Hi I searched the web and found the example Open a folder using Process.Start to open the folder. I followed it and created a console app but the folder is opened my document folder instead of my input folder. For my testing, I executed it in cmd prompt by typing "\sharefuser01\users$\tester\2012". It opened the "\sharefuser01\users$" folder. Would someone tell me how to do it. Thanks in advance.
There is my code:
Sub Main(ByVal args() As String)
Dim psi As New ProcessStartInfo(args(0))
Process.Start("explorer.exe", args(0))
End Sub
Process.Start("directory path")
or
Dim Proc As String = "Explorer.exe"
Dim Args As String =
ControlChars.Quote &
IO.Path.Combine("C:\", "Folder with spaces in the name") &
ControlChars.Quote
Process.Start(Proc, Args)
Related
How can i open .exe file from the multiple folders in single click using vb.net or any other way?
tried using process.start method but it's not working properly and found error can't find path.
Example:
For Each Dir As String In Directory.GetDirectories(Application.StartupPath)
Process.Start(Dir & "\" & "*.exe")
Next
This will try to run all EXE files in the folder "myPath" and subfolders
Imports System.IO
Module Module1
Sub Main()
Dim pattern As String
pattern = "*.EXE"
Dim myPath As String
myPath = "your Path" ' Adjust to your needs
Dim exeLst As IEnumerable(Of String)
exeLst = Directory.EnumerateFiles(myPath, pattern, SearchOption.AllDirectories)
Dim sngFile As String
For Each sngFile In exeLst
Process.Start(sngFile)
Next
End Sub
End Module
I am trying to save a image from webbrowser but can't find an answer for it.
Example of the problem is the URL is hxxp://domain[.]com/image/?img=1234 on webbrowser it shows the image and the source is <img src='hxxp://domain[.]com/image/?img=1234'>..
I was unable to save it using the My.Computer.Network.DownloadFile and MemoryStream(tClient.DownloadData methods.
In order to download the file, I will need to session cookie also?
How can I do this?
Any image that you see in the WebBrowser has already been downloaded to your computer. It is normally cached in the folder:
C:\Users\<username>\AppData\Local\Microsoft\Windows\Temporary Internet Files
or whatever other folder is set in Internet Options. You can get your image from that folder.
The following program shows how to copy file TDAssurance_Col.png from the Temporary Internet Files folder to the C:\Temp folder.
Module Module1
Sub Main()
CopyFileFromTemporaryInternetFolder("TDAssurance_Col.png", "C:\Temp")
End Sub
Public Sub CopyFileFromTemporaryInternetFolder(filename As String, destinationFolder As String)
' Search actual path of filename.
Dim temporaryInternetFilesFolder As String = IO.Path.Combine(Environment.GetFolderPath(Environment.SpecialFolder.InternetCache), "Content.IE5")
Dim pattern As String = Path.GetFileNameWithoutExtension(filename) & "*" & Path.GetExtension(filename)
Dim pathnames() As String = Directory.GetFiles(temporaryInternetFilesFolder, pattern, SearchOption.AllDirectories)
' If file found, copy it.
If pathnames.Count > 0 Then
File.Copy(pathnames(0), Path.Combine(destinationFolder, filename))
End If
End Sub
End Module
I have a project that requires some pdf reports to be opened from my forms. Since the program can be installed in any drive, I used the winform location directory as my path. I reports are located on a directory called Reports. It works well under development becuase I the winform is under bin\debug, but when I deploy my solution and try the procedure, it does not work, the file cannot be found. I created a Reports directory after deployment, but still did not find my pdf.
Here is the code:
'Open the requested file name. The files are stored in the
'same path as the main workbook.
'#param filename file to be opened
Function OpenReports(strFileName As String) As String
Dim reportFolder As String
Try
reportFolder = Path.Combine(Directory.GetCurrentDirectory(), "Reports")
System.Diagnostics.Process.Start(reportFolder & "\" & strFileName)
Catch ex As Exception
MsgBox("The " & strFileName & " is not found on directory")
End Try
Return strFileName
End Function
Private Sub btnRptRangesToMarket_Click(sender As Object, e As EventArgs) Handles btnRptRangesToMarket.Click
'This procedure runs when the btnRptRangesToMarket is clicked
'the procedure opens the pdf below by running the OpenReports Function
OpenReports("Ranges to Market.pdf")
End Sub
Try Application.StartupPath instead of Directory.GetCurrentDirectory(). I always get good results with that property.
This is from MSDN:
The current directory is distinct from the original directory, which is the one from which the process was started.
It sounds very simple but I have searched and cannot seem to find a way to open a log file which the user just created from my windows form app. The file exits I just want to open it after it is created.
I have a Dim path As String = TextBox1.Text and once the user names and clicks ok on the savefiledialog I have a msgbox that says "Done" and when you hit OK I have tried this
FileOpen(FreeFile, path, OpenMode.Input) but nothing happens. I just want it to open the log and show it to the user so they can edit or save it again or anything.
This is where I got the above code.
http://msdn.microsoft.com/en-us/library/microsoft.visualbasic.filesystem.fileopen.aspx
Searching is difficult because everyone is trying to "Open" a file and process it during runtime. I am just trying to Show a file by Launching it like someone just double clicked it.
Here is the entire Export Button click Sub. It basically writes listbox items to file.
Private Sub btnExport_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnExport.Click
Dim sfd As New SaveFileDialog
Dim path As String = TextBox1.Text
Dim arypath() As String = Split(TextBox1.Text, "\")
Dim pathDate As String
Dim foldername As String
foldername = arypath(arypath.Length - 1)
pathDate = Now.ToString("yyyy-MM-dd") & "_" & Now.ToString("hh;mm")
sfd.FileName = "FileScannerResults " & Chr(39) & foldername & Chr(39) & " " & pathDate
sfd.InitialDirectory = Environment.GetFolderPath(Environment.SpecialFolder.Personal)
sfd.Filter = "Text files (*.txt)|*.txt|CSV Files (*.csv)|*.csv"
sfd.ShowDialog()
path = sfd.FileName
Using SW As New IO.StreamWriter(path)
If CkbxFolder.Checked = True Then
SW.WriteLine("Folders")
For Each itm As String In ListBox1.Items
SW.WriteLine(itm)
Next
End If
If CkbxFiles.Checked = True Then
SW.WriteLine("Files")
For Each itm As String In ListBox2.Items
SW.WriteLine(itm)
Next
End If
End Using
MsgBox("Done...")
FileOpen(FreeFile, path, OpenMode.Input) 'Why can't I open a file for you...
End Sub
Do not use the old VB6 methods. They are still here for compatibility reason, the new code should use the more powerful methods in the System.IO namespace.
However, as said in comments, FileOpen don't show anything for you, just opens the file
You coud write
Using sr = new StreamReader(path)
Dim line = sr.ReadLine()
if !string.IsNullOrEmpty(line) Then
textBoxForLog.AppendText(line)
End If
End Using
or simply (if the file is not too big)
Dim myLogText = File.ReadAllText(path)
textBoxForLog.Text = myLogText
As alternative, you could ask the operating system to run the program associated with the file extension and show the file for you
Process.Start(path)
To get the same behavior as if the user double-clicked it, just use System.Diagnostics.Process, and pass the filename to it's Start method:
Process.Start(path)
This will open the file using whatever the default application is for that filename based on its extension, just like Explorer does when you double-click it.
I am trying to locate a file from a program, in VB.NET
Dim exeName As String = "explorer.exe"
Dim params As String = "/e,""c:\test"",/select,""C:\test\a.txt"""
Dim processInfo As New ProcessStartInfo(exeName, params)
Process.Start(processInfo)
It opens the containing directory "c:\" but doesn't go inside to "c:\test", I would like to have the file selected...
Dim filePath As String = "C:\test\a.txt" 'Example file
Process.Start("explorer.exe", "/select," & filePath) 'Starts explorer.exe and selects desired file
You don't need the folder path in there after the /e, try this for your params:
Dim params As String = "/e, /select,""C:\temp\file.txt"""