I am a admin of a bio-metric device, there are 3 shifts are going in my office.
In time Out time Date
Shift1 6AM 2PM 5th April
Shift2 2PM 10PM 5th April
Shift3 10PM 5th April 6AM 6th April
but the 3rd shift time intime 10PM is taking as
In time Out Time
day1 out time 10PM
day2 in time 6AM
How can I make it for same date 10PM as intime and 6AM as out time in excel?
And also I want to generate it automatically.
I want the Out Time must shown as the same date.
Date Intime Outtime
5.4.17 6AM 2PM
5.4.17 2PM 10PM
5.4.17 10PM 6AM
And I want to automate the report while generating from web.
=Now() will generate a number (double type) like 42832.8008217593 where the date is shown on the left of the period and the time on the right. 10 PM (22:00:00) will be expressed as 0.9166666667. Add 8 hours to this number (1/24*8) and the result is 1.25 which means, in plain language, "next day 6 AM".
To solve your problem you can use a condition, like, If the end time is on the next day, deduct one day from the result date. This would mean 1.25 - 1 = 0.25 = 6:00AM on the day which is one day earlier than it actually is. Whether your end time is a proper date/time, like 42833.25 or a relative time like 1.25 depends upon how you enter your data.
You can extract the time from the date/time value by calculating (Date/Time - Int(Date/Time), like 1.25 - Int(1.25) = 1.25 -1 = 0.25
Related
I am trying to query this data set of hourly price date. The dataset defined daily prices at 12am - 12am UTC time, I am trying to define the days at 4pm - 4pm UTC time. Therefore I need to get the high and the low prices for each day between ex: '2021-12-15 16:00:00' and '2021-12-16 15:00:00' as that would be the open and close of the trading day.
I have this right now:
SELECT convert(date,dateadd(S, TimeStamp/1000, '1970-01-01')) as 'date'
,symbol
,Max([high]) as 'Max'
,Min([low]) as 'Min'
FROM [Crypto].[tblMessariPriceHistory]
WHERE symbol = 'DOGE'
and dateadd(S, TimeStamp/1000, '1970-01-01') between '2021-12-15 16:00:00' and '2021-12-16 15:00:00'
Group By convert(date,dateadd(S, TimeStamp/1000, '1970-01-01')),symbol
But it results like this:
date
symbol
Max
Min
2021-12-15
DOGE
0.175059052503167
0.170510833636204
2021-12-16
DOGE
0.180266282681554
0.177596458601872
I could just group by Symbol but I want to be able to do this over multiple days, and that wouldn't work.
Any ideas on how to define a select date range as a group or table over multiple days?
If you think about it, subtracting 16 h off every time would slide the time back to some time within the "starting day"
Monday 16:00 becomes midnight Monday
Monday 23:59 becomes 7:59 Monday
Tuesday 00:00 becomes 8:00 Monday
Tuesday 15:59 becomes 23:59 Monday
Tuesday 16:00 becomes midnight Tuesday
Anyway, once you've slid your time backwards 16h, you can just chop the time part off by dividing the unix time stamp by the number of milliseconds in a day and all the trades between Monday 16:00 and Tuesday 15:59:59.999 will go down as "Monday". If it were a DateTime we could cast it to a Date to achieve the same thing. It's handy to find ways of treating datetimes as decimal numbers where the integral is the date and the fractional is the time because chopping it to an int discards the time and allows daily aggregating. If you wanted hourly aggregating, adjusting the number so it represents the number of hours and fractions of an hour (divide by 3600000, the number of milliseconds in an hour) helps to the same end
--take off 16h then truncate to number of days since epoch
SELECT
(timestamp-57600000)/86400000 as timestamp,
symbol,
min(low) as minlow,
max(high) as maxhigh
FROM trades
GROUP BY (timestamp-57600000)/86400000 as timestamp, symbol
I am using postgres and wondering how I should store schedule time blocks in a way that allows me to do the following:
If I have a schedule with 3 time blocks:
Monday 8am to 12pm
Monday 10am to 4pm
Thursday 8am to 12pm
And I am trying to find all schedules between Monday and Wednesday that start at 8am.
I am storing the time_blocks as array, and I am not sure how to query them.
I suggest three columns:
dow - Day of the week as integer or string. Either would work, integer is best for storage and performance. (0 - 6; Sunday is 0)
from - time type, time of day
to - time type, time of day
Then you can select this way:
SELECT
*
FROM
"schedule"
WHERE
-- Mon, Tue, Wed
"dow" IN (1,2,3) AND
'08:00:00'::time = "from"
You could search for 8am or earlier this way:
'08:00:00'::time BETWEEN "from" AND "to"
I'm working on a booking platform which has several different rates. These rates are determined by the time of day, day of week, and day of year. Here are some examples of the interval types involved:
Monday to Friday, 9am to 5pm
Saturday and Sunday, 12am to 9am
Saturday and Sunday, 9am to 5pm
Saturday and Sunday, 5pm to 12am
December 23rd & 24th, anytime
December 26th & 27th, anytime
What is the best way to represent this, such that it's possible to query for the different effective rates on any given day?
At the moment, the way I've done is using two array type columns, days_of_week[] and hours_of_day[], populating them with the days/hours each rate applies. To account for special cases like December, I also have fields valid_from and invalid_after, however this requires a new entry for each year.
I've had a look at the datetime functions for intervals and such here but haven't seen anything that looks like it could solve this.
why not just listing them in where clause? eg for first sample:
t=# select now(),extract('dow' from now()) between 1 and 5 and now()::time between '09:00' and '17:00';
now | ?column?
-------------------------------+----------
2017-11-27 16:56:01.544642+00 | t
so you take (extract('dow' from now()) between 1 and 5 and now()::time between '09:00' and '17:00') to brackets and add same brackets over OR...
You can addthem all to a function with timestamptz as argument and return true of false to use in where clause
I need to subtract two dates (including hours and minutes), but I only need to consider working hours. That is, I need to omit lunch time (from 13 to 14 hrs), weekends and hours after 18 hrs and before 9 hrs of the following day, in a working day (from Mo to Fr). Any thoughts?
I don't mind if it's an Excel formula or a vba code.
I have this formula, but it doesn't omit lunch time:
9*(NETWORKDAYS(initial_time;ending_time)-1)-24*((MOD(initial_time;1)-MOD(ending_time;1)))
Here's a possible solution. It assumes an 8 hour work days for all but the start and end date. Also that start date/time is 9:00 or after and end date/time is 18:00 or earlier and that both are on a weekday.
=(NETWORKDAYS(A2,B2)-2)*8+IF(MOD(A2,1)>0.58333,(TIME(18,0,0)-MOD(A2,1))*24,(TIME(18,0,0)-MOD(A2,1))*24-1)+IF(MOD(B2,1)>0.58333,(MOD(B2,1)-TIME(9,0,0))*24-1,(MOD(B2,1)-TIME(9,0,0))*24)
.58333 equates to 14:00. The formula:
multiplies networkdays * 8
+ hours from start date/time until 18:00 subtracting 1 hour if start time is before 14:00
+ hours from 9:00 until end date/time subtracting 1 hour if end time is after 14:00
Of course this doesn't take any holidays into account.
Imagine I had a work schedule from 9am to 6pm. It is divided into 15 minute blocks and appointments (increments of 15 minutes) can be fitted into the times available.
Now, if I need to insert a new appointment that is 45 minutes long is there an easy query to find a block of time that is available to fit the appointment in for a given date
The basic table design is
AppointmentId
Date
StartTime
Length - 15 minute incremenents
I would like to get a list of available times to choose from, so if the only appointment for the given day is a 30 minute one at 9:30 then the list of times would be
(No times before 9:30 as the 45 minute appointment wont fit)
10:15
10:30
10:45
...
5:15pm (last time of the day the appointment will fit)
By using ranking function (i.e Row_Number()) set number for each row in each day (let say it's name is rn), then join this query with it self by this condition q2.rn = q1.rn-1 then you have end of appointment beside start of next appointment, then calculate datediff(mi) on this end and start, so this value is the gap, then write another query wrapping this query to filter records that have gap >= yourNeededTime. Also for start of day and end of day you can create 2 dummy records one for 9am and one for 6pm so that yo can handle gap of start of day to the first appointment and last appointment to the end of day.
I hope this helps