How to exponential increase every other years salary on a Column #SQL - sql

Question

Im trying to exponential increase every other years salary by %5.
for example: In my table i have 10 rows, which represents 10 years, there is a salary column in that table, i would like to write a code which will increase the salary every year by % 5 : so that it should look like this in every other row.
Year Salary
2014 10000
2015 10500
2016 11025
Anyone can help me with this please, I appreciate your time folks, have a good weekend.

Answer 1

What you have is essentially the compound interest. So use the formula to make it simple:
with years as (
select year from (values (2014),(2015),(2016),(2017)) y(year)
),
starting_salary as (
select cast(10000.0 as float) as salary
)
select
year,
starting_salary.salary * power(cast(1 + 0.05 as float), row_number() over(order by year) - 1)
from
years
cross join starting_salary
order by year;

Answer 2

You can use a recursive CTE to calculate the exponentially increased salaries for all the years in your table:
declare #salaries table (salaryYear int, salary int);
declare #minYear int, #maxYear int;
insert #salaries values (2006, 10000), (2007, NULL), (2008, NULL), (2009, NULL)
, (2010, NULL), (2011, NULL), (2012, NULL), (2013, NULL)
, (2014, NULL), (2015, NULL), (2016, NULL);
select #minYear = min(salaryYear)
, #maxYear = max(salaryYear)
from #salaries;
;with salaries as (
select salaryYear
, salary
from #salaries
where salaryYear = #minYear
union all
select salaryYear + 1
, salary * 105 / 100
from salaries
where salaryYear <= #maxYear
)
select *
from salaries

Answer 3

Similar to Radu, assuming an ID for several workers. The column SALARY is showed just for check
CREATE TABLE SAL (ID INT, YEAR SMALLINT, SALARY NUMERIC(10,2))
INSERT INTO SAL VALUES (1, 2014, 10000)
INSERT INTO SAL VALUES (1, 2015, 10000)
INSERT INTO SAL VALUES (1, 2016, 10000)
INSERT INTO SAL VALUES (1, 2017, 10000)
INSERT INTO SAL VALUES (2, 2014, 20000)
INSERT INTO SAL VALUES (2, 2015, NULL)
INSERT INTO SAL VALUES (2, 2016, NULL)
INSERT INTO SAL VALUES (2, 2017, NULL)
WITH X1 AS
(
SELECT ID, YEAR, SALARY, CAST(SALARY*1.05 AS NUMERIC(10,2)) AS SAL_UPD
FROM SAL
WHERE YEAR=2014
UNION ALL
SELECT A.ID, A.YEAR, A.SALARY, CAST(X1.SAL_UPD*1.05 AS NUMERIC(10,2)) AS SAL_UPD
FROM SAL A
INNER JOIN X1 ON A.YEAR = X1.YEAR+1 AND A.ID=X1.ID
WHERE A.YEAR>2014
)
SELECT * FROM X1
ORDER BY ID, YEAR
Output:
ID YEAR SALARY SAL_UPD
----------- ------ --------------------------------------- ---------------------------------------
1 2014 10000.00 10500.00
1 2015 10000.00 11025.00
1 2016 10000.00 11576.25
1 2017 10000.00 12155.06
2 2014 20000.00 21000.00
2 2015 NULL 22050.00
2 2016 NULL 23152.50
2 2017 NULL 24310.13
Deleting a year, the query for that ID stops:
DELETE FROM SAL WHERE YEAR=2016 AND ID = 2
ID YEAR SALARY SAL_UPD
----------- ------ --------------------------------------- ---------------------------------------
1 2014 10000.00 10500.00
1 2015 10000.00 11025.00
1 2016 10000.00 11576.25
1 2017 10000.00 12155.06
2 2014 20000.00 21000.00
2 2015 NULL 22050.00