I have an Access table looking like this:
ID Country Application Date
--------------------------------
12 France 12/01/2016
12 Germany 01/01/2017
13 Germany 01/02/2017
14 Spain 23/01/2017
14 Germany 01/02/2017
15
16 Greece 01/01/2017
I would like to get a single occurence of each ID with the most recent application date.
I tried this:
SELECT ID, Country, Max(Application Date)
FROM MyTable
GROUP BY ID
But Access refused this query and wanted me to add the country in the group by clause, which can't work then.
Moreover, I would like to be able to fetch the rows with no country and application date as well (like the row with ID=15).
The expected result would be:
ID Country Application Date
--------------------------------
12 Germany 01/01/2017
13 Germany 01/02/2017
14 Germany 01/02/2017
15
16 Greece 01/01/2017
I think this is what you may want
select t1.* from MyTable as t1 inner join
(
SELECT ID, Max(Application Date) as Application Date
FROM MyTable
GROUP BY ID
) as t2 on t1.Id=t2.ID and t1.Application Date=t2.Application Date
It works on your input data and returns correct output data. Try it, please )
SELECT d.id, MyTable.country, d.datemax
FROM (SELECT ID as id, Max(AppDate) as datemax
FROM MyTable
GROUP BY ID) as d
,MyTable
WHERE d.id = MyTable.id and datemax = MyTable.appdate
OR (datemax is null and country is null)
Related
I need a Statement that selects all patients and the amount of their appointments and when there are 3 or more appointments that are taking place on the same date they should be counted as one appointment
That is what my Statement looks so far
SELECT PATSuchname, Count(DISTINCT AKTDATUM) AS AKTAnz
FROM tblAktivitaeten
LEFT OUTER JOIN tblPatienten ON (tblPatienten.PATID=tblAktivitaeten.PATID)
WHERE (AKTDeleted<>'J' OR AKTDeleted IS Null)
GROUP BY PATSuchname
ORDER BY AKTAnz DESC
The result should look like this
PATSuchname Appointments
----------------------------------------
Joey Patner 13
Billy Jean 15
Example Name 13
As you can see Joey Patner has 13 Appointments, in the real table though he has 15 appointments but three of them have the same Date and because of that they are only counted as 1
So how can i write a Statement that does exactly that?
(I am new to Stack Overflow, sorry if the format I use is wrong and tell me if it is.
In the table it looks like this.
tblPatienten
----------
PATSuchname PATID
------------------------
Joey Patner 1
Billy Jean 2
Example Name 3
tblAktivitaeten
----------
AKTDatum PATID AKTID
-----------------------------------------
08.02.2021 1 1000 ----
08.02.2021 1 1001 ---- So these 3 should counted as 1
08.02.2021 1 1002 ----
09.05.2021 1 1003
09.07.2021 2 1004 -- these 2 shouldn't be counted as 1
09.07.2021 2 1005 --
Two GROUP BY should do it:
SELECT
x.PATID, PATSuchname, SUM(ApptCount)
FROM (
SELECT
PATID, AKTDatum, CASE WHEN COUNT(*) < 3 THEN COUNT(*) ELSE 1 END AS ApptCount
FROM tblAktivitaeten
GROUP BY
PATID, AKTDatum
) AS x
LEFT JOIN tblPatienten ON tblPatienten.PATID = x.PATID
GROUP BY
x.PATID, PATSuchname
I have one database and time to time i change some part of query as per requirement.
i want to keep record of results of both before and after result of these queries in one table and want to show queries which generate difference.
For Example,
Consider following table
emp_id country salary
---------------------
1 usa 1000
2 uk 2500
3 uk 1200
4 usa 3500
5 usa 4000
6 uk 1100
Now, my before query is :
Before Query:
select count(emp_id) as count,country from table where salary>2000 group by country;
Before Result:
count country
2 usa
1 uk
After Query:
select count(emp_id) as count,country from table where salary<2000 group by country;
After Query Result:
count country
2 uk
1 usa
My Final Result or Table I want is:
column 1 | column 2 | column 3 | column 4 |
2 usa 2 uk
1 uk 1 usa
...... but if query results are same than it shouldn't show in this table.
Thanks in advance.
I believe that you can use the same approach as here.
select t1.*, t2.* -- if you need specific columns without rn than you have to list them here
from
(
select t.*, row_number() over (order by count) rn
from
(
-- query #1
select count(emp_id) as count,country from table where salary>2000 group by country;
) t
) t1
full join
(
select t.*, row_number() over (order by count) rn
from
(
-- query #2
select count(emp_id) as count,country from table where salary<2000 group by country;
) t
) t2 on t1.rn = t2.rn
I have the below table:
name id DOB marks
rk 2 2006-02-03 00:00:00.000 30
mk 3 2006-07-07 00:00:00.000 30
pk 4 2006-04-09 00:00:00.000 30
sk 5 2006-05-03 00:00:00.000 30
fk 6 2006-08-09 00:00:00.000 30
nk 7 2007-08-06 00:00:00.000 30
How can I find the youngest student?
You can order your table by descending date of birth and then filter the first result only, which in SQL Server can be done with
select top 1 *
from yourTable
order by DOB desc
Looks like you just need the latest date of birth (assuming DOB is date of birth):
select max(dob) from yourtable
Then your query would be:
select name as youngestStudent, dob as dateOfBirth
from yourtable
where dob = (select max(dob) from yourtable)
It's simple. According to your given data "nk" is the youngest student, so you can use the following query :
select * from yourtable
where dob = (select max(dob) from yourtable)
I have a table that appears as follows:
Time Name Cust_ID Num_Calls Num_Orders
12.00 ABC 100 20 10
12.25 PQR 102 23 12
12.30 ABC 100 26 15
01.00 ABC 100 26 18
02.00 PQR 102 23 14
04.00 PQR 102 25 20
How do I delete the earlier records for each "Name & Cust_ID" and keep the most recent one. The other fields in the record may change as I run them through my Access Database, but Name and ID remains the same.
My output at the End of the Day should be:
Time Name Cust_ID Num_Calls Num_Orders
01.00 ABC 100 26 18
04.00 PQR 102 25 20
I think if your cust_id is unique, you should make it a primary key in the table.
Then whenever you have a new entry, first check and see if the current cust_id already exists.
If yes, update that entry in the table.
Else do an insert.
Try this...
This should give you your most recent records based on max(time), you could delete the complement of this set.
SELECT * FROM YOUR_TABLE A
INNER JOIN
( SELECT MAX(time) MAX_time
, NAME , CUST_ID
FROM YOUR_TABLE
GROUP BY
NAME , CUST_ID )B
ON A.NAME=B.Name
and A.CUST_ID=B.CUst_ID
and A.time =B.max_time
So you would delete the following records
DELETE FROM YOUR_TABLE
WHERE EXISTS
(SELECT * FROM YOUR_TABLE B
WHERE TIME <>( SELECT MAX(time) FROM YOUR_TABLE C WHERE B.NAME=C.Name
and C.CUST_ID=B.CUst_ID )
AND A.NAME=B.Name
and A.CUST_ID=B.CUst_ID)
I've been trying to build an sql query that finds from (table) the most recent date for selected id's that fulfill the condition where 'type' is in hierarchy 'vegetables'. My goal is to be able to get the whole row once max(date) and hierarchy conditions are met for each id.
Example values
ID DATE PREFERENCE AGE
123 1/3/2013 carrot 14
123 1/3/2013 apple 12
123 1/2/2013 carrot 14
124 1/5/2013 carrot 13
124 1/3/2013 apple 13
124 1/2/2013 carrot 14
125 1/4/2013 carrot 13
125 1/3/2013 apple 14
125 1/2/2013 carrot 13
I tried the following
SELECT *
FROM table
WHERE date in
(SELECT max(date) FROM (table) WHERE id in (123,124,125))
and preference in
(SELECT preference FROM (hierarchy_table)
WHERE hierarchy = vegetables))
and id in (123,24,125)
but it doesn't give me the most recent date for each id that meets the hierarchy conditions. (ex. in this scenario I would only get id 124)
Thank you in advance!
SELECT max(date) FROM (table) WHERE id in (123,124,125)
is giving you the max date from all dates, you need to group them.
Try replacing with:
SELECT max(date) FROM (table) GROUP BY id
This way you will get the max date for each id
I figured this out. Please see the query below as an example:
SELECT * FROM (table) t
WHERE t.date in
(SELECT max(date) FROM table sub_t where t.ID = sub_t.ID and (date !> (currentdate))
and preference in
(SELECT preference FROM (hierarchy_table) WHERE hierarchy ='vegetables')
and ID in ('124')
Change:
max(date)
To:
-- if your date data is in mm/dd/yyyy
max( str_to_date( date, '%m/%d/%Y' ) )
OR
-- if your date data is in dd/mm/yyyy
max( str_to_date( date, '%d/%m/%Y' ) )