Group By with Min and Max Date using T-SQL - sql

Question

I am trying to do some SQL on the data from the SF Bay Area Bike Share Kaggel Data
When I run this SQL:
/****** Select Bikes ******/
SELECT count(t.[id]) as TripCount
,t.[bike_id]
FROM [dbo].[trip] t
Group By t.[bike_id]
having count(t.[id]) < 25
Order By TripCount asc
I get this result:
+-----------+---------+
| TripCount | bike_id |
+-----------+---------+
| 6 | 876 |
| 18 | 323 |
| 20 | 565 |
| 24 | 476 |
| 24 | 697 |
+-----------+---------+
Where what I really want is this:
+-----------+---------+------------+------------+
| TripCount | bike_id | Min_date | Max_date |
+-----------+---------+------------+------------+
| 6 | 876 | 2014-05-22 | 2014-05-27 |
| 18 | 323 | 2013-08-30 | 2013-09-07 |
| 20 | 565 | 2013-08-29 | 2013-09-07 |
| 24 | 476 | 2013-08-29 | 2013-09-07 |
| 24 | 697 | 2013-10-15 | 2013-12-20 |
+-----------+---------+------------+------------+
where the Min Date & Max Date give respectively the first & last date the bike made a trip.
I can do this manually for each bike by running this:
SELECT
min(cast([start_date] as date)) as Min_Date
,max(cast([start_date] as date)) as Max_Date
,[bike_id]
FROM [dbo].[trip]
where bike_id = '697'
Group By bike_id
I tried this query:
/****** Script for SelectTopNRows command from SSMS ******/
SELECT
count (t.[id]) as TripCount
,min(cast(t.[start_date] as date)) as Min_Date
,max(cast(t.[start_date] as date)) as Max_Date
,[bike_id]
FROM [dbo].[trip] t
Group By count (t.[id]), bike_id
and obviously got the following error:
Cannot use an aggregate or a subquery in an expression used for the group by list of a GROUP BY clause.
Just not quite sure how to wrap my head around this...

Answer 1

You were close
SELECT
[bike_id]
,count (t.[id]) as TripCount
,min(cast(t.[start_date] as date)) as Min_Date
,max(cast(t.[start_date] as date)) as Max_Date
FROM [dbo].[trip] t
Group By bike_id