Using MailMessage with semi cologn seperation - vb.net

Question

If I manually put my address in for EmailMessage.To.Add(GetDelimitedField(x, strEmailRep, ";")) It sends me the message just fine. However If I use the code as is below which is using a list that looks like ;email1#mail.com;email2.mail.com
Then it gives an error that email address cannot be blank
Somewhere in GetDelimitedField is erasing addresses. I'm not sure where the problem is actually occurring. Here is all the code involved with this.
strmsg = "LOW STOCK ALERT: Component (" & rsMPCS("MTI_PART_NO") & ") has reached or fallen below it's minimum quantity(" & rsMPCS("MIN_QTY") & ")."
Dim EmailMessage As MailMessage = New MailMessage
EmailMessage.From = New MailAddress("noreply#mail.com")
For x = 1 To GetCommaCount(strEmailRep) + 1
EmailMessage.To.Add(GetDelimitedField(x, strEmailRep, ";"))
Next
EmailMessage.Subject = ("LOW STOCK ALERT!")
EmailMessage.Body = strmsg
EmailMessage.Priority = MailPriority.High
EmailMessage.IsBodyHtml = True
Dim smtp As New SmtpClient("smtp.mycompany.com")
smtp.UseDefaultCredentials = True
smtp.Send(EmailMessage)
Public Function GetCommaCount(ByVal sText As String)
Dim X As Integer
Dim Count As Integer
Dim Look As String
For X = 1 To Len(sText)
Look = Microsoft.VisualBasic.Left(sText, X)
If InStr(X, Look, ";", 1) > 0 Then
Count = Count + 1
End If
Next
GetCommaCount = Count
End Function
Public Function GetDelimitedField(ByRef FieldNum As Short, ByRef DelimitedString As String, ByRef Delimiter As String) As String
Dim NewPos As Short
Dim FieldCounter As Short
Dim FieldData As String
Dim RightLength As Short
Dim NextDelimiter As Short
If (DelimitedString = "") Or (Delimiter = "") Or (FieldNum = 0) Then
GetDelimitedField = ""
Exit Function
End If
NewPos = 1
FieldCounter = 1
While (FieldCounter < FieldNum) And (NewPos <> 0)
NewPos = InStr(NewPos, DelimitedString, Delimiter, CompareMethod.Text)
If NewPos <> 0 Then
FieldCounter = FieldCounter + 1
NewPos = NewPos + 1
End If
End While
RightLength = Len(DelimitedString) - NewPos + 1
FieldData = Microsoft.VisualBasic.Right(DelimitedString, RightLength)
NextDelimiter = InStr(1, FieldData, Delimiter, CompareMethod.Text)
If NextDelimiter <> 0 Then
FieldData = Microsoft.VisualBasic.Left(FieldData, NextDelimiter - 1)
End If
GetDelimitedField = FieldData
End Function

Answer 1

You can split the list easier using string.Split:
Dim strEmails = "a#test.com;b#test.com;c#test.com;"
Dim lstEmails = strEmails.Split(";").ToList()
'In case the last one had a semicolon:
If (lstEmails(lstEmails.Count - 1).Trim() = String.Empty) Then
lstEmails.RemoveAt(lstEmails.Count - 1)
End If
If (lstEmails.Count > 0) Then
lstEmails.AddRange(lstEmails)
End If