Complex join in sql with top 10 row - sql

Question

Table1:
Id Word Frequency
1 A 1
2 B 5
Table2:
Id Word SecondWord SecondFrequency
1 A A1 1
2 A A2 5
3 A A3 10
4 A A4 9
5 A A5 20
6 B B1 5
7 B B2 8
8 B B3 50
9 B B4 40
10 B B5 68
Required output
Top 3 record from “Table2” with Order by SecondFrequency Desc
Ex.
Word Frequency SecondWord SecondFrequency
A 1 A5 20
A 1 A3 10
A 1 A4 9
B 5 B5 68
B 5 B3 50
B 5 B4 40
How can i get the desire output

Answer 1

Use ROWNUMBER function based on second frequency for get you required result:
CREATE TABLE #Table1(Id TINYINT, Word VARCHAR(1),Frequency TINYINT)
CREATE TABLE #Table2(Id TINYINT, Word VARCHAR(1),SecondWord
VARCHAR(2),SecondFrequency TINYINT)
INSERT INTO #Table1(Id, Word ,Frequency)
SELECT 1,'A',1 UNION ALL
SELECT 2,'B',5
INSERT INTO #Table2(Id, Word ,SecondWord ,SecondFrequency)
SELECT 1,'A','A1',1 UNION ALL
SELECT 2,'A','A2',5 UNION ALL
SELECT 3,'A','A3',10 UNION ALL
SELECT 4,'A','A4',9 UNION ALL
SELECT 5,'A','A5',20 UNION ALL
SELECT 6,'B','B1',5 UNION ALL
SELECT 7,'B','B2',8 UNION ALL
SELECT 8,'B','B3',50 UNION ALL
SELECT 9,'B','B4',40 UNION ALL
SELECT 10,'B','B5',68
SELECT *
FROM
(
SELECT ROW_NUMBER() OVER(PARTITION BY #Table1.Word ORDER BY
SecondFrequency DESC ) RNo ,#Table1.Word ,#Table1.Frequency,
SecondWord ,SecondFrequency
FROM #Table1
JOIN #Table2 ON #Table1.Word = #Table2.Word
) A
WHERE RNo BETWEEN 1 AND 3

Answer 2

you can use Row Number. By using Row Number you can give each row with the same 'word' a number based on their SecondFrequency. those number will be reset if the 'word' is changed.
;with cte as
(
select *, ROW_NUMBER() OVER (PARTITION BY Word ORDER BY SecondFrequency DESC) AS RowNumber from table2
)
select A.Word, B.Frequency, A.SecondWord, A.SecondFrequency
from cte A left join table1 B
on A.Word = B.Word
where A.RowNumber < 4

Answer 3

Inner Join with Row_Number() will help in this case !!!
CREATE TABLE #Table1
(
Id INT
,Word VARCHAR(10)
,Frequency INT
)
INSERT INTO #Table1 SELECT 1,'A',1
UNION SELECT 2,'B',5
CREATE TABLE #Table2
(
Id INT
,Word VARCHAR(10)
,SecondWord VARCHAR(10)
,SecondFrequency INT
)
INSERT INTO #Table2 SELECT
1,'A','A1',1 UNION ALL SELECT
2,'A','A2',5 UNION ALL SELECT
3,'A','A3',10 UNION ALL SELECT
4,'A','A4',9 UNION ALL SELECT
5,'A','A5',20 UNION ALL SELECT
6,'B','B1',5 UNION ALL SELECT
7,'B','B2',8 UNION ALL SELECT
8,'B','B3',50 UNION ALL SELECT
9,'B','B4',40 UNION ALL SELECT
10,'B','B5',68
SELECT * FROM #Table1
SELECT * FROM #Table2
SELECT X.Word,X.Frequency,X.SecondWord,X.SecondFrequency
FROM
(SELECT T1.Word,T1.Frequency,T2.SecondWord,T2.SecondFrequency,ROW_NUMBER() OVER(PARTITION BY T1.WORD ORDER BY T2.SecondFrequency desc) as RN
FROM #Table1 T1
JOIN #Table2 T2
ON T1.Word = T2.Word
) AS X
WHERE X.RN<=3

Answer 4

get the top 3 rows from Table_2
join the Table_1
the syntax is : ROW_NUMBER() OVER(PARTITION BY COL1 ORDER BY COL2) AS num
COL1 is the column to group and COL2 is the column to sort , num is the sorted number to be used to limit the results
SELECT t2.Word,
t1.Frequency,
t2.SecondWord,
t2.SecondFrequency
FROM
(SELECT *
FROM
(SELECT Word,
SecondWord,
SecondFrequency,
ROW_NUMBER() over(PARTITION BY Word
ORDER BY SecondFrequency DESC) AS num
FROM Table_2) T
WHERE T.num <= 3 ) t2
JOIN Table_1 AS t1 ON t2.Word = t1.Word
ORDER BY t2.SecondFrequency DESC;