I am trying to make a query in Progress. I should select all records older than exactly one year, so the current date minus 1 year. I have tried several possibilities but became every time an error. The query belongs to a join and should take every record of the previous year up to the current date minus one year:
left outer join data.pub."vc-669" as det2
on deb.cddeb = det2.cddeb
and det2.jaar = year(curdate()) - 1
and det2."sys-date" < date(month(curdate()), day(curdate()), year(curdate()) - 1)
That should simply be:
and det2."sys-date" < add-interval( curdate(), - 1, 'year' )
(As this already deals with the year, there is no need to look at det2.jaar, too.)
https://documentation.progress.com/output/ua/OpenEdge_latest/index.html#page/dvref/add-interval-function.html
Related
Say I have this table:
month
num_of_fruits
harvested
2022-01-01
133
3
2022-02-01
145
12
2022-03-01
123
5
2022-04-01
111
4
2022-05-01
164
9
..
..
..
I want to be able to set a new column called lost based on the month and num_of_fruits columns. To set this lost column, requires a calculation. The calculation is harvested - (num_of_fruits - num_of_fruits(last_month))
I'm having trouble in the parenthesis part - getting the last month's num_of_fruits. I have this to start:
select
id,
"month",
num_of_fruits,
harvested,
harvested - (num_of_fruits - num_of_fruits WHERE date_trunc('month', "month" - interval '1' month)) as lost,
selecting other columns..
It's giving me an error in the where clause.
Can you have a where clause inside a select statement? How would I take the last month's num_of_fruits and subtract it with this month's num_of_fruits - all while inside the select statement?
Any help or advice will greatly help me! Thank you so much in advance!
If you want to check other rows in the table, you will likely want either a subquery in your SELECT or to join the table to itself.
I think you are probably trying to do:
SELECT
harvested - (num_of_fruits - (SELECT num_of_fruits FROM mytable t2 WHERE t2.month = date_trunc('month', t1."month" - interval '1' month))) as lost
FROM mytable t1
Note that I created a whole new subquery (SELECT/FROM/WHERE) within your existing SELECT statement, instead of just adding a stray WHERE clause.
I also changed your condition so that it actually has a compares the result of DATETRUNC with something.
It's not clear to me that you actually need the DATETRUNC here (and, if you do, you might want it on both sides of the comparison), but you can use the basic idea above and fix the condition to match your needs.
An alternative (joining to self) to consider might be:
SELECT
t1.harvested - (t1.num_of_fruits - t2.num_of_fruits)
FROM mytable t1 LEFT OUTER JOIN mytable t2
ON t2.month = date_trunc('month', t1."month" - interval '1' month)))
If you know that you always have one row per month, so the previous row (ordered by month) is also the previous month, you could just use LAG:
SELECT
harvested - (num_of_fruits - LAG(num_of_fruits, 1) OVER (ORDER BY month)
FROM mytable
LAG(num_of_fruits, 1) OVER (ORDER BY month) means "the num_of_fruits from the previous row in the table when the table is ordered by month".
This SQL statement working fine for the last year, to selecting data where current month is greater than Subquery Max month match by ciient_id. Now, Subquery return Max month is 12 for the last year whether comparing current month for this year which is 1. That why the SQL statement return 0 record.
I have to find out client_id, those who are not exist in the Subquery for the current month. Either I can compare with date. Please Help me to get out of here.
SELECT c.id, p.pkg_rate AS amount
FROM tbl_client AS c
INNER JOIN tbl_package AS p ON c.pkg_id = p.id
WHERE c.status=1 AND
Month(Date())>(SELECT Month(Max([due_month])) FROM tbl_payment_due WHERE
c.id=client_id);
One approach is to format the date into a string first.
Format(Date(),"yyyymm") > (SELECT Format(Max([due_month]),"yyyymm") FROM tbl_payment_due WHERE c.id=client_id)
A second option is to add a check for the year in the WHERE clause (note: my parenthesis may be off a bit).
(Year(Now()) > (SELECT Year(Max([due_month])) FROM tbl_payment_due WHERE c.id=client_id)) OR
((Year(Now()) = (SELECT Year(Max([due_month])) FROM tbl_payment_due WHERE c.id=client_id)) AND (Month(Date())>(SELECT Month(Max([due_month])) FROM tbl_payment_due WHERE c.id=client_id)))
I have a view that produces the result shown in the image below. I need help with the logic.
Requirement:
List of all employees who achieved no less than 100% target in ALL Quarters in past two years.
"B" received 90% in two different quarters. An employee who received less than 100% should NOT be listed.
Notice that "A" didn't work for Q2-2016. An employee who didn't work for that quarter should NOT be listed.
"C" is the only one who worked full two years, and received 100% in each quarter.
Edit: added image link showing Employee name,Quarter, Year, and the score.
https://i.imgur.com/FIXR0YF.png
The logic is pretty easy, it's math with quarters that is a bit of a pain.
There are 8 quarters in the last two years, so you simply need to select all the employee names in the last two years with a target >= 100%, group by employee name, and apply a HAVING clause to limit the output to those employees with count(*) = 8.
To get the current year and quarter, you can use these expressions:
cast(extract('year' from current_date) as integer) as yr,
(cast(extract('month' from current_date) as integer)-1) / 3 + 1 as quarter;
Subtract 2 from the current year to find the previous year and quarter. The code will be clearer if you put these expressions in a subquery because you will need them multiple times for the quarter arithmetic. To do the quarter arithmetic you must extract the integer value of the quarter from the text values you have stored.
Altogether, the solution should look something like this:
select
employee
from
(select employee, cast(right(quarter,1) as integer) as qtr, year
from your_table
where target >= 100
) as tgt
cross join (
select
cast(extract('year' from current_date) as integer) as yr,
(cast(extract('month' from current_date) as integer)-1) / 3 + 1 as quarter
) as qtr
where
tgt.year between qtr.yr-1 and qtr.yr
or (tgt.year = qtr.yr - 2 and tgt.qtr > qtr.quarter)
group by
employee
having
count(*) = 8;
This is untested.
If you happen to be using Postgres and expect to be doing a lot of quarter arithmetic you may want to define a custom data type as described in A Year and Quarter Data Type for PostgreSQL
I have this schema
and I want to have a query to calculate the cost per consultant per hour per month. In other words, a consultant has a salary per month, I want to divide the amount of the salary between the hours that he/she worked that month.
SELECT
concat_ws(' ', consultants.first_name::text, consultants.last_name::text) as name,
EXTRACT(MONTH FROM tasks.init_time) as task_month,
SUM(tasks.finish_time::timestamp::time - tasks.init_time::timestamp::time) as duration,
EXTRACT(MONTH FROM salaries.payment_date) as salary_month,
salaries.payment
FROM consultants
INNER JOIN tasks ON consultants.id = tasks.consultant_id
INNER JOIN salaries ON consultants.id = salaries.consultant_id
WHERE EXTRACT(MONTH FROM tasks.init_time) = EXTRACT(MONTH FROM salaries.payment_date)
GROUP BY (consultants.id, EXTRACT(MONTH FROM tasks.init_time), EXTRACT(MONTH FROM salaries.payment_date), salaries.payment);
It is not possible to do this in the select
salaries.payment / SUM(tasks.finish_time::timestamp::time - tasks.init_time::timestamp::time)
Is there another way to do it? Is it possible to solve it in one query?
Assumptions made for this answer:
The model is not entirely clear to me, so I am assuming the following:
you are using PostgreSQL
salaries.date is defined as a date column that stores the day when a consultant was paid
tasks.init_time and task.finish_time are defined as timestamp storing the data & time when a consultant started and finished work on a specific task.
Your join on only the month is wrong as far as I can tell. For one, because it would also include months from different years, but more importantly because this would lead to a result where the same row from salaries appeared several times. I think you need to join on the complete date:
FROM consultants c
JOIN tasks t ON c.id = t.consultant_id
JOIN salaries s ON c.id = s.consultant_id
AND t.init_time::date = s.payment_date --<< here
If my assumptions about the data types are correct, the cast to a timestamp and then back to a time is useless and wrong. Useless because you can simply subtract to timestamps and wrong because you are ignoring the actual date in the timestamp so (although unlikely) if init_time and finish_time are not on the same day, the result is wrong.
So the calculation of the duration can be simplified to:
t.finish_time - t.init_time
To get the cost per hour per month, you need to convert the interval (which is the result when subtracting one timestamp from another) to a decimal indicating the hours, you can do this by extracting the seconds from the interval and then dividing that by 3600, e.g.
extract(epoch from sum(t.finish_time - t.init_time)) / 3600)
If you divide the sum of the payments by that number you get your cost per hour per month:
SELECT concat_ws(' ', c.first_name, c.last_name) as name,
to_char(s.payment_date, 'yyyy-mm') as salary_month,
extract(epoch from sum(t.finish_time - t.init_time)) / 3600 as worked_hours,
sum(s.payment) / (extract(epoch from sum(t.finish_time - t.init_time)) / 3600) as cost_per_hour
FROM consultants c
JOIN tasks t ON c.id = t.consultant_id
JOIN salaries s ON c.id = s.consultant_id AND t.init_time::date = s.payment_date
GROUP BY c.id, to_char(s.payment_date, 'yyyy-mm') --<< no parentheses!
order by name, salary_month;
As you want the report broken down by month you should convert the month into something that contains the year as well. I used to_char() to get a string with only year and month. You also need to remove salaries.payment from the group by clause.
You also don't need the "payment month" and "salary month" because both will always be the same as that is the join condition.
And finally you don't need the cast to ::text for the name columns because they are most certainly defined as varchar or text anyway.
The sample data I made up for this: http://sqlfiddle.com/#!15/ae0c9
Somewhat unrelated, but:
You should also not put the column list of the group by in parentheses. Putting a column list in parentheses in Postgres creates an anonymous record which is something completely different then having multiple columns. This is also true for the columns in the select list.
If at all the target is putting it in one query, then just confirming, have you tried to achieve it using CTEs?
Like
;WITH cte_pymt
AS
(
//Your existing query 1
)
SELECT <your required data> FROM cte_pymt
I want to return all application dates for the current month and for the current year. This must be simple, however I can not figure it out. I know I have 2 dates for the current month and 90 dates for the current year. Right, Left, Outer, Inner I have tried them all, just throwing code at the wall trying to see what will stick and none of it works. I either get 2 for both columns or 180 for both columns. Here is my latest select statement.
SELECT count(a.evdtApplication) AS monthApplicationEntered,
count (b.evdtApplication) AS yearApplicationEntered
FROM tblEventDates a
RIGHT OUTER JOIN tblEventDates b ON a.LOANid = b.loanid
WHERE datediff(mm,a.evdtApplication,getdate()) = 0
AND datediff(yy,a.evdtApplication, getdate()) = 0
AND datediff(yy,b.evdtApplication,getdate()) = 0
You don't need any joins at all.
You want to count the loanID column from tblEventDates, and you want to do it conditionally based on the date matching the current month or the current year.
SO:
SELECT SUM( CASE WHEN Month(a.evdtApplication) = MONTH(GEtDate() THEN 1 END) as monthTotal,
count(*)
FROM tblEventDates a
WHERE a.evdtApplication BETWEEN '2008-01-01' AND '2008-12-31'
What that does is select all the event dates this year, and add up the ones which match your conditions. If it doesn't match the current month it won't add 1. Actually, don't even need to do a condition for the year because you're just querying everything for that year.