Group by in PIVOT operator - sql

Question

How do i use the group by clause in the PIVOT operator?
I tried with the following code but i get the null values and the results are not getting aggregated.
select EmpName, CHN,HYD FROM location
PIVOT (Sum(salary) for EmpLoc in ([CHN], [HYD]))
AS
pivottable
I want the final output to be like this.
CHN HYD
kunder 400 200
shetty 150 150
or
CHN HYD Total
kunder 400 200 600
shetty 150 150 300
Total 550 350 900

Answer 1

Just add the derived column Total=CHN+HYD and a sub-query to create the Total Row
The Seq (though not displayed) will put the Total row at the bottom
Declare #YourTable table (EmpLoc varchar(25),EmpName varchar(25),Salary int)
Insert Into #YourTable values
('HYD','kunder',200)
,('HYD','shetty',150)
,('CHN','shetty',150)
,('CHN','kunder',200)
,('CHN','kunder',200)
Select EmpName, CHN,HYD,Total=CHN+HYD
From (
Select Seq=0,EmpLoc,EmpName,Salary From #YourTable
Union All
Select Seq=1,EmpLoc,'Total',Salary From #YourTable
) A
pivot (sum(Salary) for EmpLoc in ([CHN], [HYD])) P
Returns
EmpName CHN HYD Total
kunder 400 200 600
shetty 150 150 300
Total 550 350 900

Answer 2

Declare #YourTable table (EmpLoc varchar(25),EmpName varchar(25),Salary int)
Insert Into #YourTable values
('HYD','kunder',200)
,('HYD','shetty',150)
,('CHN','shetty',150)
,('CHN','kunder',200)
,('CHN','kunder',200)
;with cte as
(
SELECT * from
(
select * from #YourTable
) as y
pivot
(
sum(salary)
for EmpLoc in ([CHN], [HYD])
) as p
)
SELECT
EmpName,sum(CHN)CHN ,sum(HYD)HYD
FROM CTE
GROUP BY EmpName;

Answer 3

I have no issue using your code from your example to get your desired results. I am guessing that your query is not as simple as your example, and as such is introducing other complications not shown here.
You may need to use a subquery and pivot using just the columns necessary for the pivot and join back to the rest of your query to get the results you are looking for using pivot().
Using conditional aggregation may be a simpler solution:
select
empname
, CHN = sum(case when emploc = 'CHN' then salary else 0 end)
, HYD = sum(case when emploc = 'HYD' then salary else 0 end)
--, Total = sum(salary) /* Optional total */
from location
group by empname
rextester demo: http://rextester.com/LYRH81756
returns:
+---------+-----+-----+
| EmpName | CHN | HYD |
+---------+-----+-----+
| kunder | 400 | 200 |
| shetty | 150 | 150 |
+---------+-----+-----+