I'm really new to TensorFlow and MI in general. I've been reading a lot, been searching days, but haven't really found anything useful, so..
My main problem is that every single tutorial/example uses images/words/etc., and the outcome is just a vector with numbers between 0 and 1 (yeah, that's the probability). Like that beginner tutorial, where they want to identify numbers in images. So the result set is just a "map" to every single digit's (0-9) probability (kind of). Here comes my problem: I have no idea what the result could be, it could be 1, 2, 999, anything.
So basically:
input: [1, 2, 3, 4, 5]
output: [2, 4, 6, 8, 10]
This really is just a simplified example. I would always have the same number of inputs and outputs, but how can I get the predicted values back with TensorFlow, not just something like [0.1, 0.1, 0.2, 0.2, 0.4]? I'm not really sure how clear my question is, if it's not, please ask.
Related
I need to sample n different values taken from a set of integers.
These integers should have different occurence probability. E.g. the largest the lukilier.
By using the random package I can sample a set of different values from the set, by maeans of the method
random.sample
However it doesn't seem to provide the possibility to associate a probability distribution.
On the other hand there is the numpy package which allows to associate the distribution, but it returns a sample with repetitions. This can be done with the method
numpy.random.choice
I am looking for a method (or a way around) to do what the two methods do, but together.
You can actually use numpy.random.choice as it has the replace parameter. If set to False, the sampling will be done wihtout remplacement.
Here's a random example:
>>> np.random.choice([1, 2, 4, 6, 9], 3, replace=False, p=[1/2, 1/8, 1/8, 1/8, 1/8])
>>> array([1, 9, 4])
I have a pandas dataframe df with many rows. For each row, I want to calculate the cosinus similarity between the row's columns A (first vector) and the row's columns B (second vector). At the end, I aim to get a vector with one cosine similarity value for each row. I have found a solution but it seems to me like it could be done much faster without this loop. May anyone give me some feedback on this code?
Thank you very much!
for row in np.unique(df.index):
cos_sim[row]=scipy.spatial.distance.cosine(df[df.index==row][columnsA],
df[df.index==row][columnsB])
df['cos_sim']=cos_sim
Here comes some sample data:
df = pd.DataFrame({'featureA1': [2, 4, 1, 4],
'featureA2': [2, 4, 1, 4],
'featureB1': [10, 2, 1, 8]},
'featureB2': [10, 2, 1, 8]},
index=['Pit', 'Mat', 'Tim', 'Sam'])
columnsA=['featureA1', 'featureA2']
columnsB=['featureB1', 'featureB2']
This is my desired output (cosine similarity for Pit, Mat, Tim and Sam):
cos_sim=[1, 1, 1, 1]
I am already receiving this output with my method, but I am sure the code could be improved from a performance perspective
several things you can improve on :)
Take a look at the DataFrame.apply function. pandas already offers you looping "under the hood".
df['cos_sim'] = df.apply(lambda _df: scipy.spatial.distance.cosine(_df[columnsA], _df[columnsB])
or something similar should be more performant
Also take a look at DataFrame.loc
df[df.index==row][columnsA]
and
df.loc[row,columnsA]
should be equivalent
If you really have to iterate over the dataframe (should be avoided again due to performance penalties and it is more difficult to read and understand), pandas gives you a generator for the rows (and id)
for index, row in df.iterrows():
scipy.spatial.distance.cosine(row[columnsA], row[columnsB])
Finally as mentioned above to get better answers on stackoverflow, always provide a concrete example where the problem is reproducible. Otherwise it is much harder to interpret the question correctly and to test a solution.
Pretty old post but I am replying for future readers. I created https://github.com/ma7555/evalify for all those rowwise similarity/distance calculations (disclaimer: i am the owner of the package)
I'm making a prolog program to play 'the game of nim', and the program is working fine. I am trying to make a user interface to play the game, where at first, the user has to say he wants the initial state of the game to be. However, when I execute the code shown in the code snippet, the write only gets executed after I type in some input.
Does anyone know how to solve this?
init(List) :-
write('Enter number of matches in heaps [N1, N2, N3]:'),
read(List).
I want the output to be:
?- init(X).
Enter number of matches in heaps [N1, N2, N3]: [1, 3, 5].
X = [1, 3, 5].
But I'm getting:
?- init(X).
[1, 3, 5].
Enter number of matches in heaps [N1, N2, N3]:
X = [1, 3, 5].
Numpy's broadcasting rules have bitten me once again and I'm starting to feel there may be a way of thinking about this
topic that I'm missing.
I'm often in situations as follows: the first axis of my arrays is reserved for something fixed, like the number of samples. The second axis could represent different independent variables of each sample, for some arrays, or it could be not existent when it feels natural that there only be one quantity attached to each sample in an array. For example, if the array is called price, I'd probably only use one axis, representing the price of each sample. On the other hand, a second axis is sometimes much more natural. For example, I could use a neural network to compute a quantity for each sample, and since neural networks can in general compute arbitrary multi valued functions, the library I use would in general return a 2d array and make the second axis singleton if I use it to compute a single dependent variable. I found this approach to use 2d arrays is also more amenable to future extensions of my code.
Long story short, I need to make decisions in various places of my codebase whether to store array as (1000,) or (1000,1), and changes of requirements occasionally make it necessary to switch from one format to the other.
Usually, these arrays live alongside arrays with up to 4 axes, which further increases the pressure to sometimes introduce singleton second axis, and then have the third axis represent a consistent semantic quality for all arrays that use it.
The problem now occurs when I add my (1000,) or (1000,1) arrays, expecting to get (1000,1), but get (1000,1000) because of implicit broadcasting.
I feel like this prevents giving semantic meaning to axes. Of course I could always use at least two axes, but that leads to the question where to stop: To be fail safe, continuing this logic, I'd have to always use arrays of at least 6 axes to represent everything.
I'm aware this is maybe not the best technically well defined question, but does anyone have a modus operandi that helps them avoid these kind of bugs?
Does anyone know the motivations of the numpy developers to align axes in reverse order for broadcasting? Was computational efficiency or another technical reason behind this, or a model of thinking that I don't understand?
In MATLAB broadcasting, a jonny-come-lately to this game, expands trailing dimensions. But there the trailing dimensions are outermost, that is order='F'. And since everything starts as 2d, this expansion only occurs when one array is 3d (or larger).
https://blogs.mathworks.com/loren/2016/10/24/matlab-arithmetic-expands-in-r2016b/
explains, and gives a bit of history. My own history with the language is old enough, that the ma_expanded = ma(ones(3,1),:) style of expansion is familiar. octave added broadcasting before MATLAB.
To avoid ambiguity, broadcasting expansion can only occur in one direction. Expanding in the direction of the outermost dimension makes seems logical.
Compare (3,) expanded to (1,3) versus (3,1) - viewed as nested lists:
In [198]: np.array([1,2,3])
Out[198]: array([1, 2, 3])
In [199]: np.array([[1,2,3]])
Out[199]: array([[1, 2, 3]])
In [200]: (np.array([[1,2,3]]).T).tolist()
Out[200]: [[1], [2], [3]]
I don't know if there are significant implementation advantages. With the striding mechanism, adding a new dimension anywhere is easy. Just change the shape and strides, adding a 0 for the dimension that needs to be 'replicated'.
In [203]: np.broadcast_arrays(np.array([1,2,3]),np.array([[1],[2],[3]]),np.ones((3,3)))
Out[203]:
[array([[1, 2, 3],
[1, 2, 3],
[1, 2, 3]]), array([[1, 1, 1],
[2, 2, 2],
[3, 3, 3]]), array([[1., 1., 1.],
[1., 1., 1.],
[1., 1., 1.]])]
In [204]: [x.strides for x in _]
Out[204]: [(0, 8), (8, 0), (24, 8)]
I have a 1-D array in numpy v. I'd like to copy it to make a matrix with each row being a copy of v. That's easy: np.broadcast_to(v, desired_shape).
However, if I'd like to treat v as a column vector, and copy it to make a matrix with each column being a copy of v, I can't find a simple way to do it. Through trial and error, I'm able to do this:
np.broadcast_to(v.reshape(v.shape[0], 1), desired_shape)
While that works, I can't claim to understand it (even though I wrote it!).
Part of the problem is that numpy doesn't seem to have a concept of a column vector (hence the reshape hack instead of what in math would just be .T).
But, a deeper part of the problem seems to be that broadcasting only works vertically, not horizontally. Or perhaps a more correct way to say it would be: broadcasting only works on the higher dimensions, not the lower dimensions. I'm not even sure if that's correct.
In short, while I understand the concept of broadcasting in general, when I try to use it for particular applications, like copying the col vector to make a matrix, I get lost.
Can you help me understand or improve the readability of this code?
https://en.wikipedia.org/wiki/Transpose - this article on Transpose talks only of transposing a matrix.
https://en.wikipedia.org/wiki/Row_and_column_vectors -
a column vector or column matrix is an m × 1 matrix
a row vector or row matrix is a 1 × m matrix
You can easily create row or column vectors(matrix):
In [464]: np.array([[1],[2],[3]]) # column vector
Out[464]:
array([[1],
[2],
[3]])
In [465]: _.shape
Out[465]: (3, 1)
In [466]: np.array([[1,2,3]]) # row vector
Out[466]: array([[1, 2, 3]])
In [467]: _.shape
Out[467]: (1, 3)
But in numpy the basic structure is an array, not a vector or matrix.
[Array in Computer Science] - Generally, a collection of data items that can be selected by indices computed at run-time
A numpy array can have 0 or more dimensions. In contrast in MATLAB matrix has 2 or more dimensions. Originally a 2d matrix was all that MATLAB had.
To talk meaningfully about a transpose you have to have at least 2 dimensions. One may have size one, and map onto a 1d vector, but it still a matrix, a 2d object.
So adding a dimension to a 1d array, whether done with reshape or [:,None] is NOT a hack. It is a perfect valid and normal numpy operation.
The basic broadcasting rules are:
a dimension of size 1 can be changed to match the corresponding dimension of the other array
a dimension of size 1 can be added automatically on the left (front) to match the number of dimensions.
In this example, both steps apply: (5,)=>(1,5)=>(3,5)
In [458]: np.broadcast_to(np.arange(5), (3,5))
Out[458]:
array([[0, 1, 2, 3, 4],
[0, 1, 2, 3, 4],
[0, 1, 2, 3, 4]])
In this, we have to explicitly add the size one dimension on the right (end):
In [459]: np.broadcast_to(np.arange(5)[:,None], (5,3))
Out[459]:
array([[0, 0, 0],
[1, 1, 1],
[2, 2, 2],
[3, 3, 3],
[4, 4, 4]])
np.broadcast_arrays(np.arange(5)[:,None], np.arange(3)) produces two (5,3) arrays.
np.broadcast_arrays(np.arange(5), np.arange(3)[:,None]) makes (3,5).
np.broadcast_arrays(np.arange(5), np.arange(3)) produces an error because it has no way of determining whether you want (5,3) or (3,5) or something else.
Broadcasting always adds new dimensions to the left because it'd be ambiguous and bug-prone to try to guess when you want new dimensions on the right. You can make a function to broadcast to the right by reversing the axes, broadcasting, and reversing back:
def broadcast_rightward(arr, shape):
return np.broadcast_to(arr.T, shape[::-1]).T