this code to work you need to put the parentheses "()" in the "isNotNull" function. -> The correct one is "isNotNull()".
val newDf =
df.withColumn(
"NEW_COLUMN",
concat(
when(col("COL1").isNotNull(), col("COL1")).otherwise(lit("null")),
when(col("COL2").isNotNull(), col("COL2")).otherwise(lit("null"))))