I have a circle that has a fixed diameter and center. What I need to do now is to insert the circle into the given range. Eg, given 11 boxes of column and 10 boxes of rows to be inserted in excel cell. After entering the given range, the circle will be within the selected range with its fixed center but the boxes would have different measurement for its height and width. My question is how do I insert the circle into any given range (as in 11 x 10 or 9 x 12) with different height and width of the cells?
My code:
Sub DrawCircleWithCenter()
Dim cellwidth As Single
Dim cellheight As Single
Dim ws As Worksheet
Dim rng As Range
Dim Shp2 As Shape
CellLeft = Selection.Left
CellTop = Selection.Top
ActiveSheet.Shapes.AddShape(msoShapeOval, CellLeft, CellTop, 565 / 2, 565 / 2).Select
Selection.ShapeRange.Fill.Visible = msoFalse
With Selection.ShapeRange.Line
.Visible = msoTrue
.ForeColor.RGB = RGB(0, 0, 0)
.Transparency = 0
End With
i = 182
Set Shp2 = ActiveSheet.Shapes.AddShape(i, CellLeft, CellTop, 20, 20)
Shp2.ShapeStyle = msoShapeStylePreset1
Set rng = ActiveWindow.VisibleRange
Selection.Left = rng.Width / 2 - Selection.Width / 2
Selection.Top = rng.Height / 2 - Selection.Height / 2
Shp2.Left = rng.Width / 2 - Shp2.Width / 2
Shp2.Top = rng.Height / 2 - Shp2.Height / 2
End Sub
If I'm understanding you correctly this could be what you're after:
Sub DrawCircleWithCenter(rng As Range)
Dim Shp1 As Shape, Shp2 As Shape
Set Shp1 = ActiveSheet.Shapes.AddShape(msoShapeOval, rng.Left, rng.Top, rng.Width, rng.Height)
Shp1.Fill.Visible = msoFalse
With Shp1.Line
.Visible = msoTrue
.ForeColor.RGB = RGB(0, 0, 0)
.Transparency = 0
End With
Set Shp2 = ActiveSheet.Shapes.AddShape(182, rng.Left, rng.Top, 20, 20)
Shp2.ShapeStyle = msoShapeStylePreset1
Shp1.Left = rng.Left
Shp1.Top = rng.Top
Shp2.Left = rng.Left + rng.Width / 2 - Shp2.Width / 2
Shp2.Top = rng.Top + rng.Height / 2 - Shp2.Height / 2
End Sub
Sub Test()
Dim rng As Range
Set rng = Selection
DrawCircleWithCenter rng
End Sub
You can modify the Test subroutine to supply the range you're after. In the above case I use the selection that the user has highlighted in the present worksheet to draw the cross and oval centered inside it. If you choose a square area the oval becomes a circle, with a rectangular area it'll be squashed into an ellipse. It'll also work if you have varying cell widths and heights in the range you select.
Related
I have a spreadsheet that involves the user resizing some rectangular shapes, which are set on a background of an Excel grid with column width = row height = 10pixels. The purpose of this background is to give a scale to the plan, which is made by the shapes; in this case, one column or row represents 10cm - there is a thick border after every 10 cells to represent a metre:
When the user resizes the rectangle, I would like the text inside the rectangle to display the dimensions, according to the scale of the plan. I have read many articles about how the shapes dimensions are provided in points, and the columns and rows in pixels (or a unit based on the font), and have found the conversion function between them, but it does not seem to give the results I would expect - the values for the width and height depend on the level of zoom, giving smaller and smaller results as I zoom out, even though the displayed pixel width remains the same.
Is there a way to consistently convert the pixel units of the grid to the points unit of the shapes such that I can essentially count how many column widths and row heights comprise the shape dimensions? Here is the macro I have written so far:
Option Explicit
Dim sh As Shape
Dim dbPx_Per_Unit As Double
Dim strUnit As String
Dim UserSelection As Variant
Dim strText As String
Dim strWidth As String
Dim strHeight As String
Sub LabelShapeSize()
Set UserSelection = ActiveWindow.Selection
'is selection a shape?
On Error GoTo NoShapeSelected
Set sh = ActiveSheet.Shapes(UserSelection.Name)
On Error Resume Next
'pixels are the units for the columns and rows
'dbPx_Per_Unit = InputBox("there are this many pixels per unit:", "Conversion Rate", 10)
dbPx_Per_Unit = 100
'strUnit = InputBox("Unit Name:", "Units", "M")
strUnit = "M"
With sh
'Width and length is measured in points, so we need to convert the points to pixels to get the actual size
strWidth = Format(Application.ActiveWindow.PointsToScreenPixelsX(.Width) / dbPx_Per_Unit, "#,##0.0")
strHeight = Format(Application.ActiveWindow.PointsToScreenPixelsY(.Height) / dbPx_Per_Unit, "#,##0.0")
'this is our message that will be in the shape
strText = strWidth & strUnit & " x " & strHeight & strUnit
With .TextFrame2
.VerticalAnchor = msoAnchorMiddle
With .TextRange.Characters
.ParagraphFormat.FirstLineIndent = 0
.ParagraphFormat.Alignment = msoAlignCenter
.Text = strText
'I'll sort something out for dark shapes at some point, but for now let's just write in black ink
With .Font
.Fill.Visible = msoTrue
.Fill.ForeColor.ObjectThemeColor = msoThemeColorDark1
.Fill.Solid
.Size = 10
End With
End With
End With
End With
Exit Sub
'No shape error
NoShapeSelected:
MsgBox "You must select a shape to calculate dimensions!", vbCritical, "Object not set to an instance of a Nobject"
End Sub
****** for completeness, here is the final script I wrote implementing the solution in the answer below ******
Option Explicit
Dim sh As Shape
Dim db_Cols_Per_Unit As Double
Dim strUnit As String
Dim strText As String
Dim userSelection As Variant
Dim ws As Worksheet
Dim clrBackground As Long
Dim leftCol As Integer
Dim colWidth As Integer
Dim topRow As Integer
Dim rowHeight As Integer
Sub LabelShapeSize()
Set userSelection = ActiveWindow.Selection
Set ws = ActiveSheet
db_Cols_Per_Unit = 10
strUnit = "M"
'is selection a shape?
On Error GoTo NoShapeSelected
Set sh = ActiveSheet.Shapes(userSelection.Name)
On Error Resume Next
topRow = 1
rowHeight = 0
leftCol = 1
colWidth = 0
With sh
While ws.Cells(1, leftCol).Left <= .Left 'Move left until we find the first column the shape lies within
leftCol = leftCol + 1
Wend
While ws.Cells(1, leftCol + colWidth).Left <= .Left + .Width 'Continue moving left until we find the first column the shape does not lie within
colWidth = colWidth + 1
Wend
While ws.Cells(topRow, 1).Top <= .Top 'Move down until we find the first row the shape lies within
topRow = topRow + 1
Wend
While ws.Cells(topRow + rowHeight, 1).Top <= .Top + .Height 'Continue moving down until we find the first row the shape does not lie within
rowHeight = rowHeight + 1
Wend
'this is our message that will be in the shape
strText = Format(colWidth / db_Cols_Per_Unit & strUnit, "#,##0.0") & " x " & rowHeight / Format(db_Cols_Per_Unit, "#,##0.0") & strUnit
clrBackground = .Fill.ForeColor.RGB
With .TextFrame2
.VerticalAnchor = msoAnchorMiddle
With .TextRange.Characters
.ParagraphFormat.FirstLineIndent = 0
.ParagraphFormat.Alignment = msoAlignCenter
.Text = strText
With .Font
.Fill.Visible = msoTrue
.Fill.ForeColor.RGB = ContrastColor(clrBackground)
.Fill.Solid
.Size = 10
End With
End With
End With
End With
Exit Sub
'No shape error
NoShapeSelected:
MsgBox "You must select a shape to calculate dimensions!", vbCritical, "Object not set to an instance of a Nobject"
End Sub
Function ContrastColor(clrBackground As Long) As Long
Dim brightness As Integer
Dim luminance As Double
Dim r As Integer
Dim g As Integer
Dim b As Integer
r = clrBackground Mod 256
g = (clrBackground \ 256) Mod 256
b = (clrBackground \ 65536) Mod 256
luminance = ((0.199 * r) + (0.587 * g) + (0.114 * b)) / 255
If luminance > 0.5 Then
brightness = 0
Else
brightness = 255
End If
ContrastColor = RGB(brightness, brightness, brightness)
End Function
thanks to #Gacek answer in this question for the luminance function.
I believe your best bet would be to make use of the Left, Top, Width, and Height cell properties. They'll tell you the value in Excel's weird format (the same units as used by the shapes), so you won't need to do any conversions.
The downside is that as far as I know of, there's no way to get the row/column that exists at a given top/left value, so you need to search through all the rows/columns until you find the one that matches your shape's boundaries.
Here's a quick example (there's probably an off-by-one error in here somewhere)
Dim UserSelection As Variant
Dim ws As Worksheet
Dim sh As Shape
Dim leftCol As Integer
Dim colWidth As Integer
Dim topRow As Integer
Dim rowHeight As Integer
Set ws = ActiveSheet
Set UserSelection = ActiveWindow.Selection
Set sh = ActiveSheet.Shapes(UserSelection.Name)
leftCol = 1
colWidth = 0
While ws.Cells(1, leftCol).Left <= sh.Left 'Move left until we find the first column the shape lies within
leftCol = leftCol + 1
Wend
While ws.Cells(1, leftCol + colWidth).Left <= sh.Left + sh.width 'Continue moving left until we find the first column the shape does not lie within
colWidth = colWidth + 1
Wend
topRow = 1
rowHeight = 0
While ws.Cells(topRow, 1).Top <= sh.Top 'Move down until we find the first row the shape lies within
topRow = topRow + 1
Wend
While ws.Cells(topRow + rowHeight, 1).Top <= sh.Top + sh.height 'Continue moving down until we find the first row the shape does not lie within
rowHeight = rowHeight + 1
Wend
MsgBox "Shape is " & colWidth & " columns wide by " & rowHeight & " rows high"
I am using a macro to insert a chart into a spreadsheet:
Option Explicit
Sub Macro1()
Dim overskrifter As Range
Dim i As Long
Dim høgde As Long, breidde As Long
Call fjernkurver
i = 1
høgde = 240: breidde = 350
Set overskrifter = Oppsummering.Range("C5:L5")
With Kurver.Shapes.AddChart2(201, xlColumnClustered)
.Name = "Graf_" & i
With .Chart.SeriesCollection.NewSeries
.XValues = overskrifter
.Values = overskrifter.Offset(i, 0)
.Name = Oppsummering.Range("B5").Offset(i, 0)
' "Olive"
.Points(1).Format.Fill.ForeColor.RGB = RGB(128, 128, 0)
' "Dark khaki"
.Points(8).Format.Fill.ForeColor.RGB = RGB(189, 183, 107)
' Green (Atlantis)
.Points(9).Format.Fill.ForeColor.RGB = RGB(146, 208, 80)
With .Format.Line
.Visible = msoTrue
.Weight = 0.5
'.ForeColor.RGB = RGB(0, 0, 205)
.ForeColor.RGB = RGB(255, 0, 0)
.Transparency = 0
End With
End With
.Height = høgde
.Width = breidde
.Top = 5 + ((i - 1) \ 3) * (5 + høgde)
.Left = 5 + ((i - 1) Mod 3) * (5 + breidde)
.Chart.HasTitle = True
.Chart.ChartGroups(1).GapWidth = 150
.Chart.ChartGroups(1).Overlap = 0
End With
End Sub
Sub fjernkurver()
Dim co As ChartObject
For Each co In Kurver.ChartObjects
co.Delete
Next co
End Sub
For the most part it works fine, but I am having some issues with this part of the code:
With .Format.Line
.Visible = msoTrue
.Weight = 0.5
'.ForeColor.RGB = RGB(0, 0, 205)
.ForeColor.RGB = RGB(255, 0, 0)
.Transparency = 0
End With
It is supposed to add a border around all the bars in the graph, red with RGB(255,0,0), blue with RGB(0,0,255).
However, as far as I can tell, no border is added to any of the bars. Can someone please point out where I am going wrong here?
The chart ends up looking like this:
It appears that the .Format.Line property of a series applies to something else than the border of a bar chart - a guess would be that it is the line connecting the datapoints of e.g. a line or scatter chart.
To actually outline the bars, I replaced the offending code;
With .Format.Line
.Visible = msoTrue
.Weight = 0.5
.ForeColor.RGB = RGB(255, 0, 0)
.Transparency = 0
End With
with
.Border.LineStyle = xlContinuous
.Border.Color = 9851952
.Format.Line.Weight = 0.5
Please don't ask me why .Format.Line.Weight still applies to the border, at least I got it working. Big props to the people who'd written the thread where I found the answer on Ozgrid forums.
I am having a problem with a program for my Excel VBA course. I have written a program to add 5 each of lines, rectangles, ovals and triangles to a worksheet this is the btnAddShapes click event. In the cmdAlignRectangles click event I am trying to take only the rectangles that were added and align them all in the C column. I have used a For Each loop to select all the shapes on the sheet, the For Each loop structure is required for the assignment. Then I used an If/Then statement to select the shape Type msoShapeRectangle. I used the name that I assigned in when creating the rectangles such as "Box1" using the counter I to iterate through each rectangle, it is this statement that is giving me an error saying that the item with that name was not found. I must use the Left property of the Range and Shape objects to move the rectangles.? Any help or guidance would be greatly appreciated.
Private Sub btnAddShapes_Click()
Randomize
For I = 1 To 5
ActiveSheet.Shapes.AddShape(msoShapeRectangle, 50, 100, 100, 65).Select
With Selection
.Name = "Box" & I
.Left = Int(422 * Rnd)
.Top = Int(422 * Rnd)
End With
ActiveSheet.Shapes.AddLine(10 + I * (Rnd * 133), 50 + I * (Rnd * 133), 125 + I * (Rnd * 133), 250 + I * (Rnd * 133)).Select
With Selection
.Name = "Line" & I
End With
ActiveSheet.Shapes.AddShape(msoShapeOval, 275, 240, 108, 44).Select
With Selection
.Name = "Oval" & I
.Left = Int(444 * Rnd)
.Top = Int(444 * Rnd)
End With
ActiveSheet.Shapes.AddShape(msoShapeIsoscelesTriangle, 514, 220, 93, 71).Select
With Selection
.Name = "Triangle" & I
.Left = Int(377 * Rnd)
.Top = Int(377 * Rnd)
End With
Next I
End Sub
Private Sub btnRemoveShapes_Click()
Dim sh As Shape
For Each sh In ActiveSheet.Shapes
If Not (sh.Type = msoOLEControlObject Or sh.Type = msoFormControl Or sh.Type = msoTextBox) Then sh.Delete
Next sh
End Sub
Private Sub cmdAlignRectangles_Click()
Dim allRectangles As Shapes
Dim sh As Shape
Dim I As Integer
Set allRectangles = ActiveSheet.Shapes
I = 1
For Each sh In allRectangles
If sh.Type = msoShapeRectangle Then
ActiveSheet.Shapes("Box" & I).Left = Cells(I, 3).Left
End If
I = I + 1
Next
End Sub
The error is that in the creation loop you create 4 shapes for each 1, I going from 1 to 5. On the other hand, in the alignment loop you iterate one I for each shape. Therefore, when I reaches 6 (with the 6th shape), the object named "Box6" does not exist.
A simpler way to achieve this would be to modify our test by examining the name of the shape, like this, for example:
If sh.Type = msoShapeRectangle And InStr(sh.Name, "Box") = 1 Then
sh.Left = Cells(I, 3).Left
End If
p.s. you can also drop the first part of the test
A piece of my code goes through a range of cells and if some cell satisfies certain criteria - inserts the shape in this cell. It works, but I would like to find out an alternative approach avoiding select.
'above - code to find satisfying cell
ActWS.Activate 'Activate Sheet
ActWS.Cells(rActPlan - 1, vReturnColumn).Select 'Select satisfying cell
ActiveSheet.Shapes.AddShape(msoShapeOval, ActiveCell.Left, ActiveCell.Top, ActiveCell.Width, ActiveCell.Height).Select
Selection.ShapeRange.Fill.Visible = msoFalse
With Selection.ShapeRange.Line
.Visible = msoTrue
.ForeColor.RGB = RGB(0, 255, 0)
.Weight = 2.25
End With
This code removes all .Select and ActiveCell references:
With ActWs
Dim rng as Range
Set rng = .Cells(rActPlan - 1, vReturnColumn)
Dim shp as Shape
Set shp = .Shapes.AddShape(msoShapeOval, rng.Left, rng.Top, rng.Width, rng.Height)
With shp.ShapeRange
.Fill.Visible = msoFalse
With .Line
.Visible = msoTrue
.ForeColor.RGB = RGB(0, 255, 0)
.Transparency = 0
.Weight = 2.25
End With
End With
End With
AddShape() returns the just-added shape object, so you should be able to use something like the code below - then refer to shp instead of Selection
Dim shp as Shape
Set shp = ActiveSheet.Shapes.AddShape(msoShapeOval, ActiveCell.Left, _
ActiveCell.Top, ActiveCell.Width, ActiveCell.Height)
I have been working on a macro for the past week to automatically create charts in excel. I have gotten pretty far along with it (thanks in large part to help from this website and its users), but I am stuck on a seemingly insignificant step. For some reason my line with markers graph shows up with discolorations in it. What I mean by this is that the middle fill of the marker is the standard blue that excel defaults to. I think the issue lies with the [ .Visible = msoTrue] line but no matter how I manipulate the code, I cannot make my markers one solid color.
The code is below
Sub DM1R_Graph()
Dim ws As Worksheet
For Each ws In Sheets
ws.Activate
If ws.Name <> "WSNs" Then
Dim sht As Worksheet
Dim xVals As Range, yVals As Range
Dim co As Shape, cht As Chart, s As Series
Set sht = ActiveSheet
Set co = sht.Shapes.AddChart()
Set cht = co.Chart
'remove any existing series
Do While cht.SeriesCollection.Count > 0
cht.SeriesCollection(1).Delete
Loop
cht.ChartType = xlLineMarkers
'get the extent of the XValues...
'below is the first Y axis entry (Oil)
'(change the 2nd offset number to get what you want)
Set xVals = sht.Range(sht.Range("B2"), sht.Cells(Rows.Count, "B").End(xlUp))
Set yVals = xVals.Offset(0, 2)
Set s = cht.SeriesCollection.NewSeries
s.XValues = xVals
s.Values = yVals
With s.Format.Fill
.Visible = msoTrue
.ForeColor.RGB = RGB(0, 176, 80)
.Transparency = 0
.Solid
End With
With s.Format.Line
.Visible = msoTrue
.ForeColor.RGB = RGB(0, 176, 80)
.Transparency = 0
End With
'below is the second y axis entry (Gas)
Set xVals = sht.Range(sht.Range("B2"), sht.Cells(Rows.Count, "B").End(xlUp))
Set yVals = xVals.Offset(0, 4)
Set s = cht.SeriesCollection.NewSeries
s.XValues = xVals
s.Values = yVals
With s.Format.Fill
.Visible = msoTrue
.ForeColor.RGB = RGB(255, 0, 0)
.Transparency = 0
.Solid
End With
With s.Format.Line
.Visible = msoTrue
.ForeColor.RGB = RGB(255, 0, 0)
.Transparency = 0
End With
'below is the third y axis entry (water)
Set xVals = sht.Range(sht.Range("B2"), sht.Cells(Rows.Count, "B").End(xlUp))
Set yVals = xVals.Offset(0, 5)
Set s = cht.SeriesCollection.NewSeries
s.XValues = xVals
s.Values = yVals
With s.Format.Fill
.Visible = msoTrue
.ForeColor.RGB = RGB(0, 176, 240)
.Transparency = 0
.Solid
End With
With s.Format.Line
.Visible = msoTrue
.ForeColor.RGB = RGB(0, 176, 240)
.Transparency = 0
End With
'end Y axis entries
cht.HasLegend = True
'below applies the legend names to be whatever are in parenthesis'
cht.Legend.Select
ActiveChart.SeriesCollection(1).Name = "Oil (BO)"
ActiveChart.SeriesCollection(2).Name = "Gas (MCF)"
ActiveChart.SeriesCollection(3).Name = "Water (BW)"
'below applies the data labels
cht.SeriesCollection(1).Select
cht.SeriesCollection(1).ApplyDataLabels
cht.SeriesCollection(2).Select
cht.SeriesCollection(2).ApplyDataLabels
cht.SeriesCollection(3).Select
cht.SeriesCollection(3).ApplyDataLabels
'below orients the datalabels to either above,below,right,or left
cht.SeriesCollection(1).Select
ActiveChart.SeriesCollection(1).DataLabels.Select
Selection.Position = xlLabelPositionRight
cht.SeriesCollection(2).Select
ActiveChart.SeriesCollection(2).DataLabels.Select
Selection.Position = xlLabelPositionAbove
cht.SeriesCollection(3).Select
ActiveChart.SeriesCollection(3).DataLabels.Select
Selection.Position = xlLabelPositionLeft
'below moves the chart
Dim iChart As Long
Dim lTop As Double
lTop = ActiveSheet.Range("Q10").Top
For iChart = 1 To ActiveSheet.ChartObjects.Count
ActiveSheet.ChartObjects(iChart).Top = lTop
ActiveSheet.ChartObjects(iChart).Left = ActiveSheet.Range("Q1").Left
lTop = lTop + ActiveSheet.ChartObjects(iChart).Height + ActiveSheet.Range("5:7").Height
Next
'below deals with the chart title
cht.SetElement (msoElementChartTitleAboveChart)
With cht.ChartTitle
.Text = sht.Name & Chr(10) & "Oil,Gas, and Water Production Through Well Life "
.Characters.Font.Size = 12
End With
'below adds a filter to one column. You cannot have more than 1 filter per sheet.
Columns("L:L").Select
Selection.AutoFilter
End If
Next ws
End Sub
Below is a picture showing what I mean. You can see it obviously in the red series, but it also appears in the green and blue series as well.
I believe you need to set the MarkerBackgroundColor on the series.
s.MarkerBackgroundColor = RGB(255, 0, 0)