File input for select statement in shell scipt - sql

I have a text file which has inputs for select statement.
sqlplus -s $USERNAME/$PASSWORD#$HOST<< EOF
spool $DIRECTORY/UPDATE.xls
select acc,cr,dr from count where acc in $DIRECTORY/acc.txt;
spool off;
exit
EOF
Please let me know how to use the text file as input at highlighted part.

You can just use the back tics for that in combination with the cat command. So
select acc,cr,dr from count where acc in `cat $DIRECTORY/acc.txt`;

Related

variable passed to sql from shell is not working

My code is:
#!/bin/sh
cat tmp_ts.log | awk ' {print $8}'
lookup=$8
sqlplus -s "sys/Orcl1234 as sysdba" << EOF
SELECT tablespace_name FROM dba_tablespaces WHERE tablespace_name='$lookup';
exit;
EOF
and my output is:
IAM_OIM
no rows selected
In this variable lookup I have passed to select statement but it's not working.
My end result should be with select statement. See below the output of select query:
See below:
My end result should be this but that variable is not working in select statement.
#!/bin/sh
lookup="$(awk '/tablespace/{print $8;exit}' tmp_ts.log)"
echo "Querying database with lookup = $lookup"
sqlplus -s "sys/Orcl1234 as sysdba" <<EOF
SELECT tablespace_name FROM dba_tablespaces WHERE tablespace_name='$lookup';
exit;
EOF
You have to use awk's output to set lookup. The shell knows nothing about the $8 which was set in awk. Also, I have ensured that awk exits after the first matching line, so that there is no risk of returning multiple values, or simply empty lines as it did in your version.
You can fill lookup with a command like awk, sed or cut.
lookup=$(cut -d" " -f8 tmp_ts.log)
You should add some checks, like #Dario did (with an exit after the first match and only converting lines with tablespace, but what to do when no lines match?).
When you don't add the checks you can skip setting the $lookup:
sqlplus -s "sys/Orcl1234 as sysdba" << EOF
SELECT tablespace_name FROM dba_tablespaces
WHERE tablespace_name='$(sed 's/.*tablespace- //' tmp_ts.log)';
exit;
EOF

Why does the following sqlcmd call returns 0 rows when in a bat file? (passing manually)

I am having trouble writing up a batch script. I've narrowed it down to what seems to break and I am providing an example. The following code, when pasted into a console returns 10 rows:
set TESTRUNID=111222
set QUERY="select distinct col1 from Table where col2='%TESTRUNID%' and col3 LIKE '%es'"
start /B /wait sqlcmd -S dahost -U usr -P pwd -Q %QUERY% -o resfile.txt
When I put it in a batch script, it returns 0 rows!
#echo off
setlocal EnableDelayedExpansion
REM remark
REM remark
set TESTRUNID=111222
set QUERY="select distinct col1 from Table where col2='%TESTRUNID%' and col3 LIKE '%es'"
start /B /wait sqlcmd -S dahost -U usr -P pwd -Q %QUERY% -o resfile.txt
I think you are mixing up the use of the percent sign to mean (1) batch variable expansion, and (2) SQL wildcard. Inside a batch file, use a double %% sign for an SQL wildcard:
set QUERY="select distinct col1 from Table where col2='%TESTRUNID%' and col3 LIKE '%%es'"
The double % sign gets translated to a single % sign before it's passed to SQLCMD.

How to execute a query stored in a variable in SQL*Plus

Is there any way to pass a query to SQL*Plus through a variable?
I'm aware SQL*Plus has the capability to execute a file like:
sqlplus user/pass#db #filename
Within a kornshell script I'm trying to do:
query="select * from dual;"
sqlplus user/pass#db $query
There might have solution to do that BUT I can achieve the same goal using the following method.
[oracle#myserver Desktop]$ $ORACLE_HOME/bin/sqlplus -s jay/passsword#db <<!
select * from dual;
exit
!
D
-
X
Update, you can store the returned result in a variable as shown below.
query="select * from dual;"
var=$($ORACLE_HOME/bin/sqlplus -s jay/pass#db <<!
set pages 0
set head off
set feed off
$query
!
);

Pass shell variables to SQL statement

I want to pass shell variables to sql statement. Both shell script and SQL statement are present in the same script file.
I want the values of the variables retMonth, retLastDay and retPrvYear in the SQL statement.
Below is the code.
If I execute this, it prints - " partition_date between '01--' and '--' \ 0 0] 1 1] 12-DEC-14 1"
How can I have values of retMonth, retLastDay and retPrvYear in SQL statement?
echo $retMonth //This prints 07
echo $retLastDay //This prints 31
echo $retPrvYear //This prints 2015
count=$(sqlplus -s ${DBA_ORACLE_USER}/${DBA_ORACLE_PWORD}#${ORACLE_SID} <<END
#connect ${DBA_ORACLE_USER}/${DBA_ORACLE_PWORD}#${ORACLE_SID}
set serveroutput on
set linesize 1000
set heading off
set feedback off
define lastMonth=$retMonth
define lastYear=$retPrvYear
define lastDay=$retLastDay
SELECT count(1)
FROM MYTABLE
WHERE partition_date between '01-$lastMonth-$lastYear' and '$lastDay-$lastMonth-$lastYear'
);
END
)
Try using quoted shell variables directly without using define directives:
count=$(sqlplus -s "${DBA_ORACLE_USER}/${DBA_ORACLE_PWORD}#${ORACLE_SID}" <<END
set serveroutput on
set linesize 1000
set heading off
set feedback off
SELECT count(1)
FROM MYTABLE
WHERE partition_date between
"01-$retMonth-$retPrvYear" and "$retLastDay-$retMonth-$retPrvYear";
END
)

Store SQL query string into variable BASH

I have a select statement inside a bash script that returns the latest date in the DB. I run this query 4 times so I want to define it just once and assing the text to a variable.
#!/bin/bash
linux commands;
database_date=$(sqlplus -s/nolog $USER/$USER#BRMDPP <<END
set pagesize 0 feedback off verify off heading off echo off;
SELECT ...
exit;
END
)
commands that change the database date;
last_date=$(sqlplus -s/nolog $USER/$USER#BRMDPP <<END
set pagesize 0 feedback off verify off heading off echo off;
SELECT ...
exit;
END
)
commands that change the database date;
How can I store this big string $(sqlplus ... into one variable and use it again?
Thank you
One way would be to make use of a function:
foo() {
sqlplus -s/nolog $USER/$USER#BRMDPP <<END
set pagesize 0 feedback off verify off heading off echo off;
SELECT ...
exit;
END
}
and later invoke it by saying:
value=$(foo)
In order to get the value returned by the function, say echo "$value" (note that quoting variables is important).