I have a timequery that has the following.
ID, StaffName, PName, Description, startd1, endd1, startt1, endt1, startd2, endd2, startt2, endt2, startd3, endd3, startt3, endt3, startd4, endd4, startt4, endt4, startd5, endd5, startt5, endt5
I need to split the row so it will show
ID, StaffName, PName, Description, startd1, endd1, startt1, endt1
ID, StaffName, PName, Description, startd2, endd2, startt2, endt2
ID, StaffName, PName, Description, startd3, endd3, startt3, endt3
ID, StaffName, PName, Description, startd4, endd4, startt4, endt4
ID, StaffName, PName, Description, startd5, endd5, startt5, endt5
Any help would be appreciated.
The generic way in SQL is to use union all:
select ID, StaffName, PName, Description, startd1 as startd, endd1 as endd, startt1 as startt, endt1 as endt
from t
union all
select ID, StaffName, PName, Description, startd2, endd2, startt2, endt2
from t
union all
select ID, StaffName, PName, Description, startd3, endd3, startt3, endt3
from t
union all
select ID, StaffName, PName, Description, startd4, endd4, startt4, endt4
from t
union all
select ID, StaffName, PName, Description, startd5, endd5, startt5, endt5
from t;
If you have a large table, there are more efficient methods. This requires scanning the table once for each subquery.
The column names come from the first subquery, which renames them so there are no numbers.
Related
I have data that I want to display similar to a cross-tab query but not quite. The data I have looks like this with each segment of data on a different row:
I want the data to be consolidated to be all on one row for each client, like this:
I've attempted this with a cross-tab query but I'm not wanting to total any of the fields and there are several data point for each product (Type, Name, PurchaseDate, etc).
Any help is greatly appreciated!
Not a very practical presentation of data but it is possible. Need a unique identifier field - autonumber should serve - I called it RID. Consider:
Query 1:
SELECT RID, ID, FirstName, LastName, Dept, ProductType AS Data, "PT" AS Cat FROM Table1
UNION SELECT RID, ID, FirstName, LastName, Dept, ProductName, "PN" FROM Table1
UNION SELECT RID, ID, FirstName, LastName, Dept, PurchaseDate, "PD" FROM Table1
UNION SELECT RID, ID, FirstName, LastName, Dept, PurchaseCost, "PC" FROM Table1
UNION SELECT RID, ID, FirstName, LastName, Dept, DeliveryDate, "DD" FROM Table1;
Query 2:
TRANSFORM First(Query1.Data) AS FirstOfData
SELECT Query1.ID, Query1.FirstName, Query1.LastName, Query1.Dept
FROM Query1
GROUP BY Query1.ID, Query1.FirstName, Query1.LastName, Query1.Dept
PIVOT DCount("*","Query1","ID=" & [ID] & " AND Cat='" & [Cat] & "' AND RID<" & [RID])+1 & [Cat];
However, there is a limit of 255 fields so there may be more data than can be handled.
How to merge the duplicate records in single rows.
You need aggregation :
select id, max(lname) as lname, max(fname) as fname, max(address) as address,
max(zip) as zip, max(city) as city, max(state) as state, max(phone)
from table t
group by id;
You can use aggregation:
select id, max(lname) as lname, max(fname) as fname, max(address) as address,
. . .
from t
group by id;
with a as (
select a.*, row_number() over (partition by department order by attributeID) rn
from attributes a),
e as (
select employeeId, department, attribute1, 1 rn from employees union all
select employeeId, department, attribute2, 2 rn from employees union all
select employeeId, department, attribute3, 3 rn from employees
)
select e.employeeId, a.attributeid, e.department, a.attribute, a.meaning,
e.attribute1 as value
from e join a on a.department=e.department and a.rn=e.rn
order by e.employeeId, a.attributeid
this query is written by Ponder Stibbons for the answer of this question. But i am too dizzy with it as i quite don't understand what is going on here. i am new to SQL . so i would appreciate if anyone can explain what is happening on this query . thank you
Basically he unpivots the data using 3 select statements (1 for each attribute) and UNION them together to make a common table expression so that he gets rows for each employees attribute.
select employeeId, department, attribute1, 1 rn from employees union all
select employeeId, department, attribute2, 2 rn from employees union all
select employeeId, department, attribute3, 3 rn from employees
The other table he using a window function to assign a number to attribute, department. He uses this number later to join back to his unpivoted data. He posted his code for the example.
select a.*, row_number() over (partition by department order by attributeID) rn
from attributes a
I would suggest you use his example data he provided and run the following. This will show you the CTEs. I think once you see that data it will make more sense.
with a as (
select a.*, row_number() over (partition by department order by attributeID) rn
from attributes a),
e as (
select employeeId, department, attribute1, 1 rn from employees union all
select employeeId, department, attribute2, 2 rn from employees union all
select employeeId, department, attribute3, 3 rn from employees
)
SELECT * from a
SELECT * from e
I need to write a query in sql server to data get like this.
Essentially it is group by dept, race, gender and then
SUM(employees_of_race_by_gender),Sum(employees_Of_Dept).
I could get data of first four columns, getting sum of employees in that dept is becoming difficult.
Could you pls help me in writing the query?
All these details in same table Emp. Columns of Emp are Emp_Number, Race_Name,Gender,Dept
Your "num_of_emp_in_race" is actually by Gender too
SELECT DISTINCT
Dept,
Race_name,
Gender,
COUNT(*) OVER (PARTITION BY Dept, Race_name, Gender) AS num_of_emp_in_race,
COUNT(*) OVER (PARTITION BY Dept) AS num_of_emp_dept
FROM
MyTable
You should probably have this
COUNT(*) OVER (PARTITION BY Dept, Gender) AS PerDeptRace
COUNT(*) OVER (PARTITION BY Dept, Race_name) AS PerDeptGender,
COUNT(*) OVER (PARTITION BY Dept, Race_name, Gender) AS PerDeptRaceGender,
COUNT(*) OVER (PARTITION BY Dept) AS PerDept
Edit: the DISTINCT appears to be applied before the COUNT (which would odd based on this) so try this instead
SELECT DISTINCT
*
FROM
(
SELECT
Dept,
Race_name,
Gender,
COUNT(*) OVER (PARTITION BY Dept, Race_name, Gender) AS num_of_emp_in_race,
COUNT(*) OVER (PARTITION BY Dept) AS num_of_emp_dept
FROM
MyTable
) foo
Since the two sums you're looking for are based on a different aggregation, you need to calculate them separately and join the result. In such cases I first build the selects to show me the different results, making it easy to catch errors early:
SELECT Dept, Gender, race_name, COUNT(*) as num_of_emp_in_race
FROM Emp
GROUP BY 1, 2, 3
SELECT Dept, COUNT(*) as num_of_emp_in_dept
FROM Emp
GROUP BY 1
Afterwards, joining those two is pretty straight forward:
SELECT *
FROM ( first statement here ) as by_race
JOIN ( second statement here ) as by_dept ON (by_race.Dept = by_dept.Dept)
I have a simple query on Oracle.
SELECT DISTINCT City, Name, Surname FROM Persons
Is there any alternative sql query for the same query without DISTINCT ?
Have a look at this article
Example as;
select City
from (
select City,
row_number() over
(partition by City
order by City) rownumber
from Persons
) t
where rownumber = 1
SELECT City, Name, Surname FROM Persons
UNION
SELECT City, Name, Surname FROM Persons
SELECT First(City), First(Name), First(Surname)
FROM Persons
GROUP BY City, Name, Surname