Create a link to a part of a webpage in VB.Net - vb.net

How would I go about creating a link to a specific part of a webpage in a vb.net program?
I want it to act like the links in the contents page on Wikipedia.
The link will go here:
Private Sub LauncherHelp_MouseUp(ByVal sender As System.Object, ByVal e As System.Windows.Forms.MouseEventArgs)
If e.Button <> MouseButtons.Right Then Return
Dim cms = New ContextMenuStrip
Dim item1 = cms.Items.Add("Copy Link")
item1.Tag = 1
AddHandler item1.Click, AddressOf menuChoice_LauncherHelp
cms.Show(popuw_Link, e.Location)
End Sub
Private Sub menuChoice_LauncherHelp(ByVal sender As Object, ByVal e As EventArgs)
Dim item = CType(sender, ToolStripMenuItem)
Dim selection = CInt(item.Tag)
If selection = 1 Then
My.Computer.Clipboard.SetText("link") '<== The link goes here.'
MessageBox.Show("Link Copied to Clipboard.")
End If
End Sub
I'm grateful for any help.
Regards
T54
P.S. Please feel free to correct my spelling.

This is not related to VB. It is achieved with HTML anchors.
These are placed at the particular position within the HTML markup an being referenced in the link via hash tag #
For example you put <a href="#chapter1"> in the source of i.e. index.html and open it in the browser via index.html#chapter1
The browser will then scroll to the position of the anchor tag.

Related

Download Image under the Mouse pointer via WebBrowser

I'm navigating to Google Images using a WebBrowser control. The aim is to be able to right click on any image and download and populate a PictureBox background.
I have my own ContextMenuStrip with Copy on it and have disabled the built in context menu.
The issue I am having is that the coordinate returned from CurrentDocument.MouseMove are always relative to the first (top left) image.
So my code works correctly if the Image I want is the very first image on the page, however clicking on any other Images always returns the coordinates of the first image.
It would appear that the coordinates are relative to each Image rather than the page.
Private WithEvents CurrentDocument As HtmlDocument
Dim MousePoint As Point
Dim Ele As HtmlElement
Private Sub Google_covers_Load(sender As Object, e As EventArgs) Handles MyBase.Load
WebBrowser1.IsWebBrowserContextMenuEnabled = False
WebBrowser1.ContextMenuStrip = ContextMenuStrip1
End Sub
Private Sub WebBrowser1_Navigated(sender As Object, e As WebBrowserNavigatedEventArgs) Handles WebBrowser1.Navigated
CurrentDocument = WebBrowser1.Document
End Sub
Private Sub CurrentDocument_MouseMove(sender As Object, e As HtmlElementEventArgs) Handles CurrentDocument.MouseMove
MousePoint = New Point(e.MousePosition.X, e.MousePosition.Y)
Me.Text = e.MousePosition.X & " | " & e.MousePosition.Y
End Sub
Private Sub ContextMenuStrip1_Opening(sender As Object, e As System.ComponentModel.CancelEventArgs) Handles ContextMenuStrip1.Opening
Ele = CurrentDocument.GetElementFromPoint(MousePoint)
If Ele.TagName = "IMG" Then
CopyToolStripMenuItem.Visible = True
Else
CopyToolStripMenuItem.Visible = False
End If
End Sub
Private Sub CopyToolStripMenuItem_Click(sender As System.Object, e As System.EventArgs) Handles CopyToolStripMenuItem.Click
Dim ToImg = Ele.GetAttribute("src")
mp3_row_edit.PictureBox1.BackgroundImage = New System.Drawing.Bitmap(New IO.MemoryStream(New System.Net.WebClient().DownloadData(ToImg)))
ToImg = Nothing
End Sub
This code allow to use a standard WebBrowser control to navigate to the Google Image search page and select/download an Image with a right-click of the Mouse.
To test it, drop a WebBrowser Control and a FlowLayoutPanel on a Form and navigate to a Google Image search page.
Things to know:
WebBrowser.DocumentCompleted: This event is raised each time one of the Sub-Documents inside a main HtmlDocument page is completed. Thus, it can be raised multiple times. We need to check whether the WebBrowser.ReadyState = WebBrowserReadyState.Complete.
Read these note about this: How to get an HtmlElement value inside Frames/IFrames?
The images in the Google search page can be inserted in the Document in 2 different manners: both using a Base64Encoded string and using the classic src=[URI] format. We need to be ready to get both.
The mouse click position can be espressed in either absolute or relative coordinates, referenced by the e.ClientMousePosition or e.OffsetMousePosition.
Read the notes about this feature here: Getting mouse click coordinates in a WebBrowser Document
The WebBrowser emulation mode can be important. We should use the most recent compatible mode available in the current machine.
Read this answer and apply the modifications needed to have the most recent Internet Explorer mode available: How can I get the WebBrowser control to show modern contents?.
Note that an event handler is wired up when the current Document is completed and is removed when the Browser navigates to another page. This prevents undesired calls to the DocumentCompleted event.
When the current Document is complete, clicking with the right button of the Mouse on an Image, creates a new PictureBox control that is added to a FlowLayouPanel for presentation.
The code in the Mouse click handler (Protected Sub OnHtmlDocumentClick()) detects whether the current image is a Base64Encoded string or an external source URI.
In the first case, it calls Convert.FromBase64String to convert the string into a Byte array, in the second case, it uses a WebClient class to download the Image as a Byte array.
In both cases, the array is then passed to another method (Private Function GetBitmapFromByteArray()) that returns an Image from the array, using Image.FromStream() and a MemoryStream initialized with the Byte array.
The code here is not performing null checks and similar fail-proof tests. It ought to, that's up to you.
Public Class frmBrowser
Private WebBrowserDocumentEventSet As Boolean = False
Private base64Pattern As String = "base64,"
Private Sub frmBrowser_Load(sender As Object, e As EventArgs) Handles MyBase.Load
WebBrowser1.ScriptErrorsSuppressed = True
WebBrowser1.IsWebBrowserContextMenuEnabled = False
End Sub
Private Sub WebBrowser1_DocumentCompleted(sender As Object, e As WebBrowserDocumentCompletedEventArgs) Handles WebBrowser1.DocumentCompleted
If WebBrowser1.ReadyState = WebBrowserReadyState.Complete AndAlso WebBrowserDocumentEventSet = False Then
WebBrowserDocumentEventSet = True
AddHandler WebBrowser1.Document.MouseDown, AddressOf OnHtmlDocumentClick
End If
End Sub
Protected Sub OnHtmlDocumentClick(sender As Object, e As HtmlElementEventArgs)
Dim currentImage As Image = Nothing
If Not (e.MouseButtonsPressed = MouseButtons.Right) Then Return
Dim source As String = WebBrowser1.Document.GetElementFromPoint(e.ClientMousePosition).GetAttribute("src")
If source.Contains(base64Pattern) Then
Dim base64 As String = source.Substring(source.IndexOf(base64Pattern) + base64Pattern.Length)
currentImage = GetBitmapFromByteArray(Convert.FromBase64String(base64))
Else
Using wc As WebClient = New WebClient()
currentImage = GetBitmapFromByteArray(wc.DownloadData(source))
End Using
End If
Dim p As PictureBox = New PictureBox() With {
.Image = currentImage,
.Height = Math.Min(FlowLayoutPanel1.ClientRectangle.Height, FlowLayoutPanel1.ClientRectangle.Width)
.Width = .Height,
.SizeMode = PictureBoxSizeMode.Zoom
}
FlowLayoutPanel1.Controls.Add(p)
End Sub
Private Sub WebBrowser1_Navigating(sender As Object, e As WebBrowserNavigatingEventArgs) Handles WebBrowser1.Navigating
If WebBrowser1.Document IsNot Nothing Then
RemoveHandler WebBrowser1.Document.MouseDown, AddressOf OnHtmlDocumentClick
WebBrowserDocumentEventSet = False
End If
End Sub
Private Function GetBitmapFromByteArray(imageBytes As Byte()) As Image
Using ms As MemoryStream = New MemoryStream(imageBytes)
Return DirectCast(Image.FromStream(ms).Clone(), Image)
End Using
End Function
End Class

combox selected index didnt work on picturebox

Now what i was doing is when i click a button group box 1 and group box 2 will show out i want to select the combobox item than the picturebox item will load
and this can be used it multiple time like when button-5 clicked the combobox item name will change and the picture will change too.
Private Sub Button4_Click(sender As Object, e As EventArgs) Handles Button4.Click
GroupBox1.Show()
GroupBox2.Show()
comboboxselectdiffrent.Items.Add("pizza_ChickenSupreme")
comboboxselectdiffrent.Items.Add("pizza_CockadoodleBacon")
If comboboxselectdiffrent.SelectedIndex = 0 Then
PictureBox1.Image = PIZZA_HUT_SYSTEM_NEW_VER.My.Resources.Resources.pizza_ChickenSupreme
ElseIf comboboxselectdiffrent.SelectedIndex = 1 Then
PictureBox1.Image = PIZZA_HUT_SYSTEM_NEW_VER.My.Resources.Resources.pizza_CockadoodleBacon
End If
End Sub
Can anyone tell me what i was do wrong? i have no idea why it wont work
After looking at your code personality I would have the event trigger from the combobox click, that way it will save the user having to first click on the combo to select their pizza and then having to click on a button to load the picture & details. Nevertheless try this.
Public Class Form1
Private Sub Form1_Load(sender As Object, e As EventArgs) Handles MyBase.Load
ComboBox1.Items.Add("pizza_ChickenSupreme")
ComboBox1.Items.Add("pizza_CockadoodleBacon")
ComboBox1.DropDownStyle = ComboBoxStyle.DropDownList
End Sub
Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
GroupBox1.Show()
GroupBox2.Show()
Select Case ComboBox1.SelectedItem
Case Is = "pizza_ChickenSupreme"
PictureBox1.ImageLocation = "Pictures/mypic.jpg"
Case Is = "pizza_CockadoodleBacon"
PictureBox1.ImageLocation = "Pictures/mypic1.jpg"
End Select
End Sub
End Class
Using a custom Folder within the solution explorer will be better than using a setting resource. Create a folder and drag your pictures into it and change the name of the image location to suit your needs.
Also i think using the items name is better than the items index because what happens if someone reason that indexed item is to change from 1 to 5, you would have to recode it all, but by using the items name, it has more detail as to what to look for.
If you have any problems, leave a comment and I will do my best to help you out.Happy Coding!

How to get the filepath of an image dropped onto a button in VB

I am attempting to get the filepath of an image that is dropped onto a button in VB. I have set the button to allow drop and I have set up this segment to hold the event code:
Private Sub btnDropZone_drop(sender As Object, e As EventArgs) Handles btnDropZone.DragDrop
End Sub
How would I go about getting the filepath from this event as a string? Thanks in advance!
A button is a pretty small drop target, but it would work the same as anything else: examine e As DragEventArgs:
Private Sub btnDropZone_drop(sender As Object,
e As EventArgs) Handles btnDropZone.DragDrop
'ToDo check the format to see what was dropped
Dim Files As String() = CType(e.Data.GetData(DataFormats.FileDrop), String())
For Each s As String In Files
ListBox1.Items.Add(Path.GetFileName(s))
Next
End Sub
When you are trying to figure out what to do in an event, always look up the meaning and contents of the eventargs

Text is selected in the text box

When I load the form where some text has been given to text box. All the text in that textbox is highlighted. I want vb not to load it this way.
How to fix it.
Thanks
Furqna
You could set the tab index on your textbox to something else so that it's not the lowest index.
You could set the TextBox1.SelectionLength = 0 in the form.activated event.
I don't like this as much because if the user had the text hilited and minized the application then they will lose the hilite, but is fairly easy to do. I guess you could use a flag to make sure it only did it on the first activate.
You could set a timer event in the load to clear it immediately after the load event, but that seems like overkill. I have worked at places where they had a standard function that happened on every form 100 ms after load because of problems such as this.
You could try this(it looks like a workaround):
Private Sub TextBox1_GotFocus(ByVal sender As Object, ByVal e As System.EventArgs) Handles TextBox1.GotFocus
TextBox1.SelectionStart = TextBox1.Text.Length
End Sub
It depends on the TabIndex of your TextBox, if it has the lowest TabIndex it gets focus and therefore it's Text is selected.
' VS.net 2013. Use the "Shown" event.
' GotFocus isn't soon enough.
Private Sub Form_Shown(sender As Object, e As EventArgs) Handles Me.Shown
TB.SelectionLength = 0
End Sub
Type 1 Method
Dim speech = CreateObject("sapi.spvoice")
speech.speak(TextBox1.Text)
Type 2 Method
Dim oVoice As New SpeechLib.SpVoice
Dim cpFileStream As New SpeechLib.SpFileStream
'Set the voice type male or female and etc
oVoice.Voice = oVoice.GetVoices.Item(0)
'Set the voice volume
oVoice.Volume = 100
'Set the text that will be read by computer
oVoice.Speak(TextBox1.Text, SpeechLib.SpeechVoiceSpeakFlags.SVSFDefault)
oVoice = Nothing
Type 3 Method
Imports System.Speech.Synthesis
Public Class Form1
Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
Dim spk As New SpeechSynthesizer
For Each voice As InstalledVoice In spk.GetInstalledVoices
ListBox1.Items.Add(voice.VoiceInfo.Name)
Next
ListBox1.SelectedIndex = 0
End Sub
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim spk As New SpeechSynthesizer
spk.SelectVoice(ListBox1.SelectedItem.ToString)
spk.Speak(TextBox1.Text)
End Sub
End Class
This will also happen sometimes if The TextChanged or other similar Event is fired twice for the control.
When creating each form. Each object is indexed you can set the tab Index higher then the indexed object. Example: On the third form you put a text box in.
private void textBox1_TextChanged(object sender, EventArgs e)
This was the 12th object in the project, it would be indexed at 12. if you put the tab index higher then the indexed objects throughout the project. Tab index 1000 (problem solved.)
Have a great day.
Scooter

RichTextBox in VB.NET

I want set a line of text link in rich text box of vb.net. Like for example: I want to know you
The word want, I want to set a link word.
Can I do that?
This is how I would do it.
Dim linkLa As New LinkLabel
linkLa.LinkColor = Color.Red
Dim link As LinkLabel.Link = linkLa.Links.Add(0, 13, "http://www.stackoverflow.com")
linkLa.Text = "Stackoverflow"
AddHandler linkLa.LinkClicked, AddressOf Link_Clicked
richTextBox1.Controls.Add(linkLa)
Private Sub Link_Clicked(ByVal sender As Object, ByVal e As EventArgs)
MessageBox.Show("clicked")
End Sub
I have an answer for you. This will allow you to show the link target address as a tooltip. (little pop up bubble.) Other than that, it's similar to Stan R.'s answer.
Put this code under the "add link" button (or whatever you're calling it) in your program
Note: I put comments before each line, so it's easier to follow!
'define the text and link targets
Dim linktext As String = LinkTextbox.Text 'LinkTextbox is just the textbox where the user inputs the text of the link
Dim linktarget As String = LinkTargetTextbox.Text 'LinkTargetTextBox is just the textbox where the user inputs the target URL of the link
'Define the LinkLabel
Dim lnk As New LinkLabel
'if you want, you can set the different properties, like font or linkcolor, programmatically after defining the linklabel, for instance:
lnk.LinkColor = Color.Blue
'set tooltip
lnk.Tooltip = linktarget
'set the link target
Dim lk As LinkLabel.Link = lnk.Links.Add(0, 13, linktarget)
'set the link text
lnk.Text = linktext
'EventHandler
AddHandler lnk.LinkClicked, AddressOf LinkClicked
'Add the control to the richtextbox
RichTextBox1.Controls.Add(lnk)
'This is the Subroutine that the label will run when clicked (Make sure to put your "End Sub" before this, because it's not part of the button's subroutine)
Private Sub LinkClicked(ByVal sender As Object, ByVal e As EventArgs)
'send link to the browser
Process.Start(linktarget)
End Sub