I am trying to create a report that gives me number to an event that occurred in the week, month and quarter of a specific date.
I have been able to so so for weeks and months but having issue with quarter. I want results for quarter of that specific year- like in the example below for 2016 only.
For example
declare #date date set #date = '2016/02/30'
select case_id, event_date
from #total
WHERE datepart(quarter, event_DATE) = datepart(quarter, #date)
order by 2
when I use this code it gives me result for not only 2016 but also for same quater of 2015,2014 (previous years).
case_id event_date
1234 1986-02-06
5567 2014-01-04
3456 2015-03-11
6378 2016-02-23
4789 2016-02-06
6782 2016-01-04
2346 2016-03-11
9098 2016-02-23
what I want: only for 2016 and not previous years.
case_id event_date
4789 2016-02-06
6782 2016-01-04
2346 2016-03-11
9098 2016-02-23
You could try adding a condition for the year:
[...] AND datepart(year, event_DATE) = datepart(year, #date)
You query would look something like
SELECT case_id, event_date
FROM #total
WHERE datepart(quarter, event_DATE) = datepart(quarter, #date)
AND datepart(year, event_DATE) = datepart(year, #date)
ORDER BY 2
declare #date date set #date = '2016/02/30'
select case_id, event_date
from #total
WHERE datepart(quarter, event_DATE) = datepart(quarter, #date)
AND datepart(YYYY,event_DATE) = '2016'
order by 2
Related
I am using Covid world data, which tracks number of new_cases every day. I have data from 2020-01-01 to present day. This is my current query:
SELECT MIN(date) as week, datepart(iso_week, date) week_num, sum(new_cases) as [Total Cases]
FROM covid_data_cleaned
GROUP BY DATEPART(iso_week, date), DATEPART(year, date)
ORDER BY MIN(date) DESC
Which gives me pretty much what I want except for when the year changes:
week week_num Total Cases
2022-01-10 2 20803473
2022-01-03 1 17217248
**2022-01-01 52 2115780**
**2021-12-27 52 7971560**
2021-12-20 51 5561762
I want to figure out the workaround to combining the '52' values together. Alternatively, my dataset has 112 weeks; can I assign the values 1-112 to the whole dataset rather than 1-52 for each year?
You could aggregate on a correction via a CASE WHEN for the iso year.
SELECT
min(weekstart) as [week]
, [iso_week] as weeknum
, sum(new_cases) as [Total Cases]
FROM
(
SELECT
min([date]) as weekstart
, datepart(iso_week, [date]) as [iso_week]
, case
when month(min([date])) = 1
and datepart(iso_week, [date]) >= 52
then year([date]) - 1
when month(min([date])) = 12
and datepart(iso_week, [date]) = 1
then year([date]) + 1
else year([date])
end as iso_year
, sum(new_cases) as new_cases
FROM covid_data_cleaned
GROUP BY year([date]), datepart(iso_week, [date])
) q
GROUP BY iso_year, [iso_week]
ORDER BY [week] DESC;
Instead of iso week, you can use week.
DECLARE #table table(datev date, new_Cases int)
INSERT INTO #table values
('2022-01-01',123),('2022-01-09',432),('2022-01-03',123),('2021-12-27',234);
SELECT MIN(datev) as week, datepart(week, datev) week_num, sum(new_cases) as [Total Cases]
FROM #table
GROUP BY DATEPART(week, datev), DATEPART(year, datev)
ORDER BY MIN(datev) DESC
week
week_num
Total Cases
2022-01-09
3
432
2022-01-03
2
123
2022-01-01
1
123
2021-12-27
53
234
How to get the complete week number, startdate and enddate of complete year.
Note
Week starts from Sunday to Saturday
at the same time week no 1 (ex: 01-01-2020 to 04-01-2020) and last week should be (ex:27-12-2020 to 31-12-2020)
Expecting result
WeekNo WeekStartDate WeekEndDate
===================================
1 2019-01-01 2019-01-05
2 2019-01-06 2019-01-12
3 2019-01-13 2019-01-19
4 2019-01-20 2019-01-26
5 2019-01-27 2019-02-02
6 2019-02-03 2019-02-09
7 2019-02-10 2019-02-16
8 2019-02-17 2019-02-23
9 2019-02-24 2019-03-02
...
...upto end of the year
Actually I tried this one also rextester
If you are interested in 2019 only, then the following code will produce exactly what you are looking for:
DECLARE #weekNum INT = 1;
WITH Weeks AS (
SELECT #weekNum AS WeekNo
UNION ALL
SELECT WeekNo + 1 FROM Weeks WHERE WeekNo + 1 <= 53
)
SELECT WeekNo,
CASE
WHEN WeekStartDate < '2019-01-01' THEN CONVERT(DATE, '2019-01-01')
ELSE CONVERT(DATE, WeekStartDate)
END AS WeekStartDate,
CASE
WHEN WeekEndDate > '2019-12-31' THEN CONVERT(DATE, '2019-12-31')
ELSE CONVERT(DATE, WeekEndDate)
END AS WeekEndDate
FROM (
SELECT WeekNo,
DATEADD(WEEK, WeekNo - 1, '2018-12-30') AS WeekStartDate,
DATEADD(WEEK, WeekNo - 1, '2019-01-05') AS WeekEndDate
FROM Weeks
) a
OUTPUT:
WeekNo WeekStartDate WeekEndDate
1 2019-01-01 2019-01-05
2 2019-01-06 2019-01-12
3 2019-01-13 2019-01-19
4 2019-01-20 2019-01-26
5 2019-01-27 2019-02-02
6 2019-02-03 2019-02-09
7 2019-02-10 2019-02-16
8 2019-02-17 2019-02-23
...
51 2019-12-15 2019-12-21
52 2019-12-22 2019-12-28
53 2019-12-29 2019-12-31
Edit following OP comment about variable start and end dates
Following OP's comment about varying start and end dates, I've revisited the code and made it such that is can work between any two dates:
DECLARE #startDate DATE = CONVERT(DATE, '2019-01-01');
DECLARE #endDate DATE = CONVERT(DATE, '2019-12-31');
DECLARE #weekNum INT = 1;
WITH Weeks AS (
SELECT #weekNum AS WeekNo
UNION ALL
SELECT WeekNo + 1 FROM Weeks WHERE WeekNo + 1 <= DATEDIFF(WEEK, #StartDate, #EndDate) + 1
)
SELECT WeekNo,
CASE
WHEN WeekStartDate < #startDate THEN #startDate
ELSE CONVERT(DATE, WeekStartDate)
END AS WeekStartDate,
CASE
WHEN WeekEndDate > #endDate THEN #endDate
ELSE CONVERT(DATE, WeekEndDate)
END AS WeekEndDate
FROM (
SELECT WeekNo,
DATEADD(WEEK, WeekNo - 1, OffsetStartDate) AS WeekStartDate,
DATEADD(WEEK, WeekNo - 1, OffsetEndDate) AS WeekEndDate
FROM Weeks
INNER JOIN (
SELECT CASE
WHEN DATEPART(WEEKDAY, #startDate) = 1 THEN #startDate
ELSE DATEADD(DAY, 1 - DATEPART(WEEKDAY, #startDate), #startDate)
END AS OffsetStartDate,
CASE
WHEN DATEPART(WEEKDAY, #startDate) = 1 THEN DATEADD(DAY, 6, #startDate)
ELSE DATEADD(DAY, 7 - DATEPART(WEEKDAY, #startDate), #startDate)
END AS OffsetEndDate
) a ON 1 = 1
) a
Simply modify #startDate and #endDate to reflect the desired start and end dates. The format of the string is YYYY-MM-DD.
This will output a variable number of weeks between the two dates, starting and ending on the specified date (creating partial weeks as needed). Hopefully, as per the requirement.
Slightly update on above answer of Martin. You can pass #startDate and #endDate based on your preference.
DECLARE #startDate DATETIME = '2019-01-01'
DECLARE #endDate DATETIME = '2021-01-01'
DECLARE #totalWeeks BIGINT= NULL
SELECT #totalWeeks =datediff(ww,#startdate,#enddate)
DECLARE #weekNum INT = 1;
WITH Weeks AS (
SELECT #weekNum AS WeekNo
UNION ALL
SELECT WeekNo + 1 FROM Weeks WHERE WeekNo + 1 <= #totalWeeks
)
SELECT WeekNo,
CASE
WHEN WeekStartDate < #startDate THEN CONVERT(DATE, '2019-01-01')
ELSE CONVERT(DATE, WeekStartDate)
END AS WeekStartDate,
CASE
WHEN WeekEndDate > #endDate THEN CONVERT(DATE, '2019-12-31')
ELSE CONVERT(DATE, WeekEndDate)
END AS WeekEndDate
FROM (
SELECT WeekNo,
DATEADD(WEEK, WeekNo - 1, #startDate) AS WeekStartDate,
DATEADD(WEEK, WeekNo - 1, #endDate) AS WeekEndDate
FROM Weeks
) a
OPTION (MAXRECURSION 1000);
I have a table like this
id Date Amount
1 2016-09-29 09:25:37.000 25.13
2 2016-08-01 17:20:39.000 598.00
3 2016-09-29 09:24:47.000 15.60
4 2016-07-28 17:50:11.000 61.80
5 2016-07-28 17:53:56.000 31.40
6 2016-07-22 10:40:27.000 74.16
I'm trying to get two columns like this,
MonthYear Total
Sep 2016 40.73
Aug 2016 598.00
Jul 2016 167.36
But, I want to get most recent year and month to top.
Try this sql,
SELECT CONVERT(CHAR(4), Date, 100) + CONVERT(CHAR(4), Date, 120)
AS MonthYear, SUM(Amount)
AS Total,
CAST(CONVERT(varchar(4), Date, 120) AS int)
AS Year, DATEPART(m, Date) As Month
FROM your_table
GROUP BY CONVERT(CHAR(4), Date, 100) + CONVERT(CHAR(4), Date,120),CAST(CONVERT(varchar(4), Date, 120) AS int), DATEPART(m, Date)
ORDER BY Year DESC, Month DESC
Just an other perspective.
Query
SELECT t.[MonthYear], SUM(t.[Amount]) AS [Total] FROM(
SELECT RIGHT((CONVERT(VARCHAR(11), [Date], 106)), 8) as [MonthYear], [Amount]
FROM [your_table_name]
)t
GROUP BY t.[MonthYear];
Try below
SELECT Datename(MONTH, [Date]) month_name,
Year([Date]) year,
Sum([Amount]),
Month([date]) month_no
FROM #Table1
GROUP BY Datename(MONTH, [Date]),
Year([Date]),
Month([date])
ORDER BY Month([date]) DESC,
Year([Date]),
Datename(MONTH, [Date])
I have a table called dates,
Opendate | Closedate
------------+---------------
2015-07-09 | 2016-08-10
I am expecting the output like,
opendate | closedate | diff
------------+---------------+----------------------
2015-07-09 | 2016-08-10 | 1year 1month 1day
2015-07-09 | 2016-03-01 | 8 months 20 days
2015-07-09 | 2015-07-11 | 2 days
But when I run this query:
SELECT opendate,
closedate,
Datediff(year, opendate, closedate) AS years,
Datediff(month, opendate, closedate) AS months,
Datediff(day, opendate, closedate) AS days
FROM dates
It is giving me an output like,
opendate | closedate | years | months | days
------------+---------------+-------+--------+---------
2015-07-09 | 2016-08-10 | 1 | 13 | 397
How can we calculate 1 year 1 month and 1 day
You can use Stacked CTE to find one by one the next year, month and date.
Explanation
Query Below first finds out the DATEDIFF Years of opendate and closedate and checks if the resulting date is greater than closedate. if it is, the actual year difference is DATEDIFF of Y -1. use this new date and fetch the DATEDIFF of months using the same logic and then get the difference in days.
Online Example
Query
WITH D(Opendate,Closedate)AS
(
SELECT CAST('2015-07-09' AS DATE),CAST('2016-08-10' AS DATE)
UNION ALL
SELECT CAST('2015-07-09' AS DATE),CAST('2016-03-01' AS DATE)
UNION ALL
SELECT CAST('2015-07-09' AS DATE),CAST('2015-07-11' AS DATE)
),Y AS
(
SELECT Opendate,Closedate,
CASE
WHEN DATEADD(YEAR,DATEDIFF(YEAR,Opendate,Closedate),Opendate) > Closedate
THEN DATEDIFF(YEAR,Opendate,Closedate) - 1
ELSE DATEDIFF(YEAR,Opendate,Closedate)
END Years
FROM D
), YDate as
(
SELECT Opendate,Closedate,Years,DATEADD(YEAR,Years,Opendate) as Newopendate
FROM Y
),M AS
(
SELECT Opendate,Closedate,Years,Newopendate,
CASE WHEN DATEADD(MONTH,DATEDIFF(MONTH,Newopendate,Closedate),Newopendate) > Closedate
THEN DATEDIFF(MONTH,Newopendate,Closedate) - 1
ELSE DATEDIFF(MONTH,Newopendate,Closedate)
END Months
FROM YDate
)
SELECT Opendate,Closedate,Years,Months,DATEDIFF(Day,DATEADD(MONTH,Months,Newopendate),Closedate) as days
FROM M
Result
Opendate Closedate Years Months days
09-07-2015 00:00 10-08-2016 00:00 1 1 1
09-07-2015 00:00 01-03-2016 00:00 0 7 21
09-07-2015 00:00 11-07-2015 00:00 0 0 2
SELECT opendate,
closedate,
( ( Datediff(year, opendate, closedate) + 'years' )+
(( Datediff(month, opendate, closedate) -
12 * Datediff(year, opendate, closedate)) + 'months') +
( Datediff(day, opendate, closedate) -
( Datediff(year, opendate, closedate) * 365 -
(Datediff(month, opendate, closedate) * 12) )) + 'days'
FROM dates
The logic is you concatenate the years and then deduct the no of months of a year. Similarly deduct for days as well
Create one function as Below
CREATE FUNCTION dbo.GetYearMonthDays
(
#FromDate DATETIME
)
RETURNS NVARCHAR(100)
AS
BEGIN
DECLARE #date datetime, #tmpdate datetime, #years int, #months int, #days int
SELECT #date =#FromDate
SELECT #tmpdate = #date
SELECT #years = DATEDIFF(yy, #tmpdate, GETDATE()) - CASE WHEN (MONTH(#date) > MONTH(GETDATE())) OR (MONTH(#date) = MONTH(GETDATE()) AND DAY(#date) > DAY(GETDATE())) THEN 1 ELSE 0 END
SELECT #tmpdate = DATEADD(yy, #years, #tmpdate)
SELECT #months = DATEDIFF(m, #tmpdate, GETDATE()) - CASE WHEN DAY(#date) > DAY(GETDATE()) THEN 1 ELSE 0 END
SELECT #tmpdate = DATEADD(m, #months, #tmpdate)
SELECT #days = DATEDIFF(d, #tmpdate, GETDATE())
RETURN CONVERT(varchar(10), #years) +' Years ' + CONVERT(varchar(10), #months) + ' Month ' + CONVERT(varchar(10), #days) + ' Days'
END
GO
And use is as below
SELECT opendate,
closedate,dbo.GetYearMonthDays(closedate)
FROM dates
This will give you what you wants.
I have a table with "date" column. Each row represents a survey.
date
11/19/2013 5:51:41 PM
11/22/2013 1:30:38 PM
11/23/2013 3:09:17 PM
12/2/2014 5:24:17 PM
12/25/2014 11:42:56 AM
1/6/2014 2:24:49 PM
I want to count the number of survey per month cumulatively. As you see from the above table, there are 3 surveys for Nov 2013, 2 surveys for Dec 2013, 1 survey for Jan 2014. The cumulative number of survey per month would be:
month | year | number_of_survey
11 | 2013 | 3
12 | 2013 | 5
1 | 2014 | 6
I have this query which shows correct number of surveys for 2013, and number of survey for 2014 is not cumulative.
with SurveyPerMonth as -- no of Survey per month
(
select datepart(month, s.date) as month,
datepart(year, s.date) as year,
count(*) as no_of_surveys
from myTable s
group by datepart(year, s.date), datepart(month, s.date)
)
select p1.month, p1.year, sum(p2.no_of_surveys) as surveys -- cumulatively
from SurveyPerMonth p1
inner join SurveyPerMonth p2 on p1.month >= p2.month and p1.year>=p2.year **-- the problem is probably comes from this line of code**
group by p1.month, p1.year
order by p1.year, p1.month;
This query returns:
month | year | surveys
11 | 2013 | 3
12 | 2013 | 5
1 | 2014 | 1 // 2014 is not cumulative
How can I calculate cumulative number of surveys per month for 2014 as well?
Something like this ?
SELECT date = create_date INTO #myTable FROM master.sys.objects
;WITH perMonth ( [year], [month], [no_of_surveys])
AS (SELECT DatePart(year, s.date) ,
DatePart(month, s.date),
COUNT(*)
FROM #myTable s
GROUP BY datepart(year, s.date),
datepart(month, s.date))
SELECT [year],
[month],
[no_of_surveys] = ( SELECT SUM([no_of_surveys])
FROM perMonth agg
WHERE (agg.[year] < pm.[year])
OR (agg.[year] = pm.[year] AND agg.[month] <= pm.[month]))
FROM perMonth pm
ORDER BY [year], [month]
Edit: seems I missed the ball with < and >, fixed it and added small example
'--This should work.I have added a new column 'monthyear'
with surveypermonth as -- no of survey per month
(
select datepart(month, s.date) as month,
datepart(year, s.date) as year,
datepart(year, s.date) *100 + datepart(month, s.date) as monthyear,
count(*) as no_of_surveys
from test s
group by datepart(year, s.date), datepart(month, s.date),datepart(year, s.date)*100 + datepart(month, s.date)
)
select a.month,substring(cast(monthyear as varchar(6)),1,4) as year,surveys from
(
select p1.month, p1.monthyear as monthyear, sum(p2.no_of_surveys) as surveys
from surveypermonth p1
inner join surveypermonth p2 on p1.monthyear>=p2.monthyear
group by p1.month, p1.monthyear
--order by p1.monthyear, p1.month
)a