Sub-query, group and having in SilverStripe ORM - orm

I'm using SilverStripe ORM.
I need to get all companies that are at least in ALL of the desired Specializing (no less):
class CompanyPage extends Page {
private static $many_many = [
"Specializings" => "Specializing",
];
}
class Specializing extends DataObject {
private static $belongs_many_many = [
"CompanyPages" => "CompanyPage",
];
}
I have an array filled with desiring specializing ids ( $specIds ).
This gets companies that are at at least in one of the desired specializing, but it isn't that I need.
$companyPages = CompanyPage::get()->filter([
"Specializings.ID:ExactMatch" => $specIds,
]);
I can achive my task with this SQL-query
select * from CompanyPage c1 join (
select c.ID from CompanyPage c
join CompanyPage_Specializings cs on cs.CompanyPageID = c.ID
where cs.SpecializingID in (14,15)
group by c.ID having count(c.ID) = 2
) c2 on c1.ID = c2.ID
But how can I achive it with SilverStripe ORM?
I can't find anything about having by aggregated functions in ORM

You can use SQLQuery to build more complex DB queries in SilverStripe or if you want to run the RAW SQL you can use DB:Query()
https://docs.silverstripe.org/en/3/developer_guides/model/sql_query/
Both of these will return a MySQLResultSet rather than a SS_List which means when you iterate over the code you would use something like this
foreach($results AS $result){
$varname = $results['propertyname'];
}
rather than the below if you used the straight SS ORM.
foreach($results AS $result){
$varname = $results->propertyname;
}
Once you have the MySQLResult set you could iterate through it to build an ArrayList which you can use in your template or alternatively use this Module to convert the MySQLResultSet to a SS_List (just remember if you use this module that the relationship benefit that you get from the straight ORM isn't maintained - e.g. $has_one relationships etc).
https://github.com/burnbright/silverstripe-sqlquerylist
I hope this helps.

Related

Transforming Raw Sql to Laravel equolent

I have written this SQL code
SELECT drugs.*, COUNT(*) as 'views' from drugs INNER JOIN drug_seen on drugs.id = drug_seen.drug_id GROUP BY drugs.id order by views ASC
And now I am trying to write in in the Laravel equolent but I am facing some troubles.
This is what I have tried
$drugs = Drug::select(DB::raw('drugs.*,count(*) as views'))
->join('drug_seen', 'drugs.id', 'drug_seen.drug.id')
->groupBy('drug.id')->orderByRaw('views');
I am having errors like column not found i think the code is not written properly
Drug class
class Drug extends Model
{
use HasFactory;
use SoftDeletes;
...
...
...
public function drugVisits()
{
return $this->hasMany(DrugSeen::class);
}
Hop this will solve your problem.
$drugs = Drug::with('drugVisits')->get();
$drugs->count(); //for total records in drugs table.
You have typo error in join instead on drug_id you use drug.id
Try this:
$drugs = Drug::select(DB::raw('drugs.*,count(*) as views'))
->join('drug_seen', 'drugs.id', 'drug_seen.drug_id')
->groupBy('drugs.id')->orderByRaw('views');
}
As soon as you use join() you're leaving Eloquent and entering Query\Builder, losing the benefits of Model configurations in the process. And with() eager-loads aren't the answer, if you're looking to filter the results by both tables. What you want is whereHas().
Also, as far as your grouping and count manipulation there, I think you're looking more for Collection handling than SQL groups.
$drugModel = app(Drugs::class);
$results = $drugModel->whereHas('drugVisits')->with('drugVisits')->get();
$organizedResults = $results
->groupBy($drugModel->getKey())
->sortyBy(function (Drugs $drugRecord) {
return $drugRecord->drugVisits->count();
});
If you want to have a 'views' property that carries the count in the root-level element, it would look like this:
$drugModel = app(Drugs::class);
$results = $drugModel->whereHas('drugVisits')->with('drugVisits')->get();
$organizedResults = $results
->groupBy($drugModel->getKey())
->map(function (Drugs $drugRecord) {
$drugRecord->views = $drugRecord->drugVisits->count();
return $drugRecord;
});
->sortyBy('views');

Laravel/SQL: How to fetch data from multiple table in a single query? that too using 'where'

Working on a search functionality on Laravel App(Blog/Posts).
There are multiple types of posts (each having a separate table in the database)
Like Business posts, Social Life posts etc..
Below is the search function on SearchController
class SearchController extends Controller
{
public function search(Request $request, $query = null)
{
if($query == null)
return redirect()->route('home');
$search = Business::where([['title','like','%'.$query.'%'],['status','=',1]])
->orWhere([['description','like','%'.$query.'%'],['status','=',1]])
->paginate(10);
return view('front.search',[
'results' => $search,
'query' => $query
]);
}
}
So basically my question is how to add other types of Post's table also?
My main motive is that when someone searches for anything, the result should be fetched from all types of posts table(business, nature, life & so on..).
You have to maintain common id in both the table
NOTE: Join is the preferable method
$querys = DB::table('Business')->where([['Business.title','like','%'.$query.'%'],['Business.status','=',1]])
->orWhere([['Business.description','like','%'.$query.'%'],['Business.status','=',1]]);
$querys->join('socialtable','socialtable.userid','=','Business.userid');
// Just join the social table
$querys->where('socialtable.title', 'like','%'.$query.'%');
$result = $querys->paginate(10);
If you have a model called Book, like this:
class Book extends Model
{
/**
* Get the author that wrote the book.
*/
public function author()
{
return $this->belongsTo('App\Author');
}
}
Then you can retrieve all of your books with authors like this:
$books = App\Book::with(['author'])->get();
Check out Eager loading from Laravel documentation.
Just add table name before every field
$querys = DB::table('Business')->where([['Business.title','like','%'.$query.'%'],['Business.status','=',1]])
->orWhere([['Business.description','like','%'.$query.'%'],['Business.status','=',1]]);
$querys->join('socialtable','socialtable.userid','=','Business.userid');
// Just join the social table
$querys->where('socialtable.title', 'like','%'.$query.'%');
$result = $querys->paginate(10);

Preserve Order of IN in ORM Order

I'm trying to do a query where I preserve the order of the ids in a IN statement. I can't seem to do it with either the Model Manage Query Builder or the standard ORM 'order' array parameter. Am I missing something? I keep getting:
UNEXPECTED TOKEN IDENTIFIER(, NEAR TO 'id`enter code here`,17743,16688,16650
Here's my model manager:
$query = $this->modelsManager->createQuery('SELECT * FROM Projects WHERE id IN ('.implode(',', array_keys($finalIterations)).')
ORDER BY FIELD(id,'.implode(',', array_keys($finalIterations)).'');
It's pretty obvious PhQL doesn't like the FIELD key word. Is there a way for me to do what I'm trying to do with PhQL? It seems I will not be able to do what I need to.
Unfortunately as previously said, this is missing a feature in Phalcon.
Have a look at this function, I've put it into my ModelBase abstract class which is parent class of all my models. It uses PhQL variable binding, so it's safe for handling direct user input.
You could have reimplemented custom \Phalcon\Mvc\Model\Criteria but this solution seems to be easier to work with, at least for me.
ModelBase abstract
public function appendCustomOrder( \Phalcon\Mvc\Model\CriteriaInterface &$criteria, $orderField, array &$orderValues = [] ) {
if(!empty($orderValues)) {
$queryKeys = $bindParams = [];
foreach($orderValues as $key => $id) {
$queryKey = 'pho'.$key;
$queryKeys[] = ':'.$queryKey.':';
$bindParams[$queryKey] = $id;
}
// TODO: add support for multiple orderBy fields
$criteria->orderBy('FIELD('.$orderField.','.implode(',',$queryKeys).')');
// there's no 'addBind' function, need to merge old parameters with new ones
$criteria->bind( array_merge( (array) #$criteria->getParams()['bind'], $bindParams ) );
}
}
Controller usage
$projectIDs = [17743, 16688, 16650];
$projectsModel = new Projects();
$criteria = $projectsModel->query->inWhere( 'id', $projectIDs );
$projectsModel->appendCustomOrder( $criteria, 'id', $projectIDs );
$projectsData = $criteria->execute();
This will generate valid PhQL syntax similar to this one:
SELECT `projects`.`id` AS `id`, `projects`.`title` AS `title`
FROM `projects`
WHERE `projects`.`id` IN (:phi0, :phi1, :phi2)
ORDER BY FIELD(`projects`.`id`, :pho0, :pho1, :pho2)

Symfony2 + Doctrine - Filtering

I've got a OneToMany relationship where one football team has many players. I want to list all football teams and display the name of the captain for each team.
Each player entity has a foreign key (team_id) and a field 'captain' which is set to 0 or 1. I'm currently running the following query:
$teams = $this
->getDoctrine()
->getRepository('FootballWebsiteBundle:Team')
->createQueryBuilder('t')
->setFirstResult(($pageNumber * $resultPerPage) - $resultPerPage)
->setMaxResults($resultPerPage)
->add('where','t.deleted = 0')
->add('orderBy', 't.name DESC')
->getQuery()->getResult();
Then when I loop through each team in twig I run team.getTeamCaptain().getName() which is a filter within my Team entity:
public function getTeamCaptain() {
$them = $this->players->filter(function($p) {
return $p->getCaptain() == 1;
});
return $them->first();
}
Is there a better way to run this query?
First of all, you may want to fetch-join the players of each retrieved team to avoid having them lazy loaded during rendering of the template. Here's the DQL:
SELECT
t, p
FROM
FootballWebsiteBundle:Team t
LEFT JOIN
t.players p
WHERE
t.deleted = 0
ORDER BY
t.name DESC
Which can be built with following query builder API calls:
$teamsQuery = $this
->getDoctrine()
->getRepository('FootballWebsiteBundle:Team')
->createQueryBuilder('t')
->addSelect('p')
->leftJoin('t.players', 'p')
->add('where','t.deleted = 0')
->add('orderBy', 't.name DESC')
->getQuery()
Then you wrap this query into a Paginator object (since setMaxResults and setFirstResult cannot be trusted when fetch-joining):
$paginator = new \Doctrine\ORM\Tools\Pagination\Paginator($teamsQuery, true);
$teamsQuery
->setFirstResult(($pageNumber * $resultPerPage) - $resultPerPage)
->setMaxResults($resultPerPage)
In your view you can then iterate on the teams like following pseudo-code:
foreach ($paginator as $team) {
echo $team->getTeamCaptain() . "\n";
}
You can also gain some extra performance in your getTeamCaptain method by using the Selectable API:
public function getTeamCaptain() {
$criteria = new \Doctrine\Common\Collections\Criteria();
$criteria->andWhere($criteria->expr()->eq('captain', 1));
return $this->players->matching($criteria)->first();
}
The advantage here is mainly relevant when the association players is not yet initialized, since this will avoid loading it entirely. This is not the case, but I consider it a good practice (instead of re-inventing collection filtering logic).

Criteria API - Using UPPER in a ElementCollection

I have a class
#Entity
public class Person{
...
#ElementCollection
private Set<String> tags;
...
}
I want to use the JPA 2.0 Criteria API to search over these tags - but in a case insensitive way. Thus I want to both set the search parameter to UPPER and the column to UPPER (Pseudo-SQL: select p.* from Person p join Tags t on p.id=t.pId where upper(t.name)=upper('searchParameter'); )
Here is my code without the UPPER on the tags:
CriteriaBuilder builder = this.em.getCriteriaBuilder();
CriteriaQuery<Person> query = builder.createQuery(Person.class);
Root<Person> root = query.from(Person.class);
return this.em.createQuery(query.select(root).where(
builder.isMember(builder.upper(builder.literal(searchTag)),
root.get(Person_.tags)))).getResultList();
where searchTag is the input parameter.
How can I assign the UPPER to the Person_.tags "Column"?
In other words I want to write this Query with Criteria API:
SELECT p FROM Person p JOIN p.tags t WHERE UPPER(t) = UPPER('searchString')
Thank you
Ok, I finally have the solution:
cQuery.where(
builder.equal(
builder.upper(cQuery.from(Relation.class).join(Relation_.aliase)
.as(String.class)),
builder.upper(builder.literal(alias))
)
);
One has to use the ".as(..)" method.
suburbCriteria = criteriaBuilder.equal(
criteriaBuilder.upper(root.get(Property_.suburb)),
criteriaBuilder.upper(criteriaBuilder.literal(searchBean.getSuburb())));
You need to call upper and literal property name on joined Tags from Person.
CriteriaBuilder builder = this.em.getCriteriaBuilder();
CriteriaQuery<Person> query = builder.createQuery(Person.class);
Root<Person> root = query.from(Person.class);
Join<Person, Tag> tags = root.join(Person_.tags);
query.where(builder.isMember(
builder.upper(builder.literal(searchTag)),
builder.upper(builder.literal(tags.get(Tag_.name)))
));
return this.em.createQuery(query).getResultList();
I omitted query.select(root), not sure if it is required.
Tou can also omit builder.literal() on Tag_.name since is String.
If I am wrong somewhere, please edit my answer for further users.
Hope this helps.