SQL - extracting all pairs only once - sql

Question

Problem statement:
a table with N columns, K out of which are used in a criterion to determine pairs of rows
such a criterion involving the K columns can simply be if columns c_1, c2, .. c_k are equal for the two different rows part of a pair (the criterion itself is not relevant, only the fact that it must be used)
the requirement is to extract all potential pairs, but only once. This means that if for a row there are more than 2 potential other rows that can form a pair given the above criterion, then only one pair must be extracted
Simple example:
Input table:
A | B | C
x | y | z
w | y | z
u | y | z
u | v | z
v | v | z
Criterion: B and C columns must be the same for two rows to be part of a pair.
Output:
x | y | z
w | y | z
u | v | z
v | v | z
What hints do you have for solving the problem in pure SQL (or in the Oracle dialect, if specific features help)?

Answer 1

If you can use window analytic function:
CREATE TABLE TT1 (A VARCHAR(4), B VARCHAR(4), C VARCHAR(4))
INSERT INTO TT1 VALUES ('x','y','z')
INSERT INTO TT1 VALUES ('w','y','z')
INSERT INTO TT1 VALUES ('u','y','z')
INSERT INTO TT1 VALUES ('u','v','z')
INSERT INTO TT1 VALUES ('v','v','z')
INSERT INTO TT1 VALUES ('k','w','z')
SELECT A.A, A.B, A.C
FROM
(SELECT *, ROW_NUMBER() OVER (PARTITION BY B,C ORDER BY A DESC) RN, COUNT(*) OVER (PARTITION BY B,C ) RC
FROM TT1) A
WHERE A.RN <=2 AND RC>1
Output:
A B C
---- ---- ----
v v z
u v z
x y z
w y z

Answer 2

Use the COUNT() analytic function partitioning on those rows you want to match as pairs:
SELECT A, B, C
FROM (
SELECT t.*,
COUNT(*) OVER (
PARTITION BY B, C
ORDER BY A
ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW
) AS current_rn,
COUNT(*) OVER (
PARTITION BY B, C
ORDER BY A
ROWS BETWEEN UNBOUNDED PRECEDING AND 1 FOLLOWING
) AS next_rn
FROM table_name t
)
WHERE MOD( current_rn, 2 ) = 0
OR MOD( next_rn, 2 ) = 0;
Output:
A B C
- - -
u y z
w y z
u v z
v v z